R + MonetDB - group by memory footprint - r

I'm about to start using MonetDB soon, but it's a high fixed cost for switching over from MySQL. The main appeal is compiled in-database R.
Question is: How does MonetDB's memory footprint evolve with WHERE and GROUP BY
Consider the following case
"select firm,yearmonth,R_funct_calculate_something(x,y,z,d,e)
FROM monetdb_db.db_table1
WHERE yearmonth between '1999-01-01' and '2010-01-01'
group by firm,yearmonth"
It seems like MonetDB OUGHT to read data equivalent to the size of...
(1)
[size(x)+size(y)+size(z)+size(d)+size(e)+size(firm)+size(yearmonth)] *
group_size
where group size is the size of individual members of firm,yearmonth. I guess in this case bounded at 11years*12months of data.
For me, its obvious that we'll read in only data along the column dimension, but it seems less obvious the row dimension.
(2) Another possibility is instead of group_size, it reads THE WHOLE TABLE into memory.
(3) Another possibility is instead of group_size or the whole table size, it reads the portion of the table that corresponds to the WHERE statement.
Which is it? If its (2) then there's no point for me to switch in the case of very very long datasets, because the whole table being read into memory defeats the point of larger-than-memory data, but I imagine the brilliant minds at MonetDB are doing the smartest thing they can.
Thanks!

Related

For memory, what should be done when you need to constantly grow a vector to an unknown upper limit?

Suppose that you are dealing with a potentially infinite amount of data. Suppose further that you do not have this data stored in memory, but can generate individual terms at will. Finally, suppose that you want to do some experiment on this data that will involve checking a large but unknown amount of terms in a way that necessitates keeping a great many of them in memory. Toy problems with Recamán's sequence, like "find the minimum number terms needed in that sequence for the first 25 even numbers to have appeared", are what I have in mind as typical examples.
The obvious solution to this sort of problem would be to write some code like:
list<-c(first term)
while([not found enough terms yet])
{
nextTerm<-Whatever
if(this term worked){list<-c(list,nextTerm)}
}
However, building a big vector like this by adding one new term at a time is your memory's worst nightmare. The alternative that I often see suggested is to pre-allocate a big vector in memory by making the first line of your code something like list<-numeric(10^6), but those solutions suppose that we have some rough idea of how many terms we need to check, which isn't always the case. So what can we do when we are dealing with an ever-growing list of unknown required length?
This is very popular subject in R check this answer: https://stackoverflow.com/a/45195098/5442527
Summing up:
Do not use c() to bind as providing value by index [ is much faster. I know that it might seem surprising that you could grow pre-allocated vector. Make an iter variable before while loop and increase the index inside the if statement.
Normally like in Python you do not have to care about it when using append. Even starting with empty list is not an problem as the list (reserved memory) grows expotentialy (x2x2x1.5x1.2...) when you pass some perimeter number of elements. Link Over-allocating

Queries on the same big data dataset

Lets say I have a very big dataset (billions of records), one that doesnt fit on a single machine and I want to have multiple unknown queries (its a service where a user can choose a certain subset of the dataset and I need to return the max of that subset).
For the computation itself I was thinking about Spark or something similar, problem is Im going to have a lot of IO/network activity since Spark is going to have to keep re-reading the data set from the disk and distributing it to the workers, instead of, for instance, having Spark divide the data among the workers when the cluster goes up and then just ask from each worker to do the work on certain records (by their number, for example).
So, to the big data people here, what do you usually do? Just have Spark redo the read and distribution for every request?
If I want to do what I said above I have no choice but to write something of my own?
If the queries are known but the subsets unknown, you could precalculate the max (or whatever the operator) for many smaller windows / slices of the data. This gives you a small and easily queried index of sorts, which might allow you to calculate the max for an arbitrary subset. In case a subset does not start and end neatly where your slices do, you just need to process the ‘outermost’ partial slices to get the result.
If the queries are unknown, you might want to consider storing the data in a MPP database or use OLAP cubes (Kylin, Druid?) depending on the specifics; or you could store the data in a columnar format such as Parquet for efficient querying.
Here's a precalculating solution based on the problem description in the OP's comment to my other answer:
Million entries, each has 3k name->number pairs. Given a subset of the million entries and a subset of the names, you want the average for each name for all the entries in the subset. So each possible subset (of each possible size) of a million entries is too much to calculate and keep.
Precalculation
First, we split the data into smaller 'windows' (shards, pages, partitions).
Let's say each window contains around 10k rows with roughly 20k distinct names and 3k (name,value) pairs in each row (choosing the window size can affect performance, and you might be better off with smaller windows).
Assuming ~24 bytes per name and 2 bytes for the value, each window contains 10k*3k*(24+2 bytes) = 780 MB of data plus some overhead that we can ignore.
For each window, we precalculate the number of occurrences of each name, as well as the sum of the values for that name. With those two values we can calculate the average for a name over any set of windows as:
Average for name N = (sum of sums for N)/(sum of counts for N)
Here's a small example with much less data:
Window 1
{'aaa':20,'abcd':25,'bb':10,'caca':25,'ddddd':50,'bada':30}
{'aaa':12,'abcd':31,'bb':15,'caca':24,'ddddd':48,'bada':43}
Window 2
{'abcd':34,'bb':8,'caca':22,'ddddd':67,'bada':9,'rara':36}
{'aaa':21,'bb':11,'caca':25,'ddddd':56,'bada':17,'rara':22}
Window 3
{'caca':20,'ddddd':66,'bada':23,'rara':29,'tutu':4}
{'aaa':10,'abcd':30,'bb':8,'caca':42,'ddddd':38,'bada':19,'tutu':6}
The precalculated Window 1 'index' with sums and counts:
{'aaa':[32,2],'abcd':[56,2],'bb':[25,2],'caca':[49,2],'ddddd':[98,2],'bada':[73,2]}
This 'index' will contain around 20k distinct names and two values for each name, or 20k*(24+2+2 bytes) = 560 KB of data. That's one thousand times less than the data itself.
Querying
Now let's put this in action: given an input spanning 1 million rows, you'll need to load (1M/10k)=100 indices or 56 MB, which fits easily in memory on a single machine (heck, it would fit in memory on your smartphone).
But since you are aggregating the results, you can do even better; you don't even need to load all of the indices at once, you can load them one at a time, filter and sum the values, and discard the index before loading the next. That way you could do it with just a few megabytes of memory.
More importantly, the calculation should take no more than a few seconds for any set of windows and names. If the names are sorted alphabetically (another worthwhile pre-optimization) you get the best performance, but even with unsorted lists it should run more than fast enough.
Corner cases
The only thing left to do is handle the case where the input span doesn't line up exactly with the precalculated windows. This requires a little bit of logic for the two 'ends' of the input span, but it can be easily built into your code.
Say each window contains exactly one week of data, from Monday through Sunday, but your input specifies a period starting on a Wednesday. In that case you would have to load the actual raw data from Wednesday through Sunday of the first week (a few hundred megabytes as we noted above) to calculate the (count,sum) tuples for each name first, and then use the indices for the rest of the input span.
This does add some processing time to the calculation, but with an upper bound of 2*780MB it still fits very comfortably on a single machine.
At least that's how I would do it.

Metadata of a Spark DataFrame (RDD)

I am benchmarking spark in R via "sparklyr" and "SparkR". I test different functions on different Testdata. In two particular cases, where I count the amount of zeros in a column and the amount of NA's in a column, I realized that no matter how big the data is, the result is there in less than a second. All the other computations scale with the size of the data.
So I don't think that Spark computes anything there, but that those cases are stored somewhere in the meta data, and that it computed these results while loading the data. I tested my functions and they always give me the right result.
Can anyone confirm whether the number of zeros and number of nulls in a column is stored in a dataframe's metadata, and if not, why does it return so quickly with the correct value?
There is no metadata associated to a Spark DataFrame that would contain columnar data; therefore, my guess is that the performance difference you measured is caused by something else. Hard to tell without a reproducible example.

How to use daply (from plyr) on 2billion rows using less memory

Does any one know, how one could apply the following function that converts 3 columns table into a matrix using a file that has 2 billion rows (with less than 10GB memory).
where x is 1st, y is 2nd and z is 3rd column.
library(plyr)
daply(a, .(x, y), function(x) x$z)
If you cannot load all the tuples at once
I know this is not the answer you are looking for: use SQLite.
The problem with R is that it must load the entire frame at once. If you don't have enough memory, then it simply can't continue.
SQLite is way smarter than R to do aggregates. Perhaps the most important feature is that it optimizes the memory available, and if it can, it does not need to read all the elements at once. See this for details on how to do it.
http://www.r-bloggers.com/using-sqlite-in-r/
If SQLite does not support the aggregate you want, you can create it yourself (see user defined functions in SQLite).
Alternatively you can try to partition your data (outside R), so you can aggregate in stages. But that will still require some sort of program that can read process the files in less than the available memory. Unix/MacOS/Linux sort is one of those utilities that can deal with more-than-available-memory data. It might be useful.

Sample A CSV File Too Large To Load Into R?

I have a 3GB csv file. It is too large to load into R on my computer. Instead I would like to load a sample of the rows (say, 1000) without loading the full dataset.
Is this possible? I cannot seem to find an answer anywhere.
If you don't want to pay thousands of dollars to Revolution R so that you can load/analyze your data in one go, sooner or later, you need to figure out a way to sample you data.
And that step is easier to happen outside R.
(1) Linux Shell:
Assuming your data falls into a consistent format. Each row is one record. You can do:
sort -R data | head -n 1000 >data.sample
This will randomly sort all the rows and get the first 1000 rows into a separate file - data.sample
(2) If the data is not small enough to fit into memory.
There is also a solution to use database to store the data. For example, I have many tables stored in MySQL database in a beautiful tabular format. I can do a sample by doing:
select * from tablename order by rand() limit 1000
You can easily communicate between MySQL and R using RMySQL and you can index your column to guarantee the query speed. Also you can verify the mean or standard deviation of the whole dataset versus your sample if you want taking the power of database into consideration.
These are the two most commonly used ways based on my experience for dealing with 'big' data.

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