I'm trying to use combo box to control multiple page. I have created some custom widget via coding and also some QFrame in widget form too. But I can't seem to find any solution to go around this. I have try to use Qstackwidget but the program hand in the process.
stackedWidget = new QStackedWidget;
parentLayout1 = new QWidget;
parentLayout2 = new QWidget;
layout1 = new QGridLayout(parentLayout1);
layout2 = new QGridLayout(parentLayout2);
//Default layout to be linearity
layout1->addWidget(ui->TimeL, 0,1);
layout1->addWidget(ui->FreqL, 0,7);
layout1->addWidget(time1, 1,1,3,4);
layout1->addWidget(ui->PlusL, 4,3);
layout1->addWidget(time2, 5,1,3,4);
layout1->addWidget(ui->EqualL, 8,3);
layout1->addWidget(time3, 9,1,3,4);
layout1->addWidget(freq1, 1,7,3,4);
layout1->addWidget(ui->PlusL2, 4,9);
layout1->addWidget(freq2, 5,7,3,4);
layout1->addWidget(ui->EqualL2, 8,9);
layout1->addWidget(freq3, 9,7,3,4);
layout1->addWidget(ui->ProFrame,0,15,3,2);
layout1->addWidget(ui->InfoFrame,10,15,2,2);
layout1->addWidget(ui->LinearFrame,3,15,7,2);
stackedWidget->widget(1)->show();
Can you help me out with this problem? Note that I have multiple Qframe in my form. But I can't seem to hide them when i only want to display 1 qframe.
You have parentLayout1 and parentLayout2 but you never added them to the stacked widget and trying to access the second widget (stackedWidget->widget(1)). Add this before that line.
stackedWidget->addWidget(parentLayout1);
stackedWidget->addWidget(parentLayout2);
Also, you haven't added anything to the second layout layout2.
Related
I'm trying to implement simple tabbed interface with Qt5. I use QTabWidget with QToolBars placed inside its tabs and I add QActions to the QToolBars.
That works but causes the following issue: any action remains accessible only while its parent tab is active. If I try to use keyboard shortcut for currently "invisible" action, I will have no success. Since there's no menu etc, the tabs are the only place, where the actions are placed.
Here's how I add the elements to the toolbar:
QTabWidget *ribbon = new QTabWidget(window);
QToolBar *tool_bar_game = new QToolBar(tab_game);
QAction *action_go_to_next_level = new QAction(window);
action_go_to_next_level->setText(QApplication::translate("Window", "&Next", 0));
action_go_to_next_level->setIcon(QIcon::fromTheme("go-last"));
action_go_to_next_level->setShortcut(QApplication::translate("Window", "PgDown", 0));
ribbon->addTab(tool_bar_game, tr("Game"));
tool_bar_game->addAction(action_go_to_next_level);
and a screenshot:
How can I make the action accessible with shortcuts, even when the action's parent tab is not currently opened?
I'm not surprised that this doesn't work, effectively you try to use a shortcut on a hidden widget. It would be very confusing if this worked.
The obvious workaround for this is to add the shortcut instead of to the QAction to a widget that is always active. Personally, I suggest the window.
Without having tested the code, I believe this should work:
QTabWidget *ribbon = new QTabWidget(window);
QToolBar *tool_bar_game = new QToolBar(tab_game);
QAction *action_go_to_next_level = new QAction(window);
action_go_to_next_level->setText(QApplication::translate("Window", "&Next", 0));
action_go_to_next_level->setIcon(QIcon::fromTheme("go-last"));
QShortcut *page_down = new QShortcut(QKeySequence("PgDown"), window);
// trigger the action when the shortcut is activated
QObject::connect(page_down, &QShortcut::activated,
action_go_to_next_level, &QAction::trigger);
ribbon->addTab(tool_bar_game, tr("Game"));
tool_bar_game->addAction(action_go_to_next_level);
I have a (very simple yet) QTreeView showing some rows:
m_cameraModel = new QStandardItemModel(this);
QSortFilterProxyModel* cameraProxyModel = new QSortFilterProxyModel(this);
cameraProxyModel->setSourceModel(m_cameraModel);
ui.CameraTreeView->setModel(cameraProxyModel);
m_cameraModel->appendRow(new QStandardItem("Panavision"));
m_cameraModel->appendRow(new QStandardItem("Panaflex"));
Here I want to disable the first row "Panavision" so that it is still visible but can't be selected any more and is somehow greyed-out so that the user can see this entry is not active.
May be this is some kind of beginner-question, but how can this be done?
Thanks!
I would try to do that in the following way:
// Get item that corresponds to the first row
QStandardItem *item = m_cameraModel->item(0, 0);
// Disable the item.
item->setFlags(Qt::NoItemFlags);
You'd want to use the QItemDelegate class, which allows you to disable the row you want to amongst other things. There's a good question here on StackOverflow that shows how to do a very basic example: How to set a delegate for a single cell in Qt item view?
I want to undock a QWidget from a QTabWiget (is set as centralWidget). The tab contains some Open Scene Graph content (OpenGL Window). When removing the Tab from the list and putting it into a new Dialog Window (=> undocking from tab) the scene data seems to be corrupt. It works with "standard widgets" but the osg seems to forget the scene.
Surprisingly, undocking works when using a QDockWidget (scene is visible after undocking the window).
Anyone knows how to undock a tab without corrupting the osgViewer?
Code called for to undock from tab and show in new dialog window:
QWidget* gv = // points to an osgViewer in a qt widget
QDialog* dlg = new QDialog(this);
dlg->setWindowTitle("hello earth");
QHBoxLayout* pMainLay = new QHBoxLayout;
gv->setMinimumSize(100,100);
gv->setGeometry(100,100,300,300);
pMainLay->addWidget(gv);
dlg->setLayout(pMainLay);
ui->tabWidget->removeTab(0); // removes the tab at position 0 (docked window)
dlg->show(); // should show the undocked dialog
There is nothing to see in the new dialog. Did I missed something?
How to "copy" the osg view properly into a new widget/dialog? Should I use a composite viewer for this kind of task? It seems there is not even the empty osg view visible (no blue canvas)...
It could be that something's going screwy when you add the osgViewer to another widget before removing it from the QTabWidget. Changing the order might help.
QWidget* gv = // points to an osgViewer in a qt widget
ui->tabWidget->removeTab(0); // removes the tab at position 0 (docked window)
QDialog* dlg = new QDialog(this);
dlg->setWindowTitle("hello earth");
QHBoxLayout* pMainLay = new QHBoxLayout;
pMainLay->addWidget(gv);
dlg->setLayout(pMainLay);
dlg->show(); // should show the undocked dialog
I wanted to make an app which is when started it shows a menu. It is just like when you open a Messaging app in S60. Here is a screenshot.
How do I make it? I have tried to make the centralWidget of the QMainWindow as QMenu, and adding QAction to the QMenu. But when I'm running it, the app don't show anything. And I have tried to make the QMenu using QMenuBar. And it is show okay. But I can't use the up/down key to select menu in the device. And when I press the options key (Qt::PositiveSoftKey), the menubar shows up too. And I didn't even add that to menuBar() which is owned by QMainWindow.
Here is my first code:
QAction* act1= new QAction(tr("act1"),this);
QObject::connect(tes,SIGNAL(triggered()),this,SLOT(close()));
QAction* act2= new QAction(tr("act2"),this);
QObject::connect(tes,SIGNAL(triggered()),this,SLOT(close()));
QMenu* menu = new QMenu(this);
menu->addAction(act1);
menu->addAction(act2);
setCentralWidget(menu);
And it shows nothing at the apps.
And here is my second try:
Qt Code: Switch view
QAction* act1= new QAction(tr("act1"),this);
QObject::connect(tes,SIGNAL(triggered()),this,SLOT(close()));
QAction* act2= new QAction(tr("act2"),this);
QObject::connect(tes,SIGNAL(triggered()),this,SLOT(close()));
QMenuBar* menubar = new QMenuBar(this);
QMenu* menu = menubar->addMenu(tr("menu"));
menu->addAction(act1);
menu->addAction(act2);
setCentralWidget(menu);
It shows the menu. But when I deploy to the device, I can't use the keypad to select the menu. And at the simulator, if I click other place than the QAction item, the menu lost.
I am using another approach by using QPushButton with Vertical Layout. Here is the code:
QWidget* centralWidget = new QWidget(this);
QScrollArea* scrollArea = new QScrollArea(this);
scrollArea->setWidget(centralWidget);
scrollArea->setWidgetResizable(true);
setCentralWidget(scrollArea);
QVBoxLayout* centralLayout = new QVBoxLayout(centralWidget);
QPushButton* button1 = new QPushButton(tr("button 1"));
QPushButton* button2 = new QPushButton(tr("button 2"));
centralLayout->addWidget(button1);
centralLayout->addWidget(button2);
centralLayout->setContentsMargins(0,0,0,0);
button1->setFocus();
Here it's look:
Okay, and that's look good enough. But if that's have 8 button. If it is only have 2 button, it looks like this:
looks kind of weird, huh? Any way to prevent this?
For me, the UI that you're trying to replicate is a list of options, so, why don't try to create the UI based on a list widget?
Asumming that you're going to use a list, you have to options from which you have to choose based on your needs and your app requirements:
Qt Widgets: Available in all the Qt supported Plataforms. Created for desktop and works great on it, but in feel strange on mobile devices. Take a look to the QListWidget and QListView.
Qt Quick: It isn't available for S40 phones or S60 3rd edition, not available for non-touch phones, basically. Created for "touch enabled UI's", it doesn't offer a stable set of widgets (buttons, comboboxes) yet, but it offers a set of primitives (like rectangles or images) that gives you a lot of freedom to create your UI's and it looks pretty good. I think that this is what Lucian used to create the UI from his answer.
This examples could be of particular interest: http://doc.qt.io/archives/qt-4.7/all-examples.html
Run the QtDemo to see all the examples live!
Hope it helps!
EDIT: Adding example of QListWidget
MainWindow::MainWindow(QWidget *parent)
: QMainWindow(parent), ui(new Ui::MainWindow)
{
ui->setupUi(this);
for(int i=0; i<10; i++) {
QListWidgetItem *item = new QListWidgetItem(QIcon("Qt.png"), QString("Item %1").arg(i));
ui->listWidget->insertItem(i, item);
}
ui->listWidget->setIconSize(QSize(64, 64));
connect(ui->listWidget, SIGNAL(itemClicked(QListWidgetItem*)), this, SLOT(onItemClicked(QListWidgetItem*)));
}
void MainWindow::onItemClicked(QListWidgetItem *item)
{
QMessageBox::information(this, "", QString("%1 pressed").arg(item->text()));
}
You have all the freedom in the world to create your layout the way you like. Want those buttons closer together? Want them centered in the view?
The attached image took me 30 seconds to create and looks already decent (according to my pour designer skills).
I'm trying to get every widget to scale with change in window size. I have a main window which has a QTabWidget with a QWidget holder for each tab. I then have a custom widget with a seperate .ui file that I set to fill the QWidget space of the tab. The problem is, I can't get the contents of the QWidget to expand, only the tab and QWidget of the main window. Also, I noticed if i change the ui->setupUi( ) argument for the custom widget from "this" to "parent" the problem is fixed, and the custom widget will scale correctly. The only problem with this is none of the buttons work when I do that. The application output reads out "No Slot" found errors for the buttons. What is the correct way to make this connection?
Edit: Example code
MainWindow:: ...
{
//assign customWidget to widget placeholder on tabWidget.
//holder is just a blank widget set in gridLayout on tab widget.
CustomWidget * customWidget = new CustomWidget(ui->customWidgetHolder);
setCentralWidget(ui->tabWidget);
//This gets the sizing I want with the tabs, but
//doesn't pass it past the customWidgetHolder.
}
From what I undertand, you need to use a layout, for your custom widget inside your tab
QTabWidget* tabWidget = new QTabWidget();
QWidget* tab = new QWidget();
QVBoxLayout* verticalLayout = new QVBoxLayout(tab);
YourWidget* widget = new YourWidget(tab);
verticalLayout->addWidget(widget);
tabWidget->addTab(tab, QString());
But you'll need to be more specific (code sample ?) about the SIGNAL/SLOT connection you've made if you want answer about it.