Using spreadsheet to count consecutive cells - multidimensional-array

Question

So I want to use Google spreadsheet to find how many times does five consecutive cells have a value greater than a given value in a row,but one cell cant be a part of two set of consecutive cells.For example i want to count the number of times a particular item was bought in a month for consecutive five days but if it was bought for 7 days at a stretch it will only be counted as one whereas if it is multiple of five it will be counted as many multiples of five.
For Ex:If cells 1-5 have a value greater than the given value it should give me a count of 1, but if cells 1-9 also are greater than the given value even then it should give me count of 1 but if 1-10 have a value greater than the given value then it should give me a count of 2.I hope this was clear.
I want to write this code in Google Drive using custom function, I tried writing a code in C.
*
int x; //no. of rows
int y; //no. of columns
int arr[x][y]; //array to store numbers
int count[x];
int i,j,k; //for loops
for(i=0;i<x;i++) //set count to 0 for all rows
count[x]=0;
for(i=0;i<x;i++)
{
for(j=0;j<y;j++)
{
for(k=1;k<=5, j<y;k++, j++)
{
if(!arr[i][j]>0)
{
break;
}
else if(k==5 && arr[i][j]!<1)
{
count[i]++;
j--;
}
}
}
}
//display the count array now to see result.
*

Answer 1

You can do this without writing code. That's kinda the purpose of a spreadsheet.
You have one column, say column A, with the values.
In the next column, start a counter that increments each row if the value in the first column is >= your preset value, and reset the counter if not. The formula would be something like (for cell B2)
=IF(A2>=$E$1,B1+1,0)
In the next column, calculate the multiples of 5. For cell C2:
=IF(MOD(B2,5)=0,C1+1,C1)
Copy those cells down to the bottom of the list in column A, and the last value will be the count of values that exceeded cell $e1 a multiple of 5 consecutive times.

Answer 2

Another way using native Sheets functions:
=ArrayFormula((ROWS(A:A)-LEN(REGEXREPLACE(CONCATENATE(LEFT(A:A>=1)),"TTTTT","")))/5)
and using a custom function:
function countGroups(range, comparisonValue, groupSize) {
var v = comparisonValue || 1; // default to comparing to 1 if not specified
var n = groupSize || 5; // default to groups of 5 if not specified
var count = 0, counter = 0;
for (var i = 0, length = range.length; i < length; i++) {
if (range[i][0] >= v) {
counter++;
if (counter == n) {
counter = 0;
count++;
}
}
else
counter = 0;
}
return count;
}