Using jq, how can I limit values based on a key - jq

Question

For an input file that looks like this:
{
"employees": [
{
"number": "101",
"tags": [
{
"value": "yes",
"key": "management"
},
{
"value": "joe",
"key": "login"
},
{
"value": "joe blogs",
"key": "name"
}
]
},
{
"number": "102",
"tags": [
{
"value": "no",
"key": "management"
},
{
"value": "jane",
"key": "login"
},
{
"value": "jane doe",
"key": "name"
}
]
},
{
"number": "103",
"tags": [
{
"value": "no",
"key": "management"
},
{
"value": "john",
"key": "login"
},
{
"value": "john doe",
"key": "name"
}
]
}
]
}
... I'd like to get details for all non-management employees so that the desired output looks like this:
{
"number": "102",
"name": "jane doe",
"login": "jane"
}
{
"number": "103",
"name": "john doe",
"login": "john"
}
I can't figure out how to limit results based on a key without selecting that key (in this case "management")

Answer 1

The following is a slightly more succinct solution:
.employees[]
| .tags |= from_entries
| select(.tags.management == "no")
| {number, "name": .tags.name, "login": .tags.login}

Answer 2

Using from_entries, this worked for me:
$ jq '.employees[] | {number: .number, tags: .tags | from_entries} | select(.tags.management=="no") | {number: .number, name: .tags.name, login: .tags.login}' input
... and the output is:
{
"number": "102",
"name": "jane blogs",
"login": "jane"
}
{
"number": "103",
"name": "john doe",
"login": "john"
}
There may be a better way to achieve what I wanted, so I'll leave the question open for a while if someone wants to offer a better solution.

Answer 3

Here is another solution which uses from_entries
.employees[]
| {number} + (.tags | from_entries)
| if .management == "no" then {number, name, login} else empty end