Reading values for variable in a file using unix - unix

Question

I have a file parama.out having 3 variables like:
p_id
P_level
p_name
And the value for these variable will be User Input at the run-time. I tried using while loop but instead of asking for the user input its moving to the next line and throwing an error.
I used the code:
cat params.out |\
while read line
do
echo "Please provide the value for $line:\c"
read $line
done

Answer 1

There are a few things I used to make this work.
Put "read $line" on a seperate line (or user && or ; to seperate the two commands).
Remove the "\" after pipe to while (I removed the cat and pipe way to input the file).
Add "/dev/tty" to the read command, to let it know where the input should come from. Otherwise it'll take input from the file.
while read line
do
echo "Please provide the value for $line:"
read $line </dev/tty
echo "p_id: $p_id"
echo "p_level: $p_level"
echo "p_name: $p_name"
done < params.out
This gives the following output:
Please provide the value for p_id:
a
p_id: a
p_level:
p_name:
Please provide the value for p_level:
s
p_id: a
p_level: s
p_name:
Please provide the value for p_name:
d
p_id: a
p_level: s
p_name: d