Function to plot model with one variable varying and others constant - r

It's simple, but I can't remember how this procedure is called, hence I was not able to find the function to do so. I want to explore the effects and gradients of a simple lm() model by plotting the response of one variable at a time, the others being kept constant.
Can anybody tell me which function to use to do so? I seem to remember it's a function generating several plots, or something like this. It could be something akin to sensitivity analysis... Sorry for the beginner question.
Thank you in advance!

The car package has a lot of utilities for analyzing regression models. This sounds like a component+residual plot (or partial residuals plot).
library(car) # for avPlots(...)
fit <- lm(mpg~wt+hp+disp, mtcars)
crPlots(fit)
As noted in the comments, termplot(...) does basically the same thing.

Related

How to run Longitudinal Ordinal Logistic Regression in R

I'm working with a large data set with repeated patients over multiple months with ordered outcomes on a severity scale from 1 to 5. I was able to analyze the first set of patients using the polr function to run a basic ordinal logistic regression model, but now want to analyze association across all the time points using a longitudinal ordinal logistic model. I can't seem to find any clear documentation online or on this site so far explaining which package to use and how to use it. I am also an R novice so any simple explanations would be incredibly useful. Based on some initial searching it seems like the mixor function might be what I need though I am not sure how it works. I found it on this site
https://cran.r-project.org/web/packages/mixor/vignettes/mixor.pdf
Would appreciate a simple explanation of how to use this function if this is the right one, or would happily take any alternate suggestions with an explanation.
Thank you in advance for your help!

R: Evaluate Gradient Boosting Machines (GBM) for Regression

Which are the best metrics to evaluate the fit of a GBM algorithm in R (metrics, graphs, ratios)? And how interpret them?
I think maybe you are overthinking this one! Take a step back and think about what matters... the error. You have forecasted values and you have observed values. the difference tells you most of what you need to know when comparing across models. Basic measures like MSE, MPE, etc. should do fine. If you are looking to refine within a given model, I would recommend taking a look at the gbm documentation. For example, you can pass your gbm model object to summary(), to get the relative influence of each of your variables. Additionally, you can find a lot of information in the documentation, so if you haven't taken a look, I would recommend doing so! I have posted the link at the bottom.
-Carmine
gbm_documentation

Trouble with abline

I'm having trouble plotting 2 abline()s on a graph of the log10 Brain mass and log10 body mass. I'm following someone else's script but it just doesn't work for me. This is what I have:
This is the graph produced:
Why are the lines off there like that? Are the values I'm getting for the intercept and slope incorrect, or am I using the wrong ones? I've done other examples of this and its worked OK, but I've always ended up using the first model, never the second one so I'm not sure if I'm using the right values.
If you want to represent a linear regression of the log of the body mass compared to the log of the brain mass, the code is:
model <- lm(log10(brain)~log10(body))
then
abline(model$coefficients[2], model$coefficients[1])
When you don't know which parameter to enter in a function, use the help of that function. For abline(), the first parameter is the slope and the second one is the intercept.
Currently, your model use log10(brain), log10(body) and class.
If you want to assess the quality of your model, look at the residuals.
plot(model)
You can also just use the result of your lm like this:
model <- lm(log10(brain)~log10(body))
plot(log10(brain)~log10(body))
abline(model,col=2)

Order lattice panel by regression intercept

Example dataset here
Let us build a simple lattice plot from this data for linear regression, with separate panels for each Subject
xyplot(Measurement~HOL|Subject,groups=Treatment,data=Data,
type=c('p','r'),auto.key=T,aspect="xy")
The issue is, I would like to visually inspect if the slopes-and-intercepts are correlated. Thus, I would like to order the panels by linear-regression intercept as opposed to by Subject (this was done in Douglas Bates' book "lme4: Mixed-effects modeling with R" Figure 3.1, but I cannot find example code). I know I can change the order of panels by hand by adding
index.cond=list(c(1,2,3, etc))
But this is extraordinarily inefficient, especially since I would like to do this for multiple response variables.
Does anyone have an automated way to do this? I am also open to attempting this in ggplot2 if it has any built in functions, but as I understand, there is no way to easily change the aspect to a 45degree such as the
aspect="xy"
does in Lattice.
Thank you in advance for any thoughts
If you want to order by regression intercept, it's best to run the regression. For example, with your data we can do
cf<-sapply(Data$Subject, function(x)
coef(lm(Measurement~HOL, data=subset(Data, Subject==x))))
which will give a slope/intercept for each person, we can then create a new factor of Subjects ordered by the intercept with
Sx<-reorder(Data$Subject, cf[1,])
and then use that variable as the grouping variable in the plot
xyplot(Measurement~HOL|Sx,groups=Treatment,data=Data,
type=c('p','r'),auto.key=T,aspect="xy")
And in ggplot you can fix the ratio of x/y with +coord_fixed(ratio=1)

How can I estimate the logarithmic form of data points using R?

I have data points that represent a logarithmic function.
Is there an approach where I can just estimate the function that describes this data using R?
Thanks.
I assume that you mean that you have vectors y and x and you try do fit a function y(x)=Alog(x).
First of all, fitting log is a bad idea, because it doesn't behave well. Luckily we have x(y)=exp(y/A), so we can fit an exponential function which is much more convenient. We can do it using nonlinear least squares:
nls(x~exp(y/A),start=list(A=1.),algorithm="port")
where start is an initial guess for A. This approach is a numerical optimization, so it may fail.
The more stable way is to transform it to a linear function, log(x(y))=y/A and fit a straight line using lm:
lm(log(x)~y)
If I understand right you want to estimate a function given some (x,y) values of it. If yes check the following links.
Read about this:
http://en.wikipedia.org/wiki/Spline_%28mathematics%29
http://en.wikipedia.org/wiki/Polynomial_interpolation
http://en.wikipedia.org/wiki/Newton_polynomial
http://en.wikipedia.org/wiki/Lagrange_polynomial
Googled it:
http://www.stat.wisc.edu/~xie/smooth_spline_tutorial.html
http://stat.ethz.ch/R-manual/R-patched/library/stats/html/smooth.spline.html
http://www.image.ucar.edu/GSP/Software/Fields/Help/splint.html
I never used R so I am not sure if that works or not, but if you have Matlab i can explain you more.

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