trsp := &http.Transport{
TLSClientConfig: &tls.Config{InsecureSkipVerify: true},
}
Url := "https://127.0.0.1:8080"
client := &http.Client{Transport: trsp}
request, _ := http.NewRequest("POST", Url, nil)
k, _ := os.Open(nameOfFile)
request.Header.Set("Action", "download"+k.Name())
...
...
client.Do(request)
I have server, and I need to upload to server a file. What should I do with request? As I think I shoud write into request.Body and then, from server handle this query
you need use the "mime/multipart"package to make the http body. like this.
http://matt.aimonetti.net/posts/2013/07/01/golang-multipart-file-upload-example/
func newfileUploadRequest(uri string, params map[string]string, paramName, path string) (*http.Request, error) {
file, err := os.Open(path)
if err != nil {
return nil, err
}
defer file.Close()
body := &bytes.Buffer{}
writer := multipart.NewWriter(body)
part, err := writer.CreateFormFile(paramName, filepath.Base(path))
if err != nil {
return nil, err
}
_, err = io.Copy(part, file)
for key, val := range params {
_ = writer.WriteField(key, val)
}
err = writer.Close()
if err != nil {
return nil, err
}
return http.NewRequest("POST", uri, body)
}
Related
trying to post multipart/form-data image using go
image file receive from request client and already saved as multipart.File
here my code
func postImage(file multipart.File, url string, filename string) (*http.Response, error) {
r, w := io.Pipe()
defer w.Close()
m := multipart.NewWriter(w)
defer m.Close()
errchan := make(chan error)
defer close(errchan)
go func() {
part, err := m.CreateFormFile("file", filename)
log.Println(err)
if err != nil {
errchan <- err
return
}
if _, err := io.Copy(part, file); err != nil {
errchan <- err
return
}
}()
merr := <-errchan
if merr != nil {
return nil, merr
}
resp, err := http.Post(url, m.FormDataContentType(), r)
if err != nil {
return nil, err
}
defer resp.Body.Close()
return resp, err
}
when i try using it, it stuck at part, err := m.CreateFormFile("file", filename) never return anything
any solution?
Thanks
Use the pipe error to propagate the error back to the main goroutine. Close the write side of the pipe to prevent the client from blocking forever on read. Close the read side of the pipe to ensure that the goroutine exits.
func postImage(file multipart.File, url string, filename string) (*http.Response, error) {
r, w := io.Pipe()
// Close the read side of the pipe to ensure that
// the goroutine exits in the case where http.Post
// does not read all of the request body.
defer r.Close()
m := multipart.NewWriter(w)
go func() {
part, err := m.CreateFormFile("file", filename)
if err != nil {
// The error is returned from read on the pipe.
w.CloseWithError(err)
return
}
if _, err := io.Copy(part, file); err != nil {
// The error is returned from read on the pipe.
w.CloseWithError(err)
return
}
// The http.Post function reads the pipe until
// an error or EOF. Close to return an EOF to
// http.Post.
w.Close()
}()
resp, err := http.Post(url, m.FormDataContentType(), r)
if err != nil {
return nil, err
}
defer resp.Body.Close()
return resp, err
}
I'm trying to pass the values I get in the arg / flag --BODY="{user: root}" as the body of the post request I'm trying to do, I've already used json.Marshal and even so I wasn't successful, thanks for the help !
Code below:
func Custom(method string, url string, token string, data string) {
req, err := http.NewRequest("POST", url, bytes.NewBuffer(data))
req.Header.Add("Authorization", FormatBearerToken(token))
// req.Header.Set("Content-Type", "application/json")
if err != nil {
log.Println("Request failed, ", err)
}
client := &http.Client{}
resp, err := client.Do(req)
if err != nil {
log.Println(err)
}
defer resp.Body.Close()
body, _ := ioutil.ReadAll(resp.Body)
log.Println("response Body:", string(body))
}
I'm trying to create a simple http service with the endpoint to download file to the local system in Go. The link comes in ?uri tag, but when I want to get it I receive an empty string. I tried to parse the form of my request but it didn't help. Here is my code:
func main() {
http.HandleFunc("/download", DownloadHandler)
log.Fatal(http.ListenAndServe(":8080", nil))
}
func DownloadHandler(writer http.ResponseWriter, request *http.Request) {
prsErr := request.ParseForm()
if prsErr != nil{
panic(prsErr)
}
uri := request.FormValue("?uri")
_, _ = writer.Write([]byte(uri))
err := DownloadFile("img.png", uri)
if err != nil {
panic(err)
}
}
func DownloadFile(filepath string, url string) error {
// Create the file
out, err := os.Create(filepath)
if err != nil {
return err
}
defer out.Close()
// Get the data
resp, err := http.Get(url)
if err != nil {
return err
}
defer resp.Body.Close()
// Write the body to file
_, err = io.Copy(out, resp.Body)
if err != nil {
return err
}
return nil
}
I will appreciate any help! Thank you!
invalid at request.FormValue("?uri")
uri := request.FormValue("uri")
How do I POST to an API with Content-Type: multipart/form-data, []byte parameters and string arguments? I have tried, but it is failing.
Error message:
details: "[301 301 Moved Permanently]<!DOCTYPE HTML PUBLIC \"-//IETF//DTD HTML 2.0//EN\">\r\n<html>\r\n301 Moved Permanently\r\n<body bgcolor=\"white\">\r\n301 Moved Permanently\r\n<p>The requested resource has been assigned a new permanent URI.</p >\r\n<hr/>Powered by Tengine/2.1.0</body>\r\n</html>\r\n"
Go code:
func NewPost2(url string) ([]byte, error) {
m := make(map[string]interface{}, 0)
m["fileName"] ="good"
m["name"] = Base64ToByte("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")
b, _ := json.Marshal(m)
httpReq, err := http.NewRequest("POST", url, bytes.NewBuffer(b))
httpReq.Header.Set("Content-Type", "multipart/form-data;charset=UTF-8")
client := &http.Client{}
resp, err := client.Do(httpReq)
if err != nil {
return nil, err
}
defer resp.Body.Close()
if resp.StatusCode < 200 || resp.StatusCode >= 300 {
b, _ := ioutil.ReadAll(resp.Body)
return nil, fmt.Errorf("[%d %s]%s", resp.StatusCode, resp.Status, string(b))
}
respData, err := ioutil.ReadAll(resp.Body)
if err != nil {
return nil, err
}
return respData, nil
}
Now, I am very happy with the mood to share my solution
func NewPostFile(url string, paramTexts map[string]interface{}, paramFile FileItem) ([]byte, error) {
// if paramFiles ==nil {
// return NewPost(url,paramTexts,header,transport)
// }
bodyBuf := &bytes.Buffer{}
bodyWriter := multipart.NewWriter(bodyBuf)
for k, v := range paramTexts {
bodyWriter.WriteField(k, v.(string))
}
fileWriter, err := bodyWriter.CreateFormFile(paramFile.Key, paramFile.FileName)
if err != nil {
fmt.Println(err)
//fmt.Println("Create form file error: ", error)
return nil, err
}
fileWriter.Write(paramFile.Content)
contentType := bodyWriter.FormDataContentType()
bodyWriter.Close()
fmt.Println(bodyBuf.String())
resp, err := http.Post(url, contentType, bodyBuf)
if err != nil {
return nil, err
}
defer resp.Body.Close()
fmt.Println(resp)
if resp.StatusCode < 200 || resp.StatusCode >= 300 {
b, _ := ioutil.ReadAll(resp.Body)
return nil, fmt.Errorf("[%d %s]%s", resp.StatusCode, resp.Status, string(b))
}
respData, err := ioutil.ReadAll(resp.Body)
if err != nil {
return nil, err
}
fmt.Println(string(respData))
return respData, nil
}
type FileItem struct {
Key string //image_content
FileName string //test.jpg
Content []byte //[]byte
}
I wrapped the multipart code in a function, as you need to Close it before you
can make a request. Also my method is using # as a heuristic, similar to
cURL [1]:
package main
import (
"bytes"
"io"
"mime/multipart"
"os"
"strings"
)
func createForm(form map[string]string) (string, io.Reader, error) {
body := new(bytes.Buffer)
mp := multipart.NewWriter(body)
defer mp.Close()
for key, val := range form {
if strings.HasPrefix(val, "#") {
val = val[1:]
file, err := os.Open(val)
if err != nil { return "", nil, err }
defer file.Close()
part, err := mp.CreateFormFile(key, val)
if err != nil { return "", nil, err }
io.Copy(part, file)
} else {
mp.WriteField(key, val)
}
}
return mp.FormDataContentType(), body, nil
}
Example:
package main
import "net/http"
func main() {
form := map[string]string{"profile": "#portrait.jpg", "name": "John"}
ct, body, err := createForm(form)
if err != nil {
panic(err)
}
http.Post("https://stackoverflow.com", ct, body)
}
https://curl.se/docs/manpage.html#-F
On a 301 response, the new url is specified in the headers of the response, not its body
(see https://en.wikipedia.org/wiki/HTTP_301)
try printing :
resp.Header["Location"]
If you have this error as a final response, this also means that the http.Client chose to not follow this redirection.
The doc says that the dafult policy for a Client is to follow up to 10 redirects.
In order to debug redirects, you can write your own CheckRedirect function, which can for instance print the sequence of urls
I need to call multiple URL at the same time. My functions get called at the same time (in milli seconds) but the moment I add a Http post request to the code it gets called one after the other. Below is the code:
Check(url1)
Check(url2)
func Check(xurl string) {
nowstartx := time.Now()
startnanos := nowstartx.UnixNano()
nowstart := startnanos / 1000000
fmt.Println(nowstart)
json = {"name" : "test"}
req, err := http.NewRequest("POST", xurl, bytes.NewBuffer(json))
req.Header.Set("X-Custom-Header", "myvalue")
req.Header.Set("Content-Type", "application/json")
client := &http.Client{}
resp, err := client.Do(req)
if err != nil {
panic(err)
} else {
defer resp.Body.Close()
body, _ = ioutil.ReadAll(resp.Body)
}
}
Appreciate help, I need to get the same time (in milliseconds) when I run the program.
This is achieved by using Goroutines
go Check(url1)
go Check(url2)
func Check(xurl string) {
nowstartx := time.Now()
startnanos := nowstartx.UnixNano()
nowstart := startnanos / 1000000
fmt.Println(nowstart)
json = {"name" : "test"}
req, err := http.NewRequest("POST", xurl, bytes.NewBuffer(json))
req.Header.Set("X-Custom-Header", "myvalue")
req.Header.Set("Content-Type", "application/json")
client := &http.Client{}
resp, err := client.Do(req)
if err != nil {
panic(err)
} else {
defer resp.Body.Close()
body, _ = ioutil.ReadAll(resp.Body)
}
}