I am adding text to different panels of a xyplot in lattice and was wondering if anyone knows a way to not specify a x and y coordinates or is there something similar to legend where you can say upper left or upper right,etc?
I ask because I want to use scales=free in the plotting code, but when I do the text in the mytext code ends up covering up parts of the graph and doesn't make for a good plot. I would like to have a way to plot the graphs without making individual plots because in my real dataset I have up to 10 grouping factor levels (sams in the code). The example provided is not as extreme as the real data.
Example data
d_exp<-data.frame(sams=c(rep("A",6),rep("B",6),rep("C",6)),
gear=c(rep(1:2,9)),
fraction=c(.12,.61,.23,.05,.13,.45,0.3,.5,.45,.20,.35,.10,.8,.60,.10,.01,.23,.03),
interval=c(rep(c(0,10,20),6)))
d_exp<-d_exp[order(d_exp$sams,d_exp$gear,d_exp$interval),]
Plot with scales=same. mytext x and y coordinates are specified.
mytext<-c("N=3","N=35","N=6")
panel.my <- function(...) {
panel.superpose(col=c("red","blue"),lwd=1.5,...)
panel.text(x=2.5,y=0.5,labels=mytext[panel.number()],cex=.8)
}
xyplot(fraction~interval | sams, data=d_exp,groups=gear,type="l",
scales=list(relation="same",y=list(alternating=1,cex=0.8),x=list(alternating=1,cex=.8,abbreviate=F)),
strip = strip.custom(bg="white", strip.levels = T),drop.unused.levels=T,as.table=T,
par.strip.text=list(cex=0.8),panel=panel.my)
Same thing with scales=free. Text is in odd places because all text has the same coordinates.
xyplot(fraction~interval | sams, data=d_exp,groups=gear,type="l",
scales=list(relation="free",y=list(alternating=1,cex=0.8),x=list(alternating=1,cex=.8,abbreviate=F)),
strip = strip.custom(bg="white", strip.levels = T),drop.unused.levels=T,as.table=T,
par.strip.text=list(cex=0.8),panel=panel.my)
Thanks for any help.
You can use grid.text() to specify units in a range-independent way. For example
library(grid)
panel.my <- function(...) {
panel.superpose(col=c("red","blue"),lwd=1.5,...)
grid.text(x=.5,y=.8,label=mytext[panel.number()])
}
With grid.text the x and y values use npc units by default which range from 0 to 1. So x=.5 means centered and y=.8 means 80% of the way to the top.
Related
Is there a way to add text labels to the points on a scatterplot? Each point has a string associated with it as its label. I like to label only as many points as it can be done withour overlapping?
df = DataFrame(x=rand(100), y=rand(100), z=randstring.(fill(5,100)))
scatter(df.x, df.y)
annotate!(df.x, df.y, text.(df.z))
using StatisticalGraphics package:
using InMemoryDatasets
using StatisticalGraphics
using Random
ds=Dataset(x=rand(100), y=rand(100), z=randstring.(fill(5,100)))
sgplot(ds, Scatter(x=:x,y=:y,labelresponse=:z))
Here is something I wrote for Makie.jl that suited my needs:
Non-overlapping labels for scatter plots
It works best for single line, short text labels, and where all labels have similar lengths with one another. It is still WIP, as I am working to improve it for placement of longer text labels.
Here are some samples of what it can do:
Essentially, you call function viz to plot a scatter chart on your (x, y) data set:
resolution = (600, 600) # figure size (pixels) -- need not be a equal dimension
fontpt = 12 # label font size (points)
flabel = 1.5 # inflate the label size to create some margins
fdist = 0.3 # inflate the max. distance between a label and its
# anchor point before a line is drawn to connect. them.
# Smaller values would create more connecting lines.
viz(x, y, labels; resolution=resolution, flabel=flabel, fdist=fdist, fontpt=fontpt)
where labels is a list containing the text labels for every pair of (x, y) point.
You can use the extra named argument series_annotations in the scatter function. Here us an example where I use "1", "2", etc. as labels:
using Plots
x = collect(0:0.1:2)
y = sinpi.(x)
scatter(x, y, series_annotations = text.(1:length(x), :top))
Avoiding overlaps is more difficult. You could customize your label with empty "" for duplicates where the points are the same, or see for Makie: Makie: Non-overlapping label placement algorithm for scatter plots
I'm trying plots a graph lines using ggplot library in R, but I get a good plots but I need reduce the gradual space or height between rows grid lines because I get big separation between lines.
This is my R script:
library(ggplot2)
library(reshape2)
data <- read.csv('/Users/keepo/Desktop/G.Con/Int18/input-int18.csv')
chart_data <- melt(data, id='NRO')
names(chart_data) <- c('NRO', 'leyenda', 'DTF')
ggplot() +
geom_line(data = chart_data, aes(x = NRO, y = DTF, color = leyenda), size = 1)+
xlab("iteraciones") +
ylab("valores")
and this is my actual graphs:
..the first line is very distant from the second. How I can reduce heigth?
regards.
The lines are far apart because the values of the variable plotted on the y-axis are far apart. If you need them closer together, you fundamentally have 3 options:
change the scale (e.g. convert the plot to a log scale), although this can make it harder for people to interpret the numbers. This can also change the behavior of each line, not just change the space between the lines. I'm guessing this isn't what you will want, ultimately.
normalize the data. If the actual value of the variable on the y-axis isn't important, just standardize the data (separately for each value of leyenda).
As stated above, you can graph each line separately. The main drawback here is that you need 3 graphs where 1 might do.
Not recommended:
I know that some graphs will have the a "squiggle" to change scales or skip space. Generally, this is considered poor practice (and I doubt it's an option in ggplot2 because it masks the true separation between the data points. If you really do want a gap, I would look at this post: axis.break and ggplot2 or gap.plot? plot may be too complexe
In a nutshell, the answer here depends on what your numbers mean. What is the story you are trying to tell? Is the important feature of your plots the change between them (in which case, normalizing might be your best option), or the actual numbers themselves (in which case, the space is relevant).
you could use an axis transformation that maps your data to the screen in a non-linear fashion,
fun_trans <- function(x){
d <- data.frame(x=c(800, 2500, 3100), y=c(800,1950, 3100))
model1 <- lm(y~poly(x,2), data=d)
model2 <- lm(x~poly(y,2), data=d)
scales::trans_new("fun",
function(x) as.vector(predict(model1,data.frame(x=x))),
function(x) as.vector(predict(model2,data.frame(y=x))))
}
last_plot() + scale_y_continuous(trans = "fun")
enter image description here
Is it possible to put a text box so many cm/inches above a line in graph in R? (Whithout changing scale of graph). So im plotting the image using plot and i want to specify that the text using the function: text() but I always want the text to be 1cm above the arrow at the specified x-coordinate.
enter image description here
You can do this simply with ?text. So not entirely with cm's but if you know the range of your data you can position your text as data points in the plot.
Example:
Let's make some test data.
dat <- matrix(rnorm(3*4), ncol=2)
colnames(dat) <- c("v1", "v2")
Create a scatter plot. You can of course apply text to any graphical plot, but I'm keeping it simple.
plot(v2 ~ v1, data = dat)
And now just create a line, in whatever direction. I'll just go with an abline at height 1.0 on the y-axis
abline(h=1.0)
text(1,1,"this is an abline", pos = 1)
With text I add text on position 1,1 (x, y) in the plot. I adjust it with pos so It doesn't get crossed by the abline.
Good luck!
iFacColName <- "hireMonth"
iTargetColName <- "attrition"
iFacVector <- as.factor(c(1,1,1,1,10,1,1,1,12,9,9,1,10,12,1,9,5))
iTargetVector <- as.factor(c(1,1,0,1,1,0,0,1,1,0,1,0,1,1,1,1,1))
sp <- spineplot(iFacVector,iTargetVector,xlab=iFacColName,ylab=iTargetColName,main=paste0(iFacColName," vs. ",iTargetColName," Spineplot"))
spLabelPass <- sp[,2]/(sp[,1]+sp[,2])
spLabelFail <- 1-spLabelPass
text(seq_len(nrow(sp)),rep(.95,length(spLabelPass)),labels=as.character(spLabelPass),cex=.8)
For some reason, the text() function only plots one label far to the right of the graph. I have used this format to apply data labels to other types of graphs, so I am confused.
EDIT: added more code to make example work
You're not placing your labels inside the plotting region. It only extends to around 1.3 on the x axis. Try plotting something like
text(
cumsum(prop.table(table(iFacVector))),
rep(.95, length(spLabelPass)),
labels = as.character(round(spLabelPass, 1)),
cex = .8
)
and you'll get something like
This is obviously not the right positions for the labels, but you should be able to figure that out by yourself. (You're going to have to subtract half of the frequency for each bar from the cumulative frequency and account for the fact that the bars are padded with some amount of whitespace.
I'm looking to plot a set of sparklines in R with just a 0 and 1 state that looks like this:
Does anyone know how I might create something like that ideally with no extra libraries?
I don't know of any simple way to do this, so I'm going to build up this plot from scratch. This would probably be a lot easier to design in illustrator or something like that, but here's one way to do it in R (if you don't want to read the whole step-by-step, I provide my solution wrapped in a reusable function at the bottom of the post).
Step 1: Sparklines
You can use the pch argument of the points function to define the plotting symbol. ASCII symbols are supported, which means you can use the "pipe" symbol for vertical lines. The ASCII code for this symbol is 124, so to use it for our plotting symbol we could do something like:
plot(df, pch=124)
Step 2: labels and numbers
We can put text on the plot by using the text command:
text(x,y,char_vect)
Step 3: Alignment
This is basically just going to take a lot of trial and error to get right, but it'll help if we use values relative to our data.
Here's the sample data I'm working with:
df = data.frame(replicate(4, rbinom(50, 1, .7)))
colnames(df) = c('steps','atewell','code','listenedtoshell')
I'm going to start out by plotting an empty box to use as our canvas. To make my life a little easier, I'm going to set the coordinates of the box relative to values meaningful to my data. The Y positions of the 4 data series will be the same across all plotting elements, so I'm going to store that for convenience.
n=ncol(df)
m=nrow(df)
plot(1:m,
seq(1,n, length.out=m),
# The following arguments suppress plotting values and axis elements
type='n',
xaxt='n',
yaxt='n',
ann=F)
With this box in place, I can start adding elements. For each element, the X values will all be the same, so we can use rep to set that vector, and seq to set the Y vector relative to Y range of our plot (1:n). I'm going to shift the positions by percentages of the X and Y ranges to align my values, and modified the size of the text using the cex parameter. Ultimately, I found that this works out:
ypos = rev(seq(1+.1*n,n*.9, length.out=n))
text(rep(1,n),
ypos,
colnames(df), # These are our labels
pos=4, # This positions the text to the right of the coordinate
cex=2) # Increase the size of the text
I reversed the sequence of Y values because I built my sequence in ascending order, and the values on the Y axis in my plot increase from bottom to top. Reversing the Y values then makes it so the series in my dataframe will print from top to bottom.
I then repeated this process for the second label, shifting the X values over but keeping the Y values the same.
text(rep(.37*m,n), # Shifted towards the middle of the plot
ypos,
colSums(df), # new label
pos=4,
cex=2)
Finally, we shift X over one last time and use points to build the sparklines with the pipe symbol as described earlier. I'm going to do something sort of weird here: I'm actually going to tell points to plot at as many positions as I have data points, but I'm going to use ifelse to determine whether or not to actually plot a pipe symbol or not. This way everything will be properly spaced. When I don't want to plot a line, I'll use a 'space' as my plotting symbol (ascii code 32). I will repeat this procedure looping through all columns in my dataframe
for(i in 1:n){
points(seq(.5*m,m, length.out=m),
rep(ypos[i],m),
pch=ifelse(df[,i], 124, 32), # This determines whether to plot or not
cex=2,
col='gray')
}
So, piecing it all together and wrapping it in a function, we have:
df = data.frame(replicate(4, rbinom(50, 1, .7)))
colnames(df) = c('steps','atewell','code','listenedtoshell')
BinarySparklines = function(df,
L_adj=1,
mid_L_adj=0.37,
mid_R_adj=0.5,
R_adj=1,
bottom_adj=0.1,
top_adj=0.9,
spark_col='gray',
cex1=2,
cex2=2,
cex3=2
){
# 'adJ' parameters are scalar multipliers in [-1,1]. For most purposes, use [0,1].
# The exception is L_adj which is any value in the domain of the plot.
# L_adj < mid_L_adj < mid_R_adj < R_adj
# and
# bottom_adj < top_adj
n=ncol(df)
m=nrow(df)
plot(1:m,
seq(1,n, length.out=m),
# The following arguments suppress plotting values and axis elements
type='n',
xaxt='n',
yaxt='n',
ann=F)
ypos = rev(seq(1+.1*n,n*top_adj, length.out=n))
text(rep(L_adj,n),
ypos,
colnames(df), # These are our labels
pos=4, # This positions the text to the right of the coordinate
cex=cex1) # Increase the size of the text
text(rep(mid_L_adj*m,n), # Shifted towards the middle of the plot
ypos,
colSums(df), # new label
pos=4,
cex=cex2)
for(i in 1:n){
points(seq(mid_R_adj*m, R_adj*m, length.out=m),
rep(ypos[i],m),
pch=ifelse(df[,i], 124, 32), # This determines whether to plot or not
cex=cex3,
col=spark_col)
}
}
BinarySparklines(df)
Which gives us the following result:
Try playing with the alignment parameters and see what happens. For instance, to shrink the side margins, you could try decreasing the L_adj parameter and increasing the R_adj parameter like so:
BinarySparklines(df, L_adj=-1, R_adj=1.02)
It took a bit of trial and error to get the alignment right for the result I provided (which is what I used to inform the default values for BinarySparklines), but I hope I've given you some intuition about how I achieved it and how moving things using percentages of the plotting range made my life easier. In any event, I hope this serves as both a proof of concept and a template for your code. I'm sorry I don't have an easier solution for you, but I think this basically gets the job done.
I did my prototyping in Rstudio so I didn't have to specify the dimensions of my plot, but for posterity I had 832 x 456 with the aspect ratio maintained.