This may seem obvious but I'm having a hard time finding the answer.
I have a List of file paths which are stored as relative file paths.
("~\Data\1f492f55-c7ad-44ae-8cbc-93885ac4383a.jpg")
These files can be jpgs,docs or PDFs.
How can I give a View functionality?
You may use the File method to render content of a file (PDF /JPG etc..)
public ActionResult Index()
{
var filePath = #"C:\\temp\tempFile.pdf";
return File(filePath, "application-pdf", "YourFriendlyFileName.pdf");
}
You may change the code the get the file paths and replace it with the hardcoded file path above.
Upload them to the application and use relative path.
As localhost:80/images/image1.jpg
Found the below solution.This support any file types.
public FileResult Download(int id)
{
var filePath = #"~\\Data\0e383d46-021d-48b4-9f03-e9a70bc894f7.jpg";
//var filePath = #"~\\Data\\file.pdf";
//var filePath = #"~\\Data\\word.docx";
string fileName = Path.GetFileName(careTakerFile.FilePath);
return File(filePath, System.Net.Mime.MediaTypeNames.Application.Octet, fileName);
}
Related
I am creating json files FileSystem.AppDataDirectory, "test"," {Hour}.json "; I can see the files on the device in Xcode.. once I return only one with this Path.Combine(FileSystem.AppDataDirectory, "test",".json") then I can read its content.
However once I need to return all files from the directory and list the path to them in my application
var result = Directory.EnumerateFiles(FileSystem.AppDataDirectory, "test");
The result is empty
this is the path /var/mobile/Containers/Data/Application/02A91048-0016-4E20-A8A6-EB2A89649F1F/Library
which is correct an I see the files the physical. Where am I doing mistake?
I have also tried this
var test = FileSystem.OpenAppPackageFileAsync(FileSystem.AppDataDirectory);
but I am getting unauthorized exception
you are looking for files in the test subfoloder
the signature of EnumerateFiles is
public static System.Collections.Generic.IEnumerable<string> EnumerateFiles (string path, string searchPattern);
so you want to do this
var path = Path.Combine(FileSystem.AppDataDirectory,"test");
var result = Directory.EnumerateFiles(path, "*.json");
I have an ASP.NET MVC3 application and I want to link_to an image file (png, jpeg, gif, etc), and when user clicks on it, the file goes to download, instead of the browser shows it; is there any way to do this?
take your link something like this:
#Html.ActionLink(
"Download Image", // text to show
"Download", // action name
["DownloadManager", // if need, controller]
new { filename = "my-image", fileext = "jpeg" } // file-name and extension
)
and action-method is here:
public FilePathResult Download(string filename, string fileext) {
var basePath = Server.MapPath("~/Contents/Images/");
var fullPath = System.IO.Path.Combine(
basePath, string.Concat(filename.Trim(), '.', fileext.Trim()));
var contentType = GetContentType(fileext);
// The file name to use in the file-download dialog box that is displayed in the browser.
var downloadName = "one-name-for-client-file." + fileext;
return File(fullPath, contentType, downloadName);
}
private string GetContentType(string fileext) {
switch (fileext) {
case "jpg":
case "jpe":
case "jpeg": return "image/jpeg";
case "png": return "image/x-png";
case "gif": return "image/gif";
default: throw new NotSupportedException();
}
}
UPDATE:
in fact, when a file is sending to a browser, this key/value will be generated in http-header:
Content-Disposition: attachment; filename=file-client-name.ext
which file-client-name.ext is the name.extension that you want the file save-as it on client system; for example, if you want to do this in ASP.NET (none mvc), you can create a HttpHandler, write the file-stream to Response, and just add the above key/value to the http-header:
Response.Headers.Add("Content-Disposition", "attachment; filename=" + "file-client-name.ext");
just this, enjoy :D
Well technically your browser is downloading it.
I don't think you can directly link to an image, and have the browser prompt to download.
You could try something where instead of linking directly to the image, you link to a page, which serves up the image in a zip file perhaps - which of course would prompt the download to occur.
Yes, you can.
Now, you'll need to customize this to suit your needs, but I created a FileController that returned files by an identifier (you can easily return by name).
public class FileController : Controller
{
public ActionResult Download(string name)
{
// check the existence of the filename, and load it in to memory
byte[] data = SomeFunctionToReadTheFile(name);
FileContentResult result = new FileContentResult(data, "image/jpg"); // or whatever it is
return result;
}
}
Now, how you read that file or where you get it from is up to you. I then created a route like this:
routes.MapRoute(null, "files/{name}", new { controller = "File", action = "Download"});
My database has a map of identifiers to files (it's actually more complex than this, but I am omitting that logic for brevity), I can write urls like:
"~/files/somefile"
And the relevant file is downloaded.
I don't think this is possible but a simple message saying right click to save image would suffice I think.
private void ZipExtract(string zipfilename)
{
var path = Server.MapPath(#"~/Files");
ZipFile zip = ZipFile.Read(zipfilename);
zip.ExtractSelectedEntries("name=*.jpg,*.jpeg,*.png,*.gif,*.bmp", " ", path,ExtractExistingFileAction.OverwriteSilently);
}
[HttpPost]
public ContentResult Uploadify(HttpPostedFileBase filedata)
{
var path = Server.MapPath(#"~/Files");
var filePath = Path.Combine(path, filedata.FileName);
if (filedata.FileName.Contains(".zip"))
{
ZipExtract(filedata.FileName);
}
filedata.SaveAs(filePath);
}
what's the error you see? Exception? Other condition? You need to add some additional context to your question. But there are a couple things that stick out even without a better description.
employ a using() clause with the ZipFile class; it is IDisposable.
It looks like you try to extract the zip file before you call .SaveAs(). If I read your code correctly, that means the ZipFile.Read() is trying to read a file that has not yet been created. If that is the case it will throw a FileNotFoundException. I may be wrong about this; more text from you would help clarify.
Consider:
strPath= c:\images\gallery\add.gif
I need to rename this file from add.gif to thumb1.gid, and I should write one command method, whatever the file name. We need to
replace that name with this like below.
string strfilename = **"thumb"**
****Result thum.gif**
strPath= c:\images\gallery\thum.gif **
You have several problems, looking up the value in the XML file, and renaming the file.
To look up the number corresponding to Gallery2 or whatever, I would recommend having a look at Stack Overflow question How to implement a simple XPath lookup which explains how to look up nodes/values in an XML file.
To rename a file in .NET, use something like this:
using System.IO;
FileInfo fi = new FileInfo("c:\\images\\gallery\\add.gif");
if (fi.Exists)
{
fi.MoveTo("c:\\images\\gallery\\thumb3.gif");
}
Of course, you would use string variables instead of string literals for the paths.
That should give you enough information to piece it together and solve your particular lookup-rename problem.
I created a utility method to help encapsulate how to rename a file.
public class FileUtilities
{
public static void RenameFile(string oldFilenameWithPathWithExtension, string newFilenameWithoutPathWithExtension)
{
try
{
string directoryPath = Path.GetDirectoryName(oldFilenameWithPathWithExtension);
if (directoryPath == null)
{
throw new Exception($"Directory not found in given path value:{oldFilenameWithPathWithExtension}");
}
var newFilenameWithPath = Path.Combine(directoryPath, newFilenameWithoutPathWithExtension);
FileInfo fileInfo = new FileInfo(oldFilenameWithPathWithExtension);
fileInfo.MoveTo(newFilenameWithPath);
}
catch (Exception e)
{
//Boiler plate exception handling
Console.WriteLine(e);
throw;
}
}
}
I omitted several other file system checks that could optionally be done, but as #JoelCoehoorn pointed out in a comment on this page, the File System is Volatile, so wrapping it in a try-catch may be all that is necessary.
With that class in your library, now you can simply call:
var fullFilename = #"C:\images\gallery\add.gif";
var newFilename = "Thumb.gif";
FileHelper.RenameFile(fullFilename,newFilename);
Basically I have some code to check a specific directory to see if an image is there and if so I want to assign a URL to the image to an ImageControl.
if (System.IO.Directory.Exists(photosLocation))
{
string[] files = System.IO.Directory.GetFiles(photosLocation, "*.jpg");
if (files.Length > 0)
{
// TODO: return the url of the first file found;
}
}
this is what i use:
private string MapURL(string path)
{
string appPath = Server.MapPath("/").ToLower();
return string.Format("/{0}", path.ToLower().Replace(appPath, "").Replace(#"\", "/"));
}
As far as I know, there's no method to do what you want; at least not directly. I'd store the photosLocation as a path relative to the application; for example: "~/Images/". This way, you could use MapPath to get the physical location, and ResolveUrl to get the URL (with a bit of help from System.IO.Path):
string photosLocationPath = HttpContext.Current.Server.MapPath(photosLocation);
if (Directory.Exists(photosLocationPath))
{
string[] files = Directory.GetFiles(photosLocationPath, "*.jpg");
if (files.Length > 0)
{
string filenameRelative = photosLocation + Path.GetFilename(files[0])
return Page.ResolveUrl(filenameRelative);
}
}
The problem with all these answers is that they do not take virtual directories into account.
Consider:
Site named "tempuri.com/" rooted at c:\domains\site
virtual directory "~/files" at c:\data\files
virtual directory "~/files/vip" at c:\data\VIPcust\files
So:
Server.MapPath("~/files/vip/readme.txt")
= "c:\data\VIPcust\files\readme.txt"
But there is no way to do this:
MagicResolve("c:\data\VIPcust\files\readme.txt")
= "http://tempuri.com/files/vip/readme.txt"
because there is no way to get a complete list of virtual directories.
I've accepted Fredriks answer as it appears to solve the problem with the least amount of effort however the Request object doesn't appear to conatin the ResolveUrl method.
This can be accessed through the Page object or an Image control object:
myImage.ImageUrl = Page.ResolveUrl(photoURL);
myImage.ImageUrl = myImage.ResolveUrl(photoURL);
An alternative, if you are using a static class as I am, is to use the VirtualPathUtility:
myImage.ImageUrl = VirtualPathUtility.ToAbsolute(photoURL);
This worked for me:
HttpContext.Current.Request.Url.GetLeftPart(UriPartial.Authority) + HttpRuntime.AppDomainAppVirtualPath + "ImageName";
Maybe this is not the best way, but it works.
// Here is your path
String p = photosLocation + "whatever.jpg";
// Here is the page address
String pa = Page.Request.Url.AbsoluteUri;
// Take the page name
String pn = Page.Request.Url.LocalPath;
// Here is the server address
String sa = pa.Replace(pn, "");
// Take the physical location of the page
String pl = Page.Request.PhysicalPath;
// Replace the backslash with slash in your path
pl = pl.Replace("\\", "/");
p = p.Replace("\\", "/");
// Root path
String rp = pl.Replace(pn, "");
// Take out same path
String final = p.Replace(rp, "");
// So your picture's address is
String path = sa + final;
Edit: Ok, somebody marked as not helpful. Some explanation: take the physical path of the current page, split it into two parts: server and directory (like c:\inetpub\whatever.com\whatever) and page name (like /Whatever.aspx). The image's physical path should contain the server's path, so "substract" them, leaving only the image's path relative to the server's (like: \design\picture.jpg). Replace the backslashes with slashes and append it to the server's url.
So far as I know there's no single function which does this (maybe you were looking for the inverse of MapPath?). I'd love to know if such a function exists. Until then, I would just take the filename(s) returned by GetFiles, remove the path, and prepend the URL root. This can be done generically.
The simple solution seems to be to have a temporary location within the website that you can access easily with URL and then you can move files to the physical location when you need to save them.
For get the left part of the URL:
?HttpContext.Current.Request.Url.GetLeftPart(UriPartial.Authority)
"http://localhost:1714"
For get the application (web) name:
?HttpRuntime.AppDomainAppVirtualPath
"/"
With this, you are available to add your relative path after that obtaining the complete URL.
I think this should work. It might be off on the slashes. Not sure if they are needed or not.
string url = Request.ApplicationPath + "/" + photosLocation + "/" + files[0];