I have to write the script in Gradle and I therefore have some questions.
The script must unpack the .ear file, and then included in the jar, then edit the content and save as ear (text file> jar> ear.)
1) Firstly, I would like to learn how to save a file to the current directory.
(The following code saves the file to another folder.)
task unzip(type: Copy) {
def zipFile = file('C:/Test/file.ear')
def outputDir = file('jar')
from zipTree(zipFile)
into getDestDir()
}
Phrases such as '.', '/' don't work.
2)Secondly, I would like to ask how to unpack the jar file because I can't unpack the above method. (It works only to the EAR)
3)At the end I would ask how you can convert the edited text file on the jar, and then on ear (without dependencies and manifest).
Because the resulting file do I have to file .ear
Thank you in advance for your answer.
You don't want to be writing files into your working directory. All the work should be done under the $buildDir.
A standard method is to set your into directory to a temporary location:
task myTask(type: Copy) {
from 'my/dir/'
into temporaryDir
}
You can unpack a JAR or ZIP file like so:
copy {
from zipTree('path/tozip.zip')
into temporaryDir
}
Related
I have a Jar (we'll call it a.jar) with a resource in it at path foo/bar.txt and a function as follows:
object FooBarLoader {
fun loadFooBarText() = javaClass.getResourceAsStream("foo//bar.txt")
?.bufferedReader()
?.readLines()
?.joinToString("\n")
}
When I test the function in a unit test (JUnit 4, running with Gradle 6), it loads the text from the resource file despite the obvious typo (the // in the middle of the resource path).
I also have a CLI application (in b.jar) that has a dependency on a.jar. When the CLI application calls loadFooBarText(), it got a null result due to the resource not being found. This was fixed by fixing the typo (// -> /) in the function in a.jar. No other changes were needed to fix it.
So, my question is why did the wrong path work in one situation (unit tests of a.jar) and not the other (call from b.jar)?
How do you run the unit test with a.jar ? Just run it in your IDE or use command java -jar a.jar ?
If you ran it just in IDE,I think difference is the search path between local files and zip files .
Your first application searches the file in your target directory and the second application searches it in the jar which is a compressed file.
When searching files in local path, command will be changed to right one by system.
The two commands below are the same in both Windows/Linux.
cd work//abc/ddd
cd work/abc/ddd
But when searching files in a jar file which is actually compressed zip file, path should be a restrict written or else the program will find nothing.
I try run my R Script within JavaFx. I use Renjin for this purpose and it seems to work properly with statements I run internally. But I want to run an external R Script. The project is set up with Maven so the path should be easy as the R Script is in the resources folder. The path works when I load FXML files, so I'm pretty confused why it can't find my Script.
Here's a short example:
package survey;
import javax.script.*;
import org.renjin.script.*;
import java.io.FileReader;
public class calcFunction {
public static void main(String[] args) throws Exception {
// create a script engine manager:
RenjinScriptEngineFactory factory = new RenjinScriptEngineFactory();
// create a Renjin engine:
ScriptEngine engine = factory.getScriptEngine();
engine.put("x", 4);
engine.put("y", 5);
engine.eval(new FileReader("/test.R"));
}
}
Is something missing? Thanks in advance!
EDIT1:
With my FXML files it works with the "/" path like this:
root = FXMLLoader.load(getClass().getResource("/moduleDa.fxml"));
EDIT2:
Someone who deleted his comment proposed this:
engine.eval(new FileReader(new File(".").getAbsolutePath()+"/test.R"));
It works if the script is in the root directory, where the pom.xml file is located. #James_D made it work so the R script can be located in the resources folder - thanks a lot!
If your R script is bundled as part of the application, it can't be treated as a file - you need to treat it as a resource. Typically, you will deploy your application as a Jar file, and the resources will be elements within that jar file (they won't be files in their own right).
So just treat the R script as a resource and load it as such. I don't know the renjin framework, but I assume ScriptEngine here is a javax.script.ScriptEngine, in which case ScriptEngine.eval(...) takes a Reader as a parameter, and so (if your R script is located in the root of the class path) you can do
engine.eval(new InputStreamReader(getClass().getResourceAsStream("/test.R")));
I have jar foo.jar which contains jar foo/config/baar-temp.jar.
What is the best method to rename baar-temp.jar to baar.jar?
Actually, jar format is based on zip and can be operated on as a file system using for example ZipFileSystemProvider available in Java7. That allows us to do a rather simple manipulation with the insides of one:
private void renameStuffInsideJar(String jarFilePath){
URI uri = URI.create("jar:file:"+jarFilePath);
try {
FileSystem jarFile = FileSystems.getFileSystem(uri)) {
Path pathInJarfile = jarFile.getPath("foo/config/baar-temp.jar");
Files.move(pathInZipfile,pathInZipfile.resolveSibling("baar.jar"));
} catch(IOException e){
//TODO
}
}
Alternatively, if it's not code you want, you could just open your jar file in your preferred archive manager like 7zip or WinRar and rename it using that.
I'm writing a Javafx Application where I had to include a fxml file to copy from the source to the build directory. This is my task.
task copyRequiredFiles(type: Copy) {
from '/src/com/indywiz/game/ui/view/Game2048.fxml'
into 'build/classes/main/com/indywiz/game/ui'
}
task (runui, dependsOn: ['classes', 'copyRequiredFiles'], type: JavaExec) {
main = 'com.indywiz.game.ui.Main'
classpath = sourceSets.main.runtimeClasspath
}
If I run runui task, I get Skipping task ':copy Required Files' as it has no source files.
What is going wrong? Please let me know if you need any more information.
Below is my folder structure:
You gave an absolute part for from, but it needs to be a relative path (i.e. no leading /).
So I have a bunch of data that I want to load into database from CSV. I've hacked together a solution that works in local development, but when I deploy to meteor.com, it no longer works.
I'm loading the csv file in the folder /server/data/:
function readData(name){
var fs = __meteor_bootstrap__.require('fs');
var path = __meteor_bootstrap__.require('path');
var base = path.resolve('.');
var data = fs.readFileSync(path.join(base, '/server/data/', name));
return CSVToArray(data);
}
After I deploy to meteor.com, i got:
INFO Error: ENOENT, no such file or directory '/meteor/containers/98eb1286-120b-ee84-8e98-ce673fa2eab7/public/data/categories.csv'
at Object.openSync (fs.js:240:18)
at Object.readFileSync (fs.js:128:15)
at readData (app/server/models.js:10:16)
at app/server/categories.js:6:7
at /meteor/containers/98eb1286-120b-ee84-8e98-ce673fa2eab7/bundle/server/server.js:132:63
at Array.forEach (native)
at Function.<anonymous> (/meteor/containers/98eb1286-120b-ee84-8e98-ce673fa2eab7/bundle/server/underscore.js:76:11)
at /meteor/containers/98eb1286-120b-ee84-8e98-ce673fa2eab7/bundle/server/server.js:132:7
Any idea how I can get meteor to see the csv file after deployment?
I realize this question is old, but it still ranks high on certain keyword searches. So, if you're using Meteor 0.6.5+, you can use the new Assets API.
The issue is that meteor only bundles files that it knows about (ie. JS/CSS/HTML/+more depending on which packages you use) up when it deploys.
Try putting the file you need in the public directory (this directory is exempt from the above rule).
Thanks to SamuelDavis and Tom Coleman's tips. I ended up figuring out what the problem is. Turns out the bundled app is no longer formated as client, public, and server. I ended up debugging it by running meteor bundle to create a tarball. extract the tarball and took a look inside to find where the data folder is. Tom was also right that the data folder needed to be in the public folder in order to get bundled in.
It appears that the base directory is not in the same location that contains the file '/server/data/xxx.csv'.
Before you try anything else, log the base path after calling "var base = path.resolve('.'). If that value is what you expected, log the files that appear in that directory. Again if the files are what you expected, navigate into the /server folder and print out those directories and so forth.
This should pinpoint you to which folder and/or directory is missing and should indicate where you should place the CSV file in future.