Symfony custom repository query giving error - symfony

Question

I am really new at Symfony and I am trying to get used to query builder. At the moment I am trying to join three tables and the following MySQL query gives me the results I need when I run it in PhpMyAdmin
SELECT * FROM pe_users u
LEFT JOIN pe_apply a ON u.id = a.user
LEFT JOIN pe_offer o ON a.id = o.application
However when I move this inside a Symfony Repository method
namespace Ache\AdminBundle\Repository;
use Doctrine\ORM\EntityRepository;
class AdminRepository extends EntityRepository{
public function findAllAppByStatus(){
$query = $this->getEntityManager()->createQuery(
'SELECT * FROM pe_users u
LEFT JOIN pe_apply a ON u.id = a.user
LEFT JOIN pe_offer o ON a.id = o.application
');
try {
return $query->getSingleResult();
} catch (\Doctrine\ORM\NoResultException $e) {
return null;
}
}
}
I get the error
[Syntax Error] line 0, col 7: Error: Expected IdentificationVariable |
ScalarExpression | AggregateExpression | FunctionDeclaration |
PartialObjectExpression | "(" Subselect ")" | CaseExpression, got '*'
What does this error mean? what am I doing wrong?
UPDATE
The three entities I have are as following
UserBundle:User
CoreBundle:Apply
AdminBundle:Offer
User.id links with Apply.user and Offer.application links with Apply.id

Answer 1

You can still use raw sql with Symfony if you are comfortable with that
$conn = $this->getEntityManager()->getConnection();
$sql = "SELECT * FROM pe_users u LEFT JOIN pe_apply a ON u.id = a.user LEFT JOIN pe_offer o ON a.id = o.application WHERE u.id = a.user";
$stmt = $conn->prepare($sql);
$stmt->execute();
return $stmt->fetchAll();

Answer 2

I would do :
public function findAllAppByStatus(){
$qb = $this->createQueryBuilder('u')
->leftJoin('CoreBundle:Apply', 'a', 'WITH', 'a.user = u')
->leftJoin('AdminBundle:Offer', 'o', 'WITH', 'o.application = a')
->setMaxResults(1); // if you return only 1 result, you want to be sure only one (or none) result is fetched
return $qb->getQuery()->getOneOrNullResult();
if you want to return possibly many results, as the 'All' in the method name suggests, get rid of the ->setMaxResults() and use $qb->getQuery()->getResult();
see how the queryBuilder works with objects, not tables. Joins are built on entities and properties, not tables and field names.