This is my graph:
What I need is to display just the 0 and 1 in the y-axis without 0.1 ,0.2, .., 0.9
Graph tag
The default type of the graph is a pie chart - to change it to a barchart change to You also may change the orientation.
:Example :
<graph string="Sales Order Lines" orientation="horizontal" type="bar">
Field tag
The first field is the X axis. The second one is the Y axis and the optional third one is the Z axis for 3 dimensional graphs. You can apply a few attributes to each field/axis:
group: if set to true, the client will group all item of the same value for this field. For each other field, it will apply an operator
operator: the operator to apply is another field is grouped. By default it's '+'.
Allowed values are:
+: addition
*: multiply
**: exponent
min: minimum of the list
max: maximum of the list
Related
John 10479 228c44
Tom 5780 4fffa7
Willia 5248 773095
Salem 4747 ea1c1s
john 4630 db2f0d
plot "data.txt" using 2:xtic(1):(1):3 with boxes lc rgb variable title "Messages sent"
**2:xtic(1):(1):3**
2 decides height
xtic(1) put the names of the first column on the X tics
(1) should be the boxwidth
3 should be the column gnuplot takes the rgb color from
instead, i get "skipping data file with no valid points" and nothing shows up
if i only use the first three 2:xtic(1):(1)
for some reason, gnuplot uses the third part ((1) instead of xtic(1)) as the xtic names and ignore xtic(1)
i have no idea what causes that either
i just want to save column colors in hex rgb format in files instead of using linestyles
First of all, column 3 should be integer numbers not strings. So, add 0x in front of column 3 to make them hexadecimal values. Alternatively, you could write a function to convert them to hexadecimal values.
The sequence is essential. xtic() is always last. Variable color is second last. The plotting style with boxes can be used with either two or three columns (check help boxes). However, you can use is also with just one column, then gnuplot takes the pseudocolumn 0 as implicit x-values. Apparently, together with a column for variable color gnuplot gets confused.
So, you have to specify the x-column explicitly.
And you can specify the width of the box separately, e.g. set boxwidth 0.8.
So both will work:
plot $Data u 0:2:(0.8):3:xtic(1) w boxes lc rgb var
and
set boxwidth 0.8
plot $Data u 0:2:3:xtic(1) w boxes lc rgb var
Script:
### with boxes and variable color
reset session
$Data <<EOD
John 10479 0x228c44
Tom 5780 0x4fffa7
Willia 5248 0x773095
Salem 4747 0xea1c1s
john 4630 0xdb2f0d
EOD
# set boxwidth 0.8
set style fill solid 0.3
plot $Data u 0:2:3:xtic(1) w boxes lc rgb var ti "Messages sent"
### end of script
Result:
I am learning graphical analysis using R. Here is the code, which I can not understand.
barplotVS <- barplot(table(mtcarsData$vs), xlab="Type of engine")
text(barplotVS,table(mtcarsData$vs)/2,table(mtcarsData$vs),cex=1.25)
The output is like below. I can not understand the function of text(), I googled the text() function, which shows that the parameter of text(x,y) is numeric vectors of coordinates where the text labels should be written. Can anyone tell me what is barplotVS,table(mtcarsData$vs)/2,table(mtcarsData$vs),cex=1.25 in my code.
barplotVS <- barplot(table(mtcarsData$vs), xlab="Type of engine")
print(barplotVS)
outputs:
[,1]
[1,] 0.7
[2,] 1.9
These are the positions where the center of the bars in the barplot are on the x axis.
print(table(mtcarsData$vs))
outputs:
0 1
18 14
the numbers below are the occurrences of each value that is present in mtcarsData$vs and the numbers above are the actual value that is counted.
When you run the function:
text(barplotVS,table(mtcarsData$vs)/2,table(mtcarsData$vs),cex=1.25)
the first value will be the x positions where to put the labels (i.e. 0.7 and 1.9), the second parameter will be the y positions set in this case to total counts divided by two (i.e. 9 and 7) meaning to put the labels halfway in the bars, the third will be the labels (i.e. 18 and 14) and finally cex is a value that allows to change the size of the font.
Anyway R has in general a good documentation that you can call by using the ? operator (as suggested in the comments). In order to understand try to run the code and check what each variable contains with print or str functions. If you use a IDE (e.g. RStudio) have the content of the variables in a graphical panel so you don't event need to print.
I am trying to generate a nested list with numbers, letters, and Roman numerals. R-Markdown cheatsheet shows
ordered list
item 2
sub-item 1
sub-item 2
but, this generates a sub-list with an unordered bullet. Instead of this, I need sub-list with letters and sub-sub-lists with Roman numerals like this:
1. What geoms would you use to draw the followings?
a. A line chart
i) `geom_line()`
b. A boxplot
ii) `geom_boxplot()`
Is there any way to do this? Thank you,
Luckily, I have found the answer to my question in another R-Markdown cheatsheet. The point is to put 4 spaces or 2 indents before the sub-list items and 8 spaces or 4 indents before the sub-sub-list items. The following is my code in R-Markdown:
1. What geoms would you use to draw the followings?
a. A line chart
i. `geom_bar()`
i. `geom_line()`
a. A boxplot
i. `geom_boxplot()`
i. box
a. A histogram: `geom_histogram()`
a. An area chart: `geom_area()`
The output is like this:
1. What geoms would you use to draw the followings?
a. A line chart
i. `geom_bar()`
ii. `geom_line()`
b. A boxplot
iii. `geom_boxplot()`
iv. box
c. A histogram: `geom_histogram()`
d. An area chart: `geom_area()`
I have the following basic code. The first line sums p along dimension 1 to create a 1 x column array. The next line plot A. Unfortunately, it seems that Julia assumes it must plot many lines (in this case just points) along dimension 2.
A = sum(p,dims = 1)
plot(A)
So, my question is, how can I plot a simple line when the data is in a 1 x column array?
I assume you use Plots.jl. The following is from Plots.jl's documentation.
If the argument [to plot] is a "matrix-type", then each column will map to a series, cycling through columns if there are fewer columns than series. In this sense, a vector is treated just like an "nx1 matrix".
The number of series plot(a) tries to plot is the number of columns in a.
To get a single series, you can do one of the followings
plot(vec(a)) # `vec` will give you a vector view of `a` without an allocation
plot(a') # or `plot(transpose(a))`. `transpose` does not allocate a new array
plot(a[:]) # this allocates a new array so you should probably avoid it
In GNUPLOT, I would like to plot 5 values on a single bar chart, separated with some spacing in between. If I have data formatted as such:
3342336, 3375103, 7110653, 32770, 0
where those 5 values are the y-values, how can I specify the x-values myself for where they should belong?
For example, I would like my bar chart to have each entry be of length 1,
so I plot y-value 3342336 at x-value 1,
y-value 3375103 at x-value 3,
y-value 7110653 at x-value 5,
y-value 32770 at x-value 7,
and y-value 0 at x-value 9.
I would appreciate any example code that can achieve this. Thanks.
If your data is in one row as shown, you can achieve this by using the plot for syntax looping over the column index, and calculating the x value from that index. We can grab the column by using the column function which retrieves the specified column number.
set boxwidth 1
set datafile separator comma # only if data is comma separated
plot for [i=1:5] (2*i-1):(column(i)) with boxes
If we need to ensure the same line type is used each time, we can explicitly state it in the plot command.
plot for [i=1:5] (2*i-1):(column(i)) with boxes lt 1
Additionally, if a key is to be generated, and we don't wish each plot statement to generate one, we can test for and only give a nonempty title on the first iteration (an empty title is treated the same as no title).
plot for [i=1:5] (2*i-1):(column(i)) with boxes lt 1 title (i==1)?"Title":""
If your data is separated into rows as is the normal format, this can be obtained a different way.
Gnuplot has several pseuduocolumns (see help pseudocolumns for details). In your case, column 0 is of interest. Column 0 gives the line number of the data starting at 0. Thus to get sequential odd numbers like that, you can use 2*$0+1.
For example, if your data (stored in datafile.txt) looks like
3342336
3375103
7110653
32770
0
and you wish to plot boxes of length 1 at those values, you can do
set boxwidth 1
plot "datafile.txt" u (2*$0+1):1 with boxes