Allow absolutely positioned child to render outside parent with overflow: hidden - css

Question

How to allow for absolutely positioned element to disobey it's ancestor overflow: hidden and render outside it? The situation is complicated by the fact that there is a position: relative on the element between them in the ancestor hierarchy.
Here's a pen. In this situation how to allow red inner div to render at it's full height (300px), rather than being limited by outermost parent's 150px. I cannot remove overflow: hidden from the element - I'm using it to implement a collapsing panel. I also cannot move position: relative to one of outermost element's parents - it must stay at outer element.

Answer 1

Remove overflow:hidden from the .outermost and create another element inside it with these rules: overflow:hidden; height:100%; width:100%; position:absolute; top:0; left:0; and put everything else inside it and they won't get overflown.
.outermost {
width: 400px;
height: 150px;
background-color: blue;
position:relative;
}
.outer {
position: relative;
}
.inner {
position: absolute;
left: 100px;
height: 300px;
width: 50px;
background-color: red;
z-index: 1;
}
.hideOverflow{ /* Put all the content here that's overflowing content you want hidden. And leave content you don't want to hide outside this. */
position:absolute;
top:0;
left:0;
width:100%;
height:100%;
overflow:hidden;
}
<div class="outermost">
<div class="outer">
<div class="inner">
</div>
</div>
<div class="hideOverflow">
<p>Overflowing content inside this element will be hidden.</p>
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</div>
</div>