CSS 3 Shape: inverted rounded corner "tunnel-like style" - css

I am looking to create a tunnel-like div which has inverted circle borders
As you can see it has an 'expanding tunnel effect' from left to right. Ideally the checkered background is transparent but if that is impossible I can maybe make it work with a solid background color.
Can anyone help me out creating this css3 shape? Hopefully with a jsfiddle that I can play with?
Thank you!

This can be created using a :before and :after pseudo element:
The background colour is provided with the box-shadow colour, allowing the top and bottom of the shape to be transparent
The curve is created with the border-radius like so:
(the red area is transparent)
Complete Example
div {
height: 300px;
width: 200px;
position: relative;
overflow: hidden;
}
div:before {
top: -60px;
border-bottom: solid #EEE;
border-right: solid #EEE;
border-radius: 0 0 60% 0;
box-shadow: 50px 10px 0 60px #F90;
}
div:after {
bottom: -60px;
box-shadow: 50px 10px 0 60px #F90;
border-radius: 0 60% 0 0;
border-top: solid #EEE;
border-right: solid #EEE;
}
div:before,
div:after {
content: '';
position: absolute;
width: 100%;
height: 160px;
right: 0;
border-width: 3px;
}
<div></div>

Related

button shape with transparency and only dotted border

Is it able to create a button with transparent background and a dotted border, with a custom shape?
I'm able now to do this with a background color, but when I try to to fill the inner without any color, nothing works as expected.
body{
background: #999
}
button {
height: 50px;
width: 250px;
border: dotted 1px #FFF;
border-bottom: none;
background: none;
position: relative;
}
button:after,
button:before {
content: '';
display: block;
position: absolute;
top: 100%;
width: 0;
height: 0;
border-style: solid;
}
button:after {
border-color: #fff transparent transparent transparent;
border-width: 1px 125px 0 0;
right: 1px
}
button:before {
border-color: transparent transparent #fff transparent;
border-width: 0 125px 1px 0;
left: 0
}
<body>
<button></button>
</body>
I am not so sure about a button, but you can certainly create shapes out of divs.
What you are looking for is a play with borders to create shapes.
#triangle{
width: 0;
height: 0;
border-left: 30px solid transparent;
border-right: 30px solid transparent;
border-bottom: 40px solid green;
}
<div id="triangle"></div>
As you can see, I created a triangle with just the borders, the trick is to understand the borders of a div. They are not straight, their ends are wedge shaped.
I think this is a good starting point for you.

CSS - Creating a custom arrow

Hi I am trying to create a custom arrow in CSS that looks like the image below.
Ideally I want to create this by overlaying two shapes a triangle and a rectangle (maybe using CSS :after and :before) but I'm not too savvy when it comes to CSS so I have been struggling.I started by just using borders but doesn't look like it is going to work
So far I just have:
.arrow {
width: 0;
height: 0;
border-top: 60px solid transparent;
border-bottom: 60px solid transparent;
border-left: 60px solid #ccc;
}
<div class="arrow"></div>
Not too hard to make using the :before pseudo element and some transforms:
.container {
padding: 100px;
}
.arrow {
display: inline-block;
height: 150px;
background: #000;
width: 75px;
}
.arrow:before {
content: "";
border-top: 100px solid #000;
border-left: 100px solid transparent;
border-right: 100px solid transparent;
border-bottom: 100px solid transparent;
transform: rotateZ(180deg) translateY(100%) translateX(31%);
position: relative;
display: inline-block;
}
<div class="container">
<div class="arrow"></div>
</div>
Here's another option.
.arrow{
width: 0;
height: 0;
border-top: 60px solid transparent;
border-bottom: 60px solid transparent;
border-left: 60px solid #ccc;
position: relative;
margin: 0 0 0 100px;
}
.arrow::before{
content: "";
height:50px;
width:80px;
background: #ccc;
position: absolute;
top: 0;
margin: -100%;
display: block;
transform: translateX(-160%) translateY(-50%);
}
<div class="arrow"></div>
Create one rectangle and then add triangle on top with :before pseudo-element and that is it.
.arrow {
width: 36px;
height: 50px;
background: #3F3F3F;
position: relative;
margin: 60px;
}
.arrow:before {
content: '';
border-style: solid;
border-width: 0 40px 40px 40px;
border-color: transparent transparent #3F3F3F transparent;
position: absolute;
top: 0;
left: 50%;
transform: translate(-50%, -100%);
}
<div class="arrow"></div>
To explain and demonstrate:
A CSS arrow is created by coloring 1 border side, and then moving the other 3 sides in towards the middle of the shape as transparent so they don't show but cut the remaining colored side into a triangle. The shorthand for this is TOP RIGHT BOTTOM LEFT. So to make a triangle pointing upwards you use the third property or bottom.
Using pseudo elements (incase you want the arrow added to another element) you need content:'' to "create" the pseudo element. I've set them as display: block so that they are in the flow and interact with eachother (rather than being laid on top of one another).
By giving the rectangle position: relative you can then use left: 30px (half of the triangle width) to position it in the middle of the triangle.
.arrowWrapper:before {
content: '';
display: block;
width: 0;
height: 0;
border-style: solid;
border-width: 0 60px 60px 60px;
border-color: transparent transparent black transparent;
/* border-color: TOP RIGHT BOTTOM LEFT; */
}
.arrowWrapper:after {
content: '';
position: relative;
display: block;
width: 60px;
height: 60px;
background: black;
left: 30px;
}
<div class="arrowWrapper"></div>
Lifted and modified from http://www.cssportal.com/css3-shapes/:
#eq-triangle {
width: 0;
height: 0;
border-bottom: 104px solid blue;
border-left: 60px solid transparent;
border-right: 60px solid transparent;
}
#rectangle {
width: 40px;
height: 80px;
background: blue;
margin-left: 40px;
}
<div id="eq-triangle"></div>
<div id="rectangle"></div>

How to create border bottom with 2 different color?

I need to create border bottom with two different color like below picture
How do I create the CSS?
You can use css pseudo classes i.e :after or :before.
h3 {
margin: 0;
padding-bottom: 7px;
position: relative;
border-bottom: 2px solid #ccc;
}
h3:before {
position: absolute;
background: brown;
height: 2px;
content: '';
width: 50px;
bottom: -2px;
left: 0;
}
<h3>Last Recent Post</h3>
And you can use css gradient as well:
h3 {
margin: 0;
padding-bottom: 7px;
position: relative;
}
h3:before {
position: absolute;
background: linear-gradient(to right, brown 50px, #ccc 50px);
height: 2px;
content: '';
bottom: 0;
right: 0;
left: 0;
}
<h3>Last Recent Post</h3>
The problem with the accepted solution is the bottom border has a fixed width of 50px; , hence it does not respect the length of the text. The more efficient solution would be the following:
<h2>
<span>Text length doesn't matter</span>
</h2>
CSS
h2 {
border-bottom-width: 1px;
border-bottom-style: solid;
border-bottom-color: lightgray;
}
span {
border-bottom-width: 3px;
border-bottom-style: solid;
border-bottom-color: brown;
display: inline-block;
margin: 0 0 -2px 0;
padding: 30px 3px;
}
The result will look like the following: JsFiddle link: http://jsfiddle.net/uyzndpvs/
use box-shadow with zero blur
syntax :
box-shadow : x-offset y-offset blur radius color
example : box-shadow 0 0 0 1em red , 0 0 0 2em orange.
this will emulate a border of 1em red border and then a 1em orange border.
Note that orange color has a radius of 2em ( because half of it will be covered by red color)

CSS Transform to skew the shape to a trapezium

I want to be able to skew an element in the way the image displays below.
I have been playing around with it, but dont seem to be able to get close to replicating that shape.
My css code is
transform:skew(30deg,30deg);
Is transform even the right way to do this? Please let me know the best, most browser compatible, solution.
You can apply some rotate transform around the X axis and apply an appropriate pespective before:
div {
width:300px;
height:200px;
background:url(http://placekitten.com/300/200);
border:2px solid red;
border-top-width:4px;
border-bottom-width:1px;
-webkit-transform: perspective(200px) rotateX(40deg);
margin:100px;
}
Demo
Try this:
Html
<div class="trapezium"></div>
StyleSheet
.trapezium {
border-bottom: 80px solid #fff;
border-left: 45px solid transparent;
border-right: 45px solid transparent;
padding: 0 8px 0 0;
height: 0;
width: 120px;
position: relative;
margin: 2em auto;
}
.trapezium:before {
border-bottom: 90px solid #000;
border-left: 50px solid transparent;
border-right: 50px solid transparent;
padding: 0 8px 0 0;
height: 0;
width: 130px;
position: absolute;
bottom: -85px;
left: -55px;
content: "";
z-index: -1;
}
Here is the Demo

CSS triangle custom border color

Attempting to use a custom hex color for my css triangle (border). However since it uses border properties I am unsure how to go about doing this. I would like to steer clear of javascript and css3 simply because of compatibility. I am trying to have the triangle have a white background with a 1px border (around the angled sides of the triangle) with color #CAD5E0. Is this possible? Here's what I have so far:
.container {
margin-left: 15px;
width: 200px;
background: #FFFFFF;
border: 1px solid #CAD5E0;
padding: 4px;
position: relative;
min-height: 200px;
}
.container:after {
content: '';
display: block;
position: absolute;
top: 10px;
left: 100%;
width: 0;
height: 0;
border-color: transparent transparent transparent #CAD5E0;
border-style: solid;
border-width: 10px;
}​
My fiddle: http://jsfiddle.net/4ZeCz/
You actually have to fake it with two triangles....
.container {
margin: 15px 30px;
width: 200px;
background: #fff;
border: 1px solid #a00;
position: relative;
min-height: 200px;
padding: 20px;
text-align: center;
color: #fff;
font: bold 1.5em/180px Helvetica, sans-serif;
text-shadow: 0 0 1px #000;
}
.container:after,
.container:before {
content: '';
display: block;
position: absolute;
left: 100%;
width: 0;
height: 0;
border-style: solid;
}
.container:after {
top: 10px;
border-color: transparent transparent transparent #fdd;
border-width: 10px;
}
.container:before {
top: 9px;
border-color: transparent transparent transparent #a00;
border-width: 11px;
}
Updated Fiddle here
I know you accept that but check this one also with less css:
.container {
margin-left: 15px;
width: 200px;
background: #FFFFFF;
border: 1px solid #CAD5E0;
padding: 4px;
position: relative;
min-height: 200px;
}
.container:after {
content: '';
display: block;
position: absolute;
top: 10px;
right:-7px;
width: 10px;
height: 10px;
background: #FFFFFF;
border-right:1px solid #CAD5E0;
border-bottom:1px solid #CAD5E0;
-moz-transform:rotate(-45deg);
-webkit-transform:rotate(-45deg);
}
http://jsfiddle.net/4ZeCz/3/
I think this is a simpler one using clip-path:
.container {
width: 150px;
min-height: 150px;
background: #ccc;
padding: 8px;
padding-right: 6%;
display: inline-block;
clip-path: polygon(0% 0%,0% 100%,90% 100%,90% 5%,100% 10%,90% 15%,90% 0%);
}
<div class="container">
test content
</div>
Another way to accomplish this, especially for somebody who needs this to work with equilateral or even scalene triangles like I did, is to use filter: drop-shadow(...) with multiple values and no blur radius. This has the added benefit of not needing multiple elements, or access to both :before and :after (I was trying to accomplish this with :after content that was inline, so wanted to avoid absolute positioning too).
For the above case, the :after's CSS could look like this (fiddle):
.container {
margin-left: 15px;
width: 200px;
background: #FFFFFF;
border: 1px solid #CAD5E0;
padding: 4px;
position: relative;
min-height: 200px;
}
.container:after {
content: '';
display: block;
position: absolute;
top: 10px;
left: 100%;
width: 0;
height: 0;
border-style: solid;
border-width: 20px 0 40px 15px; /* skewed to show support for non-right-angle triangles */
border-color: transparent transparent transparent #fff;
filter: drop-shadow(1px 0 0 #CAD5E0) drop-shadow(0 .5px 0 #CAD5E0);
}
<div class="container">
Test Container
</div>
I think there are some limitations or weirdness, though:
No support in IE11 (though seems fine in FF, Chrome, and Edge)
I'm not quite sure why .5px for the <offset-y> value in the second drop-shadow() above appears more like 1px than 1px would have, though I imagine it's related to trigonometry (though at least on my monitor I see no difference between the actual trig-based values or .5px or even .1px for that matter).
Borders greater than 1px (well, their appearance that way) don't seem to work well. Or at least I haven't found the solution, though see below for a less-than-optimal way to go a little bigger. (I would think the documented-but-unsupported 4th parameter (<spread-radius>) of drop-shadow() might be what I'm really looking for instead of multiple filter values, but adding it in just broke things entirely.) Here you can see what starts to happen when going beyond 1px (fiddle):
.container {
background-color: #eee;
padding: 1em;
}
.container:after {
content: "";
width: 0;
height: 0;
border-style: solid;
border-width: 20.4px 10px 0 10px;
border-color: yellow transparent transparent transparent;
margin-left: .25em;
display: inline-block;
filter: drop-shadow(-6px -4px 0 green) drop-shadow(6px -4px 0 red) drop-shadow(0 6px 0 blue);
}
<div class="container">
Test Container
</div>
Notice the funniness that the first one (green) gets applied once, but the second one (red) is getting applied both to the yellow triangle created via border as well as the green drop-shadow(), and the last one (blue) gets applied to all of the above. (Perhaps that's also related to the .5px appearance thing).
But I guess you can take advantage of these drop-shadows building on each other if you need something wider-looking than 1px, by changing them to something like the following (fiddle):
filter: drop-shadow(0 0 2.5px red) drop-shadow(0 0 0 red) drop-shadow(0 0 0 red) drop-shadow(0 0 0 red) drop-shadow(0 0 0 red) drop-shadow(0 0 0 red) drop-shadow(0 0 0 red) drop-shadow(0 0 0 red) drop-shadow(0 0 0 red);
where the very first one has a blur-radius set (2.5px in this case, though the result appears multiplied), and all the rest have blur at 0. But this will only work for the same color on all sides, and it results in some rounded-looking corners as well as quite rough edges the bigger you go.
.triangle{
position: absolute;
width:0px;
height:0px;
border-left: 45px solid transparent;
border-right: 45px solid transparent;
border-bottom: 72px solid #DB5248;
}
.triangle:after{
position: relative;
content:"!";
top:8px;
left:-8px;
color:#DB5248;
font-size:40px;
}
.triangle:before{
content:".";
color: #DB5248;
position: relative;
top:-14px;
left:-43px;
border-left: 41px solid transparent;
border-right: 41px solid transparent;
border-bottom: 67px solid white;
}

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