How to close Pyqt5 program from QML? - qt

Question

I started a project in Qt Creator initially with a C++ backend, but then switched it to use PyQt5. I have a main.qml, where when I press a button called Exit, I call Qt.quit().
However, I get a General Message stating: Signal QQmlEngine::quit() emitted, but no receivers connected to handle it.
My question is, how do I receive this signal and handle it?
Code:
main.py:
import sys
import PyQt5
from PyQt5 import QtCore
from PyQt5 import QtGui
from PyQt5 import QtQml
from PyQt5.QtCore import QObject pyqtSignal
class DestinyManager,(QtGui.QGuiApplication):
"""the app self"""
def __init__(self, argv):
super(DestinyManager, self).__init__(argv)
# Define a new signal called 'trigger' that has no arguments.
trigger = pyqtSignal()
def connect_and_emit_trigger(self):
# Connect the trigger signal to a slot.
self.trigger.connect(self.handle_trigger)
self.menuItem_Exit.clicked.connect(self.close)
# Emit the signal.
self.trigger.emit()
def handle_trigger(self):
# Show that the slot has been called.
print("trigger signal received")
def main(argv):
app = DestinyManager(sys.argv)
engine = QtQml.QQmlEngine(app)
component = QtQml.QQmlComponent(engine)
component.loadUrl(QtCore.QUrl("exit.qml"))
topLevel = component.create()
if topLevel is not None:
topLevel.show()
else:
for err in component.errors():
print(err.toString())
app.exec()
if __name__ == '__main__':
QObject,main(sys.argv)
Exit.qml:
import QtQuick 2.4
import QtQuick.Controls 1.3
import QtQuick.Window 2.2
Window {
Button {
id: btn_Exit
text: "Exit"
onClicked: Qt.quit();
}
}

Answer 1

There are a few syntax errors in the python script, but ignoring those, the code can be made to work like this:
def main(argv):
app = DestinyManager(sys.argv)
engine = QtQml.QQmlEngine(app)
engine.quit.connect(app.quit)
...
Which is to say, you simply need to connect the qml quit signal to an appropriate slot in your python script.