Select last child when odd, 2 last childs when even - css

I'm in a situation where the number of elements showed is variable, and I need a strange solution which I'm not able to achieve, I even doubt if it's achievable only with css.
I need to select the last-child if my number of elements is odd, and the last 2 child if the number of elements is even.
I've been trying with nth-last-child, :not(:nth-last-child()), odd and even, but never got a good solution.
Anyone has any idea/advice about this issue a part of adding a class "odd" like on html tables?
Thanks a lot in advance!

Here is one way...
.wrap div:last-child,
.wrap div:nth-last-of-type(-n+2):not(:nth-child(even)) {
color: red;
}
<div class="wrap">
<div>Odd</div>
<div>Even</div>
<div>Odd</div>
<div>Even</div>
<div>Odd</div>
<div>Even</div>
</div>
<hr>
<div class="wrap">
<div>Odd</div>
<div>Even</div>
<div>Odd</div>
<div>Even</div>
<div>Odd</div>
</div>

You can use CSS like so:
li:last-child:nth-child(odd) {
/* Last child AND odd */
background: red;
}
li:nth-last-child(2):nth-child(odd),
li:last-child:nth-child(even) {
/* Before last child AND odd */
/* Last child AND even */
background: green;
}
Demo: https://jsfiddle.net/hw0ehrhy/

Absolutely it can be done, with pure CSS. See the complete code below (odd child, last child red; even childs, last 2 childs green)
<html>
<head>
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.11.2/jquery.min.js"></script>
<script>
$(document).ready(function(){
$('#but1').click(function(){
var count = $('p').length;
if (count%2!=0) {$('div>p:last-child').css('background','red');}
else {$('div>p:last-child').css('background','green');alert(count);
$('div>p:nth-last-child(2)').css('background','green');
}
});
});
</script>
</head>
<body>
<button id=but1>Click</button>
<div>
<p>This is one. </p>
<p> This is two. </p>
<p> This is three. </p>
<p> This is four. </p>
<p> This is five. </p>
<p> This is six. </p>
</div>
</body>
</html>
Enjoy, the coding ;)

Related

How do I target the first div of a certain class name amongst other divs? [duplicate]

I have a bunch of elements with a class name red, but I can't seem to select the first element with the class="red" using the following CSS rule:
.home .red:first-child {
border: 1px solid red;
}
<div class="home">
<span>blah</span>
<p class="red">first</p>
<p class="red">second</p>
<p class="red">third</p>
<p class="red">fourth</p>
</div>
What is wrong in this selector and how do I correct it to target the first child with class red?
This is one of the most well-known examples of authors misunderstanding how :first-child works. Introduced in CSS2, the :first-child pseudo-class represents the very first child of its parent. That's it. There's a very common misconception that it picks up whichever child element is the first to match the conditions specified by the rest of the compound selector. Due to the way selectors work (see here for an explanation), that is simply not true.
Selectors level 3 introduces a :first-of-type pseudo-class, which represents the first element among siblings of its element type. This answer explains, with illustrations, the difference between :first-child and :first-of-type. However, as with :first-child, it does not look at any other conditions or attributes. In HTML, the element type is represented by the tag name. In the question, that type is p.
Unfortunately, there is no similar :first-of-class pseudo-class for matching the first child element of a given class. At the time this answer was first posted, the newly published FPWD of Selectors level 4 introduced an :nth-match() pseudo-class, designed around existing selector mechanics as I mentioned in the first paragraph by adding a selector-list argument, through which you can supply the rest of the compound selector to get the desired filtering behavior. In recent years this functionality was subsumed into :nth-child() itself, with the selector list appearing as an optional second argument, to simplify things as well as averting the false impression that :nth-match() matched across the entire document (see the final note below).
While we await cross-browser support (seriously, it's been nearly 10 years, and there has only been a single implementation for the last 5 of those years), one workaround that Lea Verou and I developed independently (she did it first!) is to first apply your desired styles to all your elements with that class:
/*
* Select all .red children of .home, including the first one,
* and give them a border.
*/
.home > .red {
border: 1px solid red;
}
... then "undo" the styles for elements with the class that come after the first one, using the general sibling combinator ~ in an overriding rule:
/*
* Select all but the first .red child of .home,
* and remove the border from the previous rule.
*/
.home > .red ~ .red {
border: none;
}
Now only the first element with class="red" will have a border.
Here's an illustration of how the rules are applied:
.home > .red {
border: 1px solid red;
}
.home > .red ~ .red {
border: none;
}
<div class="home">
<span>blah</span> <!-- [1] -->
<p class="red">first</p> <!-- [2] -->
<p class="red">second</p> <!-- [3] -->
<p class="red">third</p> <!-- [3] -->
<p class="red">fourth</p> <!-- [3] -->
</div>
No rules are applied; no border is rendered.
This element does not have the class red, so it's skipped.
Only the first rule is applied; a red border is rendered.
This element has the class red, but it's not preceded by any elements with the class red in its parent. Thus the second rule is not applied, only the first, and the element keeps its border.
Both rules are applied; no border is rendered.
This element has the class red. It is also preceded by at least one other element with the class red. Thus both rules are applied, and the second border declaration overrides the first, thereby "undoing" it, so to speak.
As a bonus, although it was introduced in Selectors 3, the general sibling combinator is actually pretty well-supported by IE7 and newer, unlike :first-of-type and :nth-of-type() which are only supported by IE9 onward. If you need good browser support, you're in luck.
In fact, the fact that the sibling combinator is the only important component in this technique, and it has such amazing browser support, makes this technique very versatile — you can adapt it for filtering elements by other things, besides class selectors:
You can use this to work around :first-of-type in IE7 and IE8, by simply supplying a type selector instead of a class selector (again, more on its incorrect usage in the question in a later section):
article > p {
/* Apply styles to article > p:first-of-type, which may or may not be :first-child */
}
article > p ~ p {
/* Undo the above styles for every subsequent article > p */
}
You can filter by attribute selectors or any other simple selectors instead of classes.
You can also combine this overriding technique with pseudo-elements even though pseudo-elements technically aren't simple selectors.
Note that in order for this to work, you will need to know in advance what the default styles will be for your other sibling elements so you can override the first rule. Additionally, since this involves overriding rules in CSS, you can't achieve the same thing with a single selector for use with the Selectors API, or Selenium's CSS locators.
On a final note, keep in mind that this answer assumes that the question is looking for any number of first child elements having a given class. There is neither a pseudo-class nor even a generic CSS solution for the nth match of a complex selector across the entire document — whether a solution exists depends heavily on the document structure. jQuery provides :eq(), :first, :last and more for this purpose, but note again that they function very differently from :nth-child() et al. Using the Selectors API, you can either use document.querySelector() to obtain the very first match:
var first = document.querySelector('.home > .red');
Or use document.querySelectorAll() with an indexer to pick any specific match:
var redElements = document.querySelectorAll('.home > .red');
var first = redElements[0];
var second = redElements[1];
// etc
Although the .red:nth-of-type(1) solution in the original accepted answer by Philip Daubmeier works (which was originally written by Martyn but deleted since), it does not behave the way you'd expect it to.
For example, if you only wanted to select the p here:
<p class="red"></p>
<div class="red"></div>
... then you can't use .red:first-of-type (equivalent to .red:nth-of-type(1)), because each element is the first (and only) one of its type (p and div respectively), so both will be matched by the selector.
When the first element of a certain class is also the first of its type, the pseudo-class will work, but this happens only by coincidence. This behavior is demonstrated in Philip's answer. The moment you stick in an element of the same type before this element, the selector will fail. Taking the markup from the question:
<div class="home">
<span>blah</span>
<p class="red">first</p>
<p class="red">second</p>
<p class="red">third</p>
<p class="red">fourth</p>
</div>
Applying a rule with .red:first-of-type will work, but once you add another p without the class:
<div class="home">
<span>blah</span>
<p>dummy</p>
<p class="red">first</p>
<p class="red">second</p>
<p class="red">third</p>
<p class="red">fourth</p>
</div>
... the selector will immediately fail, because the first .red element is now the second p element.
The :first-child selector is intended, like the name says, to select the first child of a parent tag. So this example will work (Just tried it here):
<body>
<p class="red">first</p>
<div class="red">second</div>
</body>
This won't work, though, if you've nested your tags under different parent tags, or if your tags of class red aren't the first tags under the parent.
Notice also that this doesn't only apply to the first such tag in the whole document, but every time a new parent is wrapped around it, like:
<div>
<p class="red">first</p>
<div class="red">second</div>
</div>
<div>
<p class="red">third</p>
<div class="red">fourth</div>
</div>
first and third will be red then.
For your case, you can use the :nth-of-type selector:
.red:nth-of-type(1)
{
border:5px solid red;
}
<div class="home">
<span>blah</span>
<p class="red">first</p>
<p class="red">second</p>
<p class="red">third</p>
<p class="red">fourth</p>
</div>
Credits to Martyn, who deleted his answer containing this approach.
More information about :nth-child() and :nth-of-type() is available at http://www.quirksmode.org/css/nthchild.html.
Be aware that this is a CSS3 selector, therefore some now outdated browser versions may not behave as expected (e.g. IE8 or older). Visit https://caniuse.com/?search=nth-of-type for more details.
The correct answer is:
.red:first-child, :not(.red) + .red { border:5px solid red }
Part I: If element is first to its parent and has class "red", it shall get border.
Part II: If ".red" element is not first to its parent, but is immediately following an element without class ".red", it shall also deserve the honor of said border.
Fiddle or it didn't happen.
Philip Daubmeier's answer, while accepted, is not correct - see attached fiddle.
BoltClock's answer would work, but unnecessarily defines and overwrites styles
(particularly an issue where it otherwise would inherit a different border - you don't want to declare other to border:none)
EDIT:
In the event that you have "red" following non-red several times, each "first" red will get the border. To prevent that, one would need to use BoltClock's answer. See fiddle
The above answers are too complex.
.class:first-of-type { }
This will select the first-type of class. MDN Source
Note: Tested with Chrome 91 and Firefox 89, June 2021.
I am surprised no one mentioned the cleanest solution:
.red:not(.red ~ .red) {
border: 1px solid red;
}
<div class="home">
<span>blah</span>
<p class="red">first</p>
<p class="red">second</p>
<p class="red">third</p>
<p class="red">fourth</p>
</div>
you could use first-of-type or nth-of-type(1)
.red {
color: green;
}
/* .red:nth-of-type(1) */
.red:first-of-type {
color: red;
}
<div class="home">
<span>blah</span>
<p class="red">first</p>
<p class="red">second</p>
<p class="red">third</p>
<p class="red">fourth</p>
</div>
To match your selector, the element must have a class name of red and must be the first child of its parent.
<div>
<span class="red"></span> <!-- MATCH -->
</div>
<div>
<span>Blah</span>
<p class="red"></p> <!-- NO MATCH -->
</div>
<div>
<span>Blah</span>
<div><p class="red"></p></div> <!-- MATCH -->
</div>
Since the other answers cover what's wrong with it, I'll try the other half, how to fix it. Unfortunately, I don't know that you have a CSS only solution here, at least not that I can think of. There are some other options though....
Assign a first class to the element when you generate it, like this:
<p class="red first"></p>
<div class="red"></div>
CSS:
.first.red {
border:5px solid red;
}
This CSS only matches elements with both first and red classes.
Alternatively, do the same in JavaScript, for example here's what jQuery you would use to do this, using the same CSS as above:
$(".red:first").addClass("first");
I got this one in my project.
div > .b ~ .b:not(:first-child) {
background: none;
}
div > .b {
background: red;
}
<div>
<p class="a">The first paragraph.</p>
<p class="a">The second paragraph.</p>
<p class="b">The third paragraph.</p>
<p class="b">The fourth paragraph.</p>
</div>
I am using below CSS to have a background image for the list ul li
#footer .module:nth-of-type(1)>.menu>li:nth-of-type(1){
background-position: center;
background-image: url(http://monagentvoyagessuperprix.j3.voyagesendirect.com/images/stories/images_monagentvoyagessuperprix/layout/icon-home.png);
background-repeat: no-repeat;
}
<footer id="footer">
<div class="module">
<ul class="menu ">
<li class="level1 item308 active current"></li>
<li> </li>
</ul>
</div>
<div class="module">
<ul class="menu "><li></li>
<li></li>
</ul>
</div>
<div class="module">
<ul class="menu ">
<li></li>
<li></li>
</ul>
</div>
</footer>
According to your updated problem
<div class="home">
<span>blah</span>
<p class="red">first</p>
<p class="red">second</p>
<p class="red">third</p>
<p class="red">fourth</p>
</div>
how about
.home span + .red{
border:1px solid red;
}
This will select class home, then the element span and finally all .red elements that are placed immediately after span elements.
Reference: http://www.w3schools.com/cssref/css_selectors.asp
For some reason none of the above answers seemed to be addressing the case of the real first and only first child of the parent.
#element_id > .class_name:first-child
All the above answers will fail if you want to apply the style to only the first class child within this code.
<aside id="element_id">
Content
<div class="class_name">First content that need to be styled</div>
<div class="class_name">
Second content that don't need to be styled
<div>
<div>
<div class="class_name">deep content - no style</div>
<div class="class_name">deep content - no style</div>
<div>
<div class="class_name">deep content - no style</div>
</div>
</div>
</div>
</div>
</aside>
The following code will definitely work well everywhere.
it is simple and short.
<div class="home">
<span>blah</span>
<p class="blue"> first-blue </p>
<p class="blue"> second-blue </p>
<p class="blue"> third-blue </p>
<p class="red"> first-red </p>
<p class="red"> second-red </p>
<p class="red"> third-red </p>
<p class="red"> fourth-red </p>
<p class="pink"> first-pink </p>
<p class="pink"> second-pink </p>
<p class="red"> new-first-red </p>
<p class="red"> new-second-red </p>
</div>
we can select the first-red with:
.home .red:not(.home .red ~ .red) {
background-color: blue;
}
if you want to select new-first-red too you should use + instead of ~.
You could use nth-of-type(1) but be sure that site doesn't need to support IE7 etc, if this is the case use jQuery to add body class then find element via IE7 body class then the element name, then add in the nth-child styling to it.
You can change your code to something like this to get it work
<div class="home">
<span>blah</span>
<p class="red">first</p>
<p class="red">second</p>
<p class="red">third</p>
<p class="red">fourth</p>
</div>
This does the job for you
.home span + .red{
border:3px solid green;
}
Here is a CSS reference from SnoopCode about that.
All in All, after reading this all page and other ones and a lot of documentation. Here's the summary:
For first/last child: Safe to use now (Supported by all modern browsers)
:nth-child() Also safe to use now (Supported by all modern browsers). But be careful it even counts siblings! So, the following won't work properly:
/* This should select the first 2 element with class display_class
* but it will NOT WORK Because the nth-child count even siblings
* including the first div skip_class
*/
.display_class:nth-child(-n+2){
background-color:green;
}
<ul>
<li class="skip_class">test 1</li>
<li class="display_class">test 2 should be in green</li>
<li class="display_class">test 3 should be in green</li>
<li class="display_class">test 4</li>
</ul>
Currently, there is a selector :nth-child(-n+2 of .foo) that supports selection by class but not supported by modern browsers so not useful.
So, that leaves us with Javascript solution (we'll fix the example above):
// Here we'll go through the elements with the targeted class
// and add our classmodifer to only the first 2 elements!
[...document.querySelectorAll('.display_class')].forEach((element,index) => {
if (index < 2) element.classList.add('display_class--green');
});
.display_class--green {
background-color:green;
}
<ul>
<li class="skip_class">test 1</li>
<li class="display_class">test 2 should be in green</li>
<li class="display_class">test 3 should be in green</li>
<li class="display_class">test 4</li>
</ul>
A quick 'n dirty jQuery solution for marking first and last element within a group of elements with the same classnames:
$('.my-selector').each(function(index, item) {
if (!$(item).next().hasClass('my-selector')) {
$(item).addClass('last');
}
if (!$(item).prev().hasClass('my-selector')) {
$(item).addClass('first');
}
});
.my-selector {
padding: 5px;
background: #ccc;
}
.my-selector.first {
background: #fcc;
}
.my-selector.last {
background: #cfc;
}
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<div>
<span>first element...</span>
<div class="my-selector">Row 1</div>
<div class="my-selector">Row 2</div>
<div class="my-selector">Row 3</div>
<div class="my-selector">Row 4</div>
<span>other elements...</span>
<div class="my-selector">Row 3</div>
<div class="my-selector">Row 4</div>
</div>
Try This Simple and Effective
.home > span + .red{
border:1px solid red;
}
just use
.home > .red ~ .red{
border: 1px solid red;
}
it will work.
I believe that using relative selector + for selecting elements placed immediately after, works here the best (as few suggested before).
It is also possible for this case to use this selector
.home p:first-of-type
but this is element selector not the class one.
Here you have nice list of CSS selectors: https://kolosek.com/css-selectors/
Could you try something like this:
.red:first-of-type {
border: 5px solid red;
}
you also can use this for last element (if you need it):
.red:last-of-type {
border: 5px solid red;
}
Try this solution:
.home p:first-of-type {
border:5px solid red;
width:100%;
display:block;
}
<div class="home">
<span>blah</span>
<p class="red">first</p>
<p class="red">second</p>
<p class="red">third</p>
<p class="red">fourth</p>
</div>
CodePen link
I think a lot of people have explained already. your code is selecting only first child of the first instance. If you want to select all the first children of red class, you need to use
.home > .red:first-child {
/* put your styling here */
}

How do i style two same class divs differently?

So basically I've got a setup that spits out the code in the following fashion..
<div class="parent">
<div class="subparent">
<div class="TARGETCLASS"></div>
</div>
<div class="subparent">
<div class="TARGETCLASS"></div>
</div>
</div> //close for the parent class
Now what I'm trying to do is to style "TARGETCLASS" that comes above one way and the "TARGETCLASS" that comes second in another way. I tried n-th child, but unable to achieve the result I'm looking for. There's no way to add additional classes or ID to the existing "TARGETCLASS" class. Otherwise I wouldn't be posting this question :)
Also, the "subparent" class also is same. for both the targetclass classes. That's the issue
Thanks in advance for taking your time to answer this question for me.
Cheers!
Looks like you've got some mal-formed tags in your html. And nth-child should work just fine. Also, make sure you place the nth-child selector on the subparent class, and not TARGETCLASS. It's common to mis-place the child selector. Try this:
<div class="parent">
<div class="subparent">
<div class="TARGETCLASS">
first-child
</div>
</div>
<div class="subparent">
<div class="TARGETCLASS">
second-child
</div>
</div>
</div>
<style>
.parent .subparent .TARGETCLASS {
background-color:#f00;
}
.parent .subparent:nth-child(1) .TARGETCLASS {
background-color:#0f0;
}
</style>
fiddle: https://jsfiddle.net/8ejxokuj/
I would use nth-of-type selector like so:
.parent{}
.parent > .subparent {} //targets both subparents
.parent > .subparent:nth-of-type(2) {} //targets the second subparent
.parent > .subparent:nth-of-type(2) > .TARGETCLASS{} //targets the child of the second subparent
The nth-of-type() selector enables you to style a specific element amongst a series, in this case we targeted the second .subparent then specified the child we needed.
I hope this helps!
It seems, it is working by the nth child.
it is about how childrens are called. Not like "Ask parent to find nth child, but ask child, how far is he from parent"
.parent .subparent:nth-child(1) {background: #FEE; color:RED;}
.parent .subparent:nth-child(2) {background: #EEF; color:blue;}
<div class="parent">
<div class="subparent">
<div class="TARGETCLASS">aaa</div>
</div>
<div class="subparent">
<div class="TARGETCLASS">bbb</div>
</div>
//close for the parent class
</div>

Alternate colours of a bunch of div elements (without using tables)

Essentially, what I have in mind is a bunch of div elements, and I want to alternate colours. I could do this using IDs, but I want to use classes to minimize the amount of extra (and potentially spaghetti) code needed.
<div id="divs">
<div class="bla">
</div>
<hr/>
<div class="bla">
</div>
</div>
I've already tried nth-child, but it didn't work.
Edit: And I want to keep the hr.
You need to remove the <hr> element, see this fiddle
HTML
<div id="divs">
<div class="bla">bla</div>
<div class="bla">bla</div>
</div>
CSS
div.bla:nth-child(even) {
background-color: #CCC;
}
div.bla:nth-child(odd) {
background-color: #FFF;
}

CSS Inheritance involving div

I've been reading a lot about CSS inheritance but I haven't been able to find anything about this question, and I'm confused. Please consider the following:
<!DOCTYPE HTML>
<html>
<head>
<style type="text/css">
.anc {
background-color: blue;
color: red;
}
.des {
background-color: inherit;
color: inherit;
}
</style>
</head>
<body>
<div class="anc">
<p class="des">
One <!-- Blue background, red text. Clearly inheritance. -->
</p>
</div>
<p class="anc">
<div class="des">
Two <!-- Why is nothing inherited here? -->
</div>
</p>
</body>
</html>
The "One" text is working as I'd expect. But I don't understand why the "Two" text doesn't have a blue background and red text as well.
Is there some special rule about inheritance for block elements as opposed to inline elements? Or something special just about div? What am I missing here? Do you have an online reference to a very thorough explanation of inheritance? Everything I've seen (and I've been looking a long time) just explains examples like "One", but doesn't address issues like "Two".
I know that there are many (better) ways to get the same visual effect I'm asking for here. But this example is about me trying to understand inheritance in general, not trying to get any particular effect on this HTML code.
Thank you so much for your help!
A <div> inside <p> tag is not valid HTML. If you check the rendered HTML, it probably looks something like this:
<p class="anc"></p>
<div class="dec">TWO</div>
<p></p>
The browser fixes the invalid nesting, but that breaks your CSS definition.
You can't nest block-level elements inside a <p> - the opening <p> ends up acting as a self-closing element and pushes the descendant div out of the <p> as a succeeding sibling. The paragraph also creates an empty <p> after the div; the structure ends up looking like:
<p class="anc"> </p>
<div class="des">Two</div>
<p></p>
A <p> can only contain inline elements. It is invalid to put a <div> in a <p>.
You swapped <div> and <p> in the second case. Also your css specifies .des, whereas your class name in the HTML is dec See working jsFiddle here.
<div class="anc">
<p class="dec">
One <!-- Blue background, red text. Clearly inheritance. -->
</p>
</div>
<div class="anc">
<p class="dec">
Two <!-- Why is nothing inherited here? -->
</p>
</div>
.anc {
background-color: blue;
color: red;
}
Also, there's no need for the inherit as the child will be rendered within the parent, whose style you set already.

nth-child doesn't respond to class selector [duplicate]

This question already has answers here:
Can I combine :nth-child() or :nth-of-type() with an arbitrary selector?
(8 answers)
Closed 1 year ago.
Unless it's not supposed to but I can't seem to get nth-child to acknowledge the class selector.
I have say 4 divs inside another div, all of various classes and ids. I need to select the first instance of a div with said class. For example:
#content .foo:nth-child(1) { margin-top: 0; }
And obviously again with first-child to get the same affect, but it doesn't affect any of the divs.
Now if I want to force it to work with that div I can do this:
#content .foo:nth-child(3) { margin-top: 0; }
It just so happens that it is the 3rd div in #content, which is pointless because I need to get the 1st instance of anything with that class.
<div id="content">
<div id="action-bar"> </div>
<div id="message"> </div>
<div class="table"> </div>
<div class="clear"> </div>
</div>
Here's a sample of the HTML, I've tried nth-of-type as well like this:
#content .table:nth-of-type(1) { margin: 0 }
Again it only responds when I say nth-of-type(3).
EDIT:
I've set up a working example of the problem I'm having here: http://jsfiddle.net/aHwS8/
Try the :nth-of-type() pseudo-selector instead:
#content .foo:nth-of-type(1) { margin-top: 0; }
Note that :nth-of-type() counts the elements with the same name. So .foo:nth-of-type(1) will not select the first element with the class foo but any first element that is the first in the list of elements grouped by the same name. If you have some document like this:
<div>
<i class="foo">1</i><i>x</i><i class="foo">2</i>
<b class="foo">3</b><b>x</b><b class="foo">4</b>
</div>
.foo:nth-of-type(1) will select the elements <i class="foo">1</i> and <b class="foo">3</b> as both are the first of its own type.
This is an old post but I ended up here seeking for an answer for similar problem. Perhaps this will help someone.
I had the following structure, wanting to select the n-th "foo"-div:
<body>
<div class='container'>
<div class='foo'></div>
</div>
<div class='container'>
<div class='foo'></div>
</div>
<div class='container'>
<div class='foo'></div>
</div>
<div class='container'>
<div class='foo'></div>
</div>
</body>
The trick was "go back" and select the parent element with repeated siblings, in this case .container and then select its child(ren):
.container:nth-of-type(3) .foo {
styles here
}
I think you're using the wrong selector, try:
#content .foo:first-of-type { margin-top: 0; }

Resources