Is it possible to create gradient borders combined with a border radius?
I created a button with an ::after element
button{
background: -webkit-gradient ...
}
button::after{
content: '';
position: absolute;
height: calc(100% - 2px);
width: calc(100% - 2px);
left: 1px;
top: 1px;
background: rgba(16,20,28,1);
border-radius: 40px;
z-index: -1;
}
Which looks like:
The problem is that the inner element should be transparent. If the background-color property of button is set to transparent, the button takes on the color (gardiet) of the ::after element:
I have found the following picture on the internet where the inner body is transparent and the border is a gradient.
There are multiple tricks to get such a border but these don't support the border-radius.
A posibility, limited in support to modern browsers (all major browser except IE) and also limited to the colors that you can achieve, is to use mix-blend-mode, that can make gray look like transparent.
Also, some special properties to get the border, to begin with
.container {
width: 300px;
height: 100px;
background-color: lightgreen;
}
.test {
position: absolute;
margin: 20px;
font-size: 30px;
border-radius: 1em;
border: solid 12px transparent;
width: 200px;
background: linear-gradient(gray,gray), linear-gradient(to right, red, blue);
background-clip: content-box, border-box;
background-origin: border-box;
mix-blend-mode: hard-light;
}
<div class="container">
<div class="test">TEST</div>
</div>
Related
This question already has answers here:
Border Gradient with Border Radius
(2 answers)
SVG with radialGradient not work in browsers
(1 answer)
Closed 2 years ago.
In following code I expect both divs to be round. But the first one with border-image applied is square. How can I fix that and make it round too?
div {
float: left;
width: 130px;
height: 130px;
margin: auto;
border: 30px solid transparent;
border-radius: 50%;
border-image: linear-gradient(45deg, red, blue) 30;
}
div + div {
margin-left: 1em;
border-image: none;
border-color: green;
}
<div></div>
<div></div>
It is not possible to combine them. The W3 Spec says:
A box's backgrounds, but not its border-image, are clipped to the appropriate curve (as determined by ‘background-clip’). Other effects that clip to the border or padding edge (such as ‘overflow’ other than ‘visible’) also must clip to the curve. The content of replaced elements is always trimmed to the content edge curve. Also, the area outside the curve of the border edge does not accept mouse events on behalf of the element.
However, you can achieve the same effect by using a multiple elements and a CSS gradient
#cont{
background: -webkit-linear-gradient(left top, crimson 0%, blue 100%);
width: 300px;
height: 300px;
border-radius: 1000px;
padding: 10px;
}
#box{
background: white;
width: 300px;
height: 300px;
border-radius: 1000px;
}
<div id="cont">
<div id="box"></div>
</div>
You can use radial-gradient background-image. And you can mask it with mask-image. border-image does not work with border-radius.
div {
float: left;
width: 190px;
height: 190px;
margin: auto;
/* border: 30px solid transparent;
border-radius: 50%;
border-image: linear-gradient(45deg, red, blue) 30;*/
border-radius: 50%;
background: linear-gradient(45deg, red, blue);
-webkit-mask-image: radial-gradient(transparent 0 65px, #000 65.5px);
mask-image: radial-gradient(transparent 0 65px, #000 65.5px);
}
div+div {
margin-left: 1em;
border-image: none;
border-color: green;
}
<div></div>
<div></div>
I'm trying to create a button that has many layers - consequently I'm having to make use of pseudo elements.
To clarify, my button is actually an anchor <a>.
I've run into an issue with one of the pseudo elements. I'm trying to give it a background while retaining a touchable target outside of the background. In order to do this, I've applied a background-clip over the content.
Everything works apart from the corners, which are applied but just not the shape I was expecting.
Button 2 is the design I'm trying to crack - by ensuring the pseudo perfectly overlays the element.
I now think I know what is happening but don't know why and how to fix it.
The padding is 6px deep, the border radius 10px. The radius is being calculated as 4px deep and 10px wide.
Any advice appreciated.
div {
margin-bottom: 20px;
}
a, a::before {
box-sizing: border-box;
}
a {
background-color: red;
border-radius: 10px;
color: white;
display: inline-block;
height: 36px;
line-height: 36px;
min-width: 100px;
position: relative;
text-align: center;
z-index: 1;
}
a::before {
background-color: rgba(0, 255, 0, 0.5);
border-radius: 10px;
content: "";
display: block;
height: 48px;
padding: 6px 0;
position: absolute;
top: -6px;
left: 0;
width: 100%;
z-index: -1;
}
.button2::before, .button2a::before {
background-clip: content-box;
}
.button2a {
margin-left: 20px;
}
.button2a::before {
background-color: blue;
}
.button3::before {
background-clip: content-box;
border-radius: 50%;
}
<div>
<p>This is a button with no background-clip - border-radius applied as expected<p>
<p><a class="button1">button 1</a></p>
</div>
<div>
<p>This has same border-radius as above, but background-clip applied on content - overlay doesn't completely disappear - leaves odd shapes at corners as can be seen on blue button. I was expecting 10px corners to mirror center</p>
<p><a class="button2">button 2</a><a class="button2a">button 2</a></p>
</div>
<div>
<p>This has same background-clip applied but uses a percentage for border-radius - seems to work as expected</p>
<p><a class="button3">button 3</a></p>
</div>
I'm trying to create a button that has many layers
What about doing things differently and instead of using pseudo element you can rely on multiple background to have multiple layers:
a.button1 {
background:
linear-gradient(to right,transparent 50%,blue 0),
linear-gradient(to bottom,orange 50%,transparent 0),
red;
border-radius: 10px;
color: white;
display: inline-block;
height: 36px;
line-height: 36px;
min-width: 100px;
text-align: center;
}
<a class="button1">button 1</a>
I've tried the perspective solution here How to transform each side of a shape separately? but can't get it to work probably due to the irregularness of the shape. Only the top and right side columns are slanted, vertical and bottom are straight. How can I do this with CSS?
Using CSS borders you can create triangles and trapezoids.
You can achieve your shape joining a triangle and a trapezoid.
.triangle {
border: 0 solid red;
border-left-width: 500px;
border-top-width: 30px;
border-top-color: transparent;
}
.trapezoid {
border: 0 solid red;
width: 500px;
border-bottom-width: 150px;
border-right-width: 30px;
border-right-color: transparent;
}
<div class="triangle"></div>
<div class="trapezoid"></div>
Method 1: Clip path
You could make use of CSS clip-path feature to clip a rectangle into the required polygon shape.
div {
box-sizing: border-box;
height: 150px;
width: 250px;
background: red;
padding: 10px;
-webkit-clip-path: polygon(0% 0%, 90% 10%, 100% 100%, 0% 100%);
clip-path: polygon(0% 0%, 90% 10%, 100% 100%, 0% 100%);
}
div#image {
background: url(http://lorempixel.com/400/200);
}
/* Just for demo */
div{
float: left;
margin: 10px;
transition: all 1s;
}
div:hover{
height: 200px;
width: 300px;
}
<div>Some text</div>
<div id="image"></div>
Pros:
Supports non-solid color fills inside the shape and also allow text to be present inside.
The shape is responsive and can adapt even if the container's dimensions change.
Cons:
Poor browser support for the CSS clip-path feature. This can be overcome by using inline SVG for the clip-path like in the below snippet as this has much better browser support.
div {
box-sizing: border-box;
height: 150px;
width: 250px;
padding: 10px;
background: red;
-webkit-clip-path: url(#clip);
clip-path: url(#clip);
}
div#image {
background: url(http://lorempixel.com/400/200);
}
/* Just for demo */
div{
float: left;
margin: 10px;
transition: all 1s;
}
div:hover{
height: 200px;
width: 300px;
}
<svg width="0" height="0">
<defs>
<clipPath id="clip" clipPathUnits="objectBoundingBox">
<path d="M0 0, 0.9 0.1, 1 1, 0 1z" />
</clipPath>
</defs>
</svg>
<div>
Some text
</div>
<div id="image"></div>
Method 2: CSS Transforms
Generally it is better not to use transforms when there is going to be content like image or text inside the shape (or) when the shape's background is not going to be a solid color because then we would either have to (a) reverse transform the child elements separately to make them look normal or (b) use absolute positioning.
For this particular shape, having text inside the shape is not a problem even while using transforms but having non solid background colors would be.
Option 1: Using two pseudo-elements
You could use a couple of pseudo-elements with skew transforms, position one on the top and the other on the right to produce the required shape. Hover the shape in snippet to see how it is created.
div {
position: relative;
height: 150px;
width: 250px;
background: red;
margin: 40px 40px 0px 0px;
}
div:after,
div:before {
position: absolute;
content: '';
background: red;
z-index: -1;
backface-visibility: hidden;
}
div:before {
height: 12.5%;
width: 100%;
top: 0px;
left: 0px;
transform-origin: right top;
transform: skewY(3deg);
}
div:after {
height: 100%;
width: 12.5%;
right: -1px;
top: -1px;
transform-origin: right top;
transform: skewX(10deg);
}
/* Just for demo */
div{
transition: all 1s;
}
div:hover{
height: 250px;
width: 300px;
}
div:hover:after{
background: blue;
}
div:hover:before{
background: green;
}
<div>Some text</div>
Pros:
Shape can be created with a single element and can have text inside it without any trouble.
Cons:
Having gradients (or) images as background for the shape is complex because they would need reverse rotation as mentioned earlier.
Shape is not 100% scalable as dimensions of the container should change proportionately for the shape to be maintained (hover on the shape in the snippet to see what I mean). Reason is same as mentioned here.
Option 2: Using one pseudo-element
This is pretty similar to the previous option except that this uses a single pseudo-element along with a overflow: hidden on the parent.
div {
position: relative;
box-sizing: border-box;
height: 200px;
width: 300px;
padding: 10px;
overflow: hidden;
}
div:after {
position: absolute;
content: '';
top: 0px;
left: -20px;
height: 100%;
width: 100%;
background: red;
transform-origin: left bottom;
transform: skewY(5deg) skewX(7.5deg);
z-index: -1;
}
div:hover {
height: 300px;
width: 500px;
transition: all 1s;
}
<div>Some text</div>
Pros:
Shape can be created with a single element and can have text inside it without any trouble.
Shape is responsive and can adapt even if the container's dimensions change .
Cons:
Same constraint as the previous option for gradient and image backgrounds.
Not suitable if the overflow: hidden on the parent is a constraint.
A solution is:
div {
width: 300px;
height: 100px;
margin:50px;
background-color: yellow;
border: 1px solid black;
}
.thisdiv {
-ms-transform: skewX(-20deg); /* IE 9 */
-webkit-transform: skewX(-20deg); /* Safari */
transform: skewX(-20deg); /* Standard syntax */
}
<div class="thisdiv">
This is the div I will skew
</div>
This is how to skew an element, if you want to make the shape you added, try using two overlaping div's, position, scale, rotate and skew, like this:
.outer-div{
position:relative;
margin:50px;
width:200px;
height:200px;
border:2px black dashed;
}
.inner-one{
position:absolute;
left:0;
bottom:0;
width:180px;
height:180px;
background:red;
}
.inner-two{
position:absolute;
bottom:2px;
right:0px;
width:200px;
height:195px;
background:red;
transform: rotate(7deg) skew(14deg) scale(0.905); /* Standard syntax */
}
<div class="outer-div">
<div class="inner-one">
</div>
<div class="inner-two">
</div>
</div>
2 Triangle Solution for Irregular Quadrilateral in CSS
In looking at your image, I notice that the skew at the top and right are really just long, narrow triangles overlaying the rectangle.
So what I did was create triangles using CSS border properties and absolutely position them over the rectangle.
#rectangle {
width: 400px;
height: 200px;
background-color: red;
margin-top: 25px;
position: relative;
}
#triangle-down {
border-left: 30px solid red;
border-right: 0;
border-top: 200px solid transparent;
position: absolute;
right: -30px;
top: 0;
}
#triangle-left {
border-top: 0;
border-bottom: 15px solid red;
border-right: 400px solid transparent;
position: absolute;
right: 0;
top: -15px;
}
<div id="rectangle">
<div id="triangle-down"></div>
<div id="triangle-left"></div>
</div>
jsFiddle demo
You could check out the clip-path property (see below from MDN), but support is very patchy. Chrome 24+ supports with prefix and FF, but only URL values, which reference a path in an SVG. You can read more about clip-path here.
Here's a basic pen - this will only work in Chrome.
From MDN
The clip-path CSS property prevents a portion of an element from getting displayed by defining a clipping region to be displayed i.e, only a specific region of the element is displayed. The clipping region is a path specified as a URL referencing an inline or external SVG, or shape method such as circle(). The clip-path property replaces the now deprecated clip property.
developer.mozilla.org/en-US/docs/Web/CSS/clip-path (sorry, not enough rep to link)
I am trying to create a background using css where one side is a solid color and the other is a texture: the two are split by a diagonal line. I would like this to be 2 separate divs since I plan to add some motion with jQuery where if you click on the right, the grey triangle gets smaller and if you click on the left the textured triangle gets smaller (like a curtain effect). Any advice would be greatly appreciated.
I think using a background gradient with a hard transition is a very clean solution:
.diagonal-split-background{
background-color: #013A6B;
background-image: -webkit-linear-gradient(30deg, #013A6B 50%, #004E95 50%);
}
Here are the examples in action: http://jsbin.com/iqemot/1/edit
You can change the placement of the diagonal line with the border pixels. With this approach you would have to position content over the background setup however.
#container {
height: 100px;
width: 100px;
overflow: hidden;
background-image: url(http://www.webdesign.org/img_articles/14881/site-background-pattern-07.jpg);
}
#triangle-topleft {
width: 0;
height: 0;
border-top: 100px solid gray;
border-right: 100px solid transparent;
}
<div id="container">
<div id="triangle-topleft"></div>
</div>
For this sort of thing you could use pseudo selectors such as :before or :after in your CSS to minimize on unnecessary HTML markup.
HTML:
<div id="container"></div>
CSS:
#container {
position: relative;
height: 200px;
width: 200px;
overflow: hidden;
background-color: grey;
}
#container:before {
content: '';
position: absolute;
left: 20%;
width: 100%;
height: 200%;
background-color: rgb(255, 255, 255); /* fallback */
background-color: rgba(255, 255, 255, 0.5);
top: 0;
-webkit-transform: rotate(45deg);
-moz-transform: rotate(45deg);
transform: rotate(45deg);
}
JSFiddle
I then attempted to to make it so that each section could expand depending on where you clicked. This unfortunately requires a little extra jQuery as the position of your click (relative to the the box) needs to be worked out.
A class is then added to the box which changes the :before pseudo object. The upside of using a class is that CSS animations are optimized better for the browser than jQuery ones.
JSFiddle
Resources:
Selecting and manipulating CSS pseudo-elements such as ::before and ::after using jQuery
Using jQuery how to get click coordinates on the target element
This method words on different sized windows and fills the screen. Even works on mobile.
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8">
<title>Diagonal</title>
<style>
*{
margin: 0;
padding: 0;
}
.diagonalimg{
width: 100%;
height: 100vh;
background-image: linear-gradient(to top left, #e394a3 50%, #8dd6a6 50%);
}
</style>
</head>
<body>
<div class="diagonalimg">
</div>
</body>
</html>
This is a full responsive solution. Note the 50.3% on the second stop point, this avoids the pixelating of the line as mentioned in the above comment by #timlg07
.responsive-diagonal {
width: 50vw;
height: 20vh;
background: linear-gradient(to right bottom, #ff0000 50%, #0000ff 50.3%);
}
<div class="responsive-diagonal"></div>
Method 1:
<div class="triangle"></div>
body {
margin: 0;
}
.triangle {
background-image: linear-gradient(to bottom right, LightGray 50%, Salmon 50%);
height: 100vh;
}
https://codepen.io/x-x00102/pen/ZEyEJyM
Method 2:
<div class="triangle"></div>
body {
margin: 0;
}
div {
width: 100vw;
height: 100vh;
}
.triangle::after {
content: '';
position: absolute;
border-top: 100vh solid LightGray;
border-right: 100vw solid Salmon;
}
https://codepen.io/x-x00102/pen/VwWwWGR
Here's a solution to add a diagonal line triangle to the end of a section, it requires one of the two sections to have a flat colour BG, but allows for the other to be a gradient or image.
The demo below shows it with the main section having a gradient, and the section below being a solid colour (in this instance, white).
/* Cruft for the demo */
body {
margin: 0;
padding: 0;
}
.gray-block {
background-image: linear-gradient(to bottom right, #000, #ccc);
color: #fff;
}
.gray-block__inner {
padding: 20px;
}
/* The actual solution */
.diagonal-end::after {
content: "";
display: block;
margin-top: -6vw; /* optionally move the diagonal line up half of its height */
border-top: 12vw solid transparent; /* change 12vw to desired angle */
border-bottom: 0px solid transparent;
border-right: 100vw solid #fff;
}
<div class="gray-block diagonal-end">
<div class="gray-block__inner">
<span>Some content</span>
</div>
</div>
I have a background image and want to add a transparent fill color on top of that. I use modern browsers like Firefox and Google Chrome.
This code works (but does not solve the problem)
background: url('bkg.jpg'), rgba(0,0,0, .5);
This code don't work (but should solve my problem)
background: rgba(0,0,0, .5), url('bkg.jpg');
Why? Solution?
https://developer.mozilla.org/en/CSS/background says:
Note: The background-color can only be defined on the last background,
as there is only one background color for the whole element.
http://www.w3.org/TR/css3-background/#layering says:
The background color, if present, is painted below all of the other
layers.
http://www.w3.org/TR/css3-background/#background-color says:
This property sets the background color of an element. The color is
drawn behind any background images.
Maybe you could use the :before/:after pseudoelements instead with absolute positioning.
http://jsfiddle.net/3mNkZ/3/
div {
background: rgba(0,255,0, .5);
width: 200px; height: 200px;
border: 10px solid red;
position: relative;
font-size: 100px;
color: white;
}
div:before {
background: url('http://placekitten.com/200/150');
content: ' ';
position: absolute;
z-index: -1;
width: 100%;
height: 100%;
}
You have to make a div that is the same size as the window to get the effect.
Here is a jsfiddle and the code below.
html{
background: url('http://tribulant.net/lightbox/files/2010/08/image-2.jpg');
}
.color {
background-color: rgb(100,0,0);
opacity: 0.5;
height: 100%;
width: 100%;
position: absolute;
top: 0px;
bottom: 0px;
}