I have the data in character format as " Mar 26, 2015 7:46:22 PM CDT " I have convert this into a Date format and also fetch the month, year and day separately.
Also is it possible to conevert it into a integer format.
Please advice.
You have to specify the format of the input string. Try:
as.POSIXct("Mar 26, 2015 7:46:22 PM CDT", format="%b %d, %Y %I:%M:%S %p")
Related
[Fri Aug 07, 2020 05:12 UTC]
I have this date format in a column, how to modify it to be 08, 07,2020 05:12
also, how to remove UTC from all columns
Check ?strptime for various format options. First convert the data to POSIXct, you can then use format to get it any format that you want.
x <- 'Fri Aug 07, 2020 05:12 UTC'
x1 <- as.POSIXct(x, format = '%a %b %d, %Y %H:%M UTC', tz = 'UTC')
x1
#[1] "2020-08-07 05:12:00 UTC"
format(x1, '%m,%d,%Y %H:%M')
#[1] "08,07,2020 05:12"
If we want to apply this for multiple columns we can use lapply. For example for first 4000 columns where your dataframe is called df we can do :
cols <- 1:4000
df[cols] <- lapply(df[cols], function(x) format(as.POSIXct(x,
format = '%a %b %d, %Y %H:%M UTC', tz = 'UTC'), '%m,%d,%Y %H:%M'))
I want to convert this kind of dates :Apr 09, 2019 to this kind of dates: Apr 09, 2019-04-09
I wrote
as.Date(Data$date, format = "%B %d, %Y")
format(as.Date(Data$date, format = "%B %d, %Y"), "%d-%m-%Y")
That code worked, however when I View(Data) I see that it had not converted.
Why? Any idea?
The reason is that the column is not updated. We need to assign (<-) the results back to the original column or a new column
Data$date <- format(as.Date(Data$date, format = "%B %d, %Y"), "%d-%m-%Y")
I’m working with date strings in R. Essentially, I have three different strings that represent date variables. I have these weird date strings from scraping data on the web.
Is it possible to convert these three different date strings into a universal format that makes it easier to perform logic on them with basic R code? Here are what the strings look like. Any help is greatly appreciated.
1. "Wed, Feb 7, 2017 7:30 pm"
2. "Wed Feb 7 08:00:04 2017"
3. "2017-02-7 13:06:14 PST" # Sys.time()
UPDATE: I now have a better understanding of as.POSIXct now, but I still don't understand why this doesn't work ?
as.POSIXct('02/15/2017, 10:00 PM', format = "%M/%D/%Y, %H:%M %r")
While your specific question has already been answered in comments.
I would like to leave this as a general reference for other people who might have similar problems and can come across this question.
So, as you have this in d.b's comment, your data time string have been parsed via command:
as.POSIXct("Wed, Feb 7, 2017 7:30 pm", format = "%A, %b %d,%Y %H:%M")
The difference between your first and the second case was in the format.
So, this is a general guidance on the format:
%a Abbreviated weekday
%A Full weekday
%b Abbreviated month
%B Full month
%c Locale-specific date and time
%d Decimal date
%H Decimal hours (24 hour)
%I Decimal hours (12 hour)
%j Decimal day of the year
%m Decimal month
%M Decimal minute
%p Locale-specific AM/PM
%S Decimal second
%U Decimal week of the year (starting on Sunday)
%w Decimal Weekday (0=Sunday)
%W Decimal week of the year (starting on Monday)
%x Locale-specific Date
%X Locale-specific Time
%y 2-digit year
%Y 4-digit year
%z Offset from GMT
%Z Time zone (character)
This is also useful if you want to do the conversions between different formats:
x <- as.POSIXct( "2017-01-15")
format(x, "%a")
[1] "Sun"
format(x, "Week of the year: %W")
[1] "Week of the year: 02"
source: https://www.stat.berkeley.edu/~s133/dates.html
as.POSIXct("Wed, Feb 7, 2017 7:30 pm", format = "%A, %b %d,%Y %H:%M", tz="PST8PDT")
as.POSIXct("Wed Feb 7 08:00:04 2017", format = "%A %b %d %H:%M:%S %Y",tz="PST8PDT")
as.POSIXct("2017-02-7 13:06:14 PST", format = "%Y-%m-%d %H:%M:%S",tz="PST8PDT")
I need to format a date variable with R. I get the current date with a simple date().
today <- date()
today
> "Mon Oct 10 1:00 2016"
I need to format this 'today' variable into a string with a specific format. below is an example of what the string should look like.
string <- ”10/10/2016 1:00 PM EDT"
string
> ”10/10/2016 1:00 PM EDT"
So the question is how do you format a character string that looks like "Mon Oct 10 1:00 2016" into ”10/10/2016 1:00 PM EDT".
I've tried working with strptime() and as.Date() functions but cannot figure out how to convert this string into a formatted date. Thanks for any help.
strftime(strptime(date(),
format = "%a %b %d %H:%M:%S %Y"),
format = "%m/%d/%Y %I:%M %p %Z")
See ??strptime.
I am new to R and I am trying to change date format in the data frame for date columns. My date column is in format Mar 13 2007 01:05:123AM. Now this date format values are same except day change and time remains same. So I was thinking to change it to format as Mar 13 2007.
I tried the following code:
df <- read.csv("mydata.csv")
df$collectdate <- format(as.Date(df$collectdate,"%b %d %Y"))
but it gives error saying "character string is not in a standard unambiguous format". What can I try next?
You could try:
date <- "Mar 13 2007 01:05:123AM"
gsub("(.*)(?=\\s\\d{2}:).*", "\\1", date, perl=TRUE)
#[1] "Mar 13 2007"
For the as.Date, it didn't show any errors.
format(as.Date(date,"%b %d %Y"), "%b %d %Y")
#[1] "Mar 13 2007