In a Plone's File content type, which property stores the file's original filename?
I'm using plone.jsonapi.routes to upload files to a plone instance. I can set the id ant the title but I can't set the associated file's filename.
For example, when I upload a file to Plone in the regular way, I can set its id and title, but additionally to that, the original file name is stored somewhere. You can see it here:
objects-essay.pdf - PDF document indicates the name the original file has.
But when I upload it with plone.jsonapi.routes that field is empty. So, I'm trying to figure it out which property stores the name to pass it to the api or to set it by hand.
Thanks.
IIRC, all Archetypes-based content types have a setFilename method that you can use to do this.
On Dexterity-based content types file's content is stored in blobs in the ZODB (instances of NamedBlobFile) and there's a parameter named filename that you can use to set it.
You can see an example of the later in plone.app.contenttypes.
Related
I am trying to pass the variables from one page to another in Drupal 7. Since in Drupal 7 we do not create the php file as such the content of the page gets saved as a plain text in DB, no files get created, so GET/POST are out of the solution.
How can I do this?
Content is saved in database, but every content is defined in some content type. And for every content type you can have different template file. Inside that template file you can put your php code reading GET/POST, or what ever.
So, you can use the usual way and read parameters from template, do what ever you want with them.
One way is to use variable_set() to save the value to database and variable_get() to retrieve the value from database.
To save the value:
variable_set('my_variable_unique_id', 'the value to be saved.');
To read the value back:
$myVariable = variable_get('my_variable_unique_id', 'default value in case could not find a saved value for the variable.');
I would like to generate an image using text and a custom font.
As it is mentioned here Output text as GIF or PNG for use in eBook
How can I store the file in my content's file field?
All you need to do is call the field accessor with a file-like object, preferably one that includes the file mime-type (image/png or image/gif in your case). Zope's OFS.File.File provides such info. Let's say your file field is simply called file (so it's setter is called setFile) and you have your image in a string variable named imagedata containing a PNG image:
from OFS.Image import File
image = File('ignored-id', 'ignored-title', imagedata, 'image/png')
contentobject.setFile(image)
Note that you may want to change your field to type ImageField though; it provides a richer interface for images, including HTML tag generation and scaling.
Get the python file-like object corresponding to the image and pass it as an argument to the field mutator method. If the field if called fooImage, then the mutator, by default, is object.setFooImage(image_file_here). Or you could pass it in using the object.update(fooImage=image_file_here) method.
I am using file upload mechanism to upload file for an employee and converting it into byte[] and passing it to varBinary(Max) to store into database.
Now I what I have to do is, if any file is already uploaded for employee, simply read it from table and show file name. I have only one column to store a file and which is of type VarBinary.
Is it possible to get all file information from VarBinary field?
Any other way around, please let me know.
If you're not storing the filename, you can't retrieve it.
(Unless the file itself contains its filename in which case you'd need to parse the blob's contents.)
If the name of the file (and any other data about the file that's not part of the file's byte data) needs to be used later, then you need to save that data as well. I'd recommend adding a column for the file name, perhaps one for its type (mime type or something like that for properly sending it back to the client's browser, etc.) and maybe even one for size so you don't have to calculate that on the fly for each file (useful when displaying a grid of files and not wanting to touch the large blob field in the query that populates the grid).
Try to stay away from using the file name for system-internal identity purposes. It's fine for allowing the users to search for a file by name, select it, etc. But when actually making the request to the server to display the file it's better to use a simple integer primary key from the table to actually identify it. (On a side note, it's probably a good idea to put a unique constraint on the file name column.)
If you also need help displaying the file to the user, you'll probably want to take the approach that's tried and true for displaying images from a database. Basically it involves having a resource (generally an .aspx page, but could just as well be an HttpHandler instead) which accepts the file ID as a query string parameter and outputs the file.
This resource would have no UI (remove everything from the .aspx except the Page directive) and would manually manipulate the response headers (this is where you'd set the content type from the file's type), write the byte stream to the client, and end the response. From the client's perspective, something like ~/MyContent/MyFile.aspx?fileID=123 would be the file. (You can suggest a file name to the browser for saving purposes in the response headers, which you'd probably want to do with the file's stored name.)
There's no shortage of quick tutorials (some several years old, it's been around for a while) on how to do this with images. Just remember that there's essentially no difference from the server's perspective if it's an image or any other kind of file. All the server needs to do is send the type in the response headers and write the file's bytes to the client. How the client handles the file is up to the browser. In the vast majority of cases, the browser will know what to do (display an image, display via a plugin a PDF, save a .doc, etc.).
I am looping through the posted values on a form with a view to doing something with them (so don't have access to the controls themselves). This is the process I have to take on this project so that is why I'm doing it this way.
On the form I will have a file upload box but I am not sure how I would upload the file that has been selected from it as I can't just do Control.SaveAs(). When I return the posted value using Request.Form.Item[i] I get the file name I chose but not the full path like I would expect.
Can someone point me in the right direction please?
Thanks.
If you want to manipulate the uploaded files directly, and not through a FileUploader control, you should use the Request.Files collection and not the Request.Form
File Upload controls only pass the file name and the contents. I'm not sure why you would need a folder name, especially since the folder name would be for the client - I can't expect that this would have any value to you since you want to save the file on the server.
As I am unsure of your goals, I would recommend using Server.MapPath("~/Folder") to find a suitable folder to save your uploaded files to
At the moment i get file extension of the file like :
string fileExt = System.IO.Path.GetExtension(filUpload.FileName);
But if the user change the file extension of the file ( for example user could rename "test.txt" to "test.jpg" ), I can't get the real extension . What's the solution ?
You seem to be asking if you can identify file-type from its content.
Most solutions will indeed attempt the file extension, but there are too many different possible file types to be reliably identifiable.
Most approaches use the first several bytes of the file to determine what they are.
Here is one list, here another.
If you are only worried about text vs binary, see this SO question and answers.
See this SO answer for checking if a file is a JPG - this approach can be extended to use other file headers as in the first two links in this answer.
Whatever the user renames the file extension to, that is the real file extension.
You should never depend on the file extension to tell you what's in the file, since it can be renamed.
See "how can we check file types before uploading them in asp.net?"
There's no way to get the 'real' file extension - the file extension that you get from the filename is the real one. If file content is your concern, you can retrieve the content type using the .ContentType property and verify that it is a content type that you are expecting - eg. image/jpg.