JavaFX window setTitle - javafx

Question

I have a main class which is the following:
public class Window extends Application {
#Override
public void start(Stage foablak) throws Exception {
Parent root = FXMLLoader.load(getClass().getResource("Foablak.fxml"));
Scene scene = new Scene(root);
foablak.setScene(scene);
foablak.setWidth(900);
foablak.setHeight(700);
foablak.setResizable(false);
foablak.setTitle("Window");
foablak.show();
}
public static void main(String[] args) {
launch(args);
}
}
How can I update the Title of the from another .java class without closing the window and open a new one?

Answer 1

Exposing properties using static, just for the sake of exposing, may be considered as a bad design. You have different ways to achieve the same, for example, expose a method from the Window class which sets the stage title.
public class Window extends Application {
private Stage stage;
#Override
public void start(Stage foablak) throws Exception {
stage = foablak;
Parent root = FXMLLoader.load(getClass().getResource("Foablak.fxml"));
Scene scene = new Scene(root);
foablak.setScene(scene);
foablak.setWidth(900);
foablak.setHeight(700);
foablak.setResizable(false);
foablak.setTitle("Window");
foablak.show();
}
public static void main(String[] args) {
launch(args);
}
public void setStageTitle(String newTitle) {
stage.setTitle(newTitle);
}
}

Answer 2

Yes, you can. Inside of your Application.start() method, save a reference to your primary Stage that you can access elsewhere, and then call Stage.setTitle().
class MyApplication extends Application {
public static Stage primaryStage;
#Override
public void start(Stage primaryStage) {
MyApplication.primaryStage = primaryStage;
// ...
}
}
MyApplication.primaryStage.setTitle("New Title");
As an aside, I would avoid calling your class Window, as that is the name of one of the JavaFX classes.

Answer 3

The following may not be the solution you were looking for, but it might be useful for some of the developers:
Scenario: There is only 1 JavaFX app; The app needs to be run
multiple times; You want to differentiate who is running the app
Attention: Pay attention of the running order of the Main and
Controller class
Solution: i. In the Controller Class, declare a private static variable, e.g., private static String strWho; ii. Expose strWho by providing a getter method. e.g.: public static String getWho(){
return strWho;
}; iii. Implement the initialize method for the Controller, and based on your need, assign a distinct value each time you run the JavaFX app. eg., #FXML
public void initialize() {
strWho = "you need to have logic here, to have a distinct value each time you run the app";
}
In the Main start method, right before you call the stage.show, set the title. eg:
primaryStage.setTitle(Controller.getWho()));
primaryStage.show();
One way to implement the logic for distinct value of the strWho each time you run the app: You can have a TextInputDialog in the Controller's initialize method, to accept user input, by asking for a name etc.