R: Read multiple files and label them based on the file name - r

I have a folder with about 400 files with the same structure. Each of these file contains 4 columns with no header, corresponding to 4 climate variables. I would need to include two new columns in each of these files, based on the name of the file. The structure of the name is MeteoData_PXCY, withX=CODE_PLOT and Y=CODE_COUNTRY. Once I have these two new columns I need to read all the files in one single dataset, and aggregate grouping by CODE_PLOT and CODE_COUNTRY to calculate mean values. Hence, the final output is 400 rows, one row per CODE_PLOT and CODE_COUNTRY.
Example file MeteoData_P1C1.csv
32509 33.91 2.9155 4494.5 13.46
32540 63.03 3.9718 6520.8 25.12
32568 71.68 8.7874 11587 58.67
32599 116.38 7.8683 13286 62.58
32629 31.12 16.097 23555 135.35
32660 56.56 16.481 21886 130.24
32690 68.59 19.737 21677 141.15
32721 55.55 18.755 18830 117.39
32752 59.88 15.598 13579 81.06
32782 43.43 12.361 8622.2 54.57
Example MeteoData_P109C19.csv
32509 18.17 -0.70355 1413.5 9.93
32540 78 -0.43607 3574.6 10.46
32568 74.43 0.38645 7478.5 22.53
32599 73.19 2.5743 12352 42.85
32629 36.75 9.4852 21244 105.57
32660 61.65 13.753 21586 117.3
32690 86.16 15.991 20452 127.89
32721 98.02 12.713 13981 76.73
32752 32.14 9.9547 10850 53.13
32782 53.46 4.4252 5041.7 21.46
In the final output I should have this structure (without “;”):
Date; Precip; Temp; Rad; Pet; CODE_PLOT; CODE_COUNTRY
32540; 63.03; 3.9718; 6520.8; 25.12; 1; 1
32568; 71.68; 8.7874; 11587; 58.67; 9; 19
For the moment, I have:
setwd("MeteoData”) # Folder in which all the files are into
filenames <- list.files(pattern=".csv")
clim <- lapply(filenames, function(x) read.csv(file=x, header=FALSE))

You could put all your files in a new folder/directory, and then create a loop using list.files:
all.dfs <- list()
for(filename in list.files("some_dir")) {
all.dfs[[length(all.dfs) + 1]] <- read.table(filename, ...)
# put in read.table call the appropriate arguments, including column names for the existing data in the files
all.dfs[[length(all.dfs)]]$CODE_PLOT <- sub(".*P(\\d*)C(\\d*)\\.csv", "\\1", filename)
all.dfs[[length(all.dfs)]]$CODE_COUNTRY <- sub(".*P(\\d*)C(\\d*)\\.csv", "\\2", filename)
}
Then merging everything into one dataframe...
big.df <- do.call(rbind, all.dfs)
Haven't tested it but feel free to ask questions in comment.

Related

Apply a particular function in all files of a folder using R

I have developed a particular R function named DNAdupstability for some Biological analysis which requires input using as fasta file (.fasta/.txt) which returns a dataframe in this format:
Sequence Position8 Position9 Position10 Position11 Position12 Position13
1 1 -1.473571 -1.473571 -1.462143 -1.412143 -1.412143 -1.371429
Position14 Position15 Position16 Position17 Position18 Position19 Position20
1 -1.372143 -1.4 -1.428571 -1.439286 -1.430714 -1.420714 -1.397143
This is a random dataframe and it continues to n positions on the basis of the input sequence. I have a folder named Random_fasta which has 1333 equal length but different fasta sequences. The developed function DNAdupstability gives the desired outcome for a single fasta sequence (the above mentioned dataframe) from the folder Random_fasta, but now I want to carry out analysis of all the other 1332 sequences using the same DNAdupstability function and a form a combined dataframe similar to this format for all the sequences
Sequence Position8 Position9 Position10 Position11 Position12 Position13
1 1 -1.434286 -1.434286 -1.446429 -1.435714 -1.445714 -1.509286
2 2 -1.522143 -1.492143 -1.463571 -1.435714 -1.492857 -1.544286
3 3 -1.232857 -1.265000 -1.333571 -1.328571 -1.330000 -1.329286
4 4 -1.799286 -1.799286 -1.799286 -1.799286 -1.730714 -1.735714
5 5 -1.547143 -1.507143 -1.535714 -1.530714 -1.478571 -1.450714
Position14 Position15 Position16 Position17 Position18 Position19 Position20
1 -1.452143 -1.402143 -1.390000 -1.457143 -1.509286 -1.498571 -1.458571
2 -1.544286 -1.544286 -1.544286 -1.544286 -1.601429 -1.715000 -1.755000
3 -1.340000 -1.328571 -1.333571 -1.344286 -1.384286 -1.446429 -1.486429
4 -1.667143 -1.605000 -1.536429 -1.486429 -1.536429 -1.605000 -1.600000
5 -1.450714 -1.450714 -1.412143 -1.372143 -1.434286 -1.531429 -1.615000
So that I could calculate the position-wise mean which will then be further used for some visualization using ggplot2. Is there any way that I could apply the same functions in all the files of the folder particularly using R and get the desired combined dataframe? Any help will be greatly appreciated!
One option is to recursively return all the files from the main folder with list.files, then apply the custom fuction by looping over the files, and convert to a single data.frame with do.call(rbind
files <- list.files('path/to/your/folder', recursive = TRUE,
pattern = "\\.txt$", full.names = TRUE)
lst1 <- lapply(files, DNAdupstability)
out <- do.call(rbind, lst1)
Or we can use map from purrr with _dfr to combine all the output from the list to a single data.frame
library(purrr)
out <- map_dfr(files, DNAdupstability)

R: read_csv reads numeric entries as logical - parsing col_logical instead of col_double

I am new to R.
I wrote a code for an assignment which reads several csv files and binds it into a data frame and then according to the id, calculates the mean of either nitrate or sulfate.
Data sample:
Date sulfate nitrate ID
<date> <dbl> <dbl> <dbl>
1 2003-10-06 7.21 0.651 1
2 2003-10-12 5.99 0.428 1
3 2003-10-18 4.68 1.04 1
4 2003-10-24 3.47 0.363 1
5 2003-10-30 2.42 0.507 1
6 2003-11-11 1.43 0.474 1
...
To read the files and create a data.frame, I wrote this function:
pollutantmean <- function (pollutant, id = 1:332) {
#creating a data frame from several files
file_m <- list.files(path = "specdata", pattern = "*.csv", full.names = TRUE)
read_file_m <- lapply(file_m, read_csv)
df_1 <- bind_rows(read_file_m)
# delete NAs
df_clean <- df_1[complete.cases(df_1),]
#select rows according to id
df_asid_clean <- filter(df_clean, ID %in% id)
#count the mean of the column
mean_result <- mean(df_asid_clean[, pollutant])
mean_result
However, when the read_csv function is applied, certain entries in nitrate column are read as col_logical, although the whole class of the column remains numeric and the entries are numeric. It seems that the code "expects" to receive logical value, although the real value is not.
Throughout the reading I get this message:
<...>
Parsed with column specification:
cols(
Date = col_date(format = ""),
sulfate = col_double(),
nitrate = col_logical(),
ID = col_double()
)
Warning: 41 parsing failures.
row col expected actual file
2055 nitrate 1/0/T/F/TRUE/FALSE 0.383 'specdata/288.csv'
2067 nitrate 1/0/T/F/TRUE/FALSE 0.355 'specdata/288.csv'
2073 nitrate 1/0/T/F/TRUE/FALSE 0.469 'specdata/288.csv'
2085 nitrate 1/0/T/F/TRUE/FALSE 0.144 'specdata/288.csv'
2091 nitrate 1/0/T/F/TRUE/FALSE 0.0984 'specdata/288.csv'
.... ....... .................. ...... ..................
See problems(...) for more details.
I tried to change the column class by writing
df_1[,nitrate] <- as.numeric(as.character(df_1[, nitrate])
, after binding rows, but it only shows that NAs are again introduced in step which calculates the mean.
What is wrong here, and how could I solve it?
Would appreciate your help!
UPDATE: tried to insert read_csv(col_types = list...), but I get "files" argument is not defined. As I understand, the R reads inside read_csv first, then lapply and because there is not "file" given at the time, it shows error.
The problem with readr::read_csv() failure in parsing the column types can be overcome by passing a col_types= argument in lapply(). We do this as follows:
pollutantmean <- function (directory,pollutant,id=1:332){
require(readr)
require(dplyr)
file_m <- list.files(path = directory, pattern = "*.csv", full.names = TRUE)[id]
read_file_m <- lapply(file_m, read_csv,col_types=list(col_date(),col_double(),
col_double(),col_integer()))
# rest of code goes here. Since I am a Community Mentor in the
# JHU Data Science Specialization, I am not allowed to post
# a complete solution to the programming assignment
}
Note that I use the [ form of the extract operator to subset the list of file names with the id vector that is an argument to the function, which avoids reading a lot of data that isn't necessary. This eliminates the need for the filter() statement in the code posted in the question.
With some additional programming statements to complete the assignment, the code in my answer produces the correct results for the three examples posted with the assignment, as listed below.
> pollutantmean("specdata","sulfate",1:10)
[1] 4.064128
> pollutantmean("specdata", "nitrate", 70:72)
[1] 1.706047
> pollutantmean("specdata", "nitrate", 23)
[1] 1.280833
Alternately we could implement lapply() with an anonymous function that also uses read_csv() as follows:
read_file_m <- lapply(file_m, function(x) {read_csv(x,col_types=list(col_date(),col_double(),
col_double(),col_integer()))})
NOTE: while it is completely understandable that students who have been exposed to the tidyverse would like to use it for the programming assignment, the fact that dplyr isn't introduced until the next course in the sequence (and readr isn't covered at all) makes it much more difficult to use for assignments in R Programming, especially the first assignment, where dplyr non-standard evaluation gives people fits. An example of this situation is yet another Stackoverflow question on pollutantmean().
With the read_csv update you don't need lapply, you can simply pass along the file path directly to read_csv as you already have defined.
Regarding the column types this can then be sen manually in the col_type argument:
col_type=cols(Date-col_date,sulfate=...)

base R faster than readr for reading multiple CSV files

There is a lot of documentation on how to read multiple CSVs and bind them into one data frame. I have 5000+ CSV files I need to read in and bind into one data structure.
In particular I've followed the discussion here: Issue in Loading multiple .csv files into single dataframe in R using rbind
The weird thing is that base R is much faster than any other solution I've tried.
Here's what my CSV looks like:
> head(PT)
Line Timestamp Lane.01 Lane.02 Lane.03 Lane.04 Lane.05 Lane.06 Lane.07 Lane.08
1 PL1 05-Jan-16 07:17:36 NA NA NA NA NA NA NA NA
2 PL1 05-Jan-16 07:22:38 NA NA NA NA NA NA NA NA
3 PL1 05-Jan-16 07:27:41 NA NA NA NA NA NA NA NA
4 PL1 05-Jan-16 07:32:43 9.98 10.36 10.41 10.16 10.10 9.97 10.07 9.59
5 PL1 05-Jan-16 07:37:45 9.65 8.87 9.88 9.86 8.85 8.75 9.19 8.51
6 PL1 05-Jan-16 07:42:47 9.14 8.98 9.29 9.04 9.01 9.06 9.12 9.08
I've created three methods for reading in and binding the data. The files are located in a separate directory which I define as:
dataPath <- "data"
PTfiles <- list.files(path=dataPath, full.names = TRUE)
Method 1: Base R
classes <- c("factor", "character", rep("numeric",8))
# build function to load data
load_data <- function(dataPath, classes) {
tables <- lapply(PTfiles, read.csv, colClasses=classes, na.strings=c("NA", ""))
do.call(rbind, tables)
}
#clock
method1 <- system.time(
PT <- load_data(path, classes)
)
Method 2: read_csv
In this case I created a wrapper function for read_csv to use
#create wrapper function for read_csv
read_csv.wrap <- function(x) { read_csv(x, skip = 1, na=c("NA", ""),
col_names = c("tool", "timestamp", paste("lane", 1:8, sep="")),
col_types =
cols(
tool = col_character(),
timestamp = col_character(),
lane1 = col_double(),
lane2 = col_double(),
lane3 = col_double(),
lane4 = col_double(),
lane5 = col_double(),
lane6 = col_double(),
lane7 = col_double(),
lane8 = col_double()
)
)
}
##
# Same as method 1, just uses read_csv instead of read.csv
load_data2 <- function(dataPath) {
tables <- lapply(PTfiles, read_csv.wrap)
do.call(rbind, tables)
}
#clock
method2 <- system.time(
PT2 <- load_data2(path)
)
Method 3: read_csv + dplyr::bind_rows
load_data3 <- function(dataPath) {
tables <- lapply(PTfiles, read_csv.wrap)
dplyr::bind_rows(tables)
}
#clock
method3 <- system.time(
PT3 <- load_data3(path)
)
What I can't figure out, is why read_csv and dplyr methods are slower for elapsed time when they should be faster. The CPU time is decreased, but why would the elapsed time (file system) increase? What's going on here?
Edit - I added the data.table method as suggested in the comments
Method 4 data.table
library(data.table)
load_data4 <- function(dataPath){
tables <- lapply(PTfiles, fread)
rbindlist(tables)
}
method4 <- system.time(
PT4 <- load_data4(path)
)
The data.table method is the fastest from a CPU standpoint. But the question still stands on what is going on with the read_csv methods that makes them so slow.
> rbind(method1, method2, method3, method4)
user.self sys.self elapsed
method1 0.56 0.39 1.35
method2 0.42 1.98 13.96
method3 0.36 2.25 14.69
method4 0.34 0.67 1.74
I would do that in the terminal(Unix). I would put all files int the same folder and then navigate to that folder (in terminal), the use the following command to create only one CSV file:
cat *.csv > merged_csv_file.csv
One observation regarding this method is that the header of each file will show up in the middle of the observations. To solve this I would suggest you do:
Get just the header from the first file
head -2 file1.csv > merged_csv_file.csv
then skip the first "X" lines from the other files, with the folling command, where "X" is the number of lines to skip.
tail -n +3 -q file*.csv >> merged_csv_file.csv
-n +3 makes tail print lines from 3rd to the end, -q tells it not to print the header with the file name (read man), >> adds to the file, not overwrites it as >.
I might have found a related issue. I am reading in nested CSV data from some simulation output, where multiple columns have CSV formatted data as elements, which I need to unnest and reshape for analysis.
With simulations where I have many runs, this resulted in thousands of elements that needed to be parsed. Using map(.,read_csv) this would take hours to transform. When I rewrote my script to apply read.csv in a lambda function, the operation would complete in seconds.
I'm curious if there is some intermediate system I/O operation or error handling that creates a bottleneck you wouldn't run into with a single input file.

Load frequent subsequences from TXT

Is it possible to load a list of frequent subsequences from a .txt file, and make TraMineR recognize it as a sequence object?
Unfortunately I don't have the raw data, therefore I am not able to recreate the analysis. The only file what I have is a .txt file containing the frequent subsequences. I assume it was created with the seqefsub() function from the TraMineR package, with maxGap=2, because the data looks like as an output of the mentioned function.
read.table() reads it as a data frame but as far as I understood, TraMineR handles event sequences as lists with many additional attributes, that for example are not contained in this file. Or I don't know how to extract them...
This is how the a couple of lines from the .txt file look like:
Subsequence Support Count
16 (WT4)-(WT3) 0.76666667 805
17 (WL2) 0.76380952 802
18 (S1) 0.76000000 798
19 (FRF,WL2) 0.74380952 781
20 (WT2)-(WT1) 0.70571429 741
To create an event sequence object from the (text) subsequences, you have to transform them into vertical time stamped event (TSE) form. The function below does the job for your data
## Function subseq.to.TSE
## puts the sequences into TSE format using
## position as timestamp
## sdf: a data frame with columns Id, Subsequence, Support and Count.
subseq.to.TSE <- function(sdf){
tse <- data.frame(id=0, event="", time=0)
k <- 0
for (i in 1:nrow(sdf)){
id <- sdf[i,"Id"]
s <- sdf[i,"Subsequence"]
ss <- gsub("\\(","",s)
ss <- gsub("\\)","",ss)
# split transitions
st <- strsplit(ss, split="-")[[1]]
for (j in 1:length(st)){
stt <- strsplit(st[j], split=",")[[1]]
for(jj in 1:length(stt)){
k <- k+1
tse[k,1] <- id
## parsing for simultaneous events
if (!(stt[jj] %in% levels(tse[,2])))
{levels(tse[,2]) <- c(levels(tse[,2]),stt[jj])}
tse[k,2] <- stt[jj]
tse[k,3] <- j
}
}
}
return(tse)
}
Here is how you would use it on the example data.
We first create the data frame that we name s.df
s.df <- data.frame(scan(what=list(Id=0, Subsequence="", Support=double(), Count=0)))
16 (WT4)-(WT3) 0.76666667 805
17 (WL2) 0.76380952 802
18 (S1) 0.76000000 798
19 (FRF,WL2) 0.74380952 781
20 (WT2)-(WT1) 0.70571429 741
# leave a blank line to end the scan
Then we extract the TSE data from s.df and create from it the event sequence object using seqecreate. Finally, we assign the counts as sequence weights.
s.tse <- subseq.to.TSE(s.df)
seqe <- seqecreate(s.tse)
seqeweight(seqe) <- s.df[,"Count"]
Now you can for instance plot the event sequences with
seqpcplot(seqe)

Download VIX futures prices from CBOE

I am trying to get historical prices for VIX futures by downloading all the CSV files on this page (http://cfe.cboe.com/Products/historicalVIX.aspx). Here is the code I am using to do this:
library(XML)
#Extract all links for url
url <- "http://cfe.cboe.com/Products/historicalVIX.aspx"
doc <- htmlParse(url)
links <- xpathSApply(doc, "//a/#href")
free(doc)
#Filter out URLs ending with csv and complete the link.
links <- links[substr(links, nchar(links) - 2, nchar(links)) == "csv"]
links <- paste("http://cfe.cboe.com", links, sep="")
#Peform read.csv on each url in links, skipping the first two URLs as they are not relevant.
c <- lapply(links[-(1:2)], read.csv, header = TRUE)
I get the error:
Error in read.table(file = file, header = header, sep = sep, quote = quote, :
more columns than column names
Upon further investigation, I realize this is because some of the CSV files are formatted differently. If I load the URL links[9] manually, I see that the first row has this disclaimer:
CFE data is compiled for the .......use of CFE data is subject to the Terms and Conditions of CBOE's Websites.
Most of the other files (e.g.links[8] and links[10]) are fine so it seems this has been randomly inserted. Is there some R magic that can be done to handle this?
Thank you.
I have a getSymbols.cfe method in my qmao package (for the getSymbols function in quantmod package) that will make this a lot easier.
#install.packages('qmao', repos='http://r-forge.r-project.org')
library(qmao)
This is from the examples section of ?getSymbols.cfe (please read the help page as the function has a few arguments that you may want to be different than the defaults)
getSymbols(c("VX_U11", "VX_V11"),src='cfe')
#all contracts expiring in 2010 and 2011.
getSymbols("VX",Months=1:12,Years=2010:2011,src='cfe')
#getSymbols("VX",Months=1:12,Years=10:11,src='cfe') #same
And it's not just for VIX
getSymbols(c("VM","GV"),src='cfe') #The mini-VIX and Gold vol contracts expiring this month
If you're not familiar with getSymbols, by default it stores the data in your .GlobalEnv and return the name of the object that was saved.
> getSymbols("VX_Z12", src='cfe')
[1] "VX_Z12"
> tail(VX_Z12)
VX_Z12.Open VX_Z12.High VX_Z12.Low VX_Z12.Close VX_Z12.Settle VX_Z12.Change VX_Z12.Volume VX_Z12.EFP VX_Z12.OpInt
2012-10-26 19.20 19.35 18.62 18.87 18.9 0.0 22043 15 71114
2012-10-31 18.55 19.50 18.51 19.46 19.5 0.6 46405 319 89674
2012-11-01 19.35 19.35 17.75 17.87 17.9 -1.6 40609 2046 95720
2012-11-02 17.90 18.65 17.55 18.57 18.6 0.7 42592 1155 100691
2012-11-05 18.60 20.15 18.43 18.86 18.9 0.3 28136 110 102746
2012-11-06 18.70 18.85 17.75 18.06 18.1 -0.8 35599 851 110638
Edit
I see now that I did not answer your question, but rather pointed you to another way to get the same error! A simple way to make your code work, is to make a wrapper for read.csv that uses readLines to see if the first row contains the disclaimer; if it does, skip the the first row, otherwise use read.csv as normal.
myRead.csv <- function(x, ...) {
if (grepl("Terms and Conditions", readLines(x, 1))) { #is the first row the disclaimer?
read.csv(x, skip=1, ...)
} else read.csv(x, ...)
}
L <- lapply(links[-(1:2)], myRead.csv, header = TRUE)
I also applied that patch to getSymbols.cfe. You can get the latest version of qmao (1.3.11) using svn checkout (see this post if you need help with that), or, you can wait until R-Forge builds it for you which usually happens pretty quickly, but could take up to a couple of days.

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