Situation
I wrote an R program which I split up into multiple R-files for the sake of keeping a good code structure.
There is a Main.R file which references all the other R-files with the 'source()' command, like this:
source(paste(getwd(), dirname1, 'otherfile1.R', sep="/"))
source(paste(getwd(), dirname3, 'otherfile2.R', sep="/"))
...
As you can see, the working directory needs to be set correctly in advance, otherwise, this could go wrong.
Now, if I want to share this R program with someone else, I have to pass all the R files and folders in relative order of each other for things to work. Hence my next question.
Question
Is there a way to replace all the 'source' commands with the actual R script code which it refers to? That way, I have a SINGLE R script file, which I can simply pass along without having to worry about setting the working directory.
I'm not looking for a solution which is an 'R package' (which by the way is one single directory, so I would lose my own directory structure). I simply wondering if there is an easy way to combine these self-referencing R files into one single file.
Thanks,
Ok I think you could use something like scaning all the files and then writting them again in the same new one. This can be done using readLines and sink:
sink("mynewRfile.R")
for(i in Nfiles){
current_file = readLines(filedir[i])
cat("\n\n#### Current file:",filedir[i],"\n\n")
cat(current_file, sep ="\n")
}
sink()
Here I have supposed all your file directories are in a vector filedir with length Nfiles, I guess you can adapt that
Related
I'm not sure how to properly ask this but basically I have a very populated single 400 line file on a kaggle competition I was working on and I want to split it up into multiple files (say one file is for data cleaning, another file is for feature engineering etc) in such a way that I can have one main file that will go from reading the csv files all the way to making the model predictions, how can I do that in R? Do I have to encapsulate the entire files into one function each and then use that? If so how does that work? Thanks in advance
You can use the source command and pass it the filename. try ?source
I'm no R-programmer (because of the problem I started learning it), I'm using Python, In a forcasting task I got a dataset signalList.rdata of a pheomenen called partial discharge.
I tried some commands to load, open and view, Hardly got a glimps
my_data <- get(load('C:/Users/Zack-PC/Desktop/Study/Data Sets/pdCluster/signalList.Rdata'))
but, since i lack deep knowledge about R, I wanted to convert it into a csv file, or any type that I can deal with in python.
or, explore it and copy-paste manually.
so, i'm asking for any solution whether using R or Python or any tool to get what's in the .rdata file.
Have you managed to load the data successfully into your working environment?
If so, write.csv is the function you are looking for.
If not,
setwd("C:/Users/Zack-PC/Desktop/Study/Data Sets/pdCluster/")
signalList <- load("signalList.Rdata")
write.csv(signalList, "signalList.csv")
should do the trick.
If you would like to remove signalList from your working directory,
rm(signalList)
will accomplish this.
Note: changing your working directory isn't necessary, it just makes it easier to read in a comment I feel. You may also specify another path for saving your csv to within the second argument of write.csv.
I used to work with R on my mac and never had any problems.
Now I would like to use it on my work computer (windows). The problem is I can't import any files to start working with them. I tried several options:
mydata<-read.table("c:/temp/myfile.csv",header=TRUE)
mydata<-read.csv("myfile.csv",header=TRUE)
mydata<-read.table("c:/myfile.csv",header=TRUE)
mydata<-read.table("Desktop/myfile.csv",header=TRUE)
I also tried to change / into \ in all variants above.
Nothing seems to work. R displays the command in red, sometimes with a comment "connection can't be opened" or "no such file or directory" (my translation from German).
I tried copying the file I want to open to a different location (desktop, c:, temp), but alas, nothing helps.
Do you have any ideas why I have this problem and how I can solve it? Thanks in advance.
There is a safer way to work with paths; just using file.path().
So, if you're trying to get a file in C:/temp/turtles.csv, then you'd use:
targetFile <- file.path('C:/', 'temp', 'turtles.csv')
read.csv( targetFile, header=TRUE )
Minor point since it showed up on Twitter; DO NOT USE PATHS THAT EXIST ONLY IN YOUR ENVIRONMENT.
Try to keep the data in a path either in or directly under where the script is.
You have three ways to do this with read.csv() function
To avoid inserting actual path you can do it simply nesting function
read.csv(file.choose(),header=TRUE)
it will open pop up for selecting your file just select file from directory
where you have saved it.
Now if you have to insert a path then just get actual location of your file
by
read.csv("C:\path\to\your\file\filename.csv",header=TRUE)
for Example
read.csv("C:\Users\Amway\Desktop\resources.csv",header=TRUE)
Best way is to have your own work space directory
so create a directory by your preferred name and just set that directory as a
R session work space by
setwd("C:\path\to\your\workspace directory\")
check your current directory by
getwd()
now if you want to read a file into R session just copy your file to work
space and just write
read.csv("resources.csv",header=TRUE)
So, it should be like this.
setwd("c:/mydir") # note / instead of \ in windows
Also.
MyData <- read.csv(file="c:/mydir/TheDataIWantToReadIn.csv", header=TRUE, sep=",")
Windows uses the other backslash.
https://www.howtogeek.com/181774/why-windows-uses-backslashes-and-everything-else-uses-forward-slashes/
I'm making a simple line in r to automatically open my generated plots.
I output the plots to a file called "plots.pdf" in the same directory as my r file, and at the end i use this two lines to try to open it:
dir <- paste("/Applications/Skim.app/Contents/MacOS/Skim ",getwd(),"/plots.pdf",sep="")
system(dir)
Basically, dir concatenates the full path of the skim app and the full path of the generated plot.
If i run the string stored at dir in a shell it works perfect, it opens the pdf file in Skim, but when i run it with system() from inside R it doesn't work (Skim says 'The document “plots.pdf” could not be opened.').
I believe this is a very little mistake somewhere in the syntax regarding the absolute/relative paths, but haven't managed to find it... Any advice is welcome! (Or a better way to achieve the same)
I found a way to bypass that problem, i just changed the path to Skim for the 'open' command and i let the system to assign the default app for pdf viewing. So:
dir <- paste("open ",getwd(),"/plots.pdf",sep="")
And it works.
I asked this question last week but was looking for how to do it with a batch script. I think it might be possible to do with R, but I'm not very experienced using it. However, after doing some research, I'm pretty sure its impossible to do it with a batch script alone so I think I'll need to use R or VBA script. I don't want someone to just throw the solution at me, if it requires using R or VBA then I'm only interested if you would link some good resources. I've been scouring the interwebs but have found nothing so far.
I need some sort of script that will:
Take the two folders as inputs
Generate a list of all the files in one of them.
For each file:
Read in the data from columns D-G
Find the matching file in the other folder and read in the same data
Compare each cell and verify that the two files match exactly
If they don’t match, report what data doesn’t match
This is what I was asked to do verbatim.
This is what I've done so far.
#echo off
setlocal disableDelayedExpansion
cls
rmdir c:\LocalDirectory/s /q
mkdir c:\LocalDirectory
xcopy "\\SERVER\Path\to\the\files" c:\LocalDirectory
cd c:\LocalDirectory
dir /b /a-d
as you can see, its not much. I can make a list of the files but I need something that can compare them. I know that I could manually do this comparison in Excel but I need to be able to do this for several files. So I'm trying to write some kind of script that will take a specific column of data in a specific excel file in a directory and compare all the rows of that column to a specific column in another xlsx file and then once its done that, generate a message that says either pass or fail. Once thats done, it should move on to the next excel file. The files that have the data thats being compared are named the exact same thing.