Im using Access 2010 when I try to input this syntax:
INSERT INTO Order ( ClientId, ProductID, EmployeeID, DeliveryID )
VAlUES ('1', '8', '3' '1');
It says syntax error in insert order statement. I used the same syntax in inserting record to my other tables and it works.
It's just a missing comma between the 2 last arguments.
Bye!
Related
I'm trying to create a trigger in which, only under certain circumstances, an insert is performed on another table. Consider the following code:
create table journal (
pk integer primary key autoincrement,
dsc varchar(10) not null
);
create table users (
name varchar(30) primary key not null
);
create trigger users_ai
after insert on users
begin
select
case
when 1 then
insert into journal(dsc) values('foo')
end;
end;
I get the following error when I run this code:
Error: near line 10: near "insert": syntax error
In production, the "1" in the when clause would be replaced by a more complex expression. I've also tried "true" and get the same results. I've also tried surrounding the insert statement in parens and get the same results. Any ideas how to accomplish what I want?
If you look at the syntax diagram for "CREATE TRIGGER", you'll see your attempt just doesn't match. You can, however, simply use the WHEN branch (without needing FOR EACH ROW):
create trigger users_ai
after insert on users
when 1 begin
insert into journal(dsc) values('foo');
end;
OK, figured it out. Instead of putting a conditional expression in the block of the trigger, I used a when clause. Here's the code that works:
create trigger users_ai
after insert on users when 1
begin
insert into journal(dsc) values('foo');
end;
If that when expression is changed to something that returns false (say 0) then the insert isn't done. In production, the expression will sometimes return true, sometimes false, which, of course, is the point of this code. Thanks everybody!
I think that you want a CASE statement, not a CASE expression.
create trigger users_ai after insert on users
begin
case
when ... then insert into journal(dsc) values('foo');
when ... then ...;
else ...;
end case;
end;
Note: if your trigger needs access to the data that was just inserted, its definition should the for each row option.
You can try to use an INSERT ... SELECT and your expression in the WHERE clause.
...
INSERT INTO journal
(dsc)
SELECT 'foo'
WHERE 1 = 1;
...
1 = 1 needs to be replaced by your Boolean expression.
CREATE TABLE IF NOT EXISTS developer (id INTEGER PRIMARY KEY AUTOINCREMENT,name TEXT, skill TEXT, yearsOfExperience INTEGER );
INSERT INTO developer(name, skill, yearsOfExperience) VALUES ('Simon', 'Ionic', '4');
INSERT INTO developer(name, skill, yearsOfExperience) VALUES ('Jorge', 'Firebase', '2');
INSERT INTO developer(name, skill, yearsOfExperience) VALUES ('Max', 'Startup', '5');
error:
Incorrect syntax near 'IF', Expecting'.', ID, or QOUTED_ID.
An expression of non-boolean type specified in a context where a condition is expected.
Incorrect syntax near 'developer'.
Incorrect syntax near 'developer'. Expecting '('.
Incorrect syntax near 'id'. Expecting '(' or SELECT.
I'm new to PL/SQL. I'm using oracle 11g XE along with sql developer. I'm trying to create to create an after insert trigger as follows
create or replace trigger tr1
after
insert ON
employee
for each row
begin
print :new.emp_id;
end;
The employee table is as follows
create table employee
( emp_id varchar2(5) primary key,
emp_name varchar2(10),
salary number,
company varchar2(10) foreign key references companies(comp_name)
);
When I run the statement I got a 'enter binds' window for the bind variable :new. But I was confused that why do I need to enter the value for :new since it is pseudorecord. Then I entered 'employee' as the values for :new. Now I'm getting the following error.
Error(2,8): PLS-00103: Encountered the symbol "" when expecting one of the following: := . ( # % ; The symbol ":=" was substituted for "" to continue.
Your problem is not in the :new pseudorecord. The error is coming from the usage of print, which is used to print the bind variable used in successful PL/SQL block or used in an EXECUTE command. For example, you can use it this way:
VARIABLE n NUMBER
BEGIN
:n := 1;
END;
/
Then
PRINT n;
But if you want to test the value being inserted, you can use DBMS_OUTPUT.PUT_LINE like this:
create or replace trigger tr1
after
insert ON
employee
for each row
BEGIN
dbms_output.put_line(:new.emp_id);
END;
/
Enable DBMS_OUTPUT window in your SQL Developer, then run
insert into employee values(1, 'empName', 1000, 'ABC');
You'll see 1 printed out.
However, you can always test the value from the table. Because the value should be already inserted into table. You can just query.
Here is my INSERT statement:
INSERT INTO customer_payment (payment_type_id, PAYMENT_METHOD, PAYMENT_STATUS, sql_sequence)
((SELECT emcpm.payment_method_type_id,
epmt.description, ecba.mandate_status
FROM cust_pay_map emcpm, payment_method_type epmt, customer_bank_account ecba
WHERE emcpm.payment_method_type_id = ecba.payment_method_type_id), MY_SEQ.nextval);
I get the error
ORA-00907: missing right parenthesis
when I run it. Please help me correct the mistake.
Add the sequence in the select statement like this:
INSERT
INTO customer_payment
(
payment_type_id,
PAYMENT_METHOD,
PAYMENT_STATUS,
sql_sequence
)
SELECT emcpm.payment_method_type_id,
epmt.description,
ecba.mandate_status ,
MY_SEQ.nextval
FROM cust_pay_map emcpm,
payment_method_type epmt,
customer_bank_account ecba
WHERE emcpm.payment_method_type_id = ecba.payment_method_type_id;
I made a sql query, below. I am getting an exception which I have shown as well. Any help is appreciated.
QUERY:
INSERT OR REPLACE INTO CLAIMS (DATE ,TIME , ADDRESS , CITY,
STATE , POSTAL , PHFNAME ,PHLNAME ,PHEMAIL ,PHPHONE ,AGENCY ,POLICY ,VEHICLENAME,
YEAR ,MAKE ,MODEL ,PLATELICENSE ,LSTATE ,VIN ,DRIVERNAME,DRFNAME ,DRLNAME ,
DRPHONE ,DREMAIL ,DRLICENSE) VALUES("Wednesday, May 4, 2011",
"10:39:10 PM EDT", "400 Chatham","Pune", "Penn", "45223", "John",
"Richard","jsmith#newyahoo.com","+1-11111111111",
"Three Rivers Insurance","(null)", "(null)", "(null)",
"(null)", "(null)","(null)", "(null)", "(null)","(null)",
"(null)", "(null)","(null)", "(null)","(null)") WHERE DATE LIKE
'Wednesday, May 4,%' AND TIME = '10:39:10 PM EDT'
Error:
SQLiteManager: Likely SQL syntax error:
[ near "WHERE": syntax error ]
Exception Name: NS_ERROR_FAILURE
Exception Message: Component returned failure code: 0x80004005 (NS_ERROR_FAILURE) [mozIStorageConnection.createStatement]
I faced the same issue for sync table for insert and update at a time and finally i use.
To use the insert or replace statement you need to use the coalesce function that required primary key column to put the where clause.
COALESCE((SELECT PRIMARY_KEY_COLUMN FROM TABLE_NAME WHERE UNIQUE_COLUMN = 'VALUE'),
(SELECT MAX(PRIMARY_KEY_COLUMN)+1 FROM TABLE_NAME))
it worked for me e.g
INSERT OR REPLACE INTO TBL_ADDRESSES
(ADDRESS_ID,ADDRESS1,ADDRESS2,ADDRESS3,ADDRESS_NAME,CITY,DB_ID)
VALUES (
COALESCE((SELECT ADDRESS_ID FROM TBL_ADDRESSES WHERE DB_ID = '111'),
(SELECT MAX(ADDRESS_ID)+1 FROM TBL_ADDRESSES)),
'IT 27','Pratap DSFSDSDDSDSF','test add ','IT 27','Jaipur','111') ;
INSERT OR REPLACE doesn't support WHERE clause, see theSQLite Insert doc. You can use a WHERE clause in UPDATE statements, see the SQLite Insert doc
Can help you if you can let us know what you wanted here ?