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Number of digits that are present in the maximum number that is formed using three digits?
Maximum factorial that is formed by three digits?
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I am not able to understand is there any thing tricky i am not getting?
i have tried 3 and 720 but it is incorrect
The maximum factorial which can be formed using 3 digits is 999!.
The answer can be easily obtained from wolfram alpha.
Number of digits in 999!.
999!=Answer
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I learn a deterministic final automat, nondeterministic,regex... And I found that is important to know a difference between ∑ and ∑1 since they both the same if ∑={0,1}, but I will answer that ∑1 is result of concatenation epsilon and 0,and the epsilon and 1.How would you answer that the question is asked by the professor?
Well, sigma is a finite set of input symbols called the alphabet ∑.
∑1 on the other hand is the word w consisting of one letter of the alphabet ∑, hence the 1 in ∑.
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I am trying to find an ascii formation to have a unit in a graph in exponent -2 and -3. For example mm^(-2). I found the relevant ascii formation for exponent 2 and 3 but i cannot find how to include the - sympol in the exponent.
Do you have any suggestions?
It depends on the character set you are using. If Unicode then there is 'SUPERSCRIPT MINUS' (U+207B) but not superscript minus two. So, as two characters, mm⁻².
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I want to understand the physical significance of n raise to some decimal power.
Like when i say 2^5. I understand that it means 2 multiplied 5 times. But how do i analyse 2^0.1.
Please suggest.
2^0.1 is the tenth root of 2. For rational powers, x^(p/q)=(x^p)^(1/q) is a combination of powers and roots.
For general real numbers,
x^y = exp(log(x)*y).
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An input sequence is given. Each stage of the iteration finds another sequence by calculating difference between n-i and n-i-1 number. We continue the process and at the end of the last iteration (iteration: n-1) we find only 1 number. What is the mathematical formulation for finding the last number as shown in the image?
Basically, the mathematical formulation is finding the n-1'th derivative of the degree-n-1 polynomial passing through all points (i,arr[i]). That derivative is guaranteed to be a constant. This is equivalent to the coefficient of the term with exponent n-1, divided by (n-1)!.
This method is a special case of what is known as Neville's Algorithm.
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From the following options, expressed in hexadecimal notation, select the answer which is a normalised floating point number: Pick 1 answer
I know the answer is one but I forgot how to work out this question, can anyone assist?
1.80800000
2.ff800000
3.80080000
4.FFF8FFFF
Normalized values are numbers where the exponent part is between 0x01 and 0xFE. Other exponents have special meanings. The first option has an exponent part of 0x01, the second and fourth options have 0xFF and the third option has 0x00.