I was trying to combine two separate date/time fields into one text box through an expression in SSRS.
My expression is:
=Format(Fields!EarlyShiftStart.Value,"hh:mm tt") & "-" & Format(Fields!LateShiftEnd.Value,"hh:mm tt")
And it looks to be correct in the report:
But I am getting a warning when I preview the report:
Warning 1 [rsRuntimeErrorInExpression] The Value expression for the
textrun ‘Textbox49.Paragraphs[0].TextRuns[0]’ contains an error: Input
string was not in a correct format
Not sure why this warning occurs, as it looks to be correct. Thoughts?
I am not sure about it but there is seems to be the wrong input string getting from the database. My best guess is that there are 2 reasons in your case this was happening
1) Some where in your data might present the null value.
If you want to avoid the warning I will suggest to you that use the expression as,
=Format(IIF(IsNothing(Fields!EarlyShiftStart.Value),"00:00",Fields!EarlyShiftStart.Value),"hh:mm tt") & "-" & Format(IIF(IsNothing(Fields!LateShiftEnd.Value),"00:00",Fields!LateShiftEnd.Value),"hh:mm tt")
This will filter out the incoming NULL values.
2) You are concatenating the two values with - so that could be the reason as you are formatting both your values as Time and then concatenating with string value. So try to change your expression as,
=CStr(Format(Fields!EarlyShiftStart.Value,"hh:mm tt")) & "-" & CStr(Format(Fields!LateShiftEnd.Value,"hh:mm tt"))
This will force convert your time values to the string and then con-cat them.
I would also suggest you to look at your incoming values if all values are in the correct format. So you can make changes in your expression accordingly.
Related
I'm writing a test case in robot framework. I'm getting the response in below json string:
{"responseTimeStamp":"1970-01-01T05:30:00",
"statusCode":"200",
"statusMsg":"200",
"_object":{"id":"TS82",
"name":"newgroup",
"desc":"ttesteste",
"parentGroups":[],
"childGroups":[],
"devices":null,
"mos":null,
"groupConfigRules" {
"version":null,
"ruleContents":null
},
"applications":null,"type":0
}
}
From that I want to take "_object" using:
${reqresstr} = ${response['_object']}
... but am getting the error "No keyword with name '=' found" error
If I try the following:
${reqresstr}= ${response['_object']}
... I'm getting the error "Keyword name cannot be empty." I tried removing the '=' but still get the same error.
How can I extract '_object' from that json string?
When using the "=" for variable assignment with the space-separated format, you must make sure you have no more than a single space before the "=". Your first example shows that you've got more than one space on either side of the "=". You must have only a single space before the = and two or more after, or robot will think the spaces are a separator between a keyword and argument.
For the "keyword must not be empty" error, the first cell after a variable name must be a keyword. Unlike traditional programming languages, you cannot directly assign a string to a variable.
To set a variable to a string you need to use the Set Variable keyword (or one of the variations such as Set Test Variable). For example:
${reqresstr}= Set variable ${response['_object']}
${reqresstr}= '${response["_object"]}'
wrap it inside quotes and two spaces after =
There is a syntax error in your command. Make sure there is a space between ${reqresstr} and =.
Using your example above:
${reqresstr} = ${response['_object']}
Morning all,
This should be a simple fix and I have searched around and found things that appear they should work, but they don't seem to though...
So - it's a simple "Open this form and show only records from This date" function and, you guessed it, good ol' US of A date formatting is the problem and no matter which way I try it nothing is solving the problem...
So - here's the form code...
DoCmd.OpenForm "frm_Prod_Runs_Edit_List", , , "# " & NEWDATE & " #"
to find NEWDATE...
I strip the date components from a couple of combo boxes (CBOYear & CBOMonth) and a field that represents the day of the month (data will be in the format "1st" or "2nd" etc...)
I concatenate the individual components...
NEWDATE = DateSerial(TempYear, TempMonth, TempDate)
A msgbox NEWDATE popup results in the correct data (ie 1/3/18)
But when I run the code it either selects everything or nothing... the only time the function works is when the day field is 13 or higher (ie 13/3/18) - thus it can determine the correct format to work with.
I'm sure the correct answer is already here somewhere - the correct question however may be something I have not thought to search for.
I have tried to use DATEVALUE() before and within the form open code. I have tried to hard code the US format to see if that works...
DoCmd.OpenForm "frm_Prod_Runs_Edit_List", , , "#3/1/18#"
No good... shows all records - same if I hard code for the AU format #1/3/18#
My PC is set up for AU format dd/mm/yy
So... Which function do I need to use to convert the AU Date string into US Date string prior to calling the Openform, so the correct records open? OR is there a better way to write the WHERE clause in the Docmd line to achieve this result? - Or do I need to reset all my date fields to US format and convert them back to AU on the forms only?
Thanks for the feedback...
In VBA and VB6, date-literals using the # syntax are always in M/dd/yyyy format, regardless of the user's date format settings. This is a legacy of VBA/VB6's development in the USA before localization was a concern (and the USA is the only country to use the illogical MM/dd/yyyy format).
Note it's M/dd/yyyy and not MM/dd/yyyy - so omit any leading zeroes.
This is documented here: https://learn.microsoft.com/en-us/dotnet/visual-basic/language-reference/data-types/date-data-type
The same rule also applies to date-literals in Access SQL (not the same thing as VBA/VB6). Fortunately in SQL Server you always use the ISO 8601 yyyy-MM-dd format in quotes... shame about Access though.
You simply need a properly formatted string expression for your date value - and the correct syntax:
Dim NEWDATE As Date
Dim WhereCondition As String
NEWDATE = DateSerial(TempYear, TempMonth, TempDate)
WhereCondition = "[NameOfYourDateField] = #" & Format(NEWDATE, "yyyy\/mm\/dd") & "#"
DoCmd.OpenForm "frm_Prod_Runs_Edit_List", , , WhereCondition
Your first problem is that you're not comparing NewDate to something.
Your second problem is that you're using string concatenation to filter by a date, and that results in the wrong date.
You can view this answer for the different ways to use parameters in Access.
Your final code should probably look something like this:
NEWDATE = DateSerial(TempYear, TempMonth, TempDate)
DoCmd.SetParameter("NewDateParam", NEWDATE)
DoCmd.OpenForm "frm_Prod_Runs_Edit_List", , , "SomeDateField = NewDateParam"
Or, if there might be time stored with the date:
NEWDATE = DateSerial(TempYear, TempMonth, TempDate)
DoCmd.SetParameter("NewDateParam", NEWDATE)
DoCmd.OpenForm "frm_Prod_Runs_Edit_List", , , "SomeDateField - NewDateParam < 1"
I am just trying to add the letter A to the beginning of the results Im bring back and I keep getting this message.
Query Failed. 3535 a character string failed conversion to a numeric value
Thanks for any help.
select
a.area_cd as CO_Area
, 'A' + a.area_cd
from intDDt.DIXX a
+ is a numeric operator in Standard SQL and Teradata and not a string concat (as in MS SQL Server). You need to use || instead:
'A' || TRIM(a.area_cd)
The TRIM results in an automatic typecast.
please try this,
select
a.area_cd as CO_Area
, ('A' + CAST(a.area_cd AS VARCHAR))
from intDDt.DIXX a
I have a csv download of data from a Management Information system. There are some variables which are dates and are written in the csv as strings of the format "2012/11/16 00:00:00".
After reading in the csv file, I convert the date variables into a date using the function as.Date(). This works fine for all variables that do not contain any blank items.
For those which do contain blank items I get the following error message:
"character string is not in a standard unambiguous format"
How can I get R to replace blank items with something like "0000/00/00 00:00:00" so that the as.Date() function does not break? Are there other approaches you might recommend?
If they're strings, does something as simple as
mystr <- c("2012/11/16 00:00:00"," ","")
mystr[grepl("^ *$",mystr)] <- NA
as.Date(mystr)
work? (The regular expression "^ *$" looks for strings consisting of the start of the string (^), zero or more spaces (*), followed by the end of the string ($). More generally I think you could use "^[[:space:]]*$" to capture other kinds of whitespace (tabs etc.)
Even better, have the NAs correctly inserted when you read in the CSV:
read.csv(..., na.strings='')
or to specify a vector of all the values which should be read as NA...
read.csv(..., na.strings=c('',' ',' '))
So, I have created a variable "batch" with datatype datetime. Now my OLEBD source has a column "addDate" eg 2012-05-18 11:11:17.470 so does empty destination which is to be populated.
now this column addDate has many dates and I want to copy all dates which are "2012-05-18 11:11:17.470"
When I put value of the variable as this date, it automatically changes to mm/dd/yyyy hh;mm AM format and hence in my conditional split transformation, it couldn't match the date with the variable and hence no records are getting copied to the destination !!
Where exactly is the problem?
Thanks!
I had this issue and the best solution I found is not “pretty”.
Basically you need to change the “expression” of the variable and the “evaluate as expression” to true (otherwise it will ignore the value on expression).
The secret is (and kind of the reason I said it is not a pretty solution) to create a second variable to evaluate the expression of the first variable because you can’t change the value of a variable based on a expression.
So let’s say your variable is called “DateVariable” and you have 23/05/2012, create a variable called “DateVar2” for example and set its expression to
(DT_WSTR,4)YEAR(#[User::DateVariable]) + "/"+RIGHT("0" +
(DT_WSTR,2)MONTH(#[User::DateVariable]),2) + "/" + RIGHT("0" +
(DT_WSTR,2)DAY(#[User::DateVariable]),2)
That will give you 2012/05/23
Just keep going to get the date on the format you want
I found the easier solution. Select datatype as string. put any desired value.
Before conditional split, you need data conversion transformation.
convert it into DT_DBTIMESTAMP then run the package.
It works!