Let me introduce myself.
My name is Vladimir, C++ programmer, I am from Serbia. two weeks ago I have started to learn objective-C and it was fine until tonight.
Problem:
I cant remove double quotes from my NSLog output.
NSLog(#"The best singers:%#", list.best);
Strings are joined with componentsJoinedByString:#" and "
I would like to get something like this:
The best singers: Mickey and John.
But I get this:
The best singers: ("Mickey", and "John").
I cant remove comma (,) and parentheses either.
I have tried with "replaceOccurencesOfString" but with no success. It can remove any character except qoute and comma.
Also I have used -(NSString *)description method to return string.
You are getting the raw output from your list (which I assume is an array). You will have to do your own formatting to get this to display in the format that you want. You can achieve this by building your string by iterating through your array. Note that this probably isn't the most efficient nor the most robust way to achieve this.
NSMutableString *finalString = [NSMutableString string];
BOOL first = YES;
for (NSString *nameString in list) {
if (first) {
[finalString appendString:nameString];
first = NO;
} else {
[finalString appendString:[NSString stringWithFormat:#" and %#", nameString]];
}
}
Related
I'm trying to use a parameter inside of a JSON string, and would like to use an inner parameter to replace an GUID. I've changed the default parameter start and end characters since curly braces are used in JSON.
I've tried to do something like this, where the json param contains my json which is similar to this below.
{"DashboardGUID":"<Dash_GUID>"}
request_json = lr_eval_string("<json>");
lr_save_string(request_json, "request_json_param");
I'm expecting the lr_eval_string to replace the with the GUID that's in this parameter, what's the best why of replacing this ID in my JSON String?
Not sure what you are asking but I will put this here in case someone comes here in the future:
main.c
Action()
{
lr_eval_json("Buffer/File=my_json.json", "JsonObject=MJO",LAST);
lr_json_stringify("JsonObject=MJO","Format=compact", "OutputParam=newJsonBody",LAST);
lr_save_string(lr_eval_string(lr_eval_string("{newJsonBody}")),"tmp");
web_reg_find("Text={mydate}",LAST);
web_rest("POST",
"URL=http://myServer.microfocus.com/url",
"Method=POST",
"EncType=raw",
"Body={tmp}",
HEADERS,
"Name=Content-Type", "Value=application/json", ENDHEADER,
LAST);
return 0;
}
my_json.json
{
"LastActionId": 0,
"Updated": "{mydate}"
}
Okay so instead of doing what I'm thinking above I ended up creating an array of char's with this {"DashboardGUID":"<Dash_GUID>", someotherdata:"123"} in 10 different positions within the array. I then randomly selected an element from this array and when doing the lr_eval_string the parameter was replaced.
Hopefully this makes sense those looking to do something similar.
I am working in C# with ASP.NET. I am familiar with this error but this time I can't solve it.
I have text in a drop-down list like this:
राम कुमार सिंह 8s2w8r
here राम कुमार सिंह is the name in HINDI while 8s2w8r is users' ID.
I need to separate these two values and need to pass them as session variables. The logic I am using is depicted in the code.
public string reverse(string s)
{
char []temp=s.ToCharArray();
Array.Reverse(temp);
return (temp.ToString());
}
string dropdowntextreversed=reverse(DropDownList1.Text);
char []delim=new char[]{' '};
string []parts=dropdowntextreversed.Split(delim,2);
string family_head_uid = reverse(parts[0]);
string family_head = reverse(parts[1]);
Session.Add("family_head", family_head);
Session.Add("family_head_uid", family_head_uid);
Response.Redirect("/WebForm1.aspx");
I always get an error as the index was outside the bounds of the array! I don't understand this because I am breaking the string into 2 parts so it should have parts[0] and parts[1]. Please suggest...
You are splitting the string into MAXIMUM 2 parts, but if there's only one you will get probably one part.
Read this documentation
Try to assert that parts.Length is == 2 or to access elemnts only there atre two elements
Try this link. As I think there is a problem in the temp.ToString() which will return System.Char[] rather than the value which are you looking for. Use string.join instead will work.
Use the following reverse method:
public string reverse(string s)
{
return String.Join(String.Empty, s.ToCharArray().Reverse());
}
I'm trying to write code that appends ending _my_ending to the filename, and does not change file extension.
Examples of what I need to get:
"test.bmp" -> "test_my_ending.bmp"
"test.foo.bar.bmp" -> "test.foo.bar_my_ending.bmp"
"test" -> "test_my_ending"
I have some experience in PCRE, and that's trivial task using it. Because of the lack of experience in Qt, initially I wrote the following code:
QString new_string = old_string.replace(
QRegExp("^(.+?)(\\.[^.]+)?$"),
"\\1_my_ending\\2"
);
This code does not work (no match at all), and then I found in the docs that
Non-greedy matching cannot be applied to individual quantifiers, but can be applied to all the quantifiers in the pattern
As you see, in my regexp I tried to reduce greediness of the first quantifier + by adding ? after it. This isn't supported in QRegExp.
This is really disappointing for me, and so, I have to write the following ugly but working code:
//-- write regexp that matches only filenames with extension
QRegExp r = QRegExp("^(.+)(\\.[^.]+)$");
r.setMinimal(true);
QString new_string;
if (old_string.contains(r)){
//-- filename contains extension, so, insert ending just before it
new_string = old_string.replace(r, "\\1_my_ending\\2");
} else {
//-- filename does not contain extension, so, just append ending
new_string = old_string + time_add;
}
But is there some better solution? I like Qt, but some things that I see in it seem to be discouraging.
How about using QFileInfo? This is shorter than your 'ugly' code:
QFileInfo fi(old_string);
QString new_string = fi.completeBaseName() + "_my_ending"
+ (fi.suffix().isEmpty() ? "" : ".") + fi.suffix();
I have a code someone wrote and there
this->llBankCode = new widgetLineEditWithLabel(tr("Bankleitzahl"), "", Qt::AlignTop, this);
QRegExpValidator *validatorBLZ = new QRegExpValidator(this);
validatorBLZ->setRegExp(QRegExp( "[0-9]*", Qt::CaseSensitive));
this->llBankCode->lineEdit->setValidator(validatorBLZ);
as it can be seen from this code, is that validatorBLZ can accept only numbers between 0 and 9. I would like to change it, that validatorBLZ would be able to get as an input whitespace as well (but not to start with a whitespace), but it wont be shown.
Example:
if i try to copy & paste a string of the format '22 34 44', the result would be an empty field. What i would like to happen is that the string '22 34 44' will be shown in the field as '223444'.
How could i do it?
You could try using:
QString string = "22 34 44";
string.replace(QString(" "), QString(""));
That will replace any spaces with a non-space.
Write your own QValidator subclass and reimplement validate and fixup. Fixup does what you ask for: changes the input in a way that makes it intermediate/acceptable.
In your case, consider the following code-snippet for fixup:
fixup (QString &input) const
{
QString fixed;
fixed.reserve(input.size());
for (int i=0; i<input.size(); ++i)
if (input.at(i).isDigit()) fixed.append(input.at(i));
input = fixed;
}
(this is not tested)
The validate function will obviously look similar, returning QValidator::Invalid when it encounters a non-digit character and returning the according position in pos.
If your BLZ is limited to Germany, you could easily add the validation feature that it only returns QValidator::Acceptable when there are eight digits, and QValidator::Intermediate else.
Anyhow, writing an own QValidator, which often is very easy and straight forward, is the best (and most future-proof) solution most of the time. RegExes are great, but C++ clearly is the more powerful language here, which in addition results in a much more readable validator ;).
I've got a string like so
Jamie(123)
And I'm trying to just show Jamie without the brackets etc
All the names are different lengths so I was wondering if there was a simple way of replacing everything from the first bracket onwards?
Some others are displayed like this
Tom(Test(123))
Jack ((4u72))
I've got a simple replace of the bracket at the moment like this
mystring.Replace("(", "").Replace(")","")
Any help would be appreciated
Thanks
VB.NET
mystring.Substring(0, mystring.IndexOf("("C)).Trim()
C#
mystring.Substring(0, mystring.IndexOf('(')).Trim();
One logic; get the index of the ( and you can trim the later part from that position.
public static string Remove(string value)
{
int pos = value.IndexOf("(");
if (pos >= 0)
{
return value.Remove(pos, remove.Length);
}
return value;
}
aneal's will work. The alternative I generally use because it's a bit more flexible is .substring.
string newstring = oldstring.substring(0,oldstring.indexof("("));
If you aren't sure that oldstring will have a "(" you will have to do the test first just as aneal shows in their answer.
String.Remove(Int32) will do what you need:
Deletes all the characters from this string beginning at a
specified position and continuing through the last position.
You will also have to .Trim() as well given the data with padding:
mystring = mystring.Remove(mystring.IndexOf("("C))).Trim()