Here is the string:
> raw.data[27834,1]
[1] "\xff$GPGGA"
I have tried advice from the following two questions, but with no luck:
How to escape a backslash in R?
How to escape backslashes in R string
Does anyone have a different solution from the above questions that might help? The ideal solution would be to remove the "\xff" portion, but for any combination of letters.
There is no backslash in that string. The displayed backslash is an escape marker. This and other features about entry and display of "special situations" are described in the ?Quotes help page.. You've been given one regex rather elliptical approach to removal. Here are a couple of other approaches .... only some of which actually succeed because the \ff is the first "character" and it's not really legal as an R character:
s <- "\xff$GPGGA"
strsplit(s, "")
#[[1]]
#[1] NA
Warning message:
In strsplit(s, "") : input string 1 is invalid in this locale
substr(s, 1,1)
#Error in substr(s, 1, 1) : invalid multibyte string at '<ff>$GP<47>GA'
gsub('.*([^A-Za-z].*)', '\\1',"\xff$GPGGA")#[1]
#[1] "$GPGGA"
?Quotes
gsub('\xff', '',"\xff$GPGGA")#[1]
#[1] "$GPGGA"
I think the reason that the regex functions don't choke on that string is that regex is actually a system mediated process whereas strsplit and substr are internal R functions.
#RichardScriven posts an example and when I tried to replicated it, I get yet a different example that shows the mapping to displayed characters is system specific. I'm on OSX 10.10.1 (Yosemite)>
cat('\xff')
ˇ
(I left off the octothorpe (#) that I would normally out in.)
Related
I'm working with the following code:
Y_Columns <- c("Y.1.1")
paste('{"ImportId":"', Y_Columns, '"}', sep = "")
The paste function produces the following output:
"{\"ImportId\":\"Y.1.1\"}"
How do I get the paste function to omit the \? Such that, the output is:
"{"ImportId":"Y.1.1"}"
Thank you for your help.
Note: I did do a search on SO to see if there were any Q's that asked "what is an escape character in R". But I didn't review all the 160 answers, only the first 20.
This is one way of demonstrating what I wrote in my comment:
out <- paste('{"ImportId":"', Y_Columns, '"}', sep = "")
out
#[1] "{\"ImportId\":\"Y.1.1\"}"
?print
print(out,quote=FALSE)
#[1] {"ImportId":"Y.1.1"}
Both R and regex patterns use escape characters to allow special characters to be displayed in print output or input. (And sometimes regex patterns need to have doubled escapes.) R has a few characters that need to be "escaped" in certain situation. You illustrated one such situation: including double-quote character inside a result that will be printed with surrounding double-quotes. If you were intending to include any single quotes inside a character value that was delimited by single quotes at the time of creation, they would have needed to be escaped as well.
out2 <- '\'quoted\''
nchar(out2)
#[1] 8 ... note that neither the surround single-quotes nor the backslashes get counted
> out2
[1] "'quoted'" ... and the default output quote-char is a double-quote.
Here's a good Q&A to review:How to replace '+' using gsub() function in R
It has two answers, both useful: one shows how to double escape a special character and the other shows how to use teh fixed argument to get around that requirement.
And another potentially useful Q&A on the topic of handling Windows paths:
File path issues in R using Windows ("Hex digits in character string" error)
And some further useful reading suggestions: Look at the series of help pages that start with capital letters. (Since I can never remember which one has which nugget of essential information, I tried ?Syntax first and it has a "See Also" list of essential reading: Arithmetic, Comparison, Control, Extract, Logic, NumericConstants, Paren, Quotes, Reserved. and I then realized what I wanted to refer you to was most likely ?Quotes where all the R-specific escape sequence letters should be listed.
Since special characters are inevitable while working data from excel.
There are so many links to eradicate special characters but when trying to remove \, we got to use \" which will eliminate both
Remove quotes ("") from a data.frame in R
Here, they remove both quotes but quotes at the end needs to be present.
> abc = c("Hi\"","Hello\\")
> abc
[1] "Hi\"" "Hello\\"
> str_replace_all(abc, "\"","")
[1] "Hi " "Hello\\"
But can we have
Hi" as an output ?
#Ronak Shah, #Chelmy88 and #Konrad Rudolph
helped me to understand where I was wrong in interpretation.
basically, it has to do with the way R renders the string in console.
Solution using cat() can resolve the confusion.
I have to request an API with an URL encoding according to RFC 3986, knowing that I have accented characters in my query.
For instance, this argument :
quel écrivain ?
should be encoded like this:
quel%20%C3%A9crivain%20%3F%0D%0A
Unfortunately, when I use URLencode, encoding, url_encode, or curlEscape, I have the resulting encoding:
URLencode("quel écrivain ?")
[1] "quel%20%E9crivain%20?"
The problem is on accented letters: for instance "é" is converted into "%E9" instead of "%C3%A9"...
I struggle with this URL encoding without finding any issue... As I don't have the hand on the API, I don't know how it handles the encoding.
A weird thing is that using POST instead of GET leads to a response in which word with accent are cutted into 2 different lines :
"1\tquel\tquel\tDET\tDET\tGender=Masc|Number=Sing\t5\tdet\t0\t_\n4\t<U+FFFD>\t<U+FFFD>\tSYM\tSYM\t_\t5\tcompound\t0\t_\n5\tcrivain\tcrivain\
As you can see, "écrivain" is splitted into "<U+FFFD>" (which is an ASCII encoding of "é") and "crivain".
I become mad with this encoding problem, if a brilliant mind could help me I would be very gratefull!
Set reserved = TRUE
i.e.
your_string <- "quel écrivain ?"
URLencode(your_string, reserved = TRUE)
# [1] "quel%20%C3%A9crivain%20%3F"
I do not think I am a brilliant mind, but I still have a possible solution for you. After using URLencode() it seems that your accented characters are converted into the trailing part of their unicode representation preceeded by a %. To convert your characters into readable characters you might turn them into "real unicode" and use the package stringi to make them readable. For your single string the solution worked on my machine, at least. I hope it also works for you.
Please note that I have introduced a % character at the end of your string to demonstrate that below gsub command should work in any case.
You might have to adapt the replacement pattern \\u00 to also cover unicode patterns that have more than the last two positions filled with something but 0, if this is relevant in your case.
library(stringi)
str <- "quel écrivain ?"
str <- URLencode(str)
#"quel%20%E9crivain%20?"
#replacing % by a single \ backslash to directly get correct unicode representation
#does not work since it is an escape character, therefore "\\"
str <- gsub("%", paste0("\\", "u00"), str , fixed = T)
#[1] "quel\\u0020\\u00E9crivain\\u0020?"
#since we have double escapes, we need the unescape function from stringi
#which recognizes double backslash as single backslash for the conversion
str <- stri_unescape_unicode(str)
#[1] "quel écrivain ?"
I am trying to remove specific multi-byte characters in R.
Multibyte <- "Sungpil_한성필_韓盛弼_Han"
The linguistic structure of Multibyte is "English_Korean_Chinese_English" What I want to remove is the Korean word only or Chinese word only (not both).
A desired result is either :
Sungpil_한성필__Han # Chinese characters were removed.
or
Sungpil__韓盛弼_Han # Korean characters were removed.
Is there a simple way to do it by using gsub? I am only aware of a method to get English-only characters.
gsub("[^A-Za-z_]", "", Multibyte)
[1] "Sungpil___Han"
Answering the question itself, yes, you may do it with a mere gsub using a PCRE regex and Unicode property classes \p{Hangul} for matching Korean chars, and \p{Han} to match Chinese chars:
> Multibyte <- "Sungpil_한성필_韓盛弼_Han"
> gsub("\\p{Hangul}+", "",Multibyte, perl=TRUE)
[1] "Sungpil__韓盛弼_Han"
> gsub("\\p{Han}+", "",Multibyte, perl=TRUE)
[1] "Sungpil_한성필__Han"
See R online demo.
However, if you have a specific structure of the input text, use the other solution.
We can try with sub
sub("[^_]+_([A-Za-z]+)$", "_\\1", Multibyte)
#[1] "Sungpil_한성필__Han"
Here is the string:
> raw.data[27834,1]
[1] "\xff$GPGGA"
I have tried advice from the following two questions, but with no luck:
How to escape a backslash in R?
How to escape backslashes in R string
Does anyone have a different solution from the above questions that might help? The ideal solution would be to remove the "\xff" portion, but for any combination of letters.
There is no backslash in that string. The displayed backslash is an escape marker. This and other features about entry and display of "special situations" are described in the ?Quotes help page.. You've been given one regex rather elliptical approach to removal. Here are a couple of other approaches .... only some of which actually succeed because the \ff is the first "character" and it's not really legal as an R character:
s <- "\xff$GPGGA"
strsplit(s, "")
#[[1]]
#[1] NA
Warning message:
In strsplit(s, "") : input string 1 is invalid in this locale
substr(s, 1,1)
#Error in substr(s, 1, 1) : invalid multibyte string at '<ff>$GP<47>GA'
gsub('.*([^A-Za-z].*)', '\\1',"\xff$GPGGA")#[1]
#[1] "$GPGGA"
?Quotes
gsub('\xff', '',"\xff$GPGGA")#[1]
#[1] "$GPGGA"
I think the reason that the regex functions don't choke on that string is that regex is actually a system mediated process whereas strsplit and substr are internal R functions.
#RichardScriven posts an example and when I tried to replicated it, I get yet a different example that shows the mapping to displayed characters is system specific. I'm on OSX 10.10.1 (Yosemite)>
cat('\xff')
ˇ
(I left off the octothorpe (#) that I would normally out in.)