d3.js equivalent to columns in R dataframes - r

I have some data stored in this format (except many cases more):
var data = [
{"name":"John", "team":"team1"},
{"name":"Megan", "team":"team2"},
{"name":"Rupert", "team":"team2"},
{"name":"Albert", "team":"team1"}
];
I want to create this:
var colourScale = d3.scale.ordinal()
.range(a)
.domain(b)
"a" being an array of all levels of "team" (i.e. ["team1","team2"] in this case).
"b" being an array of ordinal colours of the same length as "a".
colourScale() should take the "team"-value as input and return a unique colour for each team.
How do I create "a" and "b"? Is there something equivalent to R's levels(data[ ,"team"]) in javascript or d3.js?

It's not exactly your solution as you don't explicitly find your specified a or b, but I found
var colourScale = d3.scale.category10();
function colour(d) { return d.team; }
and on the object you want to colour, bound to the appropriate data, chain
.style("fill", function(d) { return colourScale(colour(d)); });
has the effect that I assume you're searching for. Hope this helps.

I think there are some extra steps you need to do. You need first to create a 'unique' set of possible domain values. Then you can create a function that maps each value to a color. Something like this perhaps:
// A function to get unique values, can be optimized further
function unique(x) {
return x.reverse().filter(function (e, i, x) {return x.indexOf(e, i+1) === -1;}).reverse();
}
var data = [
{"name":"John", "team":"team1"},
{"name":"Megan", "team":"team2"},
{"name":"Rupert", "team":"team2"},
{"name":"Albert", "team":"team1"}
];
// An arbitrary set of colors
colors = ['#005824','#1A693B','#347B53','#4F8D6B','#699F83','#83B09B','#9EC2B3','#B8D4CB','#D2E6E3','#EDF8FB','#FFFFFF','#F1EEF6','#E6D3E1','#DBB9CD','#D19EB9','#C684A4','#BB6990','#B14F7C','#A63467','#9B1A53','#91003F']
//Create the ordinary scale based on your color set above
colorScale= d3.scale.ordinal()
.domain(unique(data.map(function(d){return d.team;})))
.range(colors)
Then you can access the color by:
.style("fill",function(d){return colorScale(d.team);})
Hope this helps.

Related

How to add any symbols after prefix_?

is there any solution? e.g. I have data in Map with key favorites_ prefix and values _suffix (for example: favorites_jeans, favorites_suit,...,). I want to by dint of loop get that values and set in List, because of it I must give keys of map, right?
I want to know how can I get values of myMap["favorites_*"] (* - after the favorites_ any symbols).
List<String> favoritesStrings = ['favorite_name','favorite_jeans',];
Map<String,dynamic> myMap = {
favoritesStrings[0]:'0',
favoritesStrings[1]:'1',
'someKey':'2',
'anotherKey':'3',
};
favoritesStrings.forEach((favorite)=>print(myMap[favorite]));//prints 0 1
As per what I understood, you want to fetch value from map using "favorites_" + a dynamic value from list as key.
You just have to use String templates and use $ to insert suffix variable to build key dynamically:
List<String> suffixList = ["jeans", "suit", "shirt"];
for(String suffix in suffixList) {
var item = myMap["favorites_$suffix"];
// Do something with item
}
Hope it helps

Kotlin Map<String, List<Object>> values are changed after toSortedMap call

I got such a map
Map<String, List<Object>>
when I use
map.toSortedMap(comparator)
and comparing values by keys I got sorted map but amount of objects in each value list is also changed (reduced). It's super strange. Under the hood toSortedMap method creates TreeMap with the given comparator, I don't know TreeMap internals but I assume that any map should not change values but only manipulate with the keys. Is this something that is ok for TreeMap or is it a bug in Kotlin library?
Edit
Code I get this issue on:
val categoriesKeys = listOf("key1", "key2", etc)
val categoriesKeysOrdersMap = mapOf("key1" to 0, "key2" to 1, etc)
val model = listOf(MyModel(..), MyModel(..), etc)
val categoryKeyToModelsMap = categoriesKeys
.asSequence()
.map { key ->
key to model.filter {
it.categories?.contains(key) == true
}
}
.filter { it.second.isNotEmpty() }
.toMap()
.toSortedMap(compareBy { categoriesKeysOrdersMap[it] })
On toMap step I have the map I want but not sorted, but after toSortedMap my data is messed up. Comparator compares by int value from categoriesKeysOrdersMap using key from category.

How to separate multiple columns from a range in an array?

I have a range of data in a Google Sheet and I want to store that data into an array using the app script. At the moment I can bring in the data easily enough and put it into an array with this code:
var sheetData = sheet.getSheetByName('Fruit').getRange('A1:C2').getValues()
However, this puts each row into an array. For example, [[Apple,Red,Round],[Banana,Yellow,Long]].
How can I arrange the array by columns so it would look: [[Apple,Banana],[Red,Yellow],[Round,Long]].
Thanks.
It looks like you have to transpose the array. You can create a function
function transpose(data) {
return (data[0] || []).map (function (col , colIndex) {
return data.map (function (row) {
return row[colIndex];
});
});
}
and then pass the values obtained by .getValues() to that function..
var sheetData = transpose(sheet.getSheetByName('Fruit').getRange('A1:C2').getValues())
and check the log. See if that works for you?
Use the Google Sheets API, which allows you to specify the primary dimension of the response. To do so, first you must enable the API and the advanced service
To acquire values most efficiently, use the spreadsheets.values endpoints, either get or batchGet as appropriate. You are able to supply optional arguments to both calls, and one of which controls the orientation of the response:
const wb = SpreadsheetApp.getActive();
const valService = Sheets.Spreadsheets.Values;
const asColumn2D = { majorDimension: SpreadsheetApp.Dimension.COLUMNS };
const asRow2D = { majorDimension: SpreadsheetApp.Dimension.ROWS }; // this is the default
var sheet = wb.getSheetByName("some name");
var rgPrefix = "'" + sheet.getName() + "'!";
// spreadsheetId, range string, {optional arguments}
var single = valService.get(wb.getId(), rgPrefix + "A1:C30");
var singleAsCols = valService.get(wb.getId(), rgPrefix + "A1:C30", asColumn2D);
// spreadsheetId, {other arguments}
var batchAsCols = valService.batchGet(wb.getId(), {
ranges: [
rgPrefix + "A1:C30",
rgPrefix + "J8",
...
],
majorDimension: SpreadsheetApp.Dimension.COLUMNS
});
console.log({rowResp: single, colResp: singleAsCols, batchResponse: batchAsCols});
The reply will either be a ValueRange (using get) or an object wrapping several ValueRanges (if using batchGet). You can access the data (if any was present) at the ValueRange's values property. Note that trailing blanks are omitted.
You can find more information in the Sheets API documentation, and other relevant Stack Overflow questions such as this one.

One item per line (row) in timeline? - Vis.js

Is there a way to always have one item per line in the timeline? I don't want two or more items to share the same line, whatever the dates are.
Thanks.
You have to use groups, or if you're already using those for another purpose, you have to use subgroups.
Here's the official documentation for items, groups and subgroups (I'm assuming the website isn't gonna expire anytime soon... again...).
If you can use groups
Specify a different group for every item. You can set the group's content as an empty string, if you don't want to have a label for it on the left side of the Timeline.
If you want to arrange the groups in a specific way, specify an ordering function as the Timeline's options' groupOrder property. Example:
var options = {
// other properties...
groupOrder: function (a, b) {
if(a.content > b.content)// alphabetic order
return 1;
else if(a.content < b.content)
return -1;
return 0;
}
};
If you have to use subgroups
When you create an item, put it in the group it belongs to but also specify for it the subgroup property so that it's unique, like the item's id. For example, you can use the id itself, or add a prefix or suffix to it.
In the Timeline's options, set the stack and stackSubgroups properties to true.
In each group, set the subgroupStack property to true and specify an ordering function as the group's subgroupOrder property. Example:
var group = {
id: 1,
content: 'example group',
subgroupStack: true,
subgroupOrder: function(a, b) {
var tmp = a.start.getTime() - b.start.getTime();
return tmp === 0 ? parseInt(a.id) - parseInt(b.id) : tmp;
// if the start dates are the same, I compare the items' ids.
// this is because due to a bug (I guess) the ordering of items
// that return 0 in the ordering function might "flicker" in certain
// situations. if you want to order the items alphabetically in that
// case, compare their "content" property, or whatever other
// property you want.
}
};

$.grep on JSON data in multiple array.fields using wildcards?

First off I have looked through similar looking questions but have not found the exact problem asked or answered, so here goes :
I have a JSON Object which consists of about 900+ posts. Looking like this:
var JsonData = [{"rowNumber":563663,"hasWarning":true,"isInvoiceAccount":true,"phone":"","name":"Romerike AS","address1":"Co/Skanning","address2":"PB 52","attention":"","mobile":"","email":"fakt#bos.no","fax":"","zipCity":"N-1471 Askim","invoiceAccount":"","notes":null,"account":"3","country":"NORGE","salesRep":"4","countryCode":"no"},{"rowNumber":563674,"hasWarning":false,"isInvoiceAccount":true,"phone":"","name":"LILLEHAMMER","address1":"POSTBOKS 110","address2":"","attention":"","mobile":"","email":"","fax":"","zipCity":"N-2605 LILLEHAMMER","invoiceAccount":"","notes":null,"account":"14","country":"NORGE","salesRep":"4","countryCode":"no"},{"rowNumber":563676,"hasWarning":true,"isInvoiceAccount":true,"phone":"63929788","name":"Askim Bil AS","address1":"Postboks 82","address2":"","attention":"","mobile":"","email":"karosseri#nyg.no","fax":"","zipCity":"N-2051 Askim","invoiceAccount":"","notes":null,"account":"16","country":"NORGE","salesRep":"4","countryCode":"no"},{"rowNumber":563686,"hasWarning":false,"isInvoiceAccount":true,"phone":"69826060","name":"KAROSSERI A/S","address1":"POSTBOKS 165","address2":"","attention":"","mobile":"","email":"tkar#online.no","fax":"","zipCity":"N-1860 TRØGSTAD","invoiceAccount":"","notes":null,"account":"26","country":"NORGE","salesRep":"4","countryCode":"no"},{"rowNumber":563690,"hasWarning":false,"isInvoiceAccount":true,"phone":"","name":"AUTOSERVICE A/S","address1":"POSTBOKS 15","address2":"","attention":"","mobile":"","email":"","fax":"","zipCity":"N-2851 LENA","invoiceAccount":"","notes":null,"account":"30","country":"NORGE","salesRep":"4","countryCode":"no"},{"rowNumber":563691,"hasWarning":false,"isInvoiceAccount":false,"phone":"","name":"ØYHUS A/S","address1":"POSTBOKS 321","address2":"","attention":"John Doe","mobile":"","email":"","fax":"","zipCity":"N-2817 GJØVIK","invoiceAccount":"","notes":null,"account":"31","country":"NORGE","salesRep":"4","countryCode":"no"}];
I want to filter these data before I read them into a table using $.grep.
The JSON data have been loaded as an object.
In the HTML page I have a textfield named "filter".
The following code works, but only when I search for an exact match:
var JsonFiltered = $.grep(JsonData, function (element, index) {
return element.zipCity == $('#filter').val();
});
$.each( JsonFiltered, function ( index, value ) {
// sorting through the array adding values to a table
[...]
});
Problem 1:
I want to use Wildcards when filtering.
I read something about using regexp but I haven't found any viable examples.
Problem 2:
I want to be able to filter more than one column.
Example: filtering the word "Askim" in both element.name and element.zipCity
So I figured out the solutions myself...
Using Wildcards:
var search_term = $('#filter').val();
var search = new RegExp(search_term, "i");
var JsonFiltered = $.grep(JsonTest, function (element, index) {
var zipC = search.test(element.zipCity)
var names = search.test(element.name)
return zipC + names ;
The solution was to use "new RegExp" with the filter "i" setting.
then I took two search.tests combined them in the return command and... presto
Hope this helps anyone else.

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