What I currently have selects based on a column having the same value..
"SELECT * FROM users WHERE uuid = ?"
But what if I want to return a row based on one of the columns "containing" a string value? Some pseudo code would be:
SELECT * FROM users
WHERE column CONTAINS mystring
Any help is appreciated, I have been searching for other answers but to no avail.
SELECT * FROM users WHERE column LIKE '%mystring%' will do it.
LIKE means we're not doing an exact match (column = value), but doing some more fuzzy matching. "%" is a wildcard character - it matches 0 or more characters, so this is saying "all rows where the column has 0 or more chars followed by "mystring" followed by 0 or more chars".
Use LIKE clause.
E.g. if your string contains "pineapple123", your query would be:
SELECT * from users WHERE column LIKE 'pineapple%';
And if your string always starts with any number and ends with any number like "345pineapple4565", you can use:
SELECT * from users WHERE column LIKE "%pineapple%";
Checking variable substring ( a more generic answer )
you should use '%'||?||'%' instead
for example in python we'll have something like this:
curser.execute("SELECT * FROM users WHERE column LIKE '%'||?||'%'", (variable,) )
Just another way using instr, do not need to supply additional character.
Select * from repos where instr("column_name", "Search_string") > 1
I recently came across this problem and solved it such you can find the string 'time'
text = "SELECT * FROM database WHERE column=" + "'" + str(time) + "'"
cursor.execute(text)
The issue I found was that when you pass in the string time directly as:
..WHERE column=" + time)
it formats 'time' as "time" when you want it to format as 'time' which must be to do with the way SQLite is wrote to handle the arguments its passed.
I have time stamped all entries into a database and now I can recall any data from a specific time.
Related
I have a database with a Username column.
There are multiple section signs followed by numbers §# that format the name.
I have to make sure all names are unique, but I want to disregard the formatting character pairs.
I was going to use,
SELECT * FROM Users WHERE replace(lower(Username),'§%','') = 'name';
but I realized that would look for the percent sign and not act as a wildcard. I could really use some help.
Use a combination of INSTR and SUBSTR to isolate the name before comparing it:
SELECT *
FROM Users
WHERE LOWER(SUBSTR(Username, 1, INSTR(Username, '§%') - 1)) = 'name';
I want to count number of occurrences of a word in a string for example ,
[{"lastUpdatedDateTime":{"timestamp":1.54867752522E12},"messageStatus":"DELIVERED","phoneNumber":"+916000060000"},{"lastUpdatedDateTime":{"timestamp":1548677525220},"messageStatus":"DELIVERED","phoneNumber":"+916000060000"}]
in above string i want to count no of occurrences of a word 'DELIVERED' here it is 2.
i want to get result 2. pls help me on this. i should have to use only sql query to achieve this.
thanks in advance.
If your table's name is tablea and the column's name is col:
SELECT
(LENGTH(col) - LENGTH(REPLACE(col, '"DELIVERED"', '')))
/
LENGTH('"DELIVERED"') as counter
from tablea
remove every occurrence of "DELIVERED" and subtract the length of the string from the original string and finally divide the result with the length of "DELIVERED"
Assuming your data is in a table something like:
CREATE TABLE example(json TEXT);
INSERT INTO example VALUES('[{"lastUpdatedDateTime":{"timestamp":1.54867752522E12},"messageStatus":"DELIVERED","phoneNumber":"+916000060000"},{"lastUpdatedDateTime":{"timestamp":1548677525220},"messageStatus":"DELIVERED","phoneNumber":"+916000060000"}]');
and your instance of sqlite has the JSON1 extension enabled:
SELECT count(*) AS "Number Delivered"
FROM example AS e
JOIN json_each(e.json) AS j
WHERE json_extract(j.value, '$.messageStatus') = 'DELIVERED';
gives you:
Number Delivered
----------------
2
This will return the total number of matching entries from all rows in the table as a single value. If you want one result per row instead, it's an easy change but the exact details depend on your table definition. Adding GROUP BY e.rowid to the end of the query will work in most cases, though.
In the long run it's probably a better idea to store each object in the array as a single row in a table, broken up into the appropriate columns.
With NVARCHAR data type, I store my local language text in a column. I face a problem how to query that value from the database.
ዜናገብርኤልስ is stored value.
I wrote SQL like this
select DivisionName
from t_Et_Divisions
where DivisionName = 'ዜናገብርኤልስ'
select unicode (DivisionName)
from t_Et_Divisions
where DivisionName = 'ዜናገብርኤልስ'
The above didn't work. Does anyone have any ideas how to fix it?
Thanks!
You need to prefix your Unicode string literals with a N:
select DivisionName
from t_Et_Divisions
where DivisionName = N'ዜናገብርኤልስ'
This N prefix tells SQL Server to treat this string literal as a Unicode string and not convert it to a non-Unicode string (as it will if you omit the N prefix).
Update:
I still fail to understand what is not working according to you....
I tried setting up a table with an NVARCHAR column, and if I select, I get back that one, exact row match - as expected:
DECLARE #test TABLE (DivisionName NVARCHAR(100))
INSERT INTO #test (DivisionName)
VALUES (N'ዜናገብርኤልስ'), (N'ዜናገብርኤልስ,ኔትዎርክ,ከስተመር ስርቪስ'), (N'ኔትዎርክ,ከስተመር ስርቪስ')
SELECT *
FROM #test
WHERE DivisionName = N'ዜናገብርኤልስ'
This returns exactly one row - what else are you seeing, or what else are you expecting??
Update #2:
Ah - I see - the columns contains multiple, comma-separated values - which is a horrible design mistake to begin with..... (violates first normal form of database design - don't do it!!)
And then you want to select all rows that contain that search term - but only display the search term itself, not the whole DivisionName column? Seems rather pointless..... try this:
select N'ዜናገብርኤልስ'
from t_Et_Divisions
where DivisionName LIKE N'%ዜናገብርኤልስ%'
The LIKE searches for rows that contain that value, and since you already know what you want to display, just put that value into the SELECT list ....
I would like to run a query involving joining a table to a manually generated list but am stuck trying to generate the manual list. There is an example of what I am attempting to do below:
SELECT
*
FROM
('29/12/2014', '30/12/2014', '30/12/2014') dates
;
Ideally I would want my output to look like:
29/12/2014
30/12/2014
31/12/2014
What's your Teradata release?
In TD14 there's STRTOK_SPLIT_TO_TABLE:
SELECT *
FROM TABLE (STRTOK_SPLIT_TO_TABLE(1 -- any dummy value
,'29/12/2014,30/12/2014,30/12/2014' -- any delimited string
,',' -- delimiter
)
RETURNS (outkey INTEGER
,tokennum INTEGER
,token VARCHAR(20) CHARACTER SET UNICODE) -- modify to match the actual size
) AS d
You can easily put this in a Derived Table and then join to it.
inkey (here the dummy value 1) is a numeric or string column, usually a key. Can be used for joining back to the original row.
outkey is the same as inkey.
tokennum is the ordinal position of the token in the input string.
token is the extracted substring.
Try this:
select '29/12/2014'
union
select '30/12/2014'
union
...
It should work in Teradata as well as in MySql.
Anyone knows if String Aggregation in sqlite is possible?
If i have an animal column with 5 rows/datas, how can i combine them so that the output would be in one field
'dog','cat','rat','mice','mouse' as animals
Thanks
You're looking for something like the following:
select group_concat(animal) from animals;
This will return something like the following:
dog,cat,rat,mice,mouse
If you don't want to use a comma as the separator, you can add your own separator as a second parameter:
select group_concat(animal, '_') from animals;
which will return:
dog_cat_rat_mice_mouse
I think this will be useful:
group_concat(X)
group_concat(X,Y)
The group_concat() function returns a string which is the concatenation of all non-NULL values of X. If parameter Y is present then it is used as the separator between instances of X. A comma (",") is used as the separator if Y is omitted. The order of the concatenated elements is arbitrary.