Extracting number from a non-consistent string in R [closed] - r

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I have my data as below
Idle|Idle|Idle|Idle|Idle|Idle|Idle
Idle|56|55|49|50|53|48|54|52|Idle|Idle|Idle|Idle|Idle|Idle
Idle|49|51|48|50|50|49|50|57|56|57|56|Idle|Idle|69|86|65|Idle|Idle|Idle|Idle
I want to extract numbers in between(which is phone number in ASCII format) which is
(56|55|49|50|53|48|54|52 for 2nd line and 49|51|48|50|50|49|50|57|56|57|56 for 3rd line),
convert them to numbers between "0 and 9" and concatenate as string/number in new column as phone_number in same data set.
2nd row of new column should be 871230652 and 3rd row should be 13022129898
In ASCII format 48 represents 0 and 57 represents 9
Please help
Thanks,


Here's an approach with regular expressions:
res <- sapply(regmatches(x, gregexpr("^(?:Idle\\|)*\\K\\d+(?=\\|)|\\G(?!^)\\|\\K\\d+",
x, perl = TRUE)),
function(x) paste(as.integer(x) - 48, collapse = ""))
# [1] "" "87125064" "13022129898"
If you want to exclude the empty strings, you can use the following command:
res[as.logical(nchar(res))]
# [1] "87125064" "13022129898"
Here x is this vector:
x <- c("Idle|Idle|Idle|Idle|Idle|Idle|Idle",
"Idle|56|55|49|50|53|48|54|52|Idle|Idle|Idle|Idle|Idle|Idle",
"Idle|49|51|48|50|50|49|50|57|56|57|56|Idle|Idle|69|86|65|Idle|Idle|Idle|Idle")

Related

remove quotes from string on only numeric values in r [closed]

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Given the string, how can I get the desired outcome?
('9','','','','','','','','31.23','testing7'),('10','','','','','','','','31.23','testing10')
Desired Output
(9,'','','','','','','',31.23,'testing7'),(10,'','','','','','','',31.23,'testing10')

Try the following regex:
s <- "('9','','','','','','','','31.23','testing7'),
('10','','','','','','','','31.23','testing10')"
gsub("'(-?\\d+(?:[\\.,]\\d+)?)'", x = s, replacement = "\\1")
Regex explanation:
' match literal single quote character
() capture group
? match between 0-1 times
\\d+ match digit 1 and unlimited times
\\1 group 1
This should allow for negative numbers and decimals.
Output
"(9,'','','','','','','',31.23,'testing7'),(10,'','','','','','','',31.23,'testing10')"

Retrieve a set of string with unique substring [closed]

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I have a set of strings in R. In the form of: "X-Y-Z.3000.F.PP0016-C.A-SL-0433.P-N.fC-G.txt". I want to retrieve the set of strings containing just the first occurrence of a string. It depends on the 4th field. In this set for e.g. I have multiple string with X-Y-Z.3000....." I want only the first one having id = 3000, the same for the others.
For reproducibility:
X-Y-Z.3000.F.PP0016-C.A-SL-0433.P-N.fC-G.txt
X-Y-Z.3000.F.PP0016-C.A-SL-0433.F-N.fC-G.txt
X-Y-Z.3008.F.PP0016-C.A-SL-0433.P-N.fC-G.txt
X-Y-Z.3008.F.PP0016-C.B-SX-0433.P-N.fC-G.txt
So at the end I would only the first anche 3th string
X-Y-Z.3000.F.PP0016-C.A-SL-0433.P-N.fC-G.txt
X-Y-Z.3008.F.PP0016-C.A-SL-0433.P-N.fC-G.txt

Extract "4th field" which is 2nd field if we split on ".", then exclude duplicated items:
# data
x <- c("X-Y-Z.3000.F.PP0016-C.A-SL-0433.P-N.fC-G.txt",
"X-Y-Z.3000.F.PP0016-C.A-SL-0433.F-N.fC-G.txt",
"X-Y-Z.3008.F.PP0016-C.A-SL-0433.P-N.fC-G.txt",
"X-Y-Z.3008.F.PP0016-C.B-SX-0433.P-N.fC-G.txt")
x[ !duplicated(sapply(strsplit(x, ".", fixed = "TRUE"), "[", 2)) ]
# [1] "X-Y-Z.3000.F.PP0016-C.A-SL-0433.P-N.fC-G.txt"
# [2] "X-Y-Z.3008.F.PP0016-C.A-SL-0433.P-N.fC-G.txt"

How can I extract a substring in R? [closed]

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I have this string, for instance:
str1 = "UNCID_999277.TCGA-CV-7254-01A-11R-2016-07.111118_UNC11-SN627_0167_AD09WDACXX_TAGCTT.txt"
I would like to extract this substring, for instance:
TCGA-CV-7254
I tried something link this:
gsub(pattern = "(*.)(TCGA*)(.*)",
replacement = "\\2",
x = nameArq)
But it returns:
[1] "UNCID_999277TCGA"
Thanks for any help!

You almost had it. In the first parentheses, the period needs to come first (this means "repeat any character any number of times"). You also need some unique endpoint for the second part of your regex.
gsub(pattern = "(.*)(TCGA.*4)(.*)",
replacement = "\\2",
x = str1)

In R - how do I replace all letters in a string with other letters? [closed]

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I need to anonymize names but in a very specific way so that the format of the entire string is still the same (spaces, hyphens, periods are preserved) but all the letters are scrambled. I want to consistently replace say all A's with C's, all D's with Z's, and so on. How would I do that?

We can use chartr
chartr('AD', 'CZ', str1)
#[1] "CZ,ZC. C"
data
str1 <- c('AD,DA. C')

Maybe use gsub?
string <- "ABCDEFG"
text <- gsub('A', 'C', string )
string <- gsub('D', 'Z', string )
string
[1] "CBCZEFG"

Want to add characters to every element of a data frame [closed]

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I have a data frame of strings as below and would like to add the string "Market" to each of the elements of the data frame. Is there a function that would allow me to do this easily without having to use a for loop?
V1
1 PUBLIC_DISPATCHSCADA_20141221.zip
2 PUBLIC_DISPATCHSCADA_20141222.zip
3 PUBLIC_DISPATCHSCADA_20141223.zip
4 PUBLIC_DISPATCHSCADA_20141224.zip
5 PUBLIC_DISPATCHSCADA_20141225.zip
6 PUBLIC_DISPATCHSCADA_20141226.zip

We can use paste and specify the delimiter. In this case, I am using _ and pasteing the "Market" at the beginning of the string.
df1$V1 <- paste("Market", df1$V1, sep="_")
If we need to do this for each column
df1[] <- lapply(df1, function(x) paste("Market", x, sep="_"))

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