I can do a normal deploy using the below command
curl -i -X PUT -u $artifactoryUser:$artifactoryPassword -T /path/to/file/file.zip http://localhost/artifactory/simple/repo/groupId/artifactId/version/file.zip
However, this will not resolve or update maven layout on the artifact. Is there a way I can upload without using the artifactory-maven plugin?
I found a solution to this question I had posted.
Syntax Used:
curl -i -X PUT -K $CURLPWD "http://localhost/artifactory/$REPO/$groupId/$artifactId/$versionId/$artifactId-$versionId.$fileExt"
Ended up writing a script so that md5 & sha1 values are uploaded with the file, or else, I had to go in Artifactory and fix it manually.
#!/bin/bash
usage() {
echo "Please check the Usage of the Script, there were no enough parameters supplied."
echo "Usage: ArtifactoryUpload.sh localFilePath Repo GroupID ArtifactID VersionID"
exit 1
}
if [ -z "$5" ]; then
usage
fi
localFilePath="$1"
REPO="$2"
groupId="$3"
artifactId="$4"
versionId="$5"
ARTIFAC=http://localhost/artifactory
if [ ! -f "$localFilePath" ]; then
echo "ERROR: local file $localFilePath does not exists!"
exit 1
fi
which md5sum || exit $?
which sha1sum || exit $?
md5Value="`md5sum "$localFilePath"`"
md5Value="${md5Value:0:32}"
sha1Value="`sha1sum "$localFilePath"`"
sha1Value="${sha1Value:0:40}"
fileName="`basename "$localFilePath"`"
fileExt="${fileName##*.}"
echo $md5Value $sha1Value $localFilePath
echo "INFO: Uploading $localFilePath to $targetFolder/$fileName"
curl -i -X PUT -K $CURLPWD \
-H "X-Checksum-Md5: $md5Value" \
-H "X-Checksum-Sha1: $sha1Value" \
-T "$localFilePath" \
"$ARTIFAC/$REPO/$groupId/$artifactId/$versionId/$artifactId-$versionId.$fileExt"
Related
macOS Catalina, installed jenv 0.5.4 using homebrew, using zsh, followed all the steps listed in https://www.jenv.be/
In terminal I have the following error
Last login: Tue Dec 22 10:10:15 on ttys002
/usr/local/Cellar/jenv/0.5.4/libexec/libexec/jenv-refresh-plugins: line 14: /Users/username/.jenv/jenv.version: Permission denied
The below is the code from jenv-refresh-plugins
#!/usr/bin/env bash
# Summary: Refresh plugins links
resolve_link() {
$(type -p greadlink readlink | head -1) "$1"
}
set -e
[ -n "$JENV_DEBUG" ] && set -x
FORCE_REFRESH=0
if [ ! -f "${JENV_ROOT}/jenv.version" ]; then
echo "NONE" > ${JENV_ROOT}/jenv.version
fi
if [ "$1" = "--complete" ]; then
echo "--force"
exit
fi
if [ "$1" = "--force" ]; then
FORCE_REFRESH=1
fi
lastVersion=$(cat "${JENV_ROOT}/jenv.version" || echo "none")
currentVersion=$(jenv --version)
if [ ! "$lastVersion" == "$currentVersion" ] || [ $FORCE_REFRESH == "1" ]; then
echo "jenv has been updated, process to refresh plugin links"
for path in "${JENV_ROOT}/plugins/"*; do
if [ -L "$path" ]; then
pluginName=$(basename $path)
echo "Refresh plugin $pluginName"
ln -sfn "${JENV_INSTALL_DIR}/available-plugins/$pluginName" "${JENV_ROOT}/plugins/$pluginName"
fi
done
fi
echo "$currentVersion" > "${JENV_ROOT}/jenv.version"
jenv doctor
[OK] No JAVA_HOME set
[OK] Java binaries in path are jenv shims
[OK] Jenv is correctly loaded
Any help, much appreciated.
I just experienced this same issue on mac- it was caused because for some reason the folder /Users/username/.jenv had become locked.
I couldn't find a way to unlock it, so i just copied it to another directory, then ran sudo rm -rf /Users/username/.jenv , copied it back, and that has solved the problem.
e made a bash script as follows:
#! /bin/bash
OUTDIR=".//DATA/share/pipelines/results/"
INDIR="./DATA/share/pipelines/test_data/infile/"
projectname=$1
input_bam=$2
bins=$3
mkdir OUTDIR || true
of="${OUTDIR}"
ind="${INDIR}"
./DATA/share/pipelines/script.R \
-b "${bins}" \
-c "${projectname}" \
-o "${of}" \
-i "${ind}"
echo "first step is done"
when I run the script using the following command:
bash first.sh 30 beh
I will get this error:
mkdir: cannot create directory ‘OUTDIR’: File exists
first.sh: line 17: ./DATA/share/pipelines/script.R: No such file or directory
first step is done
do you know how to solve the problem?
When you call
bash first.sh 30 beh
$1 holds 30, $2 holds beh and $3 is not defined.
input_bam ist set to $2 but is never used.
With [ ! -d ${OUTDIR} ] you should be able to test if the directory exists.
#! /bin/bash
#Please check if it should be
# relative to the current working directory (starting with './')
# or absolute (starting with '/')
BASEDIR="/DATA/share/pipelines/" #"./DATA/share/pipelines/"
OUTDIR=${BASEDIR}"results/"
INDIR=${BASEDIR}"test_data/infile/"
projectname=$1
input_bam=$2 #This is never used
bins=$3 #This is not defined when callin >bash first.sh 30 beh<
[ ! -d ${OUTDIR} ] && mkdir ${OUTDIR} #Think you would create ${OUTDIR}
of="${OUTDIR}"
ind="${INDIR}"
./DATA/share/pipelines/script.R \
-b "${bins}" \
-c "${projectname}" \
-o "${of}" \
-i "${ind}"
echo "first step is done"
I am working through this tutorial on daemonizing php scripts. When I run the following Unix command:
. /etc/init.d/functions
#startup values
log=/var/log/Daemon.log
#verify that the executable exists
test -x /home/godlikemouse/Daemon.php || exit 0RETVAL=0
prog="Daemon"
proc=/var/lock/subsys/Daemon
bin=/home/godlikemouse/Daemon.php
start() {
# Check if Daemon is already running
if [ ! -f $proc ]; then
echo -n $"Starting $prog: "
daemon $bin --log=$log
RETVAL=$?
[ $RETVAL -eq 0 ] && touch $proc
echo
fi
return $RETVAL
}
I get the following output:
./Daemon: line 12: /etc/init.d/functions: No such file or directory
Starting Daemon: daemon: unrecognized option `--log=/var/log/Daemon.log'
I looked at my file system and there was no /etc/init.d file. Can anyone tell me what this is and where to obtain it? Also is the absence of that file what's causing the other error?
Separate your args within their own " " double-quotes:
args="--node $prog"
daemon "nohup ${exe}" "$args &" </dev/null 2>/dev/null
daemon "exe" "args"
How to write a shell script named "backup.sh" which accepts one parameter, which would be a filename/directory.
Create a backup copy of that with the .bak appended to its name.Show message on success.
If the file/directory does not exist, show a proper message.
i did up to this point.please help me to figure this out
#!/bin/sh
#create_backup.sh
And add a .bak
bak="${backup.sh}.bak"
if [ "$#" -eq 0 ]
then
exit 1;
echo "File Succesfully backuped"
fi
cp ${1} "${1}.back"
echo "File is not found "
exit 0
#!/bin/bash -e
directory=$1
cp -r $directory $directory.bak
echo "Success"
obvious caveats with pathing/error codes/etc
I want to be able to tell if a command exists on any POSIX system from a shell script.
On Linux, I can do the following:
if which <command>; then
...snip...
fi
However, Solaris and MacOS which do not give an exit failure code when the command does not exist, they just print an error message to STDOUT.
Also, I recently discovered that the which command itself is not POSIX (see http://pubs.opengroup.org/onlinepubs/9699919799/idx/utilities.html)
Any ideas?
command -v is a POSIX specified command that does what which does.
It is defined to to return >0 when the command is not found or an error occurs.
You could read the stdout/stderr of "which" into a variable or an array (using backticks) rather than checking for an exit code.
If the system does not have a "which" or "where" command, you could also grab the contents of the $PATH variable, then loop over all the directories and search for the given executable. That's essentially what which does (although it might use some caching/optimization of $PATH results).
One which utility is available as shell script in the Git repository of debianutils package of Debian Linux. The script seems to be POSIX compatible and you could use it, if you take into account copyright and license. Note that there have been some controversy whether or not and how the which utility should be deprecated; (at time of writing) current version in Git shows deprecation message whereas an earlier version added later removed -s option to enable silent operation.
command -v as such is problematic as it may output a shell function name, an alias definition, a keyword, a builtin or a non-executable file path. On the other hand some path(s) output by which would not be executed by shell if you run the respective argument as such or as an argument for command. As an alternative for using the which script, a POSIX shell function using command -v could be something like
#!/bin/sh
# Argument $1 should be the basename of the command to be searched for.
# Outputs the absolute path of the command with that name found first in
# a directory listed in PATH environment variable, if the name is not
# shadowed by a special built-in utility, a regular built-in utility not
# associated with a PATH search, or a shell reserved word; otherwise
# outputs nothing and returns 1. If this function prints something for
# an argument, it is the path of the same executable as what 'command'
# would execute for the same argument.
executable() {
if cmd=$(unset -f -- "$1"; command -v -- "$1") \
&& [ -z "${cmd##/*}" ] && [ -x "$cmd" ]; then
printf '%s\n' "$cmd"
else
return 1
fi
}
Disclaimer: Note that the script using command -v above does not find an executable whose name equals a name of a special built-in utility, a regular built-in utility not associated with a PATH search, or a shell reserved word. It might not find an executable either in case if there is non-executable file and executable file available in PATH search.
A function_command_exists for checking if a command exists:
#!/bin/sh
set -eu
function_command_exists() {
local command="$1"
local IFS=":" # paths are delimited with a colon in $PATH
# iterate over dir paths having executables
for search_dir in $PATH
do
# seek only in dir (excluding subdirs) for a file with an exact (case sensitive) name
found_path="$(find "$search_dir" -maxdepth 1 -name "$command" -type f 2>/dev/null)"
# (positive) if a path to a command was found and it was executable
test -n "$found_path" && \
test -x "$found_path" && \
return 0
done
# (negative) if a path to an executable of a command was not found
return 1
}
# example usage
echo "example 1";
command="ls"
if function_command_exists "$command"; then
echo "Command: "\'$command\'" exists"
else
echo "Command: "\'$command\'" does not exist"
fi
command="notpresent"
if function_command_exists "$command"; then
echo "Command: "\'$command\'" exists"
else
echo "Command: "\'$command\'" does not exist"
fi
echo "example 2";
command="ls"
function_command_exists "$command" && echo "Command: "\'$command\'" exists"
command="notpresent"
function_command_exists "$command" && echo "Command: "\'$command\'" does not exist"
echo "End of the script"
output:
example 1
Command: 'ls' exists
Command: 'notpresent' does not exist
example 2
Command: 'ls' exists
End of the script
Note that even the set -eu that turns -e option for the script was used the script was executed to the last line "End of the script"
There is no Command: 'notpresent' does not exist in the example 2 because of the && operator so the execution of echo "Command: "\'$command\'" does not exist" is skipped but the execution of the script continues till the end.
Note that the function_command_exists does not check if you have a right to execute the command. This needs to be done separately.
Solution with command -v <command-to-check>
#!/bin/sh
set -eu;
# check if a command exists (Yes)
command -v echo > /dev/null && status="$?" || status="$?"
if [ "${status}" = 127 ]; then
echo "<handle not found 1>"
fi
# check if a command exists (No)
command -v command-that-does-not-exists > /dev/null && status="$?" || status="$?"
if [ "${status}" = 127 ]; then
echo "<handle not found 2>"
fi
produces:
<handle not found 2>
because echo was found at the first example.
Solution with running a command and handling errors including command not found.
#!/bin/sh
set -eu;
# check if a command exists (No)
command -v command-that-does-not-exist > /dev/null && status="$?" || status="$?"
if [ "${status}" = 127 ]; then
echo "<handle not found 2>"
fi
# run command and handle errors (no problem expected, echo exist)
echo "three" && status="$?" || status="$?"
if [ "${status}" = 127 ]; then
echo "<handle not found 3>"
elif [ "${status}" -ne 0 ]; then
echo "<handle other error 3>"
fi
# run command and handle errors (<handle not found 4> expected)
command-that-does-not-exist && status="$?" || status="$?"
if [ "${status}" = 127 ]; then
echo "<handle not found 4>"
elif [ "${status}" -ne 0 ]; then
echo "<handle other error 4>"
fi
# run command and handle errors (command exists but <handle other error 5> expected)
ls non-existing-path && status="$?" || status="$?"
if [ "${status}" = 127 ]; then
echo "<handle not found 5>"
elif [ "${status}" -ne 0 ]; then
echo "<handle other error 5>"
fi
produces:
<handle not found 2>
three
./function_command_exists.sh: 34: ./function_command_exists.sh: command-that-does-not-exist: not found
<handle not found 4>
ls: cannot access 'non-existing-path': No such file or directory
<handle other error 5>
The following works in both bash and zsh and avoids both functions and aliases.
It returns 1 if the binary is not found.
bin_path () {
if [[ -n ${ZSH_VERSION:-} ]]; then
builtin whence -cp "$1" 2> /dev/null
else
builtin type -P "$1"
fi
}