How to get rid of app.php in Symfony2 URIs with Nginx - symfony

Question

I'm trying to get a clear understanding of what's going on with my nginx configuration file for Symfony2, here it is:
server {
listen 80;
autoindex on;
server_name example.com;
root /var/www/example.com/web;
rewrite ^/app\.php/?(.*)$ /$1 permanent;
location / {
index app.php;
try_files $uri $uri/ #symfony;
}
location #symfony {
rewrite ^(.*)$ /app.php/$1 last;
}
location ~ ^/app\.php(/|$) {
include fastcgi_params;
fastcgi_pass unix:/var/run/php5-fpm.sock;
fastcgi_split_path_info ^(.+\.php)(/.*)$;
fastcgi_param SCRIPT_FILENAME $document_root$fastcgi_script_name;
fastcgi_param SCRIPT_NAME $fastcgi_script_name;
}
}
In short, I'm trying to strip app.php in every possible URI that a user can set e.g. example.com/app.php/demo or just example.com/app.php.
This config actually works for URIs like ones above, but it leads to a redirect loop in case of trying to access "root" URI example.com.
And if I remove $uri/ from try_files and leave only $uri and a fallback #symfony there, everything is working fine except I can't access any directories as they're going to be processed by SF.
I'm out of ideas, did a lot of research on how nginx and rewrites actually work, but as for now it's a dead end for me. If you can find a solution to stay with $uri/ in try_files and get out of a loop at front, please let me know.

Answer 1

This solution from Nginx Tips worked for me. It's almost, but not quite, the same as yours.
server {
server_name domain.tld www.domain.tld;
root /var/www/project/web;
location / {
# try to serve file directly, fallback to rewrite
try_files $uri #rewriteapp;
}
location #rewriteapp {
# rewrite all to app.php
rewrite ^(.*)$ /app.php/$1 last;
}
location ~ ^/(app|app_dev|config).php(/|$) {
fastcgi_pass unix:/var/run/php5-fpm.sock;
fastcgi_split_path_info ^(.+.php)(/.*)$;
include fastcgi_params;
fastcgi_param SCRIPT_FILENAME $document_root$fastcgi_script_name;
fastcgi_param HTTPS off;
}
error_log /var/log/nginx/project_error.log;
}