I am trying to customize scss of foundation to have a two different classes for topbar. I have limited knowledge of scss therefore changing _settings.scss was very easy first step, which has the problem that it changes global style. I would like to do something like following without messing up global styles.
.my-topbar-first {
$topbar-bg-color: $red;
#extend .top-bar;
}
.my-topbar-second {
$topbar-bg-color: $green;
#extend .top-bar;
}
Whats the elegant way to achieve this?
when you are using $topbar-bg-color: $red; it set the $topbar-bg-color variable to what you have in $red variable.when you are using it again, it messed up the last setting.
so instead,
you have to do like this :
.my-topbar-first {
background-color: $red;
#extend .top-bar;
}
.my-topbar-second {
background-color: $green;
#extend .top-bar;
}
First of all you are duplicating code when extending .top-bar in both class names . A more DRY approach would be like this :
.my-topbar-first,
.my-topbar-second {
#extend .top-bar;
}
.my-topbar-first {
background-color: $red;
}
.my-topbar-second {
background-color: $green;
}
When using #extend or #include they should always be on the first line were you declare your properties , example:
my-topbar-second {
#extend .top-bar;
background-color: $green;
color: $white;
font-size: $top-bar-fontsize;
}
If you have more instances of .top-bar-foo you can actually write a for loop, example :
$class-slug: top-bar;
#for $i from 1 through 2 {
.#{$class-slug}-#{$i} {
background-color: $color-#{$i};
}
}
You get :
.top-bar-1 {
background-color: $color-1;
}
.top-bar-2 {
background-color: $color-2;
}
Hope this helped . If you want to learn more about Scss go on Hugo Giraudel's blog http://hugogiraudel.com/ and learn from the best .
Related
This might seem basic, but I can't figure out how to use CSS variables in LESS?
variables.css:
.root {
--header-color: white;
--content-color: yellow;
}
styles.less:
#import "../variables.css";
.header {
color: #header-color;
}
I get error "#header-color is undefined".
LESS allows you to use normal CSS code, so use one option could be just use the variable as CSS:
#import "../variables.css";
.header {
color: var(--header-color);
}
Also, you can save the css var to a LESS var:
#import "../variables.css";
#header-color: var(--header-color);
.header {
color: #header-color;
}
I'm searching a way to use a particular color depending on a class on the body tag.
I have a main scss file like this
// variables.scss
$bg-main: white;
$color-first: red;
$color-second: green;
And in my other files, I use the colors
// content.scss
.content {
.some-selector: {
// some styles
color: $color-second;
}
a:hover {
// some styles
color: $color-second;
}
}
// and same goes for menu.scss etc.
Now I have a dynamic class on the body, that changes depending on the current selected menu. I would like $color-second to be different for each body classes, and I don't know how to do that. The only solution I found was to move all the $color-second from each files into one single file, like this:
.body-1 {
.content a:hover, .content .some-selector {
color: green;
}
}
.body-2 {
.content a:hover, .content .some-selector {
color: blue;
}
}
.body-1 {
.content a:hover, .content .some-selector {
color: black;
}
}
So I don't need to write the color in each files. This works well, but if I need to set this $color-second to some other selector, I need to put that in this big file.
Is this possible to do this an other way?
I already checked these answers, but it didn't helped me much:
SASS set variable depending on CSS class
Creating or referencing variables dynamically in Sass
Merge string and variable to a variable with SASS
There are multiple ways to do this. The most obvious two which come to mind are mixins and loops:
Mixins
Just put everything you want into a single mixin, and then use it for every body class:
#mixin colored-content($color) {
.content a:hover, .content .some-selector {
color: $color;
}
/* Any other rules which use $color here */
}
.body-1 {
#include colored-content(green);
}
.body-2 {
#include colored-content('#FF0000');
}
.body-3 {
#include colored-content(darken(red, 20));
}
You can extend this example with any number of arguments (for example, $textColor and $bgColor), conditions or rules.
With this approach you will not have SCSS code repetitions, and any updates will be introduced easily.
Loop
Another way is to use a simple loop:
$body_themes: (
"body-1": green,
"body-2": #FF0000,
"body-3": darken(red, 2)
);
#each $body_class, $color in $body_themes {
.#{$body_class} {
.content a:hover, .content .some-selector {
color: $color;
}
/* Any other rules which use $color here */
}
}
It is even shorter, but imho it is less readable.
P.S. It is possible to combine mixins and loops, by the way :)
This question applies to both SASS and LESS.
I have a bunch of classes that are generated with mixins.
Inside my SASS or LESS code I want to extend those classes.
In LESS it doesn't work complaining that no such class exists (the classes show up in CSS, but obviously they are not in LESS code).
I found this feature request so I guess LESS doesn't support it.
How about SASS?
Example (LESS but I'll switch to SASS if it can do that):
.errorLevels(#x){
.level-#{x} {
font-size: unit(8 + #x,px);
}
}
.errorLevels(1);
.errorLevels(2);
.errorLevels(3);
.seriousError {
&:extend(.level-1);
}
I expect:
.level-1 {
font-size: 9px;
}
.level-2 {
font-size: 10px;
}
.level-3 {
font-size: 11px;
}
//this part is missing from output
.seriousError {
font-size: 1px;
}
You could do the following to extend a class that was generated in a mixin:
#mixin classGenerator {
.error {
color: red;
font-size: 9px;
}
}
#include classGenerator;
.seriousError {
#extend .error;
font-size: 20px;
}
EDIT
According to the changes in your question:
#mixin errorLevels($x){
.level-#{$x} {
font-size: #{12 + $x}px
}
}
#include errorLevels(1);
.seriousError {
#extend .level-1;
}
I’ve got a website that’s using a few different ‘main’ colors. The general HTML layout stays the same, only the colors change depending on the content.
I was wondering if I could set a color variable depending on the CSS selector. This way I can theme my website with a few variables and let Sass fill in the colors.
For example:
$color-1: #444;
$color-2: #555;
$color-3: #666;
$color-4: #777;
body.class-1 {
color-default: $color-1;
color-main: $color-2;
}
body.class-2 {
color-default: $color-3;
color-main: $color-4;
}
/* content CSS */
.content {
background: $color-default;
color: $color-main;
}
I was thinking of using a mixin for this, but I was wondering if there’s a better way to do this—with a function maybe? I’m not that great with Sass, so any help would be appreciated.
I think a mixin is the answer. (As I wrote, variables won’t work.)
#mixin content($color-default, $color-main) {
background: $color-default;
color: $color-main;
}
body.class-1 {
#include content(#444, #555);
}
body.class-2 {
#include content(#666, #777);
}
That SCSS compiles to this CSS:
body.class-1 {
background: #444444;
color: #555555; }
body.class-2 {
background: #666666;
color: #777777; }
If you wanted to group the color values together in your SCSS file, you could use variables in conjunction with the mixin:
$color-1: #444;
$color-2: #555;
$color-3: #666;
$color-4: #777;
body.class-1 {
#include content($color-1, $color-2);
}
body.class-2 {
#include content($color-3, $color-4);
}
as sass documentation explain nicely (https://sass-lang.com/documentation/variables):
Sass variables are all compiled away by Sass. CSS variables are included in the CSS output.
CSS variables can have different values for different elements, but Sass variables only have one value at a time.
Sass variables are imperative, which means if you use a variable and then change its value, the earlier use will stay the same. CSS variables are declarative, which means if you change the value, it’ll affect both earlier uses and later uses.
We may take advantage of that using a combination of sass and css variables to achieve what you want:
//theme colors
$red-cosmo: #e01019;
$green-cosmo: #00c398;
$primary-color: var(--primary-color);
body{
--primary-color: #{$red-cosmo};
}
body.univers-ride{
--primary-color: #{$green-cosmo};
}
So when I call my sass variable $primary-color, it will print as my css variable "var(--primary-color)" that will expand as $green-cosmo only if my body has the "univers-ride" class else it will be $red-cosmo the default color.
If you really want to get hacky you could also define your different color schemes in a single variable like $scheme1: class1 #333 #444, where the first value is always the name, and that is followed by all the colors in that scheme.
You can then use #each:
// Define your schemes with a name and colors
$scheme1: class1 #444 #555;
$scheme2: class2 #666 #777;
$scheme3: class4 #888 #999;
// Here are your color schemes
$schemes: $scheme1 $scheme2 $scheme3;
#each $scheme in $schemes {
// Here are the rules specific to the colors in the theme
body.#{nth($scheme, 1)} .content {
background-color: nth($scheme, 2);
color: nth($scheme, 3);
}
}
This will compile to:
body.class1 .content {
background-color: #444444;
color: #555555; }
body.class2 .content {
background-color: #666666;
color: #777777; }
body.class4 .content {
background-color: #888888;
color: #999999; }
Obviously if you don't want to combine body.class1 and .content in your selectors, you could just specify a mixin content($main, $default) and call it inside the #each using nth just like in the above code, but the point is you don't have to write out a rule for each of your classes.
EDIT There are lots of interesting answers on Creating or referencing variables dynamically in Sass and Merge string and variable to a variable with SASS.
You can also create a mixing that use the ampersand parent selector. http://codepen.io/juhov/pen/gbmbWJ
#mixin color {
body.blue & {
background: blue;
}
body.yellow & {
background: yellow;
}
}
UPDATE: its 2017 and variables does works!
#mixin word_font($page) {
#font-face {
font-family: p#{$page};
src: url('../../static/fonts/ttf/#{$page}.ttf') format('truetype');
font-weight: normal;
font-style: normal;
}
.p#{$page} {
font-family: p#{$page};
}
}
// Loop and define css classes
#for $i from 1 through 604 {
#include word_font($i);
}
If you don't want to use a variable for each color, you can use one variable for all kinds of colors. In the mixin you can choose the right color with nth. For instance, if you write the index of the color as 1, then you get the first color in the color variable.
$colors: #444, #555, #666, #777;
#mixin content($color-default-num, $color-main-num) {
background: nth($colors, $color-default-num);
color: nth($colors, $color-main-num);
}
body.class-1 {
#include content(1, 2);
}
For me the definite answer to my problem was creating a map of maps and loopig through them as follows:
$pallettes: (
light-theme: (
container-color: red,
inner-color: blue,
),
dark-theme: (
container-color: black,
inner-color: gray,
),
);
#each $pallette, $content in $pallettes {
.main.#{$pallette} {
background-color: map-get($content, container-color);
.inner-div {
background-color: map-get($content, inner-color);
}
}
}
You can simply override your scss variables inside of the class wrapper:
$color1: red;
$color2: yellow;
header { background: $color1; }
.override-class {
$color1: green;
header { background: $color1; }
}
Seems to work for me.
Is there a way to add scope to sass variables?
I want to be able to attach a class to my body element. The class will refer to a set of colours that the rest of the stylesheets can access.
I have tried:
#mixin theme_one{
$color: #000;
}
.theme_one{
#include theme_one;
}
and
.theme_one{
$color: #000;
}
I've just come across the same issue myself. I wanted to have different colour themes for different sections of my site.
Using a mixin seems like the best way to go. It's nicely DRY, and easy to use. The trick is not setting your colours in your main styles blocks, but rather using only the mixin for this.
I've set up the theme colours as variables at the top so they can be edited nicely, and I've set them as lists so that multiple values can be passed without hordes of variable being defined.
So:
// Variable Definitions
$defaultColor: black white grey;
$color2: blue green brown;
$color3: red white blue;
#mixin colorSet($color: $defaultColor) {
$link: nth($color, 1);
$border: nth($color, 2);
$background: nth($color, 3);
border-color: $border;
background-color: $background;
.column {
border-color: lighten($border, 10%);
}
a {
color: $link;
&:hover {
color: darken($link, 15%);
}
}
}
// Default colours
body {
#include colorSet();
}
// Scoped colours
.my-theme-3 {
#include colorSet($color3);
}
.my-theme-2 {
#include colorSet($color2);
}
Will produce something like this:
body {
border-color: white;
background-color: grey; }
body .column {
border-color: white; }
body a {
color: black; }
body a:hover {
color: black; }
.my-theme-3 {
border-color: white;
background-color: blue; }
.my-theme-3 .column {
border-color: white; }
.my-theme-3 a {
color: red; }
.my-theme-3 a:hover {
color: #b30000; }
.my-theme-2 {
border-color: green;
background-color: brown; }
.my-theme-2 .column {
border-color: #00b300; }
.my-theme-2 a {
color: blue; }
.my-theme-2 a:hover {
color: #0000b3; }
Edit: Updated to use default mixin values.
In your case no need to use mixin, If you have set of many styles then use mixin,
ie. if you have
#mixin theme_one{
$color: #000;
height: 50px;
}
then use Mixin
otherwise for single property use only variable
$color: #fff;
.some_class01{
color: $color;
background: $color;
}
.some_class22{
border-color: $color;
}
IMP: Variable should assign at the top of your code, it means don't use it after/below where you assigned it :)
Not sure if this is what you are looking for. It looks like you may have tried something similar to this,
which should probably work. (it may just be a matter of using !default)
Your body tag with a class on it..
<body class="theme_one">
</body>
Sass variables defined in stylesheet..
//THEME ONE VARIABLES
.theme_one{
$borderColor:#333 !default;
$fontColor:#999 !default;
}
//THEME TWO VARIABLES
.theme_two{
$borderColor:#CCC !default;
$fontColor:#000 !default;
}
Pre-existing CSS which will be overwritten depending on which class is used on the body tag.
h1.someheader {
color:$fontColor;
border-bottom:1px solid;
border-color:$borderColor;
}
Otherwise you could maybe try something like this. It looks like you may have tried something similar, however there seems to be an error with your mixin ... see note below.
//mixin used to set variables for properties
#mixin themeOne($fontColor,$borderColor) {
color:$fontColor;
border-color:$borderColor;
}
#include themeOne(#000,#CCC);
Pre-existing CSS
h1.someheader {
color:$fontColor
border-color:$borderColor;
border-bottom:1px solid;
}
Also note in your mixin example you are using $color:#000; ... This won't be interpreited properly as it should be color:#000; You can't use variables as selectors
unless you do something like #{$color}:#000;
I haven't quite tested this yet, so some things might need to be adjusted. If this doesn't solve your problem I hope it at least gives you some ideas.