Im having some trouble finding a way to Upload a document to the database in varbinary(max) with ASP.Net Webpages 2 and I would also like to download it.
So far what i have is this below which supposed to upload a file to a directory on the website but it isn't doing anything. Any help would be great. Thanks
var fileName = "";
var fileSavePath = "";
int numFiles = Request.Files.Count;
int uploadedCount = 0;
for (int i = 0; i < numFiles; i++)
{
var uploadedFile = Request.Files[i];
if (uploadedFile.ContentLength > 0)
{
fileName = Path.GetFileName(uploadedFile.FileName);
fileSavePath = Server.MapPath("~/UploadedFiles/" +
fileName);
uploadedFile.SaveAs(fileSavePath);
uploadedCount++;
}
}
message = "File upload complete. Total files uploaded: " +
uploadedCount.ToString();
The following code goes at the top of the page where you have your file upload. Note that you should amend the table and field names according to your database. Also, you should ensure that the form that includes your upload control has the enctype attribute set to multipart/form-data:
#{
int id = 0;
var fileName = "";
var fileMime = "";
if (IsPost) {
var uploadedFile = Request.Files[0];
fileName = Path.GetFileName(uploadedFile.FileName);
if(fileName != String.Empty)
{
fileMime = uploadedFile.ContentType;
var fileStream = uploadedFile.InputStream;
var fileLength = uploadedFile.ContentLength;
byte[] fileContent = new byte[fileLength];
fileStream.Read(fileContent, 0, fileLength);
var db = Database.Open("FileUploading");
var sql = "INSERT INTO Files (FileName, FileContent, MimeType) VALUES (#0,#1,#2)";
db.Execute(sql, fileName, fileContent, fileMime);
}
}
}
To display a file from the database, you need a separate "handler" file that contains just this code:
#{
int id = 0;
if(Request["Id"].IsInt()){
id = Request["Id"].AsInt();
var db = Database.Open("FileUploading");
var sql = "Select * From Files Where FileId = #0";
var file = db.QuerySingle(sql, id);
if(file.MimeType.StartsWith("image/")){
Response.AddHeader("content-disposition", "inline; filename=" + file.FileName);
} else {
Response.AddHeader("content-disposition", "attachment; filename=" + file.FileName);
}
Response.ContentType = file.MimeType;
Response.BinaryWrite((byte[])file.FileContent);
}
}
This file is used as the src attribute for an image file or as the URL for a link to a file that should be downloaded such as a PDF or Word file. If you call this handler file "download.cshtml", the link for an image file saved in the database should look like this:
<img src="download.cshtml?Id=#id" alt="" />
where the Id parameter value is the id fo the file in the database. A download link looks like this:
Click Here
All of this has been taken from my article: http://www.mikesdotnetting.com/Article/148/Save-And-Retrieve-Files-From-a-Sql-Server-CE-Database-with-WebMatrix. The only difference between the article which features a SQL Compact database is that the data type for files in SQL CE is image as opposed to varbinary(max) in SQL Server.
based on your code..you are not uploading the image to the database. instead u're saving the image on your folder which is located in your root / UploadedFiles
to store the image in the database..you should use this code..
using (Stream fs = uploadedFile.PostedFile.InputStream)
{
using (BinaryReader br = new BinaryReader(fs))
{
byte[] bytes = br.ReadBytes((Int32)fs.Length);
string contentType = uploadedFile.PostedFile.ContentType;
SqlParameter[] arParams = new SqlParameter[2];
arParams[0] = new SqlParameter("#ID", SqlDbType.Int);
arParams[0].Value = 1; 'example
arParams[1] = new SqlParameter("#contentType", SqlDbType.Varchar(50));
arParams[1].Value = contentType;
arParams[2] = new SqlParameter("#document", SqlDbType.Varbinary(MAX));
arParams[2].Value = bytes;
SqlHelper.ExecuteNonQuery(SQLConn, CommandType.StoredProcedure, "Upload_Attachment", arParams);
}
}
Related
I want to add a simple backup and restore option to my ASP.Net WebApplication. I created the procedure below in my database:
CREATE PROCEDURE dbo.[BackUp]
#path NVARCHAR(MAX)
AS
DECLARE #DataBaseName NVARCHAR(MAX) = DB_NAME()
BACKUP DATABASE #DataBaseName
TO DISK = #path
WITH FORMAT,
MEDIANAME = 'Backup'
GO
I created my model using entity framework. the procedure is:
public virtual int BackUp(string path)
{
var pathParameter = path != null ?
new ObjectParameter("path", path) :
new ObjectParameter("path", typeof(string));
return ((IObjectContextAdapter)this).ObjectContext.ExecuteFunction("BackUp", pathParameter);
}
But when I call Backup, I see this error:
Cannot perform a backup or restore operation within a transaction.
BACKUP DATABASE is terminating abnormally.
I solved that problem by changing Backup function to this:
public void BackUp()
{
Kimiakesht entity = new Kimiakesht();
string dataTime = DateTime.Now.ToString("yyyy-MM-dd") + "-" + DateTime.Now.ToString("HH-mm");
string directory = HttpContext.Current.Server.MapPath("~/") + "/backups/" + dataTime + "/";
string fileName = directory + dataTime + ".bak";
#region Response
HttpResponse Response = HttpContext.Current.Response;
Response.Clear();
Response.BufferOutput = false;
Response.ContentType = "application/zip";
Response.AddHeader("content-disposition", "inline; filename=\"" + dataTime + "\".zip");
#endregion
if (!Directory.Exists(directory))
Directory.CreateDirectory(directory);
// Here the procedure is called and executes successfully
entity.Database.ExecuteSqlCommand(System.Data.Entity.TransactionalBehavior.DoNotEnsureTransaction, "EXEC [dbo].[BackUp] #path = N'" + fileName + "'");
#region Compress
using (var memoryStream = new System.IO.MemoryStream())
{
using (ZipFile zip = new ZipFile())
{
zip.CompressionLevel = Ionic.Zlib.CompressionLevel.BestCompression;
zip.ParallelDeflateThreshold = -1;
zip.AddDirectory(directory);
zip.Save(memoryStream);
}
memoryStream.Position = 0;
var b = new byte[1024];
int n;
while ((n = memoryStream.Read(b, 0, b.Length)) > 0)
Response.OutputStream.Write(b, 0, n);
}
#endregion
Directory.Delete(directory, true);
Response.Close();
}
This function create backup from database, compress it and then return it to download as a HttpResponse. Finally deletes the temp directory
UPDATE
this is stored procedure content:
ALTER PROCEDURE [dbo].[BackUp]
#path NVARCHAR(MAX)
AS
DECLARE #DataBaseName NVARCHAR(MAX) = DB_NAME()
BACKUP DATABASE #DataBaseName
TO DISK = #path
WITH FORMAT,
MEDIANAME = 'Z_SQLServerBackups'
I want to export data from data table to Excel file. I need to save the file on server. I am using the console application for this project.
Since you haven't mentioned if excel is installed, i recommend EPPlus to create the excel file. It has a convenient method LoadFromDataTable:
using (var pck = new ExcelPackage())
{
var ws = pck.Workbook.Worksheets.Add("Worksheet-Name");
ws.Cells["A1"].LoadFromDataTable(dataTable1, true, OfficeOpenXml.Table.TableStyles.Medium1);
using(var fileStream = File.Create(path))
pck.SaveAs(fileStream);
}
Edit i've only just seen that you have tagged export-to-csv.
var lines = dataTable1.AsEnumerable()
.Select(r => string.Join(",", r.ItemArray));
string csv = string.Join(Environment.NewLine, lines);
File.AppendAllText(path, csv);
if (DtReqDetails != null)
{
string attachment = "attachment; filename=History.xls";
Response.ClearContent();
Response.AddHeader("content-disposition", attachment);
Response.ContentType = "application/vnd.ms-excel";
string tab = "";
foreach (DataColumn dc in DtReqDetails.Columns)
{
Response.Write(tab + dc.ColumnName);
tab = "\t";
}
Response.Write("\n");
int i;
foreach (DataRow dr in DtReqDetails.Rows)
{
tab = "";
for (i = 0; i < DtReqDetails.Columns.Count; i++)
{
Response.Write(tab + dr[i].ToString());
tab = "\t";
}
Response.Write("\n");
}
Response.End();
}
If you are using MS SQL, then they have a built-in procedure for exporting a table to an Excel spreadsheet. No coding required.
ive got a file download issue can you help me for that...
here is the code:
DirectoryInfo directoryInfo = new DirectoryInfo(Server.MapPath(#"/Bailiffs/BailiffFiles/"));
string cukurNumber = string.Empty;
if (txtCukurNumber.Text != string.Empty) {
cukurNumber = txtCukurNumber.Text;
}
FileInfo[] fileInfoEnum = directoryInfo.GetFiles(cukurNumber + "*");
Response.Clear();
Response.AddHeader("Content-Disposition", "attachment;filename=" + txtCukurNumber.Text + ".zip");
Response.ContentType = "application/zip";
using (ZipOutputStream zipStream = new ZipOutputStream(Response.OutputStream)) {
zipStream.SetLevel(9);
byte[] zipBuffer = new byte[4096];
foreach (FileInfo fileInfo in fileInfoEnum) {
string fileFullName = fileInfo.FullName;
ZipEntry zipEntry = new ZipEntry(Path.GetFileName(fileFullName));
zipEntry.DateTime = DateTime.Now;
zipStream.PutNextEntry(zipEntry);
using (FileStream fileStream = File.OpenRead(fileFullName)) {
int sourceBytes = 0;
do {
sourceBytes = fileStream.Read(zipBuffer, 0, zipBuffer.Length);
zipStream.Write(zipBuffer, 0, sourceBytes);
} while (sourceBytes > 0);
}
}
zipStream.Finish();
zipStream.Close();
Response.Flush();
Response.End();
}
this code must be get all image files by filter and save to disk but save file dialog of browser is opening just one time and one bizarre file is saving... where am i doing wrong...
thanks..
Edit : Bizzarre file issue is solved now the main issue is single file saving instead of multiple..
thanks again...
Although you are looping over each file in the directory, once you do your Response.End() on the first iteration of the loop, the response to the user is done. They would only get the first file that is found by the enumerator.
The browser doesn't have a concept of receiving multiple files in the way you are attempting.
You may consider collecting the various image files and putting them together in a ZIP file, and then returning a single ZIP back to the user.
Here is example code that will build a ZIP (using SharZipLib) of the images and reply with a single file called "images.zip"
Include these using statements for SharpZipLib:
using ICSharpCode.SharpZipLib.Core;
using ICSharpCode.SharpZipLib.Zip;
using ICSharpCode.SharpZipLib.Checksums;
Then in the method where you want to stream back the ZIP file:
DirectoryInfo directoryInfo = new DirectoryInfo(Server.MapPath(#"/Bailiffs/BailiffFiles/"));
string cukurNumber = string.Empty;
if (txtCukurNumber.Text != string.Empty) {
cukurNumber = txtCukurNumber.Text;
}
IEnumerable<FileInfo> fileInfoEnum = directoryInfo.EnumerateFiles( cukurNumber + "*" );
Response.Clear();
Response.AddHeader( "Content-Disposition", "attachment;filename=images.zip" );
Response.ContentType = "application/zip";
using( ZipOutputStream zipstream = new ZipOutputStream( Response.OutputStream ) ) {
zipstream.SetLevel( 9 ); // 0-9, 9 being the highest compression
byte[] buffer = new byte[4096];
foreach( FileInfo fileInfo in fileInfoEnum ) {
string file = fileInfo.FullName;
ZipEntry entry = new
ZipEntry( Path.GetFileName( file ) );
entry.DateTime = DateTime.Now;
zipstream.PutNextEntry( entry );
using( FileStream fs = File.OpenRead( file ) ) {
int sourceBytes;
do {
sourceBytes = fs.Read( buffer, 0, buffer.Length );
zipstream.Write( buffer, 0, sourceBytes );
} while( sourceBytes > 0 );
}
}
zipstream.Finish();
zipstream.Close();
}
Response.Flush();
Response.End();
Here is my code to post the file. I use asp fileupload control to get the file stream.
HttpWebRequest requestToSender = (HttpWebRequest)WebRequest.Create("http://localhost:2518/Web/CrossPage.aspx");
requestToSender.Method = "POST";
requestToSender.ContentType = "multipart/form-data";
requestToSender.KeepAlive = true;
requestToSender.Credentials = System.Net.CredentialCache.DefaultCredentials;
requestToSender.ContentLength = BtnUpload.PostedFile.ContentLength;
BinaryReader binaryReader = new BinaryReader(BtnUpload.PostedFile.InputStream);
byte[] binData = binaryReader.ReadBytes(BtnUpload.PostedFile.ContentLength);
Stream requestStream = requestToSender.GetRequestStream();
requestStream.Write(binData, 0, binData.Length);
requestStream.Close();
HttpWebResponse responseFromSender = (HttpWebResponse)requestToSender.GetResponse();
string fromSender = string.Empty;
using (StreamReader responseReader = new StreamReader(responseFromSender.GetResponseStream()))
{
fromSender = responseReader.ReadToEnd();
}
XMLString.Text = fromSender;
In the page load of CrossPage.aspx i have the following code
NameValueCollection postPageCollection = Request.Form;
foreach (string name in postPageCollection.AllKeys)
{
Response.Write(name + " " + postPageCollection[name]);
}
HttpFileCollection postCollection = Request.Files;
foreach (string name in postCollection.AllKeys)
{
HttpPostedFile aFile = postCollection[name];
aFile.SaveAs(Server.MapPath(".") + "/" + Path.GetFileName(aFile.FileName));
}
string strxml = "sample";
Response.Clear();
Response.Write(strxml);
I don't get the file in Request.Files. The byte array is created. What was wrong with my HttpWebRequest?
multipart/form-data doesn't consist of simply writing the file bytes to the request stream. You need to respect the RFC 1867. You may take a look at this post of how this could be done with multiple files.
I'm making a simple download service so a user can download all his images from out site.
To do that i just zip everything to the http stream.
However it seems everything is stored in memory, and the data isn't sent til zip file is complete and the output closed.
I want the service to start sending at once, and not use too much memory.
public void ProcessRequest(HttpContext context)
{
List<string> fileNames = GetFileNames();
context.Response.ContentType = "application/x-zip-compressed";
context.Response.AppendHeader("content-disposition", "attachment; filename=files.zip");
context.Response.ContentEncoding = Encoding.Default;
context.Response.Charset = "";
byte[] buffer = new byte[1024 * 8];
using (ICSharpCode.SharpZipLib.Zip.ZipOutputStream zipOutput = new ICSharpCode.SharpZipLib.Zip.ZipOutputStream(context.Response.OutputStream))
{
foreach (string fileName in fileNames)
{
ICSharpCode.SharpZipLib.Zip.ZipEntry zipEntry = new ICSharpCode.SharpZipLib.Zip.ZipEntry(fileName);
zipOutput.PutNextEntry(zipEntry);
using (var fread = System.IO.File.OpenRead(fileName))
{
ICSharpCode.SharpZipLib.Core.StreamUtils.Copy(fread, zipOutput, buffer);
}
}
zipOutput.Finish();
}
context.Response.Flush();
context.Response.End();
}
I can see the the worker process memory growing while it makes the file, and then releases the memory when its done sending. How do i do this without using too much memory?
Disable response buffering with context.Response.BufferOutput = false; and remove the Flush call from the end of your code.
use Response.BufferOutput = false; at start of ProcessRequest and flush response after each file.
FYI. This is working code to recursively add an entire tree of files, with streaming to browser:
string path = #"c:\files";
Response.Clear();
Response.ContentType = "application/zip";
Response.AddHeader("Content-Disposition", string.Format("attachment; filename=\"{0}\"", "hive.zip"));
Response.BufferOutput = false;
byte[] buffer = new byte[1024 * 1024];
using (ZipOutputStream zo = new ZipOutputStream(Response.OutputStream, 1024 * 1024)) {
zo.SetLevel(0);
DirectoryInfo di = new DirectoryInfo(path);
foreach (string file in Directory.GetFiles(di.FullName, "*.*", SearchOption.AllDirectories)) {
string folder = Path.GetDirectoryName(file);
if (folder.Length > di.FullName.Length) {
folder = folder.Substring(di.FullName.Length).Trim('\\') + #"\";
} else {
folder = string.Empty;
}
zo.PutNextEntry(new ZipEntry(folder + Path.GetFileName(file)));
using (FileStream fs = File.OpenRead(file)) {
ICSharpCode.SharpZipLib.Core.StreamUtils.Copy(fs, zo, buffer);
}
zo.Flush();
Response.Flush();
}
zo.Finish();
}
Response.Flush();