I am attempting to use the extractjson() method that includes email addresses in the source data (specifically the # symbol).
let T = datatable(MyString:string)
[
'{"user#domain.com": {"value":10}, "userdomain.com": { "value": 5}}'
];
T
| project extractjson('$.["user#domain.com"].value', MyString)
This results in a null being returned, changing the JSONPath to '$.["userdomain.com"].value' does return the correct result.
Results
I know the # sign is a used as the current node in a filter expression, does this need to be escaped when used with KQL?
Just as a side note, I run the same test using nodes 'jsonpath' package and this worked as expected.
const jp = require('jsonpath');
const data = {"user#domain.com": {"value":10}, "name2": { "value": 5}};
console.log(jp.query(data, '$["user#domain.com"].score'));
you can use the parse_json() function instead, and when you don't have to use extract_json():
print MyString = '{"user#domain.com": {"value":10}, "userdomain.com": { "value": 5}}'
| project parse_json(MyString)["user#domain.com"].value
MyString_user#domain.com_value
10
From the documentation: https://learn.microsoft.com/en-us/azure/data-explorer/kusto/query/extractjsonfunction
I am decoding form fields submitted via a HTTP POST request using request-toolbelt. I successfully instantiated a MultipartDecoder like described here. Now I would like to access the form fields by the name I have given them when sending the request.
I am able to get the name of a field like this
from requests_toolbelt.multipart import decoder
multipart_string = b"--ce560532019a77d83195f9e9873e16a1\r\nContent-Disposition: form-data; name=\"author\"\r\n\r\nJohn Smith\r\n--ce560532019a77d83195f9e9873e16a1\r\nContent-Disposition: form-data; name=\"file\"; filename=\"example2.txt\"\r\nContent-Type: text/plain\r\nExpires: 0\r\n\r\nHello World\r\n--ce560532019a77d83195f9e9873e16a1--\r\n"
content_type = "multipart/form-data; boundary=ce560532019a77d83195f9e9873e16a1"
decoder = decoder.MultipartDecoder(multipart_string, content_type)
field_name = decoder.parts[0].headers[b'Content-Disposition'].decode().split(';')[1].split('=')[1]
But this seems quite wrong. What is the usual way to access the form field names?
I use it in the following to decode the result of that method:
lst = []
for part in decoder.MultipartDecoder(postdata.encode('utf-8'), content_type_header).parts:
disposition = part.headers[b'Content-Disposition']
params = {}
for dispPart in str(disposition).split(';'):
kv = dispPart.split('=', 2)
params[str(kv[0]).strip()] = str(kv[1]).strip('\"\'\t \r\n') if len(kv)>1 else str(kv[0]).strip()
type = part.headers[b'Content-Type'] if b'Content-Type' in part.headers else None
lst.append({'content': part.content, "type": type, "params": params})
I assume because its a standard Mime header, there are functions that can do the same, but with less code as well.
I'm trying to concat 2 variables Address and Payload. After that I want to send them with http to a server but I have 2 problems. When i try to concat the 2 variables with a delimiter ';' it doesn't work. Also sending the data of Payload or Address doesn't work. This is my code:
handle_rx(Gateway, #link{devaddr=DevAddr}=Link, #rxdata{port=Port, data= RxData }, RxQ)->
Data = base64:encode(RxData),
Devaddr = base64:encode(DevAddr),
TextAddr="Device address: ",
TextPayload="Payload: ",
Address = string:concat(TextAddr, Devaddr),
Payload = string:concat(TextPayload, Data),
Json=string:join([Address,Payload], "; "),
file:write_file("/tmp/foo.txt", io_lib:fwrite("~s.\n", [Json] )),
inets:start(),
ssl:start(),
httpc:request(post, {"http://192.168.0.121/apiv1/lorapacket/rx", [], "application/x-www-form-urlencoded", Address },[],[]),
ok;
handle_rx(_Gateway, _Link, RxData, _RxQ) ->
{error, {unexpected_data, RxData}}.
I have no errors that I can show you. When I write Address or Payload individually to the file it works but sending doesn't work...
Thank you for your help!
When i try to concat the 2 variables with a delimiter ';' it doesn't work.
5> string:join(["hello", <<"world">>], ";").
[104,101,108,108,111,59|<<"world">>]
6> string:join(["hello", "world"], ";").
"hello;world"
base64:encode() returns a binary, yet string:join() requires string arguments. You can do this:
7> string:join(["hello", binary_to_list(<<"world">>)], ";").
"hello;world"
Response to comment:
In erlang the string "abc" is equivalent to the list [97,98,99]. However, the binary syntax <<"abc">> is not equivalent to <<[97,98,99]>>, rather the binary syntax <<"abc">> is special short hand notation for the binary <<97, 98, 99>>.
Therefore, if you write:
Address = [97,98,99].
then the code:
Bin = <<Address>>.
after variable substitution becomes:
Bin = <<[97,98,99]>>.
and that isn't legal binary syntax.
If you need to convert a string/list contained in a variable, like Address, to a binary, you use list_to_binary(Address)--not <<Address>>.
In your code here:
Json = string:join([binary_to_list(<<Address>>),
binary_to_list(<<Payload>>)],
";").
Address and Payload were previously assigned the return value of string:concat(), which returns a string, so there is no reason to (attempt) to convert Address to a binary with <<Address>>, then immediately convert the binary back to a string with binary_to_list(). Instead, you would just write:
Json = string:join(Address, Payload, ";")
The problem with your original code is that you called string:concat() with a string as the first argument and a binary as the second argument--yet string:concat() takes two string arguments. You can use binary_to_list() to convert a binary to the string that you need for the second argument.
Sorry I'm new to Erlang
As with any language, you have to study the basics and write numerous toy examples before you can start writing code that actually does something.
You don't have to concatenate strings. It is called iolist and is one of best things in Erlang:
1> RxData = "Hello World!", DevAddr = "Earth",
1> Data = base64:encode(RxData), Devaddr = base64:encode(DevAddr),
1> TextAddr="Device address", TextPayload="Payload",
1> Json=["{'", TextAddr, "': '", Devaddr, "', '", TextPayload, "': '", Data, "'}"].
["{'","Device address","': '",<<"RWFydGg=">>,"', '",
"Payload","': '",<<"SGVsbG8gV29ybGQh">>,"'}"]
2> file:write_file("/tmp/foo.txt", Json).
ok
3> file:read_file("/tmp/foo.txt").
{ok,<<"{'Device address': 'RWFydGg=', 'Payload': 'SGVsbG8gV29ybGQh'}">>}
I am doing an http requestlike this one:
resp, err := http.Get("http://example.com/")
Then I am getting the header link:
link := resp.Header.Get("link")
Which gives me a result like this:
<page=3>; rel="next",<page=1>; rel="prev";<page=5>; rel="last"
Question
How can I parse this into a more legible way? I specifically trying to get the last page but firstand nextpage should useful as well.
I tried with Splitsand Regular expressionswithout success.
Are you sure that is the format of the output? It looks like one of ; should be a ,.
A single Link http header with multiple values, should be of the format (notice the comma after "prev")
<page=3>; rel="next",<page=1>; rel="prev",<page=5>; rel="last"
The order should be split on , for each link. Split each link on ; for values or key-value pairs, and then if they value matches <(.*=.*)>, discard the angle brackets and use the remaining key and value.
Here's a solution of how to match your page numbers.
http://play.golang.org/p/kzurb38Fwx
text := `<page=3>; rel="next",<page=1>; rel="prev";<page=2>; rel="last"`
re := regexp.MustCompile(`<page=([0-9]+)>; rel="next",<page=([0-9]+)>; rel="prev";<page=([0-9]+)>; rel="last"`)
matches:= re.FindStringSubmatch(text)
if matches != nil {
next := matches[1]
prev := matches[2]
last := matches[3]
fmt.Printf("next = %s, prev = %s, last = %s\n", next, prev, last)
}
Later Edit: you can probably also use the xml package to achieve the same result, by parsing that output as an XML, but you would need to transform your output a bit.
I have been navigating map structures fine for a long time now. Yet, for some reason, the root of this problem escapes me. I've tried bracket notation as well, no luck.
Why doesn't the final output (null) return "[serverinfo:[listenPort:19001]]"
If I replace the two instances of ' "$instanceName" ' with simply ' services ', it works.
String instanceName = "Services"
Map serverNode = [
instances:[
"$instanceName":[
serverinfo:[
listenPort:19001
]
]
]
]
println "$instanceName"
println serverNode.instances
println serverNode.instances."$instanceName"
//output
Services
[Services:[serverinfo:[listenPort:19001]]]
null
The type of "$instanceName" is GStringImpl, not String. It's a common mistake (and hard to find!)
def serverNode = [
instances:[
("$instanceName" as String):[
serverinfo:[
listenPort:19001
]
]
]
]
as stated by #tim_yates in comment, if your interpolated string is as simple as in this example (ie ,"${property}"), then you can use the (property) syntax : Groovy put the value of the property as a key, not the word "property"