Can you explain a methods for storing program data with global access ?
I found these keywords:
- using static class to store data
- pass QList by value
- pass Qlist by reference
- use 'friend' keyword
but I cannot find any real example of storing global QList, as they say, it is a bad design to use global variables. Also there is a mention that using pointers on a QList is a bad idea because of implicit sharing (?).
So where should I store my Qlist for accessing it from a different class in an other .cpp ? So I have:
mainwindow.h
QList <SceneCard> sceneList;
QString mTitle;
public slots:
QString setValue()
{
return mTitle;
}
mainwindow.cpp
MainWindow::AddScene()
{
sceneCard = new SceneCard(sNumber);
sceneList.append(sceneCard);
mTitle = "Nejat is right!"
}
void MainWindow::showSceneCard()
{
SceneDialog D;
connect(D,SIGNAL(getValue()),this,SLOT(setValue()));
D.exec();
}
scenedialog.h
#ifndef SCENEDIALOG_H
#define SCENEDIALOG_H
#include <QDialog>
#include <QList>
namespace Ui {
class SceneDialog;
}
class SceneDialog : public QDialog
{
Q_OBJECT
public:
SceneDialog(QWidget *parent = 0);
~SceneDialog();
signals:
QString getValue();
private:
Ui::SceneDialog *ui;
QString myText;
};
scenedialog.cpp
#include "scenedialog.h"
#include "ui_scenedialog.h"
#include <QDebug>
SceneDialog::SceneDialog(QWidget *parent) :
QDialog(parent),
ui(new Ui::SceneDialog)
{
ui->setupUi(this);
myText = getValue();
qDebug() << myText; // myText is empty!!
}
You can put your list as a class member and use Qt's Signal/slot mechanism to access the list from other classes. Just make a signal in the target class, connect it to a slot in the class containing the list and make a connection between two objects of the classes. This way you can access any data member of other classes by connecting a signal to a slot returning that value and just emitting the signal and getting the return value.
For example if you have two classes like :
class A: public QObject
{
Q_OBJECT
public:
A(QObject *parent = 0);
~A();
signals:
int getValue();
private:
void someFunction()
{
int val = getValue();
}
};
class B
{
Q_OBJECT
public:
B(QObject *parent = 0);
~B();
public slots:
int getValue()
{
return someValue;
}
};
And connect the signal from an object of A to the slot in an object of B :
connect(a, SIGNAL(getValue()), b, SLOT(getValue()));
In class A you can access the value returned from getValue slot in B by just calling the signal and using the returned value.
Note that the two objects should be in the same thread for this to work. If they are in different threads then the connection type should be of type Qt::BlockingQueuedConnection :
connect(a, SIGNAL(getValue()), b, SLOT(getValue()), Qt::BlockingQueuedConnection);
Another way is two use static class members but it is not recommended unless you have a good reason to do it. If you have two classes like :
class A {
public:
static QList<int> list;
};
class B {
public:
void do_something();
};
You can access A's static data member from B like this:
void B::do_something()
{
int val = A::list[0];
...
};
Related
The common part (crating a lib) of my project currently holds a interface Class of the type:
class CanBeAddedToGroup{
public:
void addToGroup(Group& )=0;
}
Now i also wantred to use the programm on a Class containing data in a QVariant, so i started it off simple:
class DataContainingClass: public CanBeAddedToGroup{
QMap<QString,QVarient> data;
public:
void addToGroup(Group& ){
QMap<QString,QVarient>::itterator itter = data.begin();
QMap<QString,QVarient>::itterator end= data.end();
for(;itter !=end;itter ++){
<Handle Data>
}
}
};
}
Now one of the datatypes addedt to the list (outside the lib) is of the type:
class DataClass: public QObject, public CanBeAddedToGroup{
void addToGroup(Group& );
}
Q_DECLARE_METATYPE(DataClass)
And it is added to the map using "QVariant::fromValue(", now i need a way in the "DataContainingClass" to check if the Data is derived from a QObject, so i know static_cast(variant.data()) is valid.
Then i could try to dynamic_cast the Object pointer to CanBeAddedToGroup, and call it.
--- EDIT ---:
The Problem IS NOT: Having a QObject and check if it inherits another QObject, it is not even checking if a Class inherits from another one, it is to know if the data i have actually IS a QObject.
Minimal Example:
Header File:
#include <QObject>
#include <QDebug>
class DmbClass: public QObject{
Q_OBJECT
public:
DmbClass(){TST="RealOne";}
DmbClass(const DmbClass&d){TST="Clone";}
QString TST;
};
Q_DECLARE_METATYPE(DmbClass)
class Tst{
public:
virtual void tstFunct()=0;
};
class CanClass: public QObject, public Tst{
Q_OBJECT
public:
CanClass(){TST="RealOne";}
CanClass(const CanClass&d){TST="Clone";}
QString TST;
virtual void tstFunct() override{
qDebug()<<"tst";
}
};
Q_DECLARE_METATYPE(CanClass)
class DmbGadget{
Q_GADGET
public:
DmbGadget(){TST="RealOne";}
DmbGadget(const DmbGadget&d){TST="Clone";}
QString TST;
};
Q_DECLARE_METATYPE(DmbGadget)
C File:
// QObject in QVariant
DmbClass dC;
QVariant varC=QVariant::fromValue(dC);
const void* vPC = varC.data();
DmbClass dCc = varC.value<DmbClass>();
QObject* objC = (QObject*)varC.data();
QObject* schouldWork = objC->parent();
Tst* schouldBeNull = dynamic_cast<Tst*>(objC);
// Object using correct base class in QVariant
CanClass dT;
QVariant varT=QVariant::fromValue(dT);
const void* vPT = varT.data();
CanClass dTc = varC.value<CanClass>();
QObject* objT = (QObject*)varT.data();
QObject* schouldWork2 = objT->parent();
Tst* schouldNotNull = dynamic_cast<Tst*>(objT);
schouldNotNull->tstFunct();
// Q_Gadget in QVariant
DmbGadget dG;
QVariant varG=QVariant::fromValue(dG);
const void* vPG = varG.data();
DmbGadget dGg = varG.value<DmbGadget>();
QObject* objD = (QObject*)varG.data();
//QObject* schouldSegFault = objD->parent();
// base value in QVariant
QVariant var4=4;
const void* vP4 = var4.data();
QObject* obj4 = (QObject*)var4.data();
//QObject* schouldSegFault2 = obj4 ->parent();
I need a way to distinguisch cases 1&2 from 3&4 ("schouldSegFault"), without using something only defined outside of the lib.
I Already Tryed:
int tst4 = qRegisterMetaType<CanClass>("CanClass");
QMetaType help2(tst4);
But help2 has a MetaObject of 0, so i cant check for the inheriance from QObject.
Edit/for who added "Proper way to check QObject derived class type in Qt" ther was te issue in my programm that the class inherits from another QObjectclass so i cant chack for inheriance of my interface (even when defined as Q_Gadget) using inherits, since it would only be true for the first element.
PS: For everyone trying to call functions on a QVariant containing a Object rather than a pointer might be interested in this approach:
How to support comparisons for QVariant objects containing a custom type? / https://pastebin.com/tNLa0jSa
While having a global registry for types is what i wished i could avoid for the case.
Just try to use QVariant::value and see if the value in a QVariant can be converted to your target class. Here's a minimal example:
#include <QObject>
#include <QVariant>
#include <QVariantMap>
#include <QDebug>
class MyQObjectClass : public QObject {
Q_OBJECT
public:
explicit MyQObjectClass(QObject *parent = nullptr) : QObject(parent) {}
void greet() { qDebug() << "I am a MyQObjectClass!"; }
};
Q_DECLARE_METATYPE(MyQObjectClass*)
int main(int, char *[])
{
MyQObjectClass obj;
QVariantMap map;
map.insert("foo", QString("Hello World"));
map.insert("bar", QVariant::fromValue(&obj));
QVariantMap::iterator iter = map.begin();
QVariantMap::iterator end= map.end();
for(;iter !=end;iter ++) {
auto value = iter.value();
// Try to convert to MyQObjectClass*
auto obj = value.value<MyQObjectClass*>();
if (obj != nullptr) {
qDebug() << iter.key() << "is an instance of MyQObjectClass";
obj->greet();
continue;
}
qDebug() << iter.key() << "is not an instance of MyQObjectClass";
}
}
#include "main.moc"
Running it should yield the following output on the console:
"bar" is an instance of MyQObjectClass
I am a MyQObjectClass!
"foo" is not an instance of MyQObjectClass
The important parts:
Make sure the class you want to store in a QVariant derives from QObject and has the Q_OBJECT macro.
When iterating over the map, use QVariant::value() and try to convert the contained value to your target class. In the example, I use QVariant::value<MyQObjectClass*>() - according to the documentation, this either returns the contained instance of MyQObjectClass* if the value can be converted to it or - which is the case if the QVariant contains either basic values or gadgets - a default constructed value. In the case of a pointer this would be a null pointer, so just check if the value returned is null. That's it.
Never work on Qvariant::data() directly.
Update
Just as a remark: The Qobject class declared the copy constructor and assignment operators as private:
From the official documentation:
QObject has neither a copy constructor nor an assignment operator. This is by design. Actually, they are declared, but in a private section with the macro Q_DISABLE_COPY(). In fact, all Qt classes derived from QObject (direct or indirect) use this macro to declare their copy constructor and assignment operator to be private. The reasoning is found in the discussion on Identity vs Value on the Qt Object Model page.
Hence, you cannot copy around instances of QObject (and consequentially you cannot store them in QVariant). Instead, you pass around pointers to QObject instances.
Update #2
If your interface class cannot derive directly from QObject, you might consider using Qt's plugin mechanism instead. Here's the above example slightly edited to fit this approach:
#include <QObject>
#include <QVariant>
#include <QVariantMap>
#include <QDebug>
class MyInterfaceClass {
public:
MyInterfaceClass() {}
virtual ~MyInterfaceClass() {}
virtual void greet() = 0;
};
#define MyInterfaceClass_IID "org.example.MyInterfaceClass"
Q_DECLARE_INTERFACE(MyInterfaceClass, MyInterfaceClass_IID)
class MyConcreteClass : public QObject, public MyInterfaceClass {
Q_OBJECT
Q_INTERFACES(MyInterfaceClass)
public:
MyConcreteClass(QObject *parent = nullptr) : QObject(parent) {}
void greet() override { qDebug() << "I am a MyInterfaceClass!"; }
};
int main(int, char *[])
{
MyConcreteClass obj;
QVariantMap map;
map.insert("foo", QString("Hello World"));
map.insert("bar", QVariant::fromValue(&obj));
QVariantMap::iterator iter = map.begin();
QVariantMap::iterator end= map.end();
for(;iter !=end;iter ++) {
auto value = iter.value();
// Try to convert to QObject*:
auto obj = value.value<QObject*>();
if (obj != nullptr) {
// Try if we can cast to our interface class:
auto ifc = qobject_cast<MyInterfaceClass*>(obj);
if (ifc != nullptr) {
qDebug() << iter.key() << "is an instance of MyInterfaceClass";
ifc->greet();
}
continue;
}
qDebug() << iter.key() << "is not an instance of MyInterfaceClass";
}
}
#include "main.moc"
You need to:
Define your interface class and register it with Qt using the Q_DECLARE_INTERFACE macro.
Declare your concrete classes, deriving from QObject and your interface class. In addition, you need to tell Qt about the interface part using the Q_INTERFACES macro.
When checking the values in your map, first try to convert to a QObject* via QVariant::value(). If this succeeds, you can try to qobject_cast to your interface class.
Your design is completely broken: QObjects cannot be used as unrestricted values. They cannot be copied nor moved, and your implementations of copy constructors are hiding this fundamental fact.
I have two simple classes(class A and class B).
In a.h, I just declared a QPushButton:
QPushButton *testBtn = new QPushButton(this);
In b.h:
class B : public QMainWindow
{
Q_OBJECT
public:
explicit B(QWidget *parent = nullptr);
A testingA;
public slots:
void testing();
};
and b.cpp:
B::B(QWidget *parent) : QMainWindow(parent)
{
connect(testingA.testBtn, &QPushButton::clicked, this, &B::testing);
}
void B::testing()
{
qDebug() << "testing";
}
I am trying to connect the signal in class A to the slot in class B, but from the code I provide, it's not working.
So what is the right way to do it? Thanks
Edit:
According to PRIME's answer, I made a few changes.
In A's constructor, added:
connect(testBtn, &QPushButton::clicked, [this](){OnButtonClicked();});
to emit the own defined OnButtonClicked() signal;
and in B's construtor, changed to this:
connect(&testingA, &A::OnButtonClicked, this, &B::testing);
But when I clicked the button, the testing slot still not triggered.
Edit 2:
After doing some researches and trying a few times, I found that if I created B's object in A's constructor, and then connect A's signal to B's slot in A, it will work.
But I really can not figure out why I can not connect A's signal to B's slot in B.
This is what's in the main.cpp:
int main(int argc, char *argv[])
{
QApplication a(argc, argv);
B b;
A w;
w.show();
return a.exec();
}
Is that because of some reasons that A's object is out of scope in B?
Can someone tell me where I did wrong? Thanks so much.
Don't do it like this, hide your button in the class A, emit your own defined signal from class A lets call it OnButtonClicked.
Cascading code(inside A's c'tor):
connect(testBtn , &QPushButton::clicked, [this](){OnButtonClicked();});
You will also have to declare this new signal in class A now:
So class A must have folowing besides whatever it has right now:
class A
{
Q_OBJECT
signals:
void OnButtonClicked();
};
No special slot is needed since you are using a Lambda as a slot for the signal OnButtonClicked.
Connection in class B( do it in the c'tor ):
connect(testingA, &A::OnButtonClicked, this, &B::testing);
You can connect signal-to-signal in your sender object, for example widget containing the button:
class MyWidget : public QWidget
{
Q_OBJECT
QPushButton *pushButton;
public:
explicit MyWidget(QWidget *parent = nullptr) : QWidget(parent), pushButton(new QPushButton(this)) {
connect(pushButton, &QPushButton::click, this, &MyWidget::buttonClicked);
}
signals:
void buttonClicked();
public slots:
};
By the way you would normally send signals by using emit keyword, e.g.:
emit buttonClicked();
Then the consumer:
class TestObject : public QObject
{
Q_OBJECT
public:
explicit TestObject(QObject *parent = nullptr) : QObject(parent) { }
public slots:
void onButtonClicked() {
qDebug() << "clicked";
}
};
And connect both instances:
MyWidget widget;
TestObject to;
QObject::connect(&widget, &MyWidget::buttonClicked, &to, &TestObject::onButtonClicked);
in your class A you should use the signal testing of the class B, if you clicked on your button the OnButtonClicked function will be activated
A:
public slots:
void OnButtonClicked();
void A::OnButtonClicked()
{
...
emit testing(1);
}
B:
signals:
void testing(int level);
then to connect both you can do this
connect(startButton, &QPushButton::clicked, board, &A::OnButtonClicked);
I want to connect some object's signals derived from an interface class.
The connection is done in QWidget::listenToAnimal(AnimalInterface*).
This does not work because qt_metacall is not a member of 'AnimalInterface' and static assertion failed: No Q_OBJECT in the class with the signal.
Of course AnimalInterface does not have the Q_OBJECT macro and does not inherit QObject because it is an interface...
I want to connect through the interface class because I do not want to manually retype the same code for Cat and for Dog.
Is it possible to connect the signal the way I want to? Perhaps with templates? Is this perhaps a lambda-specific problem?
header:
#ifndef WIDGET_H
#define WIDGET_H
#include <QWidget>
class AnimalInterface{
public:
virtual ~AnimalInterface();
virtual void makeSound() = 0;
/*signals*/
virtual void madeSound() = 0;
};
Q_DECLARE_INTERFACE(AnimalInterface,"interface")
class Dog : public QObject, public AnimalInterface
{
Q_OBJECT
Q_INTERFACES(AnimalInterface)
public:
void makeSound();
signals:
void madeSound();
};
class Cat : public QObject, public AnimalInterface
{
Q_OBJECT
Q_INTERFACES(AnimalInterface)
public:
void makeSound();
signals:
void madeSound();
};
class Widget : public QWidget
{
Q_OBJECT
Cat *cat_;
Dog *dog_;
public:
Widget(QWidget *parent = 0);
~Widget();
void listenToAnimal(AnimalInterface *animal);
};
#endif // WIDGET_H
cpp:
#include "widget.h"
#include <QDebug>
Widget::Widget(QWidget *parent)
: QWidget(parent)
{
dog_ = new Dog;
cat_ = new Cat;
listenToAnimal(dog_);
listenToAnimal(cat_);
dog_->makeSound();
cat_->makeSound();
}
void Widget::listenToAnimal(AnimalInterface *animal)
{
connect(animal, &AnimalInterface::madeSound,
this,
[](){
qDebug()<<"animal made sound";
});
}
Widget::~Widget()
{
}
void Cat::makeSound()
{
qDebug()<<"Cat says miaow";
emit madeSound();
}
void Dog::makeSound()
{
qDebug()<<"Dog says wuff";
emit madeSound();
}
main.cpp
#include "widget.h"
#include <QApplication>
int main(int argc, char *argv[])
{
QApplication a(argc, argv);
Widget w;
w.show();
return a.exec();
}
Since you know the derived type at compile type, you can connect to the proper, statically-known QObject-derived type. No need for dynamic casting or anything of the sort. You just don't want the listenToAnimal method to be available for non-AnimalInterface-inheriting types, though, even if it they have a compatible madeSound method:
C++11
#include <type_traits>
template< class T,
typename =
typename std::enable_if<std::is_base_of<AnimalInterface, T>::value>::type >
void listenToAnimal(T * animal) {
connect(animal, &T::madeSound, this, []{ qDebug() << "animal made sound"; });
}
C++03
template <class T>
void listenToAnimal(T * animal) {
Q_UNUSED(static_cast<AnimalInterface*>(animal));
connect(animal, &T::madeSound, this, &Widget::onAnimalMadeSound);
}
You can then use it without having to spell out the type - it's already known to the compiler:
listenToAnimal(dog_);
listenToAnimal(cat_);
If the derived type is not known at compile time, you have to dynamically cast to QObject and connect by name, not by method pointer. It will assert at runtime if you've passed in a wrong type - after all, it's not enough for it to be an instance of AnimalInterface, it also needs to be a QObject instance.
void listenToAnimal(AnimalInterface * animal) {
auto object = dynamic_cast<QObject*>(animal);
Q_ASSERT(object);
connect(object, SIGNAL(madeSound()), this, SLOT(onAnimalMadeSound()));
}
The fact that the type AnimalInterface has a virtual madeSound method is somewhat relevant - it guarantees that the derived class implements the method with such a signature. It doesn't guarantee that the method is a signal, though. So you should probably rethink your design and ask yourself: "What do I gain by using a static type system when I can't really use it for static type checking"?
Most likely you should make any methods that would nominally accept the AnimalInterface*, be parametrized and take a pointer to the concrete class. Modern code generators and linkers will deduplicate such code if type erasure leads to identical machine code.
Found a solution with templates. Did not work the first time I tried, obviously did something wrong first. Here it goes...
Just replace the corresponding parts from the example in the question (and remove definition of listenToAnimal from the source file):
header:
template<class T>
void listenToAnimal(AnimalInterface *animal)
{
T *animal_derivate = dynamic_cast<T*>(animal);
if (animal_derivate){
connect(animal_derivate, &T::madeSound,
this,
[](){
qDebug()<<"animal made sound";
});
}
}
cpp:
listenToAnimal<Dog>(dog_);
listenToAnimal<Cat>(cat_);
Update:
After trying Kuba Ober's answer, it seems like this is working best now:
template<typename T>
typename std::enable_if<std::is_base_of<AnimalInterface, T>::value,void>::type
listenToAnimal(T *animal)
{
connect(animal, &T::madeSound, this, [](){ qDebug()<<"animal made sound"; });
}
However, the one point still not working is how to connect if I create an animal like AnimalInterface *bird = new Bird, because it throws the same error that the base class does not have the signal.
I have following very simple Qt project:
I have
#ifndef ABSTRACTWIDGET_H
#define ABSTRACTWIDGET_H
#include <QWidget>
#include <QVariant>
namespace Ui {
class AbstractWidget;
}
class AbstractWidget : public QWidget
{
Q_OBJECT
public:
explicit AbstractWidget(const QString &name, QWidget *parent = 0);
~AbstractWidget();
QString getName();
virtual void setValue(const QVariant & value);
protected:
Ui::AbstractWidget *ui;
};
#endif // ABSTRACTWIDGET_H
and
#ifndef SLIDERWIDGET_H
#define SLIDERWIDGET_H
#include "abstractwidget.h"
#include <QSlider>
class SliderWidget : public AbstractWidget
{
Q_OBJECT
public:
explicit SliderWidget(const QString & name, int min, int max, QWidget *parent = 0);
~SliderWidget();
void setValue(const QVariant & value);
private:
QSlider * slider;
};
#endif // SLIDERWIDGET_H
I just made setValue virtual at the super class Abstractwidget, which drops follwing linker error:
moc_abstractwidget.cpp:-1: Fehler: undefined reference to
`AbstractWidget::setValue(QVariant const&)'
collect2.exe:-1: Fehler: error: ld returned 1 exit status
Rebuilding All and Cleaning up did not help. Why is it failing to link?
Abstract is a bad nomencalture, sorry my bad. Consider it as a super class (not abstract) from which I derive other classes.
I inject in a MainWindow::Ui::QVBoxLayout dynamically those AbstractWidget classes (for instance I have multiple SliderWidgets and ColorPickerWidget : public Abstractwidget as well). I just wanted to keep it simple.
Why derive? I have multiple QWidgets (besides SliderWidget) deriving from AbstractWidget class. All of them have a QString name. I wanted to provide that name in the base class ==> AbstractWidget.
Why virtual void setValue(): Every derived class has somesting like a slider, colorpicker etc. I implement in each derived class a setValue(QVariant) so that the colorpicker sets the QColor(QVariant::toString()) and the SliderWidget sets the sliderValue with setValue(QVariant::toInt()), etc..
setValue is public everywhere (virtual base class and derived implementations).
I have a little problem with the Qt class QGraphicsScene:
To detect the current mouse coordinates I made a new class QGraphicsScenePlus with QGraphicsScene as the base class. I have already redefined the slot function mouseMoveEvent(QGraphicsSceneMouseEvent* event) and the received coordinates seem to be correct. Now I want to notify the parent QMainWindow class, where the QGraphicsScenePlus object is stored, whenever the mouse coordinates change. What is the best way to do this? I already tried to define signals and slots, but it didn't work. The slot function wasn't found during the execution of the program.
Here is the code so far:
qgraphicssceneplus.h
#ifndef QGRAPHICSSCENEPLUS_H
#define QGRAPHICSSCENEPLUS_H
#include <QObject>
#include <QGraphicsScene>
#include <QGraphicsSceneMouseEvent>
class QGraphicsScenePlus : public QGraphicsScene {
public:
QGraphicsScenePlus(QObject* parent = 0);
public slots:
void mouseMoveEvent(QGraphicsSceneMouseEvent* event);
public:
int mx = 0;
int my = 0;
};
#endif // QGRAPHICSSCENEPLUS_H
qgraphicssceneplus.cpp
#include "qgraphicssceneplus.h"
QGraphicsScenePlus::QGraphicsScenePlus(QObject* parent) : QGraphicsScene(parent) {
}
void QGraphicsScenePlus::mouseMoveEvent(QGraphicsSceneMouseEvent* mouseEvent) {
mx = mouseEvent->scenePos().x();
my = mouseEvent->scenePos().y();
this->update();
}
Comment
I am not sure how you made the above code compiled.
1. Even though you subclass from a QObject, you still need the Q_OBJECT macro to keep meta-object compiler informed:
class QGraphicsScenePlus : public QGraphicsScene {
Q_OBJECT // <--- You miss this
public:
QGraphicsScenePlus(QObject* parent = 0);
2. It's not allowed to assign primitive value in C++ class definition, do it in the constructor instead:
public:
int mx /*= 0*/;
int my /*= 0*/;
};
Solution
As for your question:
What is the best way to do this? I already tried to define signals and slots, but it didn't work.
The best way is still Signals & Slots.
Code
qgraphicssceneplus.h
class QGraphicsScenePlus : public QGraphicsScene {
Q_OBJECT
public:
QGraphicsScenePlus(QObject* parent = 0);
public slots:
void mouseMoveEvent(QGraphicsSceneMouseEvent* event);
signals:
void sendCoord(int,int); // for sending the information of coordinates
public:
int mx;
int my;
};
qgraphicssceneplus.cpp
QGraphicsScenePlus::QGraphicsScenePlus(QObject* parent) : QGraphicsScene(parent) {
mx = 0;
my = 0;
}
void QGraphicsScenePlus::mouseMoveEvent(QGraphicsSceneMouseEvent* mouseEvent) {
mx = mouseEvent->scenePos().x();
my = mouseEvent->scenePos().y();
emit sendCoord(mx, my); // emit the signal
this->update();
}
To catch the signal, define the slot in QMainWindow. For example:
public slots:
void receiveCoord(int x, int y);
and connect it to the signal of your graphic scene.
Demo