I am having a complete .aspx page which contains header,footer,textbox,tables everything. Values in these all fields come from code behind .cs file.
For different set of data i am generating different .aspx page file in tabs. so that user can take print of it.
i was doing something like this to open multiple tabs
var cust_prop_id = $('#hdnPropertyNo').val().split(',');
$.each(cust_prop_id, function (i, val) {
var myWindow = window.open('UserInfo.aspx?Prop=' + val, '', '');
});
PROBLEM STATEMENT
All of sudden client said user wont go to each tab and say "Print".
Instead generated all .aspx one below other in single tab. so in one single click user can able to print all generated .aspx files
What is the best way to do it ?
You can do this in many ways here are two most common.
Method 1
Create user control for each page which you want to be printed add these user controls in the page where user will print the page.Load each user control in separate div and place in main container and at print time get css of container div which will include all data.
Method 2
Create div for each page which you were opening in new window in a main container .Load data in divs at page load and when user press Print get all html of container div and print it.
Related
So I would like to be able to have a print button for entries in our database so users can print an entry via a print friendly "form".
My thought was to create a separate page, add labels and have those labels pull the relevant information.
I know I can add the open widget information via this code:
app.datasources.ModelName.selectKey(widget.datasource.item._key);
app.showPage(app.pages.TestPrint);
But I'm running into a few problems:
I can't get the page to open in a new window. Is this possible?
window.open(app.pages.TestPrint);
Just gives me a blank page. Does the browser lose the widget source once the new window opens?
I can't get the print option (either onClick or onDataLoad) to print JUST the image (or widget). I run
window.print();
And it includes headers + scroll bars. Do I need to be running a client side script instead?
Any help would be appreciated. Thank you!
To get exactly what you'd want you'd have to do a lot of work.
Here is my suggested, simpler answer:
Don't open up a new tab. If you use showPage like you mention, and provide a "back" button on the page to go back to where you were, you'll get pretty much everything you need. If you don't want the back to show up when you print, then you can setVisibility(false) on the button before you print, then print, then setVisibility(true).
I'll give a quick summary of how you could do this with a new tab, but it's pretty involved so I can't go into details without trying it myself. The basic idea, is you want to open the page with a full URL, just like a user was navigating to it.
You can use #TestPrint to indicate which page you want to load. You also need the URL of your application, which as far as I can remember is only available in a server-side script using the Apps Script method: ScriptApp.getService().getUrl(). On top of this, you'll probably need to pass in the key so that your page knows what data to load.
So given this, you need to assemble a url by calling a server script, then appending the key property to it. In the end you want a url something like:
https://www.script.google.com/yourappaddress#TestPage?key=keyOfYourModel.
Then on TestPage you need to read the key, and load data for that key. (You can read the key using google.script.url).
Alternatively, I think there are some tricks you can play by opening a blank window and then writing directly to its DOM, but I've never tried that, and since Apps Script runs inside an iframe I'm not sure if it's possible. If I get a chance I'll play with it and update this answer, but for your own reference you could look here: create html page and print to new tab in javascript
I'm imagining something like that, except that your page an write it's html content. Something like:
var winPrint = window.open('', '_blank', 'left=0,top=0,width=800,height=600,toolbar=0,scrollbars=0,status=0');
winPrint.document.write(app.pages.TestPage.getElement().innerHTML);
winPrint.document.close();
winPrint.focus();
winPrint.print();
winPrint.close();
Hope one of those three options helps :)
So here is what I ended up doing. It isn't elegant, but it works.
I added a Print Button to a Page Fragment that pops up when a user edits a database entry.
Database Edit Button code:
app.datasources.ModelName.selectKey(widget.datasource.item._key);
app.showDialog(app.pageFragments.FragmentName);
That Print Button goes to a different (full) Page and closes the Fragment.
Print Button Code:
app.datasources.ModelName.selectKey(widget.datasource.item._key);
app.showPage(app.pages.ModelName_Print);
app.closeDialog();
I made sure to make the new Print Page was small enough so that Chrome fits it properly into a 8.5 x 11" page (728x975).
I then created a Panel that fills the page and populated the page with Labels
#datasource.item.FieldName
I then put the following into the onDataLoad for the Panel
window.print();
So now when the user presses the Print Button in the Fragment they are taken to this new page and after the data loads they automatically get a print dialog.
The only downside is that after printing the user has to use a back button I added to return to the database page.
1.
As far as I know, you cannot combine window.open with app.pages.*, because
window.open would require url parameter at least, while app.pages.* is essentially an internal routing mechanism provided by App Maker, and it returns page object back, suitable for for switching between pages, or opening dialogs.
2.
You would probably need to style your page first, so like it includes things you would like to have printed out. To do so please use #media print
ex: We have a button on the page and would like to hide it from print page
#media print {
.app-NewPage-Button1 {
display : none;
}
}
Hope it helps.
1. Here is how it is done, in a pop up window, without messing up the current page (client script):
function print(widget, title){
var content=widget.getElement().innerHTML;
var win = window.open('', 'printWindow', 'height=600,width=800');
win.document.write('<head><title>'+title+'/title></head>');
win.document.write('<body>'+content+'</body>');
win.document.close();
win.focus();
win.print();
win.close();
}
and the onclick handler for the button is:
print(widget.root.descendants.PageFragment1, 'test');
In this example, PageFragment1 is a page fragment on the current page, hidden by adding a style with namehidden with definition .hidden{display:none;} (this is different than visible which in App Maker seems to remove the item from the DOM). Works perfectly...
2. You cannot open pages from the app in another tab. In principle something like this would do it:
var w=window.parent.parent;
w.open(w.location.protocol+'//'+w.location.host+w.location.pathname+'#PrintPage', '_blank');
But since the app is running in frame nested two deep from the launching page, and with a different origin, you will not be able to access the url that you need (the above code results in a cross origin frame access error). So you would have to hard code the URL, which changes at deployment, so it gets ugly very fast. Not that you want to anyway, the load time of an app should discourage you from wanting to do that anyway.
Within my default.ctp page I keep navigational and structural content applicable to the entire application. For example menu structures and a column based CSS. I would like to change my login page, however, to look entirely different (no menu, no columns, etc)
Is there a way to load a separate ctp file for a single URL only? e.g. /plugin/controller/login
http://book.cakephp.org/2.0/en/views.html
You can create a new layout for the login page and for that controller/action change the layout name
$this->layout = 'login';
There are two ways. First, you create your new layout file, à la login.ctp inside your View/Layout folder.
Next, in your login action, at the top you can write $this->layout = "login";. The other way you can do it is when you render the view, at the end of your action method, like this: $this->render('actionName', 'login');
I have a problem which I can't find a solution. I have a Parent page calling dynamically a default user control ( 6 different UC based on a selected item Combo X on the parent page). Within the UC, i inject (registerClientscript) a javascript which controls visibility within the UC based on a combo box. All UC has the same combo but the controls within this UC can vary.
The problem i am having is that on first load, the JS is generated correctly... but on change of Combo X from the parent, i trigger a partial refresh of the UC, which in turn re-register a new JS.
function DefineView(sender, eventArgs) {
var comboSearch = $find('%%cmbSearchType%%');
//cmbSearch Section
switch (comboSearch.get_selectedItem().get_value()) {
[[MY CODE HERE]
}
}
ScriptManager.RegisterClientScriptBlock(this, this.GetType(), "SearchVisibilityPPSA",jsFunction.Replace("%%cmbSearchType%%", cmbSearchType.ClientID),true);
As you can see, I replace the ClientID, and on first load of the page, this is resolved correctly like ctl00_PrincipalPlaceHolder_ctl00_cmbSearchType but when I change Combo X, it reloads the user control, which in turn reload the script above. In the rendered HTML, The COmbo ID is renamed to ctl00_PrincipalPlaceHolder_ctl01_cmbSearchType (Note the subtle change in name from ct00 to ct01 ) In my debug, I saw this ClientID contain the new ID but somehow it is not replaced regenrated on the rendered html.
I guess my question is how do i force the JS to be re-rendered every time this UC is called? For some reason, it is always using the original rendered JS ( which is why it is working the first time)
I think this is related to my dynamic control i was generating without assigining any id ... by forcing the id attribute, it kept it the same...
I dynamically add rows to divStaff using jquery:
$("span[id$='lblAddStaff']").click(function() {
//$(".staff_tpl").find("input[id$='txtRate']").val("0,00");
var staff_row = $(".staff_tpl");
staff_row.find(".staff_row").attr("id", "Emp" + counter);
$("div[id$='divStaff']").append(staff_row.html());
counter += 1;
});
the row that I'm adding is inside the hidden div with class=".staff_tpl"
I append the contents of this div to divStaff
When I submit the page (postback), the resulting divStaff is always empty if I try to display it like this:
lblTest.Text = divStaff.innerHtml.ToString
basically, I'm manipulating a div client side, and I want to access it server side via the code-behind of my aspx page. I think I'm missing a basic principle here.
This cannot be done.
If you want to access data you've created pn the page, you have to place it inside input fields (possibly hidden), and access it after it was posted using Request.Form["MyHiddenFieldName"].
<div>s aren't posted to the server. runat="server" elements are enechoded in the ViewState (a big string, really - you can see it in the source of your page), giving the abstraction of continuity (or the illusion of it). However, that sting isn't aware of changes you make in the DOM.
When dealing with runat="server" elements, you will see the last changes you've made on the server side, but client side changes are gone.
Only <input> (and text area, option, etc) values are posted to the server on submit, so changing these on the client will be seen on the server, after the page was posted.
Is there an accepted way to "move" a control.
My client wants to place a certain chunk of markup (representing some visual element) in one of several different places on the page. The locations are different to the point that I can't effect the change on CSS along (by floating it or something).
I considered just putting the control in multiple spots with Visible set to "false," then displaying the one in the place they wanted for that particular page.
However, the code for this control is not trivial -- there's a couple template sections, for instance. Having to dupe this in multiple places would get unwieldy. Also, I don't want to have to work with this control strictly from the code-behind for the same reason.
So, I'd like to put it in one place on the Web form, the move it around based on where I want it. Could I put Placeholders in different spots, have the control in one spot, then remove and add it to the right spot? I suspect this would work.
Does someone have a better idea? Is there a best practice for this?
I'd recommend using a placeholder control, moving your markup into a separate user control, then loading this at runtime and adding it to the relevant placeholder.
Eg.
// Load a user control
MyControl userCtrl = (MyControl) LoadControl("~/Controls/MyControl.ascx");
// Or create an instance of your control
SubclassedControl subclassedCtrl = new SubclassedControl();
// Do stuff with controls here
userCtrl.LoadData();
subclassedCtrl.Text = "Hello World";
// Check which placeholder to add controls to
PlaceHolder placeHolder = (foo=="bar") ? placeHolder1 : placeHolder2;
// Add the controls
placeHolder.Controls.Add(userCtrl);
placeHolder.Controls.Add(subclassedCtrl);
This will avoid cluttering up your page with unnecessary markup, and loading it at runtime will also avoid unnecessary confusion later, when another developer looks at the code and can't immediately see why a control is in one place in the markup, but renders on a completely different part of the page.
An alternative (and one I've seen done many times before) is through javascript and the DOM. Render your control inside a hidden div tag. So you would render your content here:
<div id='rendercontent' style='display:none'>
.. control here ..
</div>
Then, lets say you wanted to move it all here (the span tag is inside because that's what we're going to replace):
<div id='newlocation1'><span></span></div>
You would define the following javascript:
<script language="JavaScript">
function replaceNode(newElementID, targetElementID)
{
var targetElement=document.getElementById(targetElementID);
var newElement=document.getElementById(newElementID);
targetElement.replaceChild(newElement, targetElement.firstChild);
}
</script>
And when you want to move the content to the new location, call:
<script language="JavaScript">
replaceNode('rendercontent','newlocation1');
</script>
Do Web Parts do what you want to do?
Or, you can change the parent programmatically of your controls to move them into a separate area.
You can override the Render method and place the controls wherever you want in the html.
You only need to add controls to the Controls collection that must interact on the server. The rest of your HTML can just be written to the response stream. If you override Render you can create the html anyway you see fit, placing the controls in any order.
Below is an example of how to write out your html.
protected override void Render(HtmlTextWriter writer)
{
AddAttributesToRender(writer);
writer.RenderBeginTag(TagKey);
writer.RenderBeginTag(HtmlTextWriterTag.Div);
_control.RenderControl(writer);
writer.RenderEndTag();
writer.RenderEndTag();
}
You could always put panels in the pre-defined locations and add the control to the specific panel at runtime.. Here's an example adding a label (the label could be replaced with any control).
Dim lblDisplay As Label = New Label()
lblDisplay.ID = "myLabel"
lblDisplay.Text = "Some Text"
pnlDisplay.Controls.Add(lblDisplay)
As far as...
"Also, I don't want to have to work
with this control strictly from the
code-behind for the same reason."
I think you're going to have to do most of your work in the code behind.
PS.. a good example of the whole usercontrol setup can be downloaded here..
http://www.asp.net/downloads/starter-kits/time-tracker/