I have a sample table with following values
SNO | Mon
-----+-------
100 | 1
101 | 1
102 | 1
100 | 2
101 | 2
102 | 2
100 | 3
101 | 3
Now I need a query to count the total sno's which are in 3 months
The result should be 2, as 100 & 101 are in mon 1,2 and 3. However, 102 is only present in mon 1,2.
Thanks,
RK
This Query in theory should work.
SELECT
tmpTbl.sNo
FROM
tmpTbl
GROUP BY
tmpTbl.sNo
HAVING
Count(tmpTbl.monNo) = (SELECT Count(*) FROM (SELECT tmpTbl.monNo FROM tmpTbl GROUP BY tmpTbl.monNo));
The result would be,
sNo
----
100
101
I have used two SubQueries to get the result. Teh both are used in the HAVING clause of the SQL. First SqubQuery (inner most). Will get the number of Unique Month's available in your table, the outer SubQuery will then Count the number of Unique months. So the Overall Query can be translated as "SELECT the serial number FROM the table HAVING the Count of Month equal to the Number of unique records in the same table".
The reason I used SbQuery instead of a number is because of the fact this will also be applicable when your month number increases. Hope this helps !
EDIT
Here is the Query for getting the count.
SELECT
Count(*) As simpleCount
FROM
(
SELECT
tmpTbl.sNo
FROM
tmpTbl
GROUP BY
tmpTbl.sNo
HAVING
Count(tmpTbl.monNo) = (SELECT Count(*) FROM (SELECT tmpTbl.monNo FROM tmpTbl GROUP BY tmpTbl.monNo))
);
Related
I have the query
select d.did, count ( h.did ), unique_interested
from dealer as d
left outer join house as h
on h.did = d.did
left outer join (
-- cid = customer id
select hid, count (cid) as unique_interested
from is_interested
group by hid
) as ok
on h.hid = ok.hid
group by d.did
order by d.did asc
;
which is supposed to select the number of houses that each dealer is dealing, and the number of unique customers interested in said houses (as in the number of customers per dealer). This should happen even if the dealers have no houses to deal at the moment, which is why I'm using left outer joins when constructing the table the columns will be picked from.
Now, running this query against my database produces the following output:
d.did count ( h.did) unique_interested
----- -------------- ----------------
1 3
2 3 1
3 0
As you can see, instead of printing 0 in the last column, count returns null, when there is a null in one of the aparments produced by the last part of the join (as in cid is null):
select hid, count ( cid ) as unique_interested
from is_interested
group by hid
I know this is because there are apartments in the table produced by from, that no-one is interested in. But shouldn't count produce 0 instead of the actual column value null in every case?
Any explanation as to why this is happening would be appreciated, as it would lead me towards an answer to another question, which is "Why am I not getting the right number of unique interested customers per dealer from the table is_interested?", as with the current state of my database, the output should look more like:
d.did count ( h.did) unique_interested
----- -------------- ----------------
1 3 2
2 3 2
3 0 0
Below is the link of my previous quetsion.
Retain values till there is a change in value in Teradata
It worked as suggested by one of the community members #Dnoeth. Can this retention be done only for certain section of data?
I.e, Retain data only for data where Dep is A or B . When Dep is C just use same value as input and no need to retain till certain value.
Data:
Cust_id Balance st_ts Dep
123 1000 27MAY2018 A
123 350 31MAY2018 A
256 2000 29MAY2018 B
345 1000 28APR2018 C
345 1200 26MAY2018 C
Output reqd:
Cust_id Balance st_ts Dep
123 1000 27MAY2018 A
123 1000 28MAY2018 A
123 1000 29MAY2018 A
123 1000 30MAY2018 A
123 350 31MAY2018 A
256 2000 29MAY2018 B
256 2000 30MAY2018 B
256 2000 31MAY2018 B
345 1000 28APR2018 C
345 1200 26MAY2018 C
Query used:
Wth cte
{
SELECT customer_id, bal, st_ts,
-- return the next row's date
Coalesce(Min(st_ts)
Over (PARTITION BY customer_id
ORDER BY st_ts
ROWS BETWEEN 1 Following AND 1 Following)
,Date '2018-06-01') AS next_Txn_dt
FROM BAL_DET;
}
SELECT customer_id, bal
,Last(pd) -- last day of the period
FROM cTE
-- make a period of the current and next row's date
-- and return one row per day
EXPAND ON PERIOD(ST_TS, next_Txn_dt) AS pd;
Thanks
Sandy
You can add a CASE to check for Dep = 'C':
WITH cte AS
( SELECT customer_id, bal, st_ts, dep,
-- return the next row's date
CASE
WHEN dep = 'C'
THEN st_ts +1 -- simply increase date
ELSE
Coalesce(Min(st_ts)
Over (PARTITION BY customer_id
ORDER BY st_ts
ROWS BETWEEN 1 Following AND 1 Following)
,DATE '2018-06-01')
END AS next_Txn_dt
FROM BAL_DET
)
SELECT customer_id, bal
,Last(pd) -- last day of the period
,dep
FROM cTE
-- make a period of the current and next row's date
-- and return one row per day
EXPAND ON PERIOD(ST_TS, next_Txn_dt) AS pd
I have the following table:
date | id
-----------|------
unixtime_1 | 2
unixtime_1 | 7
unixtime_1 | 9
unixtime_1 | 24
unixtime_1 | 29
unixtime_1 | 21
unixtime_2 | 8
So far I get the results from such a table doing so:
SELECT date, id FROM table ORDER BY date DESC, id ASC
and I get
unixtime_1 | 2
unixtime_1 | 7
unixtime_1 | 9
unixtime_1 | 21
unixtime_1 | 24
unixtime_1 | 29
unixtime_2 | 8
I was wondering whether I could LIMIT the result so that in the range id=1-10 id=11-20 and id=21-30 I could get in the result only the record with the higher id.
So:
unixtime_1 | 9
unixtime_1 | 29
Since for id range=11-20 there isn't any record, it should be skip the range.
The range now are 1-10, 11-20, 21-30 but are custom ranges set by me according to the user request so I should be able to change them.
Is that possible via query?
Thank you
Your latest requirement should be possible to achieve merely by grouping by the date and (id - 1) / <some_number>, where in your example <some_number> would be 10.
SELECT t1.*
FROM yourTable t1
INNER JOIN
(
SELECT date, (id - 1) / 10 AS id_grp, MAX(id) AS max_id
FROM yourTable
GROUP BY date, (id - 1) / 10
) t2
ON t1.date = t2.date AND t1.id = t2.max_id
ORDER BY
t1.date, t1.id;
You may choose any range you want 1 - num by simply replacing 10 in my query with the end of the range.
If i did understand correctly and if your range is id=1-3
you could simply do:
SELECT id, date FROM table WHERE id>=1 AND id<=3 ORDER by id DESC, date DESC limit 1;
this will give you only 1 record with the highest id in the range id=1-3.
you can store it and perform another query for another range and combine them later
Try this:
SELECT date, MAX(ID) FROM table GROUP BY date
How can I create a column that has ranked the information of the table based on two or three keys?
For example, in this table the rank variable is based on Department and Name:
Dep | Name | Rank
----+------+------
1 | Jeff | 1
1 | Jeff | 2
1 | Paul | 1
2 | Nick | 1
2 | Nick | 2
I have found this solution but it's in SQL and I don't think it applies to my case as all information is in one table and the responses seem to SELECT and JOIN combine information from different tables.
Thank you in advance
You can count how many rows come before the current row in the current group:
UPDATE MyTable
SET Rank = (SELECT COUNT(*)
FROM MyTable AS T2
WHERE T2.Dep = MyTable.Dep
AND T2.Name = MyTable.Name
AND T2.rowid <= MyTable.rowid);
(The rowid column is used to differentiate between otherwise identical rows. Use the primary key, if you have one.)
my tables
DESC emp
Name Null Type
------------------------------ -------- --------------------------
EMP_NO NUMBER
EMP_NAME VARCHAR2(10)
ADDRESS VARCHAR2(15)
PH_NO NUMBER(10)
DEPT_NO NUMBER
result:
1 ram ctr 8892939927 100
2 mohan ptr 7569936347 101
3 mallu ppt 9553438342 102
4 scoot dmc 9874563210 103
5 jim plr 9236548875 104
6 ravi tpt 8562398756 105
7 manju hyd 7562398742 106
8 manoj hyd 869523654 107
9 sarath ctr 9632158769 108
10 hemanth mpk 9632147852 109
desc salary
Name Null Type
------------------------------ -------- --------------------------
EMP_NO NUMBER
SALARY NUMBER(10)
PERIOD VARCHAR2(10)
START_DATE DATE
END_DATE DATE
result:
1 12580 15months 12-DEC-07 10-DEC-10
2 15500 19months 10-JAN-07 10-DEC-11
3 7777 18months 11-JUL-07 21-APR-11
4 9999 11months 07-JUL-07 31-JAN-11
5 8500 9months 12-MAR-07 27-MAR-11
6 10000 20months 17-SEP-07 01-AUG-11
7 25000 7months 17-NOV-07 26-JUL-11
8 100000 6months 05-MAY-07 21-JUN-11
9 35000 16months 28-FEB-08 21-JUN-11
10 5000 16months 02-DEC-08 19-AUG-11
joinning query :
select emp_no,
emp_name,
dpt_no,
salary
from emp
join salary on emp.dpt_no=salary.dpt_no
but am getting error is"column is amguously defined". How to resolve this problem?
You need to fully qualify the columns in the select list (the way it's done in the JOIN condition). Otherwise Oracle wouldn't know from which table the column dept_no should be taken.
select emp.emp_no,
emp.emp_name,
emp.dpt_no,
salary.salary
from emp
join salary on emp.dpt_no=salary.dpt_no;
It's good coding style to always qualify the columns - at least in a query involving more than one table - even if they are not ambigous.
If you don't want to type the full table name, you can use a (maningful) alias:
select emp.emp_no,
emp.emp_name,
emp.dpt_no,
sal.salary,
sal.period
from emp
join salary sal
on emp.dpt_no = sal.dpt_no;
If the columnname is the same in tables (salary and emp) and youre joining the tables, you have to specify form wich table you want to selecte the column (salary or from emp)
in youre case the solution is to use salary.dpt_no instead of dpt_no
select emp_no,emp_name, salary.dpt_no,salary from emp join salary on emp.dpt_no=salary.dpt_no