Mocking a GuzzleHttp response - phpunit

Question

How should I mock a Guzzle response properly. When testing a parser I'm writing, the test html is contained in files. In my PHPUnit tests I'm doing file_read_contents and passing the result into my method. Occasionally the HTML will link to a seperate file. I can mock this response like so:
public function testAlgo()
{
$mock = new MockAdapter(function() {
$mockhtml = file_get_contents($this->dir . '/HTML/authorship-test-cases/h-card_with_u-url_that_is_also_rel-me.html');
$stream = Stream\create($mockhtml);
return new Response(200, array(), $stream);
});
$html = file_get_contents($this->dir . '/HTML/authorship-test-cases/h-entry_with_rel-author_pointing_to_h-card_with_u-url_that_is_also_rel-me.html');
$parser = new Parser();
$parser->parse($html, $adaptor = $mock);
Then in my actual method, when I make the guzzle request this code works:
try {
if($adapter) {
$guzzle = new \GuzzleHttp\Client(['adapter' => $adapter]);
} else {
$guzzle = new \GuzzleHttp\Client();
}
$response = $guzzle->get($authorPage);
So obviously this isn't ideal. Does anyone know of a better way of doing this?
$html = (string) $response->getBody();
EDIT: I'm now using the __construct() methid to set up a default Guzzle Client. Then a using a second function that can be called by tests to replace the Client with a new Client that has the mock adapter. I'm not sure if this is the best way to do things.

Answer 1

You can use the MockPlugin API, like so:
$plugin = new MockPlugin();
$plugin->addResponse(__DIR__.'/twitter_200_response.txt');
The txt file then contains everything from your response, including headers.
There are also good approaches available here: http://www.sitepoint.com/unit-testing-guzzlephp/
Also there are articles found here: http://guzzle3.readthedocs.io/testing/unit-testing.html