I have an XML file that I transform with XSLT 2.0 into xhtml. The file has a line like this:
<p>Here I refer to list item number (<lat:listref href="nr"/>) below to tell you about.....</p>
and elsewhere, nested in other elements in that same file a numbered (in CSS) list:
<ol>
<li>list item 1</i>
<li>list item 2</i>
<li><span id="nr">list</span> item 3</i>
</ol>
<lat:listref href="nr"/> must be transformed into the number 3.
So far I came up with:
<xsl:template match="lat:listref">
<xsl:variable name="l" select="#href"/>
<xsl:number select="//li[*//#id=$l]" level="single"/>
</xsl:template>
Can I do this without the need of a variable?
Define a key: <xsl:key name="k1" match="ol/li/span[#id]" use="#id"/>.
Then in your template for the lat:listref simply do <xsl:apply-templates select="key('k1', #href)/parent::li" mode="m1"/>.
Finally write a template: <xsl:template match="ol/li" mode="m1"><xsl:number/></xsl:template>
Yes. Use current() as defined by the XSLT 2.0 specification:
<xsl:template match="lat:listref">
<xsl:value-of select="count(//li[.//#id = current()/#href]/preceding-sibling::li) + 1"/>
</xsl:template>
Related
Here is my XML:
<?xml version="1.0" encoding="UTF-8"?>
<Collection>
<Content>
<ID>2779</ID>
<Type>Content</Type>
<Title>Article One</Title>
<QuickLink>/template.aspx?id=2779</QuickLink>
<Teaser />
<Html>
<root>
<NewsArticle>
<artTitle>The Comprehensive Breast Center: Quality Care on the Fast Track</artTitle>
<artThumb>
<img alt="Thumb Article One" src="/uploadedImages/Test/News/artOne.png?n=5954" />
</artThumb>
<artFull />
<releaseDate />
<contactName />
<contactPhone />
<contactEmail />
<artTeaser>The National Cancer Institute estimates that a woman in the United States has a 1 in 8 chance of developing invasive breast cancer</artTeaser>
<artText>
<p>The Comprehensive Breast Center: Quality Care on
the Fast Track</p>
<p>
How do I display the IMG tag from my XML above to an HTML document using XSLT
Something like this should do the trick:
<xsl:template match="/">
<xsl:for-each select="Collection/Content">
<xsl:copy-of select="Html/root/NewsArticle/artThumb/node()"/>
</xsl:for-each>
</xsl:template>
I should note that this assumes you're getting this from an Ektron collection -- assumption made based on your tagging of this question. This will display the image from each content block in the collection. If you want just the image from the first content block of the collection, you could remove the for-each and instead use something like this:
<xsl:template match="/">
<xsl:copy-of select="Collection/Content/Html/root/NewsArticle/artThumb/node()"/>
</xsl:template>
Also, it works either way, but i removed the slash from the front of the select on the for-each. Seemed redundant since the code is in a template that already matches on "/".
UPDATE
Some of that can be done in the workarea -- it allows you to set the css class, though I'm not sure if you can set the title attribute of an image. Here's how you could do that via XSLT. In this case, you can't copy the node whole-sale:
<xsl:template match="/">
<xsl:for-each select="Collection/Content">
<xsl:variable name="imageSrc" select="Html/root/NewsArticle/artThumb/img/#src" />
<xsl:variable name="imageId">
<xsl:text>NewsArticle_</xsl:text>
<xsl:value-of select="ID" />
<xsl:text>_image</xsl:text>
</xsl:variable>
<xsl:variable name="contentTitle" select="Html/root/NewsArticle/artTitle" />
<img id="{ $imageId }" class="myCssClass" title="{ $contentTitle }" alt="{ $contentTitle }" src="{ $imageSrc }" />
</xsl:for-each>
</xsl:template>
(Updated again - appears i misread your comment. Thanks, #MathiasMüller!)
When assigning ids to elements like this, I prefer to use a little more than just the content id. In this case, by using "NewsArticle_{Content ID}image", I allow for a container div to use an id "NewsArticle{Content Id}" if it is needed in the future without colliding with the image ids.
How do i assign a title and an alt from artTitle and also a class and id?
Building upon the answer given by #BrianOliver, this is how you output an img element whose "title" attribute reflects the content of artTitle from your input XML - the same for ID.
I assume that by "an alt from artTitle" you mean that the text content of img/#alt should also come from the artTitle element.
<xsl:template match="/">
<xsl:for-each select="Collection/Content">
<xsl:variable name="imageSrc" select="Html/root/NewsArticle/artThumb/img/#src" />
<!--xsl:variable name="imageAlt" select="Html/root/NewsArticle/artThumb/img/#alt" /-->
<xsl:variable name="imageId" select="ID"/>
<xsl:variable name="imageTitle" select="Html/root/NewsArticle/artTitle"/>
<img id="{$imageId}" class="myCssClass" title="{$imageTitle}" alt="{ $imageTitle}" src="{$imageSrc}"/>
</xsl:for-each>
</xsl:template>
However, I am not sure where the class attribute should come from.
I am new to XML (a couple of days now...)and everything is going good, however, I can't seem to get the xml processed with css style
here is my perl...
#!/usr/bin/perl -w
use strict;
use warnings;
use diagnostics;
use Text::CSV_XS;
my $csv = Text::CSV_XS->new ({ binary => 1, auto_diag => 1 });
my $ifile="elementarray.csv";
my $ofile="elementarray.xml";
open my $fh, "<", $ifile or die $ifile.": $!";
open my $out, "> ".$ofile or die "Cannot write ".$ofile.": $!";
print $out <<EOT;
<?xml version="1.0"?>
<?xml-stylesheet type="text/xsl" href="elementarray.xsl"?>
<?xml-stylesheet href="elementarray.css" title="Default style"?>
<EMAILCOMMENTS>
EOT
# First record contains list of fieldnames
#my $fields = $csv->getline($fh);
#print #$fields;
while (my $row = $csv->getline($fh)) {
last unless $row && #$row;
# Encode "<" characters as "<" and "&" as "&" in all fields
foreach (#$row) {
s/&/&/g;
s/</</g;
}
# Create hash of fields using hash slice
my %row;
#row{"Subject","Body","From: (Name)","From: (Address)","To: (Name)","To:(Address)","Date","Time"} = #$row;
print $out <<EOT;
<EMAIL>
<HEADER>
<ORIGNAME>$row{"From: (Name)"}</ORIGNAME>
<ORIGADDRESS>$row{"From: (Address)"}</ORIGADDRESS>
<DESTNAME>$row{"To: (Name)"}</DESTNAME>
<DESTADDRESS>$row{"To: (Address)"}</DESTADDRESS>
<SUBJECT>$row{"Subject"}</SUBJECT>
</HEADER>
<BODY>$row{"Body"}</BODY>
<DATE id="date">$row{"Date"}</DATE>
<TIME id="time">$row{"Time"}</TIME>
</EMAIL>
EOT
}
print $out "</EMAILCOMMENTS>\n";
$csv->eof or $csv->error_diag;
close $fh or die $ifile.": $!";
close $out or die $ofile.": $!";
Here is my xsl...
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:output indent="yes" method="html"/>
<xsl:template match="/"><!-- a 'pattern', / matches the root node -->
<html>
<head>
<title>E-mail</title>
</head>
<body>
<xsl:apply-templates/><!-- an instruction -->
</body>
</html>
</xsl:template>
<xsl:template match="HEADER">
<span STYLE="color:red; font-weight:bold; font-style:italic">
<xsl:value-of select="SUBJECT"/>
</span>
From: <xsl:call-template name="formatEmail">
<xsl:with-param name="address" select="ORIGADDRESS"/>
</xsl:call-template>
To: <xsl:call-template name="formatEmail">
<xsl:with-param name="address" select="DESTADDRESS"/>
</xsl:call-template>
</xsl:template>
<xsl:template match="EMAIL">
<xsl:apply-templates select="HEADER"/>
<pre>
<xsl:value-of select="BODY"/>
</pre>
<div>
<span>
<xsl:attribute name="id"><xsl:value-of select="date"/></xsl:attribute>
<!-- --><xsl:value-of select="DATE"/><!-- --></span>
<span>
<xsl:attribute name="id"><xsl:value-of select="time"/></xsl:attribute>
<!-- --><xsl:value-of select="TIME"/><!-- --></span>
</div>
<br />
</xsl:template>
<xsl:template name="formatEmail">
<xsl:param name="address"/>
<a>
<xsl:attribute name="href"><xsl:value-of select="concat('mailto:',$address)"/></xsl:attribute>
<xsl:value-of select="$address"/>
</a>
</xsl:template>
</xsl:stylesheet>
here is my xml (1 record)...
<?xml version="1.0"?>
<?xml-stylesheet type="text/xsl" href="elementarray.xsl"?>
<?xml-stylesheet href="elementarray.css" title="Default style"?>
<EMAILCOMMENTS>
<EMAIL>
<HEADER>
<ORIGNAME>William Holt</ORIGNAME>
<ORIGADDRESS><x#gmail.com></ORIGADDRESS>
<DESTNAME>X</DESTNAME>
<DESTADDRESS>bill#elementarray.com</DESTADDRESS>
<SUBJECT>welcome to the neighborhood</SUBJECT>
</HEADER>
<BODY>just thought i'd say hello</BODY>
<DATE id="date">07/18/2013</DATE>
<TIME id="time">11:53</TIME>
</EMAIL>
</EMAILCOMMENTS>
and here is css ( style for just to see if it is working, and it isn't :( )...
DATE{background-color:red;}
TIME{background-color:green;}
#date{background-color:yellow;}
#time{background-color:blue;}
BODY{background-color:grey;}
Sorry for the length of the post but I think you need all these files...
Although you can indeed style XML with CSS, using the xml-stylesheet processing instruction you have included in your XML, you can't transform it with XSLT at the same time. That is to say you should only really have one stylesheet processing instruction in your XML. Either you simply style your XML with CSS (which is not really a common thing to do), or your transform it to HTML with XSLT and style the HTML output with CSS.
In the latter case, remove the <?xml-stylesheet href="elementarray.css"?> instruction from your XML document, and instead output a reference to the CSS document in your first template.
<xsl:template match="/">
<html>
<head>
<title>E-mail</title>
<link href="elementarray.css" type="text/css" rel="stylesheet" />
</head>
<body>
<xsl:apply-templates/>
</body>
</html>
</xsl:template>
Now, in your CSS, I see you already have selectors for the date and time ids, so you need to ensure the relevant elements in your HTML have these ids.
At the moment, you are doing this in your XSLT
<span>
<xsl:attribute name="id"><xsl:value-of select="date"/></xsl:attribute>
<!-- --><xsl:value-of select="DATE"/><!-- --></span>
<span>
But this is setting the id attribute to have the value of the date element in your XML, but such an element does not exist! I think you meaning to use the literal string here. Now, you could do this...
<xsl:attribute name="id"><xsl:value-of select="'date'"/></xsl:attribute>
But this is verbose. You can just do this:
<xsl:attribute name="id">date</xsl:attribute>
But better still, just write it out as an attribute in the normal way:
<span id="date">
<xsl:value-of select="DATE"/>
</span>
And similarly for 'time'. This should ensure the two span tags get styled using your CSS in the HTML you output.
here my code-
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="ArrayOfLinkEntity" name="bindLink">
<ul>
<xsl:for-each select="LinkEntity[ParentLinkId=0]">
<li>
<xsl:variable name="linkId" select="LinkId"/>
<xsl:variable name="child" select="count(/ArrayOfLinkEntity/LinkEntity[ParentLinkId=$linkId])"/>
<xsl:value-of select="$child"/>
<xsl:choose>
<xsl:when test="($child > 0)">
<a href="#" data-flexmenu="flexmenu1" onclick="javascript:setPageLinkId({$linkId});">
<xsl:value-of select="LinkTitle"/>
<img src="../images/down.gif" border="0"/>
</a>
</xsl:when>
<xsl:otherwise >
<a href="#" onclick="javascript:setPageLinkId({$linkId});">
<xsl:value-of select="LinkTitle"/>
</a>
</xsl:otherwise>
</xsl:choose>
</li>
</xsl:for-each>
</ul>
</xsl:template>
</xsl:stylesheet>
but I am getting $child=0 always.but there exists children.
my xml structure-
<ArrayOfLinkEntity xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<LinkEntity>
<EntityId>00000000-0000-0000-0000-000000000000</EntityId>
<LinkId>1</LinkId>
<SequenceNo>1</SequenceNo>
<ParentLinkId>0</ParentLinkId>
<LinkTitle>Home</LinkTitle>
<SubLink />
</LinkEntity> ...
</ArrayOfLinkEntity>
What should I do? Please suggest.
but I am getting $child=0 always.but
there exists children.
If by "children" you mean a LinkEntity with ParentLinkId child that is equal to the LinkId of the current node, the result you get is correct.
The only LinkEntity has an LinkId 1, but there are no LinkEntity elements in the provided XML document whose ParentLinkId is 1.
You need to show a complete (but the shortest possible) XML document on which your code exhibits this issue. Without being able to repro the problem, no one can give you a logical advice.
From your following code:
<xsl:variable name="linkId" select="LinkId"/>
<xsl:variable name="child" select="count(/ArrayOfLinkEntity/LinkEntity[ParentLinkId=$linkId])"/>
This occurs within a for-each loop where the only nodes being looped over are LinkEntity's with ParentLinkId = 0. But from your source XML, the value of LinkId = 1, and in your variable assignment for $child, you are selecting on LinkEntity's with ParentLinkId = 1, which don't exist in your source XML data.
If I misunderstood something please let me know, but from what I can see that may be the problem.
I need to loop through an XML document (no problem over there) and check if a value that i find is already in a (a) tag in a div in my XSL document that i am generating, only if the value is not in that (a) tag i should create a new (a) tag for it and put in in the div that i am checking...
Any one knows how to do it dynamically in XSLT?
<div id="tags"><span class="l_cap"> </span>
all
<xsl:for-each select="root/nodes/node/data/genres">
<xsl:for-each select="value">
**<xsl:if test="not(contains())">**
<xsl:value-of select="current()"/>
</xsl:if>
</xsl:for-each>
</xsl:for-each>
sorry for before, what i am trying to do is: in the if statement, check if the current value is already exist in the div if not, add it, if is, don't do anything...
10x again
It sounds like you're trying to create a distinct list of all of the "genres" in your list.
Assuming a data structure which looks a bit like this:
<root>
<nodes>
<node>
<data>
<genres>
<value>One</value>
<value>Two</value>
<value>Two</value>
<value>Three</value>
<value>Two</value>
</genres>
</data>
</node>
</nodes>
</root>
And a stylesheet which looks a bit like this:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:key name="genres" match="value" use="."/>
<xsl:template match="/">
<div>
<xsl:for-each select="/root/nodes/node/data/genres/value">
<xsl:if test="generate-id(.) = generate-id(key('genres', .)[1])">
<xsl:value-of select="."/>
</xsl:if>
</xsl:for-each>
</div>
</xsl:template>
</xsl:stylesheet>
Then you will end up with something like this:
<div>
One
Two
Three
</div>
This is a fairly standard XSLT 1.0 technique. It uses keys (described here: http://www.xml.com/pub/a/2002/02/06/key-lookups.html ) to create a sort of index of all the /root/nodes/node/data/genres/value entries. Then it loops through all of the entries, but only prints the first one of each type. The end result is that each value will only be output once.
I want to use data from XML to populate a class:
E.g.
<p class="<xsl:value-of select="a:Subject"/>">English</p>
Which would generate:
<p class="English">English</p>
IS this possible?
Yes, it is possible, use the below code with Attribute Value Template
<p class="{a:Subject}">English</p>
Yes via the <xsl:attribute>
Ex:
<xsl:template match="yourXPath">
<p>
<xsl:attribute name="class">
<xsl:value-of select="a:Subject"/>
</xsl:attribute>
</p>
</xsl:template>