Why does the "right" value contain the "successful" outcome with Eithers? - functional-programming

In functional programming languages such as Scala and Haskell, there is an Either type that is often used to represent a successful result or a failure/error object. An either is said to be 'left' when it contains a failure and to be 'right' when it contains a successful result.
Is there a reason why "unsuccessful" is "left" and "successful" is "right"? Why are these directions used in the first place?

From Haskell's Data. Either documentation:
The Left constructor is used to hold an error value and the Right constructor is used to hold a correct value (mnemonic: "right" also means "correct").

This is just a guess, but in Haskell Either is monadic on its second type, which is the type associated with the Right constructor. Generic monadic code will therefore change only the right type, so the left type which remains constant is used to hold the error.
So the main reason would be that swapping the type arguments to Either so that Either a b is Left b or Right a is annoying to read for no real benefit.

Related

Reshaping 1d array to 2D pointer array Fortran

I have a pointer uvw(:,:) which is two-dimensional, and I got a 1d buffer array x(:).
Now I need to point uvw(1,:)=>x(1:ncell) and uvw(2,:)=>x(ncell+1:ncell*2) etc.
I made a very simple example. I know that array of pointers does not work, but does anybody have an idea how this can be worked around?
PS: For a pragmatic reason I do not want to wrap my uvw with a declared type. ( i am changing some bit of code, and need uvw as 2D pointer. Currently is an array, and my idea is to avoid changing the way uvw is being used as it being used thousands of times)
program test
real, allocatable,target :: x(:)
real, pointer :: ptr(:,:)
allocate(x(100) )
x = 1.
ptr(1,:) => x(1:10)
end program
The error message says:
`error #8524: The syntax of this data pointer assignment is incorrect:
either 'bound spec' or 'bound remapping' is expected in this context.
[1]
ptr(1,:) => x(1:10)
----^`
You are trying to perform pointer bounds remapping, but you have the incorrect syntax and approach.
Pointer bounds remapping is a way to have the shape of the pointer different from that of the target. In particular, the rank of the pointer and target may differ. However, in such an assignment it is necessary to explicitly specify the lower and upper bounds of the remapping; it isn't sufficient to use : by itself.
Also, you'll need to assign the whole pointer in one go. That is, you can't have "the first ten elements point to this slice, the next ten to this slice" and so on in multiple statements.
The assignment statement would be
ptr(1:10,1:10) => x
Note, that this also means that you can't actually have what you want. You are asking for the elements ptr(1,1:10) to correspond to x(1:10) and ptr(2,2:10) to correspond to x(11:20). That isn't possible: the array elements must match in order: ptr(1:10,1) being the first ten elements of ptr must instead be associated with the first ten elements x(1:10). The corrected pointer assignment above has this.
If you prefer avoiding a pointer, then the UNION/MAP is an option depending on compiler. It was added to gfortran a while ago... then you can think of the array as a rank=2 but also use the vector (Rank=1) for SIMD operations.
All this assumes that one wants to avoid pointers...

Function of parameter type in type definition

Assume I want to store I vector together with its norm. I expected the corresponding type definition to be straightforward:
immutable VectorWithNorm1{Vec <: AbstractVector}
vec::Vec
norm::eltype(Vec)
end
However, this doesn't work as intended:
julia> fieldtype(VectorWithNorm1{Vector{Float64}},:norm)
Any
It seems I have to do
immutable VectorWithNorm2{Vec <: AbstractVector, Eltype}
vec::Vec
norm::Eltype
end
and rely on the user to not abuse the Eltype parameter. Is this correct?
PS: This is just a made-up example to illustrate the problem. It is not the actual problem I'm facing.
Any calculations on a type parameter currently do not work
(although I did discuss the issue with Jeff Bezanson at JuliaCon, and he seemed amenable to fixing it).
The problem currently is that the expression for the type of norm gets evaluated when the parameterized type is defined, and gets called with a TypeVar, but it is not yet bound to a value, which is what you really need it to be called with, at the time that that parameter is actually bound to create a concrete type.
I've run into this a lot, where I want to do some calculation on the number of bits of a floating point type, i.e. to calculate and use the number of UInts needed to store a fp value of a particular precision, and use an NTuple{N,UInt} to hold the mantissa.

Reflecting on a Type parameter

I am trying to create a function
import Language.Reflection
foo : Type -> TT
I tried it by using the reflect tactic:
foo = proof
{
intro t
reflect t
}
but this reflects on the variable t itself:
*SOQuestion> foo
\t => P Bound (UN "t") (TType (UVar 41)) : Type -> TT
Reflection in Idris is a purely syntactic, compile-time only feature. To predict how it will work, you need to know about how Idris converts your program to its core language. Importantly, you won't be able to get ahold of reflected terms at runtime and reconstruct them like you would with Lisp. Here's how your program is compiled:
Internally, Idris creates a hole that will expect something of type Type -> TT.
It runs the proof script for foo in this state. We start with no assumptions and a goal of type Type -> TT. That is, there's a term being constructed which looks like ?rhs : Type => TT . rhs. The ?foo : ty => body syntax shows that there's a hole called foo whose eventual value will be available inside of body.
The step intro t creates a function whose argument is t : Type - this means that we now have a term like ?foo_body : TT . \t : Type => foo_body.
The reflect t step then fills the current hole by taking the term on its right-hand side and converting it to a TT. That term is in fact just a reference to the argument of the function, so you get the variable t. reflect, like all other proof script steps, only has access to the information that is available directly at compile time. Thus, the result of filling in foo_body with the reflection of the term t is P Bound (UN "t") (TType (UVar (-1))).
If you could do what you are wanting here, it would have major consequences both for understanding Idris code and for running it efficiently.
The loss in understanding would come from the inability to use parametricity to reason about the behavior of functions based on their types. All functions would effectively become potentially ad-hoc polymorphic, because they could (say) run differently on lists of strings than on lists of ints.
The loss in performance would come from representing enough type information to do the reflection. After Idris code is compiled, there is no type information left in it (unlike in a system such as the JVM or .NET or a dynamically typed system such as Python, where types have a runtime representation that code can access). In Idris, types can be very large, because they can contain arbitrary programs - this means that far more information would have to be maintained, and computation occurring at the type level would also have to be preserved and repeated at runtime.
If you're wanting to reflect on the structure of a type for further proof automation at compile time, take a look at the applyTactic tactic. Its argument should be a function that takes a reflected context and goal and gives back a new reflected tactic script. An example can be seen in the Data.Vect source.
So I suppose the summary is that Idris can't do what you want, and it probably never will be able to, but you might be able to make progress another way.

How to use a vector as a type parameter in Julia

This is similar to my previous question, but a bit more complicated.
Before I was defining a type with an associated integer as a parameter, Intp{p}. Now I would like to define a type using a vector as a parameter.
The following is the closest I can write to what I want:
type Extp{g::Vector{T}}
c::Vector{T}
end
In other words, Extp should be defined with respect to a Vector, g, and I want the contents, c, to be another Vector, whose entries should be the of the same type as the entries of g.
Well, this does not work.
Problem 1: I don't think I can use :: in the type parameter.
Problem 2: I could work around that by making the types of g and c arbitary and just making sure the types in the vectors match up in the constructor. But, even if I completely take everything out and use
type Extp{g}
c
end
it still doesn't seem to like this. When I try to use it the way I want to,
julia> Extp{[1,1,1]}([0,0,1])
ERROR: type: apply_type: in Extp, expected Type{T<:Top}, got Array{Int64,1}
So, does Julia just not like particular Vectors being associated with types? Does what I'm trying to do only work with integers, like in my Intp question?
EDIT: In the documentation I see that type parameters "can be any type at all (or an integer, actually, although here it’s clearly used as a type)." Does that mean that what I'm asking is impossible, and that that only types and integers work for Type parameters? If so, why? (what makes integers special over other types in Julia in this way?)
In Julia 0.4, you can use any "bitstype" as a parameter of a type. However, a vector is not a bitstype, so this is not going to work. The closest analog is to use a tuple: for example, (3.2, 1.5) is a perfectly valid type parameter.
In a sense vectors (or any mutable object) are antithetical to types, which cannot change at runtime.
Here is the relevant quote:
Both abstract and concrete types can be parameterized by other types
and by certain other values (currently integers, symbols, bools, and
tuples thereof).
So, your EDIT is correct. Widening this has come up on the Julia issues page (e.g., #5102 and #6081 were two related issues I found with some discussion), so this may change in the future - I'm guessing not in v0.4 though. It'd have to be an immutable type really to make any sense, so not Vector. I'm not sure I understand your application, but would a Tuple work?

prolog recursion

am making a function that will send me a list of all possible elemnts .. in each iteration its giving me the last answer .. but after the recursion am only getting the last answer back .. how can i make it give back every single answer ..
thank you
the problem is that am trying to find all possible distributions for a list into other lists .. the code
addIn(_,[],Result,Result).
addIn(C,[Element|Rest],[F|R],Result):-
member( Members , [F|R]),
sumlist( Members, Sum),
sumlist([Element],ElementLength),
Cap is Sum + ElementLength,
(Cap =< Ca,
append([Element], Members,New)....
by calling test .. am getting back all the list of possible answers .. now if i tried to do something that will fail like
bp(3,11,[8,2,4,6,1,8,4],Answer).
it will just enter a while loop .. more over if i changed the
bp(NB,C,OL,A):-
addIn(C,OL,[[],[],[]],A);
bp(NB,C,_,A).
to and instead of Or .. i get error :
ERROR: is/2: Arguments are not
sufficiently instantiated
appreciate the help ..
Thanks alot #hardmath
It sounds like you are trying to write your own version of findall/3, perhaps limited to a special case of an underlying goal. Doing it generally (constructing a list of all solutions to a given goal) in a user-defined Prolog predicate is not possible without resorting to side-effects with assert/retract.
However a number of useful special cases can be implemented without such "tricks". So it would be helpful to know what predicate defines your "all possible elements". [It may also be helpful to state which Prolog implementation you are using, if only so that responses may include links to documentation for that version.]
One important special case is where the "universe" of potential candidates already exists as a list. In that case we are really asking to find the sublist of "all possible elements" that satisfy a particular goal.
findSublist([ ],_,[ ]).
findSublist([H|T],Goal,[H|S]) :-
Goal(H),
!,
findSublist(T,Goal,S).
findSublist([_|T],Goal,S) :-
findSublist(T,Goal,S).
Many Prologs will allow you to pass the name of a predicate Goal around as an "atom", but if you have a specific goal in mind, you can leave out the middle argument and just hardcode your particular condition into the middle clause of a similar implementation.
Added in response to code posted:
I think I have a glimmer of what you are trying to do. It's hard to grasp because you are not going about it in the right way. Your predicate bp/4 has a single recursive clause, variously attempted using either AND or OR syntax to relate a call to addIn/4 to a call to bp/4 itself.
Apparently you expect wrapping bp/4 around addIn/4 in this way will somehow cause addIn/4 to accumulate or iterate over its solutions. It won't. It might help you to see this if we analyze what happens to the arguments of bp/4.
You are calling the formal arguments bp(NB,C,OL,A) with simple integers bound to NB and C, with a list of integers bound to OL, and with A as an unbound "output" Answer. Note that nothing is ever done with the value NB, as it is not passed to addIn/4 and is passed unchanged to the recursive call to bp/4.
Based on the variable names used by addIn/4 and supporting predicate insert/4, my guess is that NB was intended to mean "number of bins". For one thing you set NB = 3 in your test/0 clause, and later you "hardcode" three empty lists in the third argument in calling addIn/4. Whatever Answer you get from bp/4 comes from what addIn/4 is able to do with its first two arguments passed in, C and OL, from bp/4. As we noted, C is an integer and OL a list of integers (at least in the way test/0 calls bp/4).
So let's try to state just what addIn/4 is supposed to do with those arguments. Superficially addIn/4 seems to be structured for self-recursion in a sensible way. Its first clause is a simple termination condition that when the second argument becomes an empty list, unify the third and fourth arguments and that gives "answer" A to its caller.
The second clause for addIn/4 seems to coordinate with that approach. As written it takes the "head" Element off the list in the second argument and tries to find a "bin" in the third argument that Element can be inserted into while keeping the sum of that bin under the "cap" given by C. If everything goes well, eventually all the numbers from OL get assigned to a bin, all the bins have totals under the cap C, and the answer A gets passed back to the caller. The way addIn/4 is written leaves a lot of room for improvement just in basic clarity, but it may be doing what you need it to do.
Which brings us back to the question of how you should collect the answers produced by addIn/4. Perhaps you are happy to print them out one at a time. Perhaps you meant to collect all the solutions produced by addIn/4 into a single list. To finish up the exercise I'll need you to clarify what you really want to do with the Answers from addIn/4.
Let's say you want to print them all out and then stop, with a special case being to print nothing if the arguments being passed in don't allow a solution. Then you'd probably want something of this nature:
newtest :-
addIn(12,[7, 3, 5, 4, 6, 4, 5, 2], Answer),
format("Answer = ~w\n",[Answer]),
fail.
newtest.
This is a standard way of getting predicate addIn/4 to try all possible solutions, and then stop with the "fall-through" success of the second clause of newtest/0.
(Added) Suggestions about coding addIn/4:
It will make the code more readable and maintainable if the variable names are clear. I'd suggest using Cap instead of C as the first argument to addIn/4 and BinSum when you take the sum of items assigned to a "bin". Likewise Bin would be better where you used Members. In the third argument to addIn/4 (in the head of the second clause) you don't need an explicit list structure [F|R] since you never refer to either part F or R by itself. So there I'd use Bins.
Some of your predicate calls don't accomplish much that you cannot do more easily. For example, your second call to sumlist/2 involves a list with one item. Thus the sum is just the same as that item, i.e. ElementLength is the same as Element. Here you could just replace both calls to sumlist/2 with one such call:
sumlist([Element|Bin],BinSum)
and then do your test comparing BinSum with Cap. Similarly your call to append/3 just adjoins the single item Element to the front of the list (I'm calling) Bin, so you could just replace what you have called New with [Element|Bin].
You have used an extra pair of parentheses around the last four subgoals (in the second clause for addIn/4). Since AND is implied for all the subgoals of this clause, using the extra pair of parentheses is unnecessary.
The code for insert/4 isn't shown now, but it could be a source of some unintended "backtracking" in special cases. The better approach would be to have the first call (currently to member/2) be your only point of indeterminacy, i.e. when you choose one of the bins, do it by replacing it with a free variable that gets unified with [Element|Bin] at the next to last step.

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