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There's a new language Q, based on R, which was based on S ... you get the idea.
Sadly, Q appears to be very slow in automining unicoins. Plus, Q : we don't have TIME for your little games!
Clearly Q is backwards compatible to R so it inherits its speed. This is by design. Happy mining!
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I am reviewing a proof at the moment and there is terminology that I do not understand. What does it mean for a polynomial to have "integral coefficients"?
"Integral coefficients" means that the coefficients of your final answer will be integers, unless there is a markedly different context in which the question is being asked.
You can have a look at the definition here.
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I tried using recursive tree method.
and got a geometric series.
That follows :
kn^2(1+ (3/2) +(3/2)^2 +...+(3/2)^b)
The sum = a(r^m -1)/r-1.
b = log n.
Then what to do I got confused.
Have you heard of the Master's Theorem? Your example is a relatively simple subcase (no logarithms). The result is:
T = Theta(n^2)
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((A*55)/(A+1815))+4=B
eg.:
((1000*55)/(1000+1815))+4=23.53819
How can i calculate from
23.53819 1000?
A and B are variables.
Sry for my bad english ;)
Thanks any help!
Just follow the steps described before. The goal is to manipulate the expression to get all terms containing the variable to be solved for on one side.
You Have to First do what ever present in Brackets then Division, Multiplication and then Addition and Subtraction.
For any equation you have to follow the sequence.
Hope this helps
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Let's say I have a vector of 10 elements called numbers in R
numbers <- c(0,1,1,1,0,0,1,0,1,0)
and I want to replace each occurrence of 1 to 5?
this should work
v[v==1]<-5
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I have found this formula for computing Pi value:
But I need to compute only(for example - 1000th) number of Pi value. How I can do it with provided formula?
Thanks.
What you want is called a "spigot algorithm". Take a look at [1] in the section "BBP digit-extraction algorithm for pi". Good luck and have fun.
[1] http://en.wikipedia.org/wiki/Bailey%E2%80%93Borwein%E2%80%93Plouffe_formula