SCSS and direct nesting - css

I'm stuck on this one. I know I have an ability to reach all the way outside of the nested operators to add a prefix class like:
.myEl {
html.no-touch & {
}
}
and that will output:
html.no-touch .myEl {}
but I'm wondering if there is a way to escape by only one level, rather than all of them. Given this sort of input:
.myEl {
.myEl3 {
.myEl2 {} /* direct parent operator goes here? */
}
}
I would expect this sort of output:
.myEl1 .myEl2 .myEl3 {}
Is this possible?

Unfortunately, this is not possible in SASS. You'd probably have to do something like this if you don't want to nest further (which I'm sure you already knew).
.myEl1 {
.myEl3 {
/* Base styles here */
}
.myEl2 .myEl3 {
/* Specific styles here */
}
}

Related

extend from class name in another file sass

So I'm currently doing some styling, following the BEM standard.
An example of what I'm doing could be this:
.block{
&__element {
}
}
what i would like to do is this:
// file a
.block {
...
}
-
// file b
// add magic to reference the `block`class in file a
&__elelemnt {
...
}
What I'm currently doing:
// file a
.block {
...
}
-
// file b
.block__elelemnt {
...
}
(manually adding the block part to the name)
Is there any way to reference this in a smarter way?
Thanks in advance
You can have this file structure:
block-1/
--block-1.scss
--element-1.scss
--element-2.scss
block-2/
--block-1.scss
--element-1.scss
--element-2.scss
And import elements files info block files.
block.scss:
.block {
color: red;
#import "element-1.scss";
#import "element-2.scss";
}
element-1.scss:
&__element-1 {
color: green;
}
Compiles to:
.block {
color: red;
&__element-1 {
color: green;
}
}
This is perhaps the best you can do.
$namespace: "block";
.#{$namespace}-myClass {
...
}
OUTPUT
.block-myClass {
...
}
You can keep a variable $namespace at the top of your file or in a different file and import it. The advantage of using a variable is you can update it once and all your references will be updated.
SASS is all about DRY.
As in, if you want to modify anything, you should be able to modify it from one single place. If you need anything available across multiple files, consider defining its value in a _vars file and including it everywhere you need it. Also note this has nothing to do with code shortness, but with code maintainability and flexibility.
In fact, even if you do get to write more code (which, in practice, doesn't happen), the advantage of DRY far outweighs it.
Here's how it should be done:
/* _vars.scss: */
$block:block;
/* a.scss: */
#import _vars;
.#{$block} {
...
}
/* b.scss: */
#import _vars;
.#{$block}__element {
...
}
Now, whenever you need to change block value, you can do it from one place: _vars.scss.
But, in practice, most people use the initial technique (nesting):
.block {
...
&__element {
...
}
}
Chances are .block and .block__element are related and, overall, it makes more sense to put them in same file. As your app grows in complexity, you'll find it harder to keep track of your code if you over-complicate it.

Wildcard nested selector

I have the following bit of Sass code :
.c-panel-menu-c {
&.grid_6 {
float: right;
}
}
i need to have float right applied to all grids that start with grid_ . The float should only be set when the grid class is applied to an element that also has c-panel-menu-c.
I wanted to use a wildcard selector like
div[class*='grid_'] {
float:right
}
But am not sure if it's possible the way i need it. Something like
.c-panel-menu-c {
&.div[class*='grid_'] {
vertical-align: top;
}
}
Which doesnt work.
Thank you for any tips/advice.
the problem is the tag name ... you can not concatenate a tag name, for example div, at the end of another selector, like you would with a class name. Let's look at your example:
.c-panel-menu-c {
&.grid_6 {
...
}
}
will return
.c-panel-menu-c.grid_6 { ... }
which is a valid selector. But attaching 'div' at the end (lets leave out the attribute selector part for now)
.c-panel-menu-c {
&div {
...
}
}
does not make sense (and it also isn't possible in Sass, hence you get an error) as the tag name should always be before the class or id selector. This does not change if we add an attribute selector statement, so that's why it does not work the way you tried &div[class*='grid_'].
What you can do, is add the attribute selector directly to the preceding class name, like so:
.c-panel-menu-c {
&[class*='grid_'] {
...
}
}
which would compile to:
.c-panel-menu-c[class=*'grid_'] { ... }
and select everything that has the class .c-panel-menu-c and a class containing with grid_.

How to write "any span that is a child of label is extended by x, whether it has a class or not" using SASS?

I'd like that every span that is a child of a label receive an extension, and at the same time simplify the SASS and remove repetition.
e.g. I'd like to rewrite this:
label > span {
extend #informational;
}
label > span.info {
extend #informational;
/* other info stuff */
}
label > span.error {
extend #informational;
/* other error stuff */
}
Into something resembling this:
label {
span {
extend #informational;
}
span.info {
/* other info stuff */
/* this also gets extended, but no explicit extension statement here */
}
span.error {
/* other error stuff */
/* this also gets extended, but no explicit extension statement here */
}
}
because just extending the span does not also extend a span.xxx (though I'd expect it to).
Is there a way? All the combinations I've attempted (including the one above) have failed.
I've also tried this without using #extend but through repeating the CSS in informational within each relevant block, to the same effect. This makes it a CSS problem (afaics) but if it can be solved using SASS that's fine too.
You may have other style rules that are overriding whatever is in your #informational extension for your span elements with classes. That's as far as I can see as well...
If that is the case you'll have to keep your class selectors so they make up for the less specific span selector, but you can group them together like this so you don't have to repeat the extend #informational; statement (you'll also want to use > if you're specifically only looking for children, and not just descendants at any nesting level):
label {
> span, > span.info, > span.error {
extend #informational;
}
> span.info {
/* other info stuff */
}
> span.error {
/* other error stuff */
}
}
If you're not interested in which specific classes your span elements have, as long as they either have or don't have a class attribute, you could use an attribute selector instead as a cheap hack:
label {
> span, > span[class] {
extend #informational;
}
/* ... */
}

Declare a global CSS property ? Is this possible?

I have a very wierd question, I dont know wether if its possible in css or not
Suppose I have say 3 different css classes as shown below, as you can see I have a common property of all these classes, I want to declare this color somewhere else and pass a reference to it here, so if next time I want to change the color I can simply change at one place rather than changing in all the 5 classes.
I know that you can use body{}, or a wrapper for this but that would affect the colors of the entire site right ? Is there a way to do this ?
Is this even possible ?
.abc {
color:red;
}
.abc2 {
color:red;
}
.abc3 {
color:red;
}
.abc4 {
color:red;
}
.abc5 {
color:red;
}
The bad news: you can't do it in CSS.
The good news: you can write in a meta-CSS language like LESS, which then processes a LESS file to pure CSS. This is called a "mixin".
In LESS:
#errorColor: red;
.error-color {
color: #errorColor;
}
#error-1 {
.error-color;
}
.all-errors {
.error-color;
}
More info: http://lesscss.org/#-mixins
if you want to declare all of them at a time, you can use:
.abc, .abc2, .abc3, .abc4, .abc5 {
color:red;
}
Or you can declare an additional class & add to all the .abc, .abc2.... & make its color:red;.
This can not be done with CSS, but that is still a very popular thing to do by using a CSS preprocessor such as LESS, SASS, SCSS, or Stylus.
A preprocessor will let you define a variable (say $red = #F00). It will replace the variable in your CSS document with the variable value for you, allowing you to write very DRY and module CSS.
This functionality is referred to as "CSS variables", which is part of the future spec, but not yet implemented on any browsers.
For now, the best way to do this in pure CSS is to declare an additional class for the desired "global", and then add that class to all relevant items.
.abc_global { color: red; }
.abc1 { /* additional styling */ }
.abc2 { /* additional styling */ }
<div class="abc1 abc_global"></div>
<div class="abc2 abc_global"></div>
With LESS
You are able to define that red color once:
.myRedColor {
color:red;
}
Now you can call that red on any CSS styles. Even NESTED styles! It's a wicked tool!
.abc1 {
.myRedColor;
}
.abc2 {
.myRedColor;
}
.abc3 {
.myRedColor;
}
.abc4 {
.myRedColor;
}
NESTED EXAMPLE:
.abc {
.itsEasyAsOneTwoThree{
.myRedColor;
}
}
Now all of our "itsEasyAsOneTwoThree" classes that are properly nested inside of an "abc" class will be assigned the red style. No more remembering those long #867530 color codes :) How cool is that?!
You can also use PostCSS with the plugin postcss-preset-env and support custom properties/variables, then use the :root selector to add global css variables.
:root {
--color-gray: #333333;
--color-white: #ffffff;
--color-black: #000000;
}

Can the :not() pseudo-class have multiple arguments?

I'm trying to select input elements of all types except radio and checkbox.
Many people have shown that you can put multiple arguments in :not, but using type doesn't seem to work anyway I try it.
form input:not([type="radio"], [type="checkbox"]) {
/* css here */
}
Any ideas?
Why :not just use two :not:
input:not([type="radio"]):not([type="checkbox"])
Yes, it is intentional
If you're using SASS in your project, I've built this mixin to make it work the way we all want it to:
#mixin not($ignorList...) {
//if only a single value given
#if (length($ignorList) == 1){
//it is probably a list variable so set ignore list to the variable
$ignorList: nth($ignorList,1);
}
//set up an empty $notOutput variable
$notOutput: '';
//for each item in the list
#each $not in $ignorList {
//generate a :not([ignored_item]) segment for each item in the ignore list and put them back to back
$notOutput: $notOutput + ':not(#{$not})';
}
//output the full :not() rule including all ignored items
&#{$notOutput} {
#content;
}
}
it can be used in 2 ways:
Option 1: list the ignored items inline
input {
/*non-ignored styling goes here*/
#include not('[type="radio"]','[type="checkbox"]'){
/*ignored styling goes here*/
}
}
Option 2: list the ignored items in a variable first
$ignoredItems:
'[type="radio"]',
'[type="checkbox"]'
;
input {
/*non-ignored styling goes here*/
#include not($ignoredItems){
/*ignored styling goes here*/
}
}
Outputted CSS for either option
input {
/*non-ignored styling goes here*/
}
input:not([type="radio"]):not([type="checkbox"]) {
/*ignored styling goes here*/
}
Starting from CSS Selectors 4 using multiple arguments in the :not selector becomes possible (see here).
In CSS3, the :not selector only allows 1 selector as an argument. In level 4 selectors, it can take a selector list as an argument.
Example:
/* In this example, all p elements will be red, except for
the first child and the ones with the class special. */
p:not(:first-child, .special) {
color: red;
}
Unfortunately, browser support is somewhat new.
I was having some trouble with this, and the "X:not():not()" method wasn't working for me.
I ended up resorting to this strategy:
INPUT {
/* styles */
}
INPUT[type="radio"], INPUT[type="checkbox"] {
/* styles that reset previous styles */
}
It's not nearly as fun, but it worked for me when :not() was being pugnacious. It's not ideal, but it's solid.
If you install the "cssnext" Post CSS plugin, then you can safely start using the syntax that you want to use right now.
Using cssnext will turn this:
input:not([type="radio"], [type="checkbox"]) {
/* css here */
}
Into this:
input:not([type="radio"]):not([type="checkbox"]) {
/* css here */
}
https://cssnext.github.io/features/#not-pseudo-class

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