Surface plot Q in R - compable to surf() in matlab - r

I want to plot a matrix of z values with x rows and y columns as a surface similar to this graph from MATLAB.
Surface plot:
Code to generate matrix:
# Parameters
shape<-1.849241
scale<-38.87986
x<-seq(from = -241.440, to = 241.440, by = 0.240)# 2013 length
y<-seq(from = -241.440, to = 241.440, by = 0.240)
matrix_fun<-matrix(data = 0, nrow = length(x), ncol = length(y))
# Generate two dimensional travel distance probability density function
for (i in 1:length(x)) {
for (j in 1:length(y)){
dxy<-sqrt(x[i]^2+y[j]^2)
prob<-1/(scale^(shape)*gamma(shape))*dxy^(shape-1)*exp(-(dxy/scale))
matrix_fun[i,j]<-prob
}}
# Rescale 2-d pdf to sum to 1
a<-sum(matrix_fun)
matrix_scale<-matrix_fun/a
I am able to generate surface plots using a couple methods (persp(), persp3d(), surface3d()) but the colors aren't displaying the z values (the probabilities held within the matrix). The z values only seem to display as heights not as differentiated colors as in the MATLAB figure.
Example of graph code and graphs:
library(rgl)
persp3d(x=x, y=y, z=matrix_scale, color=rainbow(25, start=min(matrix_scale), end=max(matrix_scale)))
surface3d(x=x, y=y, z=matrix_scale, color=rainbow(25, start=min(matrix_scale), end=max(matrix_scale)))
persp(x=x, y=y, z=matrix_scale, theta=30, phi=30, col=rainbow(25, start=min(matrix_scale), end=max(matrix_scale)), border=NA)
Image of the last graph
Any other tips to recreate the image in R would be most appreciated (i.e. legend bar, axis tick marks, etc.)

So here's a ggplot solution which seems to come a little bit closer to the MATLAB plot
# Parameters
shape<-1.849241
scale<-38.87986
x<-seq(from = -241.440, to = 241.440, by = 2.40)
y<-seq(from = -241.440, to = 241.440, by = 2.40)
df <- expand.grid(x=x,y=y)
df$dxy <- with(df,sqrt(x^2+y^2))
df$prob <- dgamma(df$dxy,shape=shape,scale=scale)
df$prob <- df$prob/sum(df$prob)
library(ggplot2)
library(colorRamps) # for matlab.like(...)
library(scales) # for labels=scientific
ggplot(df, aes(x,y))+
geom_tile(aes(fill=prob))+
scale_fill_gradientn(colours=matlab.like(10), labels=scientific)
BTW: You can generate your data frame of probabilities much more efficiently using the built-in dgamma(...) function, rather than calculating it yourself.

In line with alexis_laz's comment, here is an example using filled.contour. You might want to increase your by to 2.40 since the finer granularity increases the time it takes to generate the plot by a lot but doesn't improve quality.
filled.contour(x = x, y = y, z = matrix_scale, color = terrain.colors)
# terrain.colors is in the base grDevices package
If you want something closer to your color scheme above, you can fiddle with the rainbow function:
filled.contour(x = x, y = y, z = matrix_scale,
color = (function(n, ...) rep(rev(rainbow(n/2, ...)[1:9]), each = 3)))
Finer granularity:
filled.contour(x = x, y = y, z = matrix_scale, nlevels = 150,
color = (function(n, ...)
rev(rep(rainbow(50, start = 0, end = 0.75, ...), each = 3))[5:150]))

Related

How can I place multiple unrelated graphs on the same axes in ggplot2?

I am trying to recreate an image found in a textbook in R, the original of which was built in MATLAB:
I have generated each of the graphs seperately, but what would be best practice them into an image like this in ggplot2?
Edit: Provided code used. This is just a transformation of normally distributed data.
library(ggplot2)
mean <- 6
sd <- 1
X <- rnorm(100000, mean = mean, sd = sd)
Y <- dnorm(X, mean = mean, sd = sd)
Y_p <- pnorm(X, mean = mean, sd = sd)
ch_vars <- function(X){
nu_vars <- c()
for (x in X){
nu_vars <- c(nu_vars, (1/(1 + exp(-x + 5))))
}
return(nu_vars)
}
nu_X <- ch_vars(X)
nu_Y <- ch_vars(Y)
data <- data.frame(x = X, y = Y, Y_p = Y_p, x = nu_X, y = nu_Y)
# Cumulative distribution
ggplot(data = data) +
geom_line(aes(x = X, y = Y_p))
# Distribution of initial data
ggplot(data = data_ch, aes(x = X)) +
geom_histogram(aes(y = ..density..), bins = 25, fill = "red", color = "black")
# Distribution of transformed data
ggplot(data = data, aes(x = nu_X)) +
geom_histogram(aes(y = ..density..), bins = 25, fill = "green", color = "black")
In short, you can't, or rather, you shouldn't.
ggplot is a high-level plotting packaging. More than a system for drawing shapes and lines, it's fairly "opinionated" about how data should be represented, and one of its opinions is that a plot should express a clear relationship between its axes and marks (points, bars, lines, etc.). The axes essentially define a coordinate space, and the marks are then plotted onto the space in a straightforward and easily interpretable manner.
The plot you show breaks that relationship -- it's a set of essentially arbitrary histograms all drawn onto the same box, where the axis values become ambiguous. The x-axis represents the values of 1 histogram and the y-axis represents another (and thus neither axis represents the histograms' heights).
It is of course technically possible to force ggplot to render something like your example, but it would require pre-computing the histograms, normalizing their values and bin heights to a common coordinate space, converting these into suitable coordinates for use with geom_rect, and then re-labeling the plot axes. It would be a very large amount of manual effort and ultimately defeats the point of using a high-level plotting grammar like ggplot.

Defining outer edge of filled 2d Contour plot in plotly

Problem: I am trying to reproduce a round filled 2d contour plot in R using plotly (have tried ggplot2 also but plotly seemed to be easier).
Data: Sample data download link -
https://drive.google.com/file/d/10Mr5yWVReQckPI6TKLY_vzPT8zWiijKl/view?usp=sharing
The data to be plotted for contour is in a column format and typically called z variable, there is x and y data also available for all values of z. A simple dataframe would look like this:
Please ignore the repeat common x and y as I have truncated decimals. The data has about 25000 rows.
Approach: I first use akima package to interpolate z variable values for given x and y to map z in 2d. This makes the z column data fit in a xy grid for 2d plotting and show contours.
Expected outcome:
Code used:
dens <- akima::interp(x = dt$`Xvalue(mm)`,
y = dt$`Yvalue(mm)`,
z = dt$Values,
duplicate = "mean",
xo=seq(min(dt$`Xvalue(mm)`), max(dt$`Xvalue(mm)`), length = 10),
yo=seq(min(dt$`Yvalue(mm)`), max(dt$`Yvalue(mm)`), length = 10))
plot_ly(x = dens$x,
y = dens$y,
z = dens$z,
colors = c("blue","grey","red"),
type = "contour")
Actual outcome:
Help Needed:
To refine edges of the actual outcome plot to something of a close match to the expected outcome image.
Many thanks in advance for your comments and help.
I found that I could increase the grid output z matrix from akima::interp() from default 40x40 to custom using nx and ny input in function.
And then in plot_ly() add contours = list(coloring = 'fill', showlines = FALSE) to hide contour lines to get output close to my expected outcome.
So working code is like this:
dens <- akima::interp(x = dt$`Xvalue(mm)`,
y = dt$`Yvalue(mm)`,
z = dt$Values,
nx = 50,
ny = 50,
duplicate = "mean",
xo=seq(min(dt$`Xvalue(mm)`), max(dt$`Xvalue(mm)`), length = 50),
yo=seq(min(dt$`Yvalue(mm)`), max(dt$`Yvalue(mm)`), length = 50))
plot_ly(x = dens$x,
y = dens$y,
z = dens$z,
colors = c("blue","grey","red"),
type = "contour",
contours = list(coloring = 'fill', showlines = FALSE))
Plotly contour plot reference was very helpful in this case:
https://plot.ly/r/reference/#contour

R: Plotting a scatterplot over a filled.contour plot

I am very new to R and have made a filled.contour plot using interpolated data like the data found in Plotting contours on an irregular grid . Using some sample data from Plotting contours on an irregular grid , I made a filled.contour and simple scatterplot using the following codes
x <- datr$Lat
y <- datr$Lon
z <- datr$Rain
require(akima)
fld <- interp(x,y,z)
filled.contour(fld)
plot(x,y)
Is there a way to make the plot(x,y) and filled.contour(fld) on the same plot (overlaying)? I have tried the points(x,y), but this doesn't match the x and y axes. In Matlab, I believe I would do this with hold, but I am unsure how to do it on R.
Thanks!
You could use the arguments plot.title or plot.axes for that:
x <- 10*1:nrow(volcano)
y <- 10*1:ncol(volcano)
filled.contour(x, y, volcano, plot.title = {
points(x = 200, y = 200)
})
(via)
One way is to read the code for filled.contour, and do a
little hacking like so:
Make your figure:
filled.contour(fld)
Define these constants by copying them from the arguments list.
nlevels = 20
zlim = range(z, finite = TRUE)
las = 1
levels = pretty(zlim, nlevels)
xlim = range(x, finite = TRUE)
ylim = range(y, finite = TRUE)
xaxs = "i"
yaxs = "i"
asp = NA
Calculate these values by copying code from the function body
mar.orig <- (par.orig <- par(c("mar", "las", "mfrow")))$mar
w <- (3 + mar.orig[2L]) * par("csi") * 2.54
Set the layout by copying code from the function body
layout(matrix(c(2, 1), ncol = 2L), widths = c(1, lcm(w)))
Noteice that the figure is actually plotted after the color scale,
but we don't wnat to reverse the order of the layout because layout
actually sets the 'current' region as the last region because the
first call to plot.new will cause the current region to wrap around
to the first region. Hence, when you set the plot window and plot the points via:
plot.window(ylim=ylim,xlim=xlim)
points(x,y)
title(main='title',
sub='Sub-Title',
xlab='This is the x axis',
ylab='This is the y axis')
They overlay figure as desired.

R - How to set the range of the colorscale in a hexbin plot

I am making a scatter plot matrix using hexbin plots to show the density of certain areas.
Example:
library(lattice)
library(hexbin)
splom(cbind(rnorm(10000),rnorm(10000),rnorm(100),rnorm(100)),
,varnames = c("A","B","C","D")
,panel = panel.hexbinplot
,lower.panel = function(x, y, ...) {
panel.fill(col = brewer.pal(9, "Greys")[ round(cor(x, y,method = "spearman") * 4 + 2)])
cpl <- current.panel.limits()
panel.text(mean(cpl$xlim), mean(cpl$ylim), round(cor(x, y,method = "spearman"),2), font=2)
}
,upper.panel = function(x, y, ...){
panel.hexbinplot(x, y, type = "r", xbins = 10, ...)
}
,pscale=0, varname.cex=1, xlab = ""
)
It seems to me, that the colorscale, i.e. which count applies to which color, is recalculated in each of the 6 hexbin plots. It doesn't make a difference here but it does in my data. How can I set all these to ONE scale, meaning that a hexagon with 25 counts has the same color in all 6 plots, no matter if the maximum count in the plot is 25 or 150.
Thanks a lot in advance.
Maybe too late, but if somebody else is having the same question...Try using the argument maxcnt, it worked for me using the package Opeanair. I generated 4 plots and every one has the same color ramp: the hexagons with the same number of counts have the same color.

Plotting a 3D surface with no interpolation?

I have a following data:
library(rgl)
x <- c(rep(1,6),
rep(3,6),
rep(6,6),
rep(9,6),
rep(12,6))
y <- c(1.35,1.39,1.48,1.29,1.35,1.32,
NA,1.5,1.44,1.6,1.5,1.41,
NA,NA,1.72,1.56,1.6,1.55,
NA,NA,NA,1.95,1.9,1.75,
NA,NA,NA,NA,2.05,1.95)
z <- rep(1:6,5)
open3d()
plot3d(x,y,z, type = 'n')
lines3d(x,y,z)
Which is plotting lines in 3d as I expect.
But I cannot get it to plot a surface3d.
As I already read some threads I might need to interpolate my data. RGL docs has not cover this subject well. I tried akima but it doesn't accept NA's.
I would like to link lines to create a surface in linear way. I aware of the NA, so I expect that surface will be decreasing in the area for bigger x (more NA's).
Do I need to perform interpolation? If yes, how to do that on my sample data?
If no, how to achieve the surface3d on my sample data?
Thanks
the solution comes to me from this thread:
Making a wireframe plot from an x,y,z data.frame
below code will work for the sample data provided above (just switch x->y,y->z,z->x)
zmat <- matrix(data = z, nrow = 6, ncol = 5, byrow = FALSE)
surface3d(x = 1:6, y = c(1,3,6,9,12), z = zmat, alpha = 0.4, colour = 'blue')

Resources