I have a standard ISO8601 date string:
2004-02-12T15:19:21+00:00
I want to know if this date is older than 10 minutes ago in Flex. So basically:
if ("2004-02-12T15:19:21+00:00" > current_time - 10mins) {
// do whatever
}
What would the syntax be in Flex? I'm basically stuck at trying to convert the string into a Flex Date Object without parsing it character by character.
If you don;t care about the timezone i.e. the date string is in the same timezone as where you are running the application then this should work.
var date:Date = DateFormatter.parseDateString("2004-02-12T15:19:21+00:00");
var now:Date = new Date();
var tenMinAgo:Number = now.time - 1000*60*10;
if (date.time < tenMinAgo) {
trace("More than 10 min ago");
}
Related
Say I have a string
"1974-03-20 00:00:00.000"
It is created using DateTime.now(),
how do I convert the string back to a DateTime object?
DateTime has a parse method
var parsedDate = DateTime.parse('1974-03-20 00:00:00.000');
https://api.dartlang.org/stable/dart-core/DateTime/parse.html
There seem to be a lot of questions about parsing timestamp strings into DateTime. I will try to give a more general answer so that future questions can be directed here.
Your timestamp is in an ISO format. Examples: 1999-04-23, 1999-04-23 13:45:56Z, 19990423T134556.789. In this case, you can use DateTime.parse or DateTime.tryParse. (See the DateTime.parse documentation for the precise set of allowed inputs.)
Your timestamp is in a standard HTTP format. Examples: Fri, 23 Apr 1999 13:45:56 GMT, Friday, 23-Apr-99 13:45:56 GMT, Fri Apr 23 13:45:56 1999. In this case, you can use dart:io's HttpDate.parse function.
Your timestamp is in some local format. Examples: 23/4/1999, 4/23/99, April 23, 1999. You can use package:intl's DateFormat class and provide a pattern specifying how to parse the string:
import 'package:intl/intl.dart';
...
var dmyString = '23/4/1999';
var dateTime1 = DateFormat('d/M/y').parse(dmyString);
var mdyString = '04/23/99';
var dateTime2 = DateFormat('MM/dd/yy').parse(mdyString);
var mdyFullString = 'April 23, 1999';
var dateTime3 = DateFormat('MMMM d, y', 'en_US').parse(mdyFullString));
See the DateFormat documentation for more information about the pattern syntax.
DateFormat limitations:
DateFormat cannot parse dates that lack explicit field separators. For such cases, you can resort to using regular expressions (see below).
Prior to version 0.17.0 of package:intl, yy did not follow the -80/+20 rule that the documentation describes for inferring the century, so if you use a 2-digit year, you might need to adjust the century afterward.
As of writing, DateFormat does not support time zones. If you need to deal with time zones, you will need to handle them separately.
Last resort: If your timestamps are in a fixed, known, numeric format, you always can use regular expressions to parse them manually:
var dmyString = '23/4/1999';
var re = RegExp(
r'^'
r'(?<day>[0-9]{1,2})'
r'/'
r'(?<month>[0-9]{1,2})'
r'/'
r'(?<year>[0-9]{4,})'
r'$',
);
var match = re.firstMatch(dmyString);
if (match == null) {
throw FormatException('Unrecognized date format');
}
var dateTime4 = DateTime(
int.parse(match.namedGroup('year')!),
int.parse(match.namedGroup('month')!),
int.parse(match.namedGroup('day')!),
);
See https://stackoverflow.com/a/63402975/ for another example.
(I mention using regular expressions for completeness. There are many more points for failure with this approach, so I do not recommend it unless there's no other choice. DateFormat usually should be sufficient.)
import 'package:intl/intl.dart';
DateTime brazilianDate = new DateFormat("dd/MM/yyyy").parse("11/11/2011");
you can just use : DateTime.parse("your date string");
for any extra formating, you can use "Intl" package.
void main() {
var dateValid = "30/08/2020";
print(convertDateTimePtBR(dateValid));
}
DateTime convertDateTimePtBR(String validade)
{
DateTime parsedDate = DateTime.parse('0001-11-30 00:00:00.000');
List<String> validadeSplit = validade.split('/');
if(validadeSplit.length > 1)
{
String day = validadeSplit[0].toString();
String month = validadeSplit[1].toString();
String year = validadeSplit[2].toString();
parsedDate = DateTime.parse('$year-$month-$day 00:00:00.000');
}
return parsedDate;
}
a string can be parsed to DateTime object using Dart default function DateTime.parse("string");
final parsedDate = DateTime.parse("1974-03-20 00:00:00.000");
Example on Dart Pad
String dateFormatter(date) {
date = date.split('-');
DateFormat dateFormat = DateFormat("yMMMd");
String format = dateFormat.format(DateTime(int.parse(date[0]), int.parse(date[1]), int.parse(date[2])));
return format;
}
I solved this by creating, on the C# server side, this attribute:
using Newtonsoft.Json.Converters;
public class DartDateTimeConverter : IsoDateTimeConverter
{
public DartDateTimeConverter()
{
DateTimeFormat = "yyyy'-'MM'-'dd'T'HH':'mm':'ss.FFFFFFK";
}
}
and I use it like this:
[JsonConverter(converterType: typeof(DartDateTimeConverter))]
public DateTimeOffset CreatedOn { get; set; }
Internally, the precision is stored, but the Dart app consuming it gets an ISO8601 format with the right precision.
HTH
A similar question to a previous one I asked, but the difference being that this not for direct rendering from an underlying field - it's instead part of a some SSJS.
This is for a view column which displays the result of a SSJS function, which returns HTML that gets rendered. This HTML includes a date from a DateTime field, which gets converted to text using #Text. The problem I have with this is, #Text converts dates using the locale settings of the server, not the browser.
Is there an alternative to #Text(dateValue,"D0S0") that's browser locale aware?
The most "XPagey" way to do this is to use a date/time converter. For example (using a stand-in for the computed value):
<xp:viewColumn columnName="">
<xp:this.value><![CDATA[#{javascript:
new java.util.Date()
}]]></xp:this.value>
<xp:this.converter>
<xp:convertDateTime type="both"/>
</xp:this.converter>
</xp:viewColumn>
That "convertDateTime", with its built-in formats, will respect the browser's provided locale. If you set the option in the Xsp Properties to use the browser's time zone and "Round trip", it should also respect the user's time zone.
I've managed to get round this by using DateFormat.getDateInstance. The only problem with this is it doesn't return a short date in the same format as the XPage date converter (no leading zeros and a 2-figure year). I've got round this though with some fiddling around with the string after.
Here's the full function:
function returnLocalShortDate(ndtDate) {
// Receives NotesDateTime object, Java date or string; returns localised date string in XPages short date format
importPackage(java.text);
if (#IsText(ndtDate)) { // string
var jsDate = #TextToTime(ndtDate);
} else if (ndtDate instanceof Date) { // Java date
var jsDate:Date = ndtDate;
} else if (#IsTime(ndtDate)) { // Notes date/time
var jsDate:Date = ndtDate[0].toJavaDate();
} else {
return("");
}
var strDate:String = java.text.DateFormat.getDateInstance(DateFormat.SHORT, context.getLocale()).format(jsDate);
var strYear = jsDate.getFullYear();
var strDateArray = strDate.split("/");
strDate = ('0' + strDateArray[0]).slice(-2) + '/' + ('0' + strDateArray[1]).slice(-2) + '/' + strYear;
return(strDate);
}
Actually, if you know the format you want, rather than what the user might want via their browser settings, you should use the SimpleDateFormatter class. You can supply the format in accordance with whatever pattern you want from the javadocs for that class. If you supply the NotesDocument object and the field name, this returns the date in dd-MMM-yyyy format.
function getFormattedDate ( doc:NotesDocument, fieldName:String ) {
importPackage(java.text);
var dateFormatter:java.text.SimpleDateFormat = new SimpleDateFormat("dd-MMM-yyyy");
var d:Date = new Date(#Today());
if ( doc.hasItem (fieldName) ) {
var valueVector:java.util.Vector = doc.getItemValueDateTimeArray(fieldName);
var iterator = valueVector.iterator();
while (iterator.hasNext()) {
var itemvalue = iterator.next();
if ((typeof(itemvalue)).endsWith("DateTime")) {
d = new Date(itemvalue.toJavaDate());
return dateFormatter.format(d);
}
}
} else {
return fieldName + " is not on the document"
}
}
I owe credit to Declan Lynch's blog entry on date formatting, which takes a little debugging because SSJS returns the date value as an Vector now.
WinRT uses the DateTimeFormatter class to turn timestamps into human-readable dates. In C++CX, you'll pass it a DateTime instance, which contains a timestamp in UTC time, and let it work its magic.
However, I have an application that consumes timestamps in local time. I'd like to format them and show them to my users, but if I pass the timestamp as is, the DateTimeFormatter will assume that it's UTC and will try to convert it to local time again, resulting in incorrect times.
How can I display local time with WinRT? Is there a way to turn back local time into UTC time?
The timestamps are generated from the machine that consumes them, so there is no risk of timezone confusion. It would also be technically feasible to produce UTC timestamps instead, but this would be rather inconvenient and I'd like to fall back to that only if it's the only way.
Thankfully, FileTimeToSystemTime, TzSpecificLocalTimeToSystemTime and SystemTimeToFileTime are all available to Windows store apps. With that, it's possible to create a function to change local back to UTC.
uint64 LocalTimeToUtcTime(uint64 local)
{
LARGE_INTEGER largeTime;
largeTime.QuadPart = local;
FILETIME intermediate;
intermediate.dwHighDateTime = largeTime.HighPart;
intermediate.dwLowDateTime = largeTime.LowPart;
SYSTEMTIME systemLocal, systemUtc;
if (!FileTimeToSystemTime(&intermediate, &systemLocal))
{
// handle error
}
if (!TzSpecificLocalTimeToSystemTime(nullptr, &systemLocal, &systemUtc))
{
// handle error
}
if (!SystemTimeToFileTime(&systemUtc, &intermediate))
{
// handle error
}
largeTime.HighPart = intermediate.dwHighDateTime;
largeTime.LowPart = intermediate.dwLowDateTime;
return largeTime.QuadPart;
}
You can use the Windows::Globalization::Calendar class to work with local time, or with time in any time zone.
The Calendar defaults to the local time zone if you don't explicitly set one. You can then use GetDateTime() to retrieve a Windows::Foundation::DateTime instance that can be used with DateTimeFormatter.
Calendar^ cal = ref new Calendar();
cal->SetToMin();
cal->Year = 2014;
cal->Month = 7;
cal->Day = 14;
cal->Hour = 12;
cal->Minute = 34;
cal->Second = 56;
DateTime dt = cal->GetDateTime();
DateTimeFormatter^ dtf = ref new DateTimeFormatter("shortdate shorttime");
String^ result = dtf->Format(dt);
Logger::WriteMessage(result->Data());
I have a flex Array Collection created from a live XML data source and am trying to use my date/time string in the array to SORT the array prior to having the UI display the info / listing... currently the array is created and displays fine but the sorting by date / time is NOT working properly...
The routine works if I change the sort field (dataSortField.name) to 'name' (just alphanumeric text string based on filenames generated by my xml source), but if I use 'datemodified' as the sort field ( i.e. 7/24/2013 12:53:02 PM ) it doesn't sort it by date, just tries to sort alphabetically so the date order is not proper at all and for example it shows 1/10/2013 10:41:57 PM then instead of 2/1/2013 11:00:00 PM next it shows 10/10/2013 5:37:18 PM. So its using the date/time as a regular text string
// SORTING THE ARRAY BY DATE DESCENDING...
var dataSortField:SortField = new SortField();
dataSortField.name = "datemodified";
dataSortField.descending = false;
var arrayDataSort:Sort = new Sort();
arrayDataSort.fields = [dataSortField];
arr.sort = arrayDataSort;
arr.refresh();
Now if I CHANGE the dataSortField.name to "name" (which are alphanumeric filenames) it sorts a-z just fine... so How do I get it to sort by DATE where my array data looks like 7/24/2013 12:00:00 PM
Now the TIME part of the date isnt necessary for my sorting needs at all, so Im just looking to sort by date and beyond that the time doesnt matter for my needs but is hard coded in my xml data source.
I tried specifying
dataSortField.numeric = true;
but that didnt work either and while I can use it to specify string or numeric theres not a DATE option as I was expecting.
so my question, to clarify, is how do I make the SORT function acknowledge that I want to sort based on a series of date / time stamps in my array? Im using apache flex 4.9.1 / fb 4.6 premium).
I use this as a date compare function:
public static function genericSortCompareFunction_Date(obj1:Object, obj2:Object):int{
// * -1 if obj1 should appear before obj2 in ascending order.
// * 0 if obj1 = obj2.
// * 1 if obj1 should appear after obj2 in ascending order.
// if you have an XML Datasource; you'll have to do something here to get the
// date objects out of your XML and into value1 and value2
var value1:Date = obj1.dateField;
var value2:Date = obj2.dateField;
if(value1 == value2){
return 0;
}
if(value1 < value2){
return -1;
}
return 1;
}
To apply this to your code; you would do something like this:
var arrayDataSort:Sort = new Sort();
arrayDataSort.compareFunction = genericSortCompareFunction_Date;
arr.sort = arrayDataSort;
arr.refresh();
I am taking date input from user in text field, which is in format DD/MM/YYYY.
How to convert this string to date object in Flex.
Platform: Adobe Flash Builder 4.6
Since Flex SDK 4.10.0 you can use
DateFormatter.parseDateString(s, "DD/MM/YYYY");
Former versions of parseDateString didn't respect a format string, so it cannot parse dateString value formatted with non default en_US format
Use DateField's stringToDate method. DateFormatter also has a parseDateString function but for some reason it's set to protected.
public function convertStringToDate(s:String):Date
{
return DateField.stringToDate(s, "DD/MM/YYYY");
}
If you are not on the latest Apache SDK (I know we aren't because of third party components) you basically have to write your own conversion.
The built in DateFormatter has the static method, parseDateString, but you have no way of specifying the format of the string. It was a bit rubbish!
If you definitely have no localisation issues and are sure the date is ALWAYS in DD/MM/YYYY format you could use the following:
public function stringToDate(date:String):Date {
// Extract year, month and day from passed in date string
var year:int = IntFromSubString(date, 6, 4);
var month:int = IntFromSubString(date, 3, 2);
var day:int = IntFromSubString(date, 0, 2);
// Always remember Flex months start from 0 (Jan=0, Feb=1 etc.) so take 1 off the parsed month
return new Date(year, month-1, day);
}
private static function IntFromSubString(date:String, start:int, length:int):int {
return parseInt(date.substr(start, length)) as int;
}