I'm getting a weird error in console after the command 'route:debug'.
`
[Symfony\Component\Config\Exception\FileLoaderLoadException]
Cannot import resource "....../src/Acme/MyBundle/Resources/config/routes.yml"
from "....../app/config/routing.yml".
(Class could not be determined for Controller identified by
"Acme\MyBundle\Controller
\ ageController"
`
where in Acme/MyBundle/config/routes.yml I have
resource: "Acme\MyBundle\Controller\PageController"
linked from app/config/routing.yml
resource: "#AcmeMyBundle/Resources/config/routes.yml"
By examining the code it seems that for some reason Yaml::parse($path) returns in $config['resource'] the controller name as "ageController", without the "P" letter
...Where am I so wrong?
Many thanks
--------EDIT-------
Thanks for the useful response from #piotrekkr.
By escaping "P" char, it works. thanks Piottekr
So it became:
Acme\MyBundle\Controller\\PageController
I think the reason is that \P is special character in YAML. From http://yaml.org/spec/1.2/spec.html#id2776092
5.7. Escaped Characters
All non-printable characters must be escaped. YAML escape sequences
use the “\” notation common to most modern computer languages. Each
escape sequence must be parsed into the appropriate Unicode character.
The original escape sequence is a presentation detail and must not be
used to convey content information.
Note that escape sequences are only interpreted in double-quoted
scalars. In all other scalar styles, the “\” character has no special
meaning and non-printable characters are not available.
And the character
[58] ns-esc-paragraph-separator ::= “P” - Escaped Unicode paragraph separator (#x2029) character.
Try using \\P in your YAML
Related
I have a $text = "Hello 😀😃😄 💜 🙏🏻 🦦üäö$"
I wanted to remove just emoji's from the text using xquery. How can i do that?
Expected result : "Hello üäö$"
i tried to use:
replace($text, '\p{IsEmoticons}+', '')
but didn't work.
it just removed smiley's
Result now: "Hello 💜 🙏🏻 🦦üäö$"
Expected result : "Hello üäö$"
Thanks in advance :)
I outlined the approach in my answer to the original question, which I updated based on your comment asking about how to strip out 💜.
Quoting from that expanded answer:
The "Emoticons" block doesn't contain all characters commonly associated with "emoji." For example, 💜 (Purple Heart, U+1F49C), according to a site like https://www.compart.com/en/unicode/U+1F49C that lets you look up Unicode character information, is from:
Miscellaneous Symbols and Pictographs, U+1F300 - U+1F5FF
This block is not available in XPath or XQuery processors, since it is neither listed in the XML Schema 1.0 spec linked above, nor is it in Unicode block names for use in XSD regular expressions—a list of blocks that XPath and XQuery processors conforming to XML Schema 1.1 are required to support.
For characters from blocks not available in XPath or XQuery, you can manually construct character classes. For example, given the purple heart character above, we can match it as follows:
replace("Purple 💜 heart", "[🌀-🗿]", "")
This returns the expected result:
Purple Heart
This approach can be applied to 🙏🏻 , 🦦, or any other character:
Locate the character's unicode block.
Craft your regular expression with the block name (if available in XPath) or character class.
Alternatively, rather than locating the blocks of characters you want to strip out, you could identify the blocks of characters you want to preserve. For example, given the example string in the original post, perhaps the goal is to preserve only those characters in the "Basic Latin" block. To do so, we can match characters NOT in this block via the \P Category Escape:
xquery version "3.1";
let $text := "Hello 😀😃😄 💜 🙏🏻 🦦üäö$"
return
replace($text, "\P{IsBasicLatin}", "")
This query returns:
Hello $
Notice that this has stripped out the characters with diacritics, which perhaps isn't desired. These characters with diacritics belong to the Latin-1 Supplement block. To preserve characters from both the Latin and Latin-1 Supplement blocks, we'd need to adjust the query as follows:
xquery version "3.1";
let $text := "Hello 😀😃😄 💜 🙏🏻 🦦üäö$"
return
replace($text, "[^\p{IsBasicLatin}\p{IsLatin-1Supplement}]", "")
... which returns:
Hello üäö$
This now preserves the characters with diacritics.
To be precise about the characters you preserve or remove, you need to consult the Unicode blocks and charts.
I have a URL like that: localhost:8080/demo/
And when I call localhost:8080/demo/''''''''' It working fine.
But when I try with localhost:8080/demo/;;; It not working and return HTTP code 404 Not Found.
I tried with few special character # % \ ? / , it returned 400 too.
Anyone can explain it for me?
Thank you so much!
These special characters are not directly allowed in URLs,
because they have special meanings there.
For example:
/ is separator within the path,
? marks the query-part of an URL,
# marks a page-internal link,
etc.
Quoted from Wikipedia: Percent-encoding reserved characters:
When a character from the reserved set (a "reserved character")
has special meaning (a "reserved purpose") in a certain context,
and a URI scheme says that it is necessary to use that character
for some other purpose, then the character must be percent-encoded.
Percent-encoding a reserved character involves converting the
character to its corresponding byte value in ASCII and then
representing that value as a pair of hexadecimal digits. The digits,
preceded by a percent sign (%) which is used as an escape character,
are then used in the URI in place of the reserved character.
For example: ; is a reserved character. Therefore, when ; shall occur
in an URL but without having its special meaning, then it needs to be
replaced by %3B as defined here
For example, in Unix, a backslash (\) is a common escape character. So to escape a full stop (.) in a regular expression, one does this:
\.
But with % encoding URL parameters, we have an escape character, %, and a control code, so an ampersand (&) doesn't become:
%&
Instead, it becomes:
%26
Any reason why? Seems to just make things more complicated, on the face of it, when we could just have one escape character and a mechanism to escape itself where necessary:
%%
Then it'd be:
simpler to remember; we just need to know which characters to escape, not which to escape and what to escape them to
encoding-agnostic, as we wouldn't be sending an ASCII or Unicode representation explicitly, we'd just be sending them in the encoding the rest of the URL is going in
easy to write an encoder: s/[!\*'();:#&=+$,/?#\[\] "%-\.<>\\^_`{|}~]/%&/g (untested!)
better because we could switch to using \ as an escape character, and life would be simpler and it'd be summer all year long
I might be getting carried away now. Someone shoot me down? :)
EDIT: replaced two uses of "delimiter" with "escape character".
Percent encoding happens not only to escape delimiters, but also so that you can transport bytes that are not allowed inside URIs (such as control characters or non-ASCII characters).
I guess it's because the URL Specification and specifically the HTTP part of it, only allow certain characters so to escape those one must replace them with characters that are allowed.
Also some allowed characters have special meanings like & and ? etc
so replacing them with a control code seems the only way to solve it
If you find it hard to recognize them, bookmark this page
http://www.w3schools.com/tags/ref_urlencode.asp
Windows copies path with backslash \, which R does not accept. So, I wanted to write a function which would convert \ to /. For example:
chartr0 <- function(foo) chartr('\','\\/',foo)
Then use chartr0 as...
source(chartr0('E:\RStuff\test.r'))
But chartr0 is not working. I guess, I am unable to escape /. I guess escaping / may be important in many other occasions.
Also, is it possible to avoid the use chartr0 every time, but convert all path automatically by creating an environment in R which calls chartr0 or use some kind of temporary use like using options
From R 4.0.0 you can use r"(...)" to write a path as raw string constant, which avoids the need for escaping:
r"(E:\RStuff\test.r)"
# [1] "E:\\RStuff\\test.r"
There is a new syntax for specifying raw character constants similar to the one used in C++: r"(...)" with ... any character sequence not containing the sequence )". This makes it easier to write strings that contain backslashes or both single and double quotes. For more details see ?Quotes.
Your fundamental problem is that R will signal an error condition as soon as it sees a single back-slash before any character other than a few lower-case letters, backslashes themselves, quotes or some conventions for entering octal, hex or Unicode sequences. That is because the interpreter sees the back-slash as a message to "escape" the usual translation of characters and do something else. If you want a single back-slash in your character element you need to type 2 backslashes. That will create one backslash:
nchar("\\")
#[1] 1
The "Character vectors" section of _Intro_to_R_ says:
"Character strings are entered using either matching double (") or single (') quotes, but are printed using double quotes (or sometimes without quotes). They use C-style escape sequences, using \ as the escape character, so \ is entered and printed as \, and inside double quotes " is entered as \". Other useful escape sequences are \n, newline, \t, tab and \b, backspace—see ?Quotes for a full list."
?Quotes
chartr0 <- function(foo) chartr('\\','/',foo)
chartr0('E:\\RStuff\\test.r')
You cannot write E:\Rxxxx, because R believes R is escaped.
The problem is that every single forward slash and backslash in your code is escaped incorrectly, resulting in either an invalid string or the wrong string being used. You need to read up on which characters need to be escaped and how. Take a look at the list of escape sequences in the link below. Anything not listed there (such as the forward slash) is treated literally and does not require any escaping.
http://cran.r-project.org/doc/manuals/R-lang.html#Literal-constants
I'm trying to create a RegEx Validator that checks the file extension in the FileUpload input against a list of allowed extensions (which are user specified). The following is as far as I have got, but I'm struggling with the syntax of the backward slash (\) that appears in the file path. Obviously the below is incorrect because it just escapes the (]) which causes an error. I would be really grateful for any help here. There seems to be a lot of examples out there, but none seem to work when I try them.
[a-zA-Z_-s0-9:\]+(.pdf|.PDF)$
To include a backslash in a character class, you need to use a specific escape sequence (\b):
[a-zA-Z_\s0-9:\b]+(\.pdf|\.PDF)$
Note that this might be a bit confusing, because outside of character classes, \b represents a word boundary. I also assumed, that -s was a typo and should have represented a white space. (otherwise it shouldn't compile, I think)
EDIT: You also need to escape the dots. Otherwise they will be meta character for any character but line breaks.
another EDIT: If you actually DO want to allow hyphens in filenames, you need to put the hyphen at the end of the character class. Like this:
[a-zA-Z_\s0-9:\b-]+(\.pdf|\.PDF)$
You probably want to use something like
[a-zA-Z_0-9\s:\\-]+\.[pP][dD][fF]$
which is same as
[\w\s:\\-]+\.[pP][dD][fF]$
because \w = [a-zA-Z0-9_]
Be sure character - to put as very first or very last item in the [...] list, otherwise it has special meaning for range or characters, such as a-z.
Also \ character has to be escaped by another slash, even inside of [...].