CSS3 full-width rotate - css

I would like to rotate a full-width div (from side to side without free space) in which will be some content.
I want the corners on the right side to touch the right side of the page and the corners on the left side to touch the left side of the page. I don't think width:200% and overflow-x:hidden is the best solution.
How can I achieve this?
Here is an example. Note that the corners don't touch the sides of the page.
.rotated {
width: 100%;
height: 100px;
background-color: red;
-moz-transform: rotate(-6deg);
-webkit-transform: rotate(-6deg);
-o-transform: rotate(-6deg);
-ms-transform: rotate(-6deg);
transform: rotate(-6deg);
}
<div class="rotated"></div>

You might find the CSS transform skewY() helpful. It will skew the element without rotating the corners.
I've also set the transform-origin to the top right so that the element doesn't skew off the top of the page.
html,body {
margin: 0;
}
.rotated {
height: 100px;
background-color: red;
-webkit-transform-origin: top right;
-ms-transform-origin: top right;
transform-origin: top right;
-webkit-transform: skewY(-6deg);
-ms-transform: skewY(-6deg);
transform: skewY(-6deg);
}
<div class="rotated"></div>
For further reference, see the Skewing and Translating example at MDN.

You could increase the horizontal proportion with scale, but the content will be scaled as well (as long as you know it you can compensate)
.rotated {
width: 100%;
height: 100px;
background-color: red;
transform: scale(1.2 , 1) rotate(-6deg);
}
<div class="rotated"></div>

Related

Rotate 45-degree element around vertical axis

I've got a series of elements, as shown in the image below:
They are rotated 45 degrees to one side (the content inside -45 degrees, to remain upright).
Now I'd like to rotate each element around a vertical axis, going through the element's center. RotateY doesn't work, as it is at a 45-degree angle.
How would you go about doing this?
The trick is to set this rotation before the 45 degrees rotation:
Notice also that to make the rotation behave really as expect, you need to set it to 0 in the base state
.container {
width: 200px;
height: 200px;
margin: 100px;
border: solid 1px;
transform: rotateY(0deg) rotate(45deg); /* needs Y at 0 deg to behave properly*/
transition: transform 2s;
}
.container:hover {
transform: rotateY(180deg) rotate(45deg); /* notice the order */
}
.inner {
margin: 50px;
transform: rotate(-45deg);
}
<div class="container">
<div class="inner">INNER</div>
</div>
This is how I interpret the question. I'm not very happy with the demo since it needs a lot of structure.
But maybe you can verify the behavior?
Basically I use a wrapper to rotate on the y-axis.
It is key to set the transform origin to the center.
The additional wrapper is used to prevent a flickering on mouse hover.
https://jsfiddle.net/nm59mqky/1/
.tile {
transform: rotateY(0);
transform-origin: center center;
}
.wrapper:hover .tile {
transform: rotateY(180deg);
}
I dont know exactly what your code looks like, but for a simple spinning tile (div) i would try something like this:
#keyframes rotate-vertical {
0% {
transform: rotate3d(0, 1, 0, 0deg);
}
100% {
transform: rotate3d(0, 1, 0, 360deg);
}
}
body {
padding: 20px;
}
.tile {
width: 65px;
height: 65px;
background-color: red;
text-align: center;
transform: rotate3d(0, 0, 1, 45deg);
display: inline-block;
}
.turndiv {
width: 65px;
}
.turndiv:hover {
animation: rotate-vertical 1.1s ease-out;
}
<div class="turndiv">
<div class="tile">
</div>
</div>
You could just do it with transform: rotate3d(); and without a parent div, but to keep it easy i did it like this.

Position AFTER transform in CSS?

Consider the following attempt to rotate a paragraph 90 degrees and position it so that the corner that was initially its top-left corner (and which therefore becomes its top-right corner after the rotation) ends up located at the top-right corner of the parent block.
HTML:
<!DOCTYPE html>
<html>
<body>
<div id="outer">
<p id="text">Foo bar</p>
</div>
</body>
</html>
CSS:
#outer {
border: solid 1px red;
width:600px;
height: 600px;
position: relative;
}
#text {
transform: rotate(90deg);
position: absolute;
top: 0;
right: 0;
}
In Firefox 19.0.2 on OS X 10.6.8, it fails. This appears to be because, despite the order in which the CSS properties were given, the transformation is applied after the positioning. In other words, the browser:
places #text such that its top-right corner is located at the top-right corner of the parent block, but only then
rotates it, with the result that what is now its top-right corner is not located at the top-right corner of the parent block.
As a result, the transform-origin property isn't much use here. If, for instance, one used transform-origin: top right; then #text would need to be moved downwards by the width it had before it was rotated.
My question: is there a way to tell the browser to apply the CSS positioning properties after the rotation; and if not, then is there instead a way to move #text downwards (e.g. using top:) by the width it had before it was rotated?
NB. Ideally the solution should not require setting a fixed width: for #text, and must not require JavaScript.
You can apply more than one transform to an element, and the order does matter. This is the simplest solution: http://jsfiddle.net/aNscn/41/
#outer {
border: solid 1px red;
width:600px;
height: 600px;
position: relative;
}
#text {
background: lightBlue;
position: absolute;
top: 0;
left: 0;
right: 0;
transform: translate(100%) rotate(90deg);
transform-origin: left top;
-webkit-transform: translate(100%) rotate(90deg);
-webkit-transform-origin: left top;
}
The transform origin is the point around which a transformation is applied. For example, the transform origin of the rotate() function is the center of rotation - https://developer.mozilla.org/en-US/docs/Web/CSS/transform-origin
Rotating -90deg.
.rotate {
position:absolute;
-webkit-transform-origin: left top;
/* Safari */
-webkit-transform: rotate(-90deg) translateX(-100%);
/* Firefox */
-moz-transform: rotate(-90deg) translateX(-100%);
/* IE */
-ms-transform: rotate(-90deg) translateX(-100%);
/* Opera */
-o-transform: rotate(-90deg) translateX(-100%);
}
Solved: here
This is the code I've added:
left: 100%;
width: 100%;
-webkit-transform-origin: left top;
I've also added some prefixed transform properties so it will be cross browser
-webkit-transform:rotate(90deg);
-moz-transform:rotate(90deg);
-ms-transform:rotate(90deg);
-o-transform:rotate(90deg);
transform:rotate(90deg);
How I did it:
I've found this question and, as the name of the website says, "fiddled" with the code to obtain this behavior. I guess the solution is left: 100%; instead of right: 0;.
(the width: 100%; is there because for some reason it wasn't 100% and the text would overflow to the next line)
You may want to try using CSS3 #keyframes animation. It will allow you to rotate and reposition in any order you like. Here is a tutorial that may help: [CSS-Tricks][1]
.container {
position: relative;
width: 200px;
height: 200px;
border: 1px solid red;
}
p {
border: 1px solid blue;
position: absolute;
top: auto;
right: 0;
display: inline-block;
margin: 0;
animation: 1s rotate 1s both;
}
#keyframes rotate {
0% {
transform-origin: top left;
transform: rotate(0deg);
right:0;
}
50% {
right:0;
}
100% {
transform-origin: top left;
transform: rotate(90deg);
right: -64px;
}
}
<div class="container">
<p>some text</p>
</div>
You might want to play around with the translate option which you can apply as the second transform function after rotate and place your element at the exact position that you want to.
There is no other way I guess to tell the browser to use the position properties after the transform function is used using plain css.
See this demo - http://codepen.io/anon/pen/klImq
Place "!important" at the end of the transform line.

Reset angle of text in skewed div using CSS

I have made a fiddle:
http://jsfiddle.net/89x4d/
I'm trying to maintain the skewed div but keep the p text straight.
Is this possible?
Thanks
You should use 20deg instead of 0deg on P to compensate for the DIV transform (since the result is the composition of transforms.)
In order to cancel the effect of the skew, you have to give positive value of transformation.
p {
-webkit-transform: skew(20deg) !important;
-moz-transform: skew(20deg) !important;
-o-transform: skew(20deg) !important;
transform: skew(20deg) !important;
}
Demo
div {
width: 200px;
height:50px;
background: red;
-webkit-transform: skew(-20deg);
-moz-transform: skew(-20deg);
-o-transform: skew(-20deg);
transform: skew(-20deg);
margin: 20px;
padding:0 25px;
}
p {
-webkit-transform: skew(20deg) !important;
-moz-transform: skew(20deg) !important;
-o-transform: skew(20deg) !important;
transform: skew(20deg) !important;
}
<div>
<p>hey i'm straight, ok?</p>
</div>
hey i'm straight, ok?
I'm not sure if you can get it to skew back, seems to distort the font too much.
skew(20) is the closest i could get, but instead you could setup 2 divs, 1 for a skew box and another to then move over it.
http://jsfiddle.net/gP9ne/3/
Setup a fiddle there for you to see
Martyn
edit: actually doesnt look any different :p i think its just the black on red with the font doesnt like my screen :p
always over thinking!
As others have pointed out, reversing the skew of the <p> can lead to some undesirable results.
It's also not super reusable in that for every new skew angle you would need a corresponding CSS selector/declaration to reverse the internal content.
As an alternative, use the :before selector to add the skewed element behind the text.
HTML
<div>
<p>hey i'm straight, ok?</p>
</div>
CSS
div {
width: 200px;
height:50px;
margin: 20px;
position:relative;
}
div:before {
content: "";
display:block;
background: red;
position:absolute;
width:100%;
height:100%;
z-index:-1;
-webkit-transform: skew(-20deg);
-moz-transform: skew(-20deg);
-o-transform: skew(-20deg);
transform: skew(-20deg);
}
And a demo.

CSS 3: text rotation bug?

I don't understand how text rotation works in CSS3.
For instance, you can see it here, the rotated text is never on the right location as you want it,
right: 0;
bottom: 0;
it will always have the gap/ margin to the right. and always overrun at the bottom of the box that contain it.
How can I fix this?
Can I use jquery to fix it or any reliable jquery plugin for text rotation out there ?
Thanks.
Positioning the text is not very difficult when you realize you can control the rotation point through...
transform-origin: 0 0 || top left
In your specific case, it works out like this:
.year
{
display: block;
writing-mode: tb-rl;
-webkit-transform: rotate(270deg);
-webkit-transform-origin: bottom left;
-moz-transform: rotate(270deg);
-moz-transform-origin: bottom left;
-o-transform: rotate(270deg);
-o-transform-origin: bottom left;
-ms-transform: rotate(270deg);
-ms-transform-origin: bottom left;
transform: rotate(270deg);
transform-origin: bottom left;
font-size: 24px;
position: absolute;
right: -50px; /*.year width*/
bottom: 0;
border: 1px solid #000000;
}
If you take out the transformation, you will notice that .year is positioned right next to it's parent box, bottom aligned. Then you specify the bottom left corner to be the "rotation point" and voila! Absolute control over your text positioning.
http://jsfiddle.net/PQ3Ga/
Positioning rotated text in CSS is very difficult. You have to remember that the position takes effect BEFORE the text is rotated. If you remove the rotation in your example, you will see that the unrotated text is correctly positioned.
To correctly position rotated text, you have to calculate how the rotation will affect the position...and then correct that position in the stylesheet.
In your case, you need:
position: absolute;
right: -11px;
bottom: 9px;

How to rotate the background image in the container?

I want to rotate the image which is placed in the button of scrollbar in Chrome. Now I have a CSS with this content:
::-webkit-scrollbar-button:vertical:decrement {
background-image: url(images/arrowup.png);
-webkit-transform: rotate(120deg);
-moz-transform: rotate(120deg);
background-repeat: no-repeat;
background-position: center;
background-color: #ECEEEF;
border-color: #999;
}
I wish to rotate the image without rotating its content.
Very well done and answered here – http://www.sitepoint.com/css3-transform-background-image/
#myelement:before {
content: "";
position: absolute;
width: 200%;
height: 200%;
top: -50%;
left: -50%;
z-index: -1;
background: url(background.png) 0 0 repeat;
transform: rotate(30deg);
}
Very easy method, you rotate one way, and the contents the other. Requires a square though
#element{
background : url('someImage.jpg');
}
#element:hover{
transform: rotate(-30deg);
}
#element:hover >*{
transform: rotate(30deg);
}
Update 2020, May:
Setting position: absolute and then transform: rotate(45deg) will provide a background:
div {
height: 200px;
width: 200px;
outline: 2px dashed slateBlue;
overflow: hidden;
}
div img {
position: absolute;
transform: rotate(45deg);
z-index: -1;
top: 40px;
left: 40px;
}
<div>
<img src="https://placekitten.com/120/120" />
<h1>Hello World!</h1>
</div>
Original Answer:
In my case, the image size is not so large that I cannot have a rotated copy of it. So, the image has been rotated with photoshop. An alternative to photoshop for rotating images is online tool too for rotating images. Once rotated, I'm working with the rotated-image in the background property.
div.with-background {
background-image: url(/img/rotated-image.png);
background-size: contain;
background-repeat: no-repeat;
background-position: top center;
}
Good Luck...
CSS:
.reverse {
transform: rotate(180deg);
}
.rotate {
animation-duration: .5s;
animation-iteration-count: 1;
animation-name: yoyo;
animation-timing-function: linear;
}
#keyframes yoyo {
from { transform: rotate( 0deg); }
to { transform: rotate(360deg); }
}
Javascript:
$(buttonElement).click(function () {
$(".arrow").toggleClass("reverse")
return false
})
$(buttonElement).hover(function () {
$(".arrow").addClass("rotate")
}, function() {
$(".arrow").removeClass("rotate")
})
PS: I've found this somewhere else but don't remember the source
I was looking to do this also. I have a large tile (literally an image of a tile) image which I'd like to rotate by just roughly 15 degrees and have repeated. You can imagine the size of an image which would repeat seamlessly, rendering the 'image editing program' answer useless.
My solution was give the un-rotated (just one copy :) tile image to psuedo :before element - oversize it - repeat it - set the container overflow to hidden - and rotate the generated :before element using css3 transforms. Bosh!
try making a div for the image only and then flipping it with transform: scaleY(-1); or transform: scaleX(-1);
if you want to have the navbar in front of the image you can make an overlapping div and set its opacity property to 0;
I tried all solutions but none helped, below is what was my problem and how I solved it:
Problem: we have an image for desktops with landscape orientation but To show the same image but rotated (portrait) for mobile screens.
How: I just rotated the actual image in my assets folder the way I wanted (portrait), and then just used media queries to call that image for my background for mobiles, and that's it.
(this was the easiest and quick solution I did.)
Update Dec 2021
Since the original question is
"..rotate the background image .."
The best answer looks to be here
https://stackoverflow.com/a/62135576/3446280

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