Can I automatically generate controller classes from FXML? - javafx

As I understand it, when using FXML to describe a Java FX scene, the controller class is written manually and it's member variables and methods can then be referenced from the .fxml file. When loading the scene using the FXMLLoader, member variables are set to the corresponding scene elements and methods are wired up to the corresponding events automatically. This works but is very cumbersome as changes need to be done in two places and any mistakes will only show up at runtime.
I've seen other GUI frameworks that allow you to instead generate the controller from a scene description as an abstract class which needs to be implemented to access the scene elements and handle the events. An example of what I mean:
I would create the following .fxml file (e.g. using the JavaFX Scene Builder):
<AnchorPane ... >
<children>
<Button fx:id="button" ... text="Button" onAction="#buttonPressed" />
</children>
</AnchorPane>
Somewhere in my build process, the following .java file would be created (e.g. using a Maven plugin):
abstract class TestController {
protected final Parent root;
protected final Button button;
{
// Load test.fxml file
// Assign scene elements to root and button
// Attach event handler to the button that calls buttonClicked()
}
protected abstract void buttonClicked(ActionEvent event);
}
I could then, possibly multiple times, create a concrete implementation of that controller:
final class TestControllerImpl extends TestController {
TestControllerImpl(String buttonLabel) {
button.setText(buttonLabel);
}
#Override
protected void buttonClicked(ActionEvent event) {
button.setText("I've been clicked! What a great day!");
}
}
Is there a project with the goal to do this? Or is there a problem with this approach applied to FXML?
I see the following benefits from this approach:
Declarations for member variables and methods for the controller are automatically generated.
All member variables are final and protected instead of non-final and either public or annotated.
The same for methods, they are protected instead of either public or annotated.
Not implementing a method or misspelling it's name will lead to a compiler error.
Programmatic setup of the scene can be done in the constructor instead of an initialize() method because the constructor will run after the scene has been loaded and its elements assigned to the member variables.

This is now supported in SceneBuilder, NetBeans and in Eclipse. Note this works out of the box in NetBeans and SceneBuilder, but in Eclipse you first need the e(fx)clipse plugin.
SceneBuilder:
With an FXML file open in the editor, enter the menu to select "View" and "Show Sample Controller Skeleton".
Eclipse:
Open the fxml file so the contents are displayed in the code editing pane (you should see the fxml as plaintext xml with syntax highlighting inside Eclipse, not rendered visually in SceneBuilder). Right-click on the code in Eclipse and select "Code" and then "Generate Controller".
NetBeans:
In NetBeans it is even easier, right-click the fxml file in the project explorer and select "Make Controller".

Update Nov 2020
This answer is now outdated.
As various more recent answers have pointed out, there are now a variety of additional different tools available for automatically generating FXML controller classes from FXML documents. Many of these are targeted as extensions, features or plugins to existing development tools, such as SceneBuilder, Idea, Eclipse or NetBeans.
I suggest that interested readers review both this answer and other answers to this question, then look at their individual use-case and toolset chain and choose the solution which is most appropriate for them from the available choices.
There is nothing I know that does exactly what you propose in your question.
Likely this answer will probably end up pretty outdated over time.
Alternate Technologies
JRuby achieves most of your outlined benefits using a slightly different approach - it uses jRuby's dynamic programming magic to automatically create Ruby class members from the FXML dynamically a runtime.
Tom Schindl wrote a tool which generates Java code from FXML. Of the approaches listed in this answer, Tom's tool seems closest to your question.
SceneBuilder Skeletons
A similar Java code generator from FXML is available in SceneBuilder View | Show Sample Controller Skeleton feature, which is described in this blog post. When I use SceneBuilder, I use this feature all the time and try to keep my controllers really light so they are almost all auto generated code from the SceneBuilder skeleton feature.
It is slightly annoying though because it doesn't achieve a clean separation of generated code from hand written code, so you need to be careful when you do updates to the FXML and want to generate a new skeleton and copy and paste it over parts of your existing Controller (plus that is a slightly error prone manual operation that takes a little bit of developer time).
Source code for SceneBuilder is available if you want to see how it works.
Potential Build Tool Plugins
Such a code generation feature might make a worthwhile addition to some of the existing build tools in the JavaFX ecosystem, such as the JavaFX Maven plugin or JavaFX Gradle plugin (or a separate plugin in it's own right).
Future Development
I believe that Oracle are also working on a feature extension for FXML for a future JavaFX release (post Java 8) which compiles FXML directly to Java byte code (class files), bypassing the Java source code step. This kind of feature would probably achieve most of your outlined benefits.

It is possible with NetBeans version 8.
Open FXML , go to Source and click generate controller.
Edit: Now can be done in any IDE , Eclipse needs a plugin thought.

For Intellij Idea IDE users, FXMLManager to the rescue. See the plugin homepage
"When clicking right mouse button on .fxml file, there is new menu item "Update Controller from FXML".
Clicking this item will modify FXML Java Controller:
Remove all #FXML fields that are missing in FXML and their getters/setters
Add all #FXML fields that are missing in Controller
#Deprecate all ActionEvent methods that are missing in FXML
Create all ActionEvent methods that are missing from Controller"

As I know, there are two kind of solutions exist in netbeans.
First, netbeans's internal feature "Make Controller", which you can see with right mouse click on the fxml document. it will generate controller class which will work with FXMLLoader. The controller's java file name should be indicated in the fxml document. (left panel -> Controller -> Controller class)
Parent root = FXMLLoader.load(getClass().getResource("FXMLDocument.fxml"));
Second, netbeans's plugin "FXML 2 JAVA Converter", which you can install from menu (Tool -> Plugin -> Available Plugin -> FXML 2 JAVA Converter). and you can see "Generate Abstract Class" menu item with right mouse click on the fxml document. It will generate source code from fxml document and you can use it as an abstract class without using FXMLLoader like normal JavaFX project not JavaFXML project.

Now you can easily do it with eclipse Just do these simple steps :
Go to your fxml file that you want to create Controller for
Right Click and Click source
Click Generate Controller
Click here to see the Picture of How to do it.

If you're using IntelliJ ide, you may have to try FXML Helper plugin.
First, install the plugin from the File | Settings... | Plugins. After the installation restart the ide, Now right click on the .fxml document and select the FXML Helper menu. That`s all.

#Feuermurmel
no there is not any ways to generate automatically controller class for particula .fxml file.
you should define dynamically declare variable and method with anotation #fxml and set(bind) in scence builder.

Related

Java FX multiple scenes crash [duplicate]

New to javaFx and wanting to use scenebuilder for GUI development, i've come across an issue with no luck searching the website nor the web in general for my problem, although similar questions have been asked, thought a different perspective could be needed. I am trying to load an FXML file through Netbeans after a quick build to test functionality so the code is simple, but i cannot get the root file to be set in the controller. my code is the following
public class Divergex extends Application {
#Override
public void start(Stage stage) throws Exception {
Parent root = FXMLLoader.load(getClass().getResource("DivergexGUI.fxml"));
Scene scene = new Scene(root);
scene.setRoot(root);
stage.setScene(scene);
stage.show();
}
Ive tried suggestions in changing fxroot to a Vbox with no luck, i continue to get a Load exception on the compile :
Exception in Application start method...
Caused by: javafx.fxml.LoadException: Root hasn't been set. Use method setRoot() before load.
yet when i use
scene.setRoot(root);
the same exception is experienced
i've narrowed the issue down to the fact that my FXML file is unable to be set as a root in the Parent object but have had no luck in tackling this. Any suggestions would be great thanks.
<fx:root> specifies a "dynamic root" for your FXML file; this means the root of the FXML file is an object that is set on the loader prior to loading the file. This is typically used for custom controls, where you want the control to be a subclass of Node that can be instantiated using regular Java code, but want to define its layout using FXML. Proper use of <fx:root> (or at least an example of how it can be used) is shown in the standard documentation. In particular, if you use <fx:root> you must:
Create an FXMLLoader instance, instead of using the static convenience FXMLLoader.load(URL) method
Call setRoot(...) on that instance, and pass in the object that is to be the root of the FXML.
For standard FXML use, you just use a regular instance declaration as the root. Almost every example available works this way: probably the best place to start is the official tutorial. In your case, since you want a VBox, you probably just need
<VBox xmlns="javafx.com/javafx/8"; xmlns:fx="javafx.com/fxml/1"; fx:controller="divergex.DivergexGUIController">
<!-- ... -->
</VBox>
Edit If Netbeans is giving you issues, I recommend using Eclipse with the e(fx)clipse plugin. There's a very barebones, but pretty much all you need, tutorial.
uncheck id::root in scence builder
or change id::root to vbox
Just you should not use fx:root construct in scene builder.
so remove this line of code from the fxml file.
For example: <fx:root prefHeight="246.0" prefWidth="479.0" type="AnchorPane" xmlns="http://javafx.com/javafx/8.0.141" xmlns:fx="http://javafx.com/fxml/1" fx:controller="application.mycontroller">
When you create FXML file with the help of Scene Builder. It uses fx: root as a pane. Replace it with Anchor Pane
AnchorPane xmlns="http://javafx.com/javafx/11.0.1" xmlns:fx="http://javafx.com/fxml/1" fx:controller="sample.controller.Controller
It works for me. Anyone can try, it may help for you

adding implementation and header files

Hi all i have created my code etc for the .h/.m that are all ready provided. But i would like to known how to add more because when i add a view controller to my storyboard. I can't have code in it i think what I'm looking for is called a second view controller .h/.m. I am creating a project in Xcode 4.2 and its a single view based application. I'm new to this but i think what i have said makes sense thanks for your time.
kind regards
open your project
press command+N to open the new file dialog
iOS > CocoaTouch
Class = YOUR_CLASS_NAME
Subclass of = SUBCLASS_TYPE (e.g. UIViewController)
etc.

Custome activity buid by an activity file

How can I use custom code (activity file not codeactivity neither activitydesginer ) as an Activity inside a Reshosted workflow designer?
I was doing the following for any activity, which I build for each ( codeactivity & activitydesginer) files, and wirte:
new ToolboxCategory("new Toolbox")
{
Tools=
{
new ToolboxItemWrapper(typeof(Flowchart)),
new ToolboxItemWrapper(typeof(SimpleWebDesigner.TEST)),
....etc
AnyHelp?
If you're talking about loading an Activity loaded from a loose xaml file, you can do this.
You have to use the the ActivityXamlServices class to Load(filename) the file at runtime. When you do this, you get the deserialized Activity instance. Of course, you must have any relevant assemblies (any assembly referenced by Activities defined in the xaml file) either loaded in the AppDomain or available for loading where the Fusion loader can find them.
Once you do this, you can create a ToolboxItemWrapper passing in activityInstance.GetType().
One thing, since the Activity xaml file is an Activity which holds other Activities, you will get the default Designer, which only shows a blank header. There is no easy way* to expand the child Activities defined in the xaml file in the designer when you drop them on the design surface.
*I believe you can construct a class that implements IActivityTemplateFactory which you can pass to the ToolboxItemWrapper which can pass the root Activity defined within your xaml file, so that when you drag/drop the item from the toolbox it will automatically add all child Activities defined in the xaml file. But I've never done this and am not sure if you can.

How to know that widget is currently is running in Qt Designer

How can I in code of the custom Qt widget know that it is currently instantiated in Qt designer?
Use case:
I build a complex custom widget that has several child widgets like QPushButton, QLabel etc.
As application logic require, when widget is created most of those sub component are not visible but in design time when I put it on a form I would like to see them.
To be able to play with style sheet at design time.
Currently what I get is a empty is only a result of constructor - minimal view (actually empty in my case).
What I am looking for is to be able to do something like
MyQWidget::(QWidget *parent)
{
....
if(isRunningInDesigner())
{
myChildWidget1->setVisible(true);
myChildWidget2->setVisible(true);
myChildWidget3->setVisible(true);
}
else
{
myChildWidget1->setVisible(false);
myChildWidget2->setVisible(false);
myChildWidget3->setVisible(false);
}
....
}
So what should I put in to this bool isRunningInDesigner() ?
From the Qt Designer manual:
To give custom widgets special behavior in Qt Designer, provide an implementation of the initialize() function to configure the widget construction process for Qt Designer specific behavior. This function will be called for the first time before any calls to createWidget() and could perhaps set an internal flag that can be tested later when Qt Designer calls the plugin’s createWidget() function.
Those are methods from the QDesignerCustomWidgetInterface plugin interface. In short: you tell the widget to behave differently when Qt Designer asks your plugin to create instances of your custom widget.

MVVM Light + Blend designer view error: Cannot find resource named 'Locator'.

The application runs fine but i could not see my design in the designer view.
It says Cannot find resource named 'Locator'. Obviously, i did not change anything in the code, i just did the data binding using the data binding dialog...
anyone facing the same problem?
There are two known occurrences where this can happen.
If you change to Blend before you built the application, the DLLs are not available yet and this error can be seen. Building the application solves the issue.
There is a bug in Expression Blend where, if you are placing a user control in another user control (or Window in WPF), and the inner user control uses a global resource, the global resource cannot be found. In that case you will get the error too.
Unfortunately I do not have a workaround for the second point, as it is a Blend bug. I hope we will see a resolution for that soon, but it seems to be still there in Blend 4.
What you can do is
Ignore the error when working on the outer user control. When you work on the inner user control, you should see the design time data fine (not very satisfying I know).
Use the d:DataContext to set the design time data context in Blend temporarily.
Hopefully this helps,
Laurent
I've come up with a reasonably acceptable workaround to this problem since it doesn't appear to have been fixed in Blend 4:
In the constructor for your XAML UserControl just add the resources it needs, provided you're in design mode within Blend. This may be just the Locator, or also Styles and Converters as appropriate.
public partial class OrdersControl : UserControl
{
public OrdersControl()
{
// MUST do this BEFORE InitializeComponent()
if (DesignerProperties.GetIsInDesignMode(this))
{
if (AppDomain.CurrentDomain.BaseDirectory.Contains("Blend 4"))
{
// load styles resources
ResourceDictionary rd = new ResourceDictionary();
rd.Source = new Uri(System.IO.Path.Combine(Environment.CurrentDirectory, "Resources/Styles.xaml"), UriKind.Absolute);
Resources.MergedDictionaries.Add(rd);
// load any other resources this control needs such as Converters
Resources.Add("booleanNOTConverter", new BooleanNOTConverter());
}
}
// initialize component
this.InitializeComponent();
}
There may be some edge cases, but its working OK for me in the simple cases where before I'd get a big red error symbol. I'd LOVE to see suggestions on how to better solve this problem, but this at least allows me to animate user controls that otherwise are appearing as errors.
You could also extract out the creation of resources to App.xaml.cs:
internal static void CreateStaticResourcesForDesigner(Control element)
{
if (AppDomain.CurrentDomain.BaseDirectory.Contains("Blend 4"))
{
// load styles resources
ResourceDictionary rd = new ResourceDictionary();
rd.Source = new Uri(System.IO.Path.Combine(Environment.CurrentDirectory, "Resources/Styles.xaml"), UriKind.Absolute);
element.Resources.MergedDictionaries.Add(rd);
// load any other resources this control needs
element.Resources.Add("booleanNOTConverter", new BooleanNOTConverter());
}
}
and then in the control do this BEFORE InitializeComponent():
// create local resources
if (DesignerProperties.GetIsInDesignMode(this))
{
App.CreateStaticResourcesForDesigner(this);
}
Note: At some point in time this stopped working for me and I ended up hardcoding the path to the Styles.xaml because I got frustrated trying to figure out which directory I was in.
rd.Source = new Uri(#"R:\TFS-PROJECTS\ProjectWPF\Resources\Styles.xaml", UriKind.Absolute);
I'm sure I could find the right path with 5 minutes work, but try this if you're at your wits end like I was!
In MyUserControl.xaml, instead of:
DataContext="{Binding Main, Source={StaticResource Locator}
use:
d:DataContext="{Binding Main, Source={StaticResource Locator}
where "d" has been previously defined as:
xmlns:d="http://schemas.microsoft.com/expression/blend/2008"
The reason and workaround explained here
http://blogs.msdn.com/b/unnir/archive/2009/03/31/blend-wpf-and-resource-references.aspx
Look at (b) part of the post.
I had a similar problem with a user control resource.
I added this in my usercontrol xaml code:
<UserControl.Resources>
<ResourceDictionary>
<ResourceDictionary.MergedDictionaries>
<ResourceDictionary Source="pack://application:,,,/GinaControls;component/Resources/GinaControlsColors.xaml"/>
</ResourceDictionary.MergedDictionaries>
</ResourceDictionary>
</UserControl.Resources>
Where GinaControls is the namespace where the control class is declared and /Resources/GinaControlsColors.xaml is the project folder and xaml resource file name.
Hope this helps.
Just add this in your App.xaml.cs at the very beginning
here's my piece of code
[STATThread()]
static void main(){
App.Current.Resources.Add("Locator", new yournamespace.ViewModel.ViewModelLocator());
}
public App(){
main();
}
Make sure the Blend has opened the entire solution and NOT just the single project containing the views. I was right-clicking in Visual Studio and selecting Open In Expression Blend. To my surprize, Blend could not find the solution file, so it only opened the single project.
When I realized this, I launched Blend directly, pointed it to the solution file, and then Blend was able to find the ViewModelLocator in my view.

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