I am currently working on a project and am running into an error that says: Syntax error in aggregate argument: Expecting a single column argument with possible 'Child' qualifier. I have a column named "Total#" in a BusinessAnalytics data table. I want to sum the column together so that I can use it to calculate a percentage of members and percentage of nonmembers. How can I fix this?
My code for a data table with running totals
Dim decTotalNumber As Decimal
Dim decPercentSales As Decimal
Dim intRow As Integer
If chkRewards.Checked = True Then
intRow = 1 'member
Else
intRow = 0 'nonmember
End If
With BusinessAnalytics.Rows(intRow)
.Item("Total#") += 1
decTotalNumber = BusinessAnalytics.Compute("SUM(Total#)", Nothing)
decPercentSales = Convert.ToDecimal(.Item("Total#")) / decTotalNumber
.Item("%Total") = decPercentSales.ToString("P1")
End With
GridView3.DataSource = BusinessAnalytics
GridView3.DataBind()
Your column name contains non-alphanumeric characters, so it should be wrapped in square brackets or "`" (grave accent) quotes.
Expression
So your statement should be:
decTotalNumber = BusinessAnalytics.Compute("SUM([Total#])", Nothing)
I want to remove the final characters "txt" if they exist at the end of a character string. However, sometimes, the characters can be found at other locations of the string also.
i.e. I would like to remove txt from "/some-text-here/txt" but not from "/txt-not-to-remove-text/" since in the last example it does not occur after the last occurance of the /
So, I only want to extract txt if it occurs at the end of the string.
string = c("/some-text-here/txt",
"/some-other-text-here/txt",
"/txt-not-to-remove-text/",
"/txt-another-line-of-text/txt")
We may use trimws
trimws(string, whitespace = "/txt", which = 'right')
-output
[1] "/some-text-here" "/some-other-text-here"
[3] "/txt-not-to-remove-text/" "/txt-another-line-of-text"
Or using sub and specify the end ($) of the string
sub("/txt$", "", string)
I'm using Standard Numeric Format Strings (see here) to format pricing on my page:
Dim price As Integer = 378
Dim s As String = (CDec(price) / 100).ToString("F")
results in string "3,78" which I print in HTML.
However, I want the decimal part "78" to be superscripted using HTML/CSS. How can I do so?
Unless the text is automatically HTML encoded (and you have access to the source of all this) you can use the <sup> tag.
To superscript only the 78 part just split the string by , (or . if that is the case) into an array and join it together again with the tag included.
For example:
Dim Parts() As String = s.Split(If(s.Contains("."), ".", ","))
Dim s2 As String = Parts(0) & ",<sup>" & Parts(1) & "</sup>"
I am using a text box for input to my SQL query. Based on the input I create a certain query and display the data in a gridview.
However I wish to make an adjustment for my users.
They often make an input like PL26... However this is not a valid name in the database to search for. Therefore I want to CHECK their input, and alter it accordingly, so they don't have to think about it.
I happen to know that when they type PL26 the correct input would be PL000026 ... The entity to search for is always "PL" + 6 characters/numbers... so if they wrote PL155, the number/string I pass to the sql query should become PL + 000 + 155 = PL000155.
I hope someone can help me how to accomplish this. That is if it is possible?
My idea/Pseudo code would be something like
If tbInput.txt's FIRST 2 CHARS are PL, then check total length of string
if StringLength < 8 characters, then
if length = 2 then ADD 4 0' after PL...
if length = 3 then add 3 0's after PL...
if length = 3 then add 3 0's after PL..
etc
....
...
Here we go:
Private Sub Button21_Click(sender As System.Object, e As System.EventArgs) Handles Button21.Click
Debug.Print(formatCode("PL1"))
Debug.Print(formatCode("PL"))
Debug.Print(formatCode("PL01"))
Debug.Print(formatCode("PL155"))
End Sub
Private Function formatCode(userInput As String) As String
Dim returnVal As String
If userInput.Length < 8 Then
returnVal = String.Concat(userInput.Substring(0, 2), userInput.Substring(2, userInput.Length - 2).PadLeft(6, "0"))
Else
returnVal = userInput
End If
Return returnVal
End Function
You may need to add some validation ensuring it starts with PL etc.
The following will work as long as there are no other non-numeric characters in between the PL and the numbers. You can always add it in your validation.
Dim newInput As String
If (input.StartsWith("PL")) Then
input = input.Remove(0, 2)
End If
' If this fails then it means the input was not valid
Dim numberPart = Convert.ToInt32(input)
newInput = "PL" + numberPart.ToString("D6")
Exctract a number by removing prefix "PL"
Parse to Integer
Use Custom Numeric Format Strings(zero placeholder) for adding zeros and prefix
Const PREFIX As String = "PL"
Dim exctractedNumber As Int32
If Int32.TryParse(tbInput.txt.Replace(PREFIX, String.Empty), exctractedNumber) = False Then
'Error nahdling
Exit Sub
End If
Dim finalFormat As String = String.Format("'{0}'000000", PREFIX)
Dim finalValue As String = exctractedNumber.ToString(finalFormat)
I would make use of the handy PadLeft method:
Dim input As String = "PL26"
Dim number As String = input.Substring(2, input.Length - 2)
If number.Length <> 6 Then
number = number.PadLeft(6, "0"C)
End If
MSDN String.PadLeft
I have raw finance text files that I'm importing into Access 2010 and exporting in Excel format. These files contain several 14 character length fields which represent dollar values. I'm having issues converting these fields into currency because of the 14th character. The 14th character is a number represented by a bracket or letter. It also dictates whether the unique field is a positive or negative value.
Positive numbers 0 to 9 start with open bracket { being zero, A being one, B being two,...I being nine.
Negative numbers -0 to -9 (I know, -0 is a mathematical faux pas but stay with me. I don't know how else to explain it.) start with close bracket } being -0, J being -1,K being -2,...R being -9.
Example data (all belonging to the same field/column):
0000000003422{ converted is $342.20
0000000006245} converted is -$624.50
0000000000210N converted is -$21.05
0000000011468D converted is $1,146.84
Here's the query that I'm working with. Each time I execute it, the entire field is deleted though. I would prefer to stick to a SQL query if possible but I'm open to all methods of resolution.
SET FIELD_1 = Format(Left([FIELD_1],12) & "." & Mid([FIELD_1],13,1) & IIf(Right([FIELD_1],1)="{",0,IIf(Right([FIELD_1],1)="A",1,IIf(Right([FIELD_1],1)="B",2,IIf(Right([FIELD_1],1)="C",3,IIf(Right([FIELD_1],1)="D",4,IIf(Right([FIELD_1],1)="E",5,IIf(Right([FIELD_1],1)="F",6,IIf(Right([FIELD_1],1)="G",7,IIf(Right([FIELD_1],1)="H",8,IIf(Right([FIELD_1],1)="I",9,"")))))))))),"$##0.00"), IIf(Right([FIELD_1],1)="}",0,IIf(Right([FIELD_1],1)="J",1,IIf(Right([FIELD_1],1)="K",2,IIf(Right([FIELD_1],1)="L",3,IIf(Right([FIELD_1],1)="M",4,IIf(Right([FIELD_1],1)="N",5,IIf(Right([FIELD_1],1)="O",6,IIf(Right([FIELD_1],1)="P",7,IIf(Right([FIELD_1],1)="Q",8,IIf(Right([FIELD_1],1)="R",9,"")))))))))),"-$##0.00")
here is a function that you can call to convert an input string like the ones in your example into a string formatted as you desire.
Private Function ConvertCurrency(strCur As String) As String
Const DIGITS = "{ABCDEFGHI}JKLMNOPQR"
Dim strAlphaDgt As String
Dim intDgt As Integer, intSign As Integer
Dim f As Integer
Dim curConverted As Currency
strAlphaDgt = Right(strCur, 1) ' Extract 1st char from right
f = InStr(DIGITS, strAlphaDgt) ' Search char in DIGITS. Its position is related to digit value
intDgt = (f - 1) Mod 10 ' Converts position into value of the digit
intSign = 1 - 2 * Int((f - 1) / 10) ' If it's in the 1st half is positive, if in the 2nd half of DIGITS it's negative
curConverted = intSign * _
CCur(Left(strCur, Len(strCur) - 1) & _
Chr(intDgt + 48)) / 100 ' Rebuild a currency value with 2 decimal digits
ConvertCurrency = Format(curConverted, _
"$#,###.00") ' Format output
End Function
If you need to have a Currency as returned value, you can change the type returned from String to Currency and return the content of curConverted variable.
Bye.