I am using a XQuery to query database in an OSB project. Consider the
following table:
userId Name Category
------ ------- --------
1 Dheepan Student
2 Raju Student
and the XQuery
let $userName:=fn-bea:execute-sql(
$dataSourceJndiName,
xs:string("NAME"),
xs:string("select NAME from USER where CATEGORY= 'Student'")
)/*:NAME[1]
return <root> {data($userName)} </root>
For this query I am getting the result as <root>Dheepan Raju</root>. But I
need to return only one row even the query returns more than one row like the
following <root>Dheepan</root>. I have used predicate [1] in the query but
no clue why it concatenates the values and returning. Can anybody tell me how
to return only the first row when more than one row is returned.
You need to use proper paranthesis:
let $userName:=(fn-bea:execute-sql(
$dataSourceJndiName,
xs:string("NAME"),
xs:string("select NAME from USER where CATEGORY= 'Student'")
)/*:NAME)[1]
return <root> {data($userName)} </root>
Related
how to manage the result of a query that returns an integer "select count(*) from table"?
1) I've tried to bind the output of a SQL Execute Statement service to an integer variable and doesn't work. (type mistmatch)
2) i've tried to use types like 'SQLResult', SQLResultRow, SQLResultColumn as well but they dont work:
Caused by: com.lombardisoftware.core.TeamWorksException: Type ismatch the value "[Element: ]" must be and instance of type atructured IBM BPM Java Class found: org.jdom.Element
3) i've tried to bind the output to a XMLElement variable and i've got this value
< resultSet recordCount=\"1\" columnCount=\"1\">5< /columnn>< /record>< /resultSet>
so now... how can I access the recordCount attribute of this node?
anyway, I don't like so manipulate a variable of XMLType, when are the types SQLResult, SQLResultRow, SQLResultColumn used?
****** EDITED *******
even if i get a result as XMLElement.. i can't manipulate it.
methods like: tw.local.result[0].rows[0].column[0].getText() don't work (the intellisense as well)
the XMLElement as an attribute "recordCount" but i don't know how to get his value..
Anyway, the only workaround that i found is to change the query in order to return a normal set of records(not a scalar value)
select field from table instead of select count(field) from table
so i could to map the output value to a list of objects and than count its length...
ugly and dirty :-(
anyone know how manipulate the XMLElement in a script block?
Please try this.
Bind the output variable from sql execute statement as 'ANY' type.
variable name - result (ANY)
Query - select count(field) as COUNTVAL from table
tw.local.totalCount = tw.local.result[0].rows[0].indexedMap.COUNTVAL;
Use Return type as XMLElement then bind a XMLElement in output mapping.
For eg: If you are using tw.local.output as ouput mapping (of type XMLElement) then,
log.info("Count "+tw.local.output.xpath('/resultSet/record/column').item(0).getText());
This will print the count
If you want to get "recordCount" Attribute then use
tw.local.output.getAttribute("recordCount");
<?xml version="1.0" encoding="UTF-8"?>
<Data>
<A><DelInfo>123-20150308-345</DelInfo><OrderNo>11</OrderNo></A>
<A><DelInfo>1204-20150308-355</DelInfo><OrderNo>15</OrderNo></A>
<A><DelInfo>153-20150408-343</DelInfo><OrderNo>10</OrderNo></A>
<A><DelInfo>44345-20150308-341</DelInfo><OrderNo>21</OrderNo></A>
<A><DelInfo>153-20150204-245</DelInfo><OrderNo>1</OrderNo></A>
<A><DelInfo>423-20150311-445</DelInfo><OrderNo>13</OrderNo></A>
..........
</Data>
I receive following XML. The DelInfo node contains a combination of
EmpId, Delivery Date and Receipt No. The OrderNo node contains the
order number wrt the Delivery Information.
The XML is stored in BaseX and I need following report to be generated from the
above XML.
<A><DelInfo>123-20150308-345</DelInfo><OrderNo>11</OrderNo><Report>20150308 - 11</Report></A>
.....
In other word, I want to insert an additional node Report with Date and Order No.
Any idea?
Replace yourdoc with your document name.
for $x in doc('yourdoc')//A
let $d := substring-before(substring-after($x/DelInfo, "-"), "-")
let $o := $x/OrderNo/text()
let $i := <C>{concat($d, " - ", $o)}</C>
return
insert node $i after $x/OrderNo
The inner substring-after() will return the string after the first -. Then, the substring-before() will return the string before the -. This way you will get the Date portion.
Let's assume my table looks like:
Code |StartDate |EndDate |Additional Attributes...
ABC |11-24-2015 |11-26-2015 | ....
ABC |12-12-2015 |12-15-2015 | ....
ABC |10-05-2015 |10-10-2015 | ....
PQR |03-24-2015 |03-27-2015 | ....
PQR |05-04-2015 |05-08-2015 | ....
Provided a Code (c) and a date range (x, y), I need to be able to query items something like:
Query => (Code = c) AND ((StartDate BETWEEN x AND y) OR (EndDate BETWEEN x AND y))
I was planning to use a Primary Key as a Hash and Range Key (Code, StartDate) with an additional LSI (EndDate) and do a query on it.
I am not sure if there is a way to achieve this. I don't want to use the SCAN operation as it seems to scan the entire table which could be very costly.
Also, would like to achieve this in a single query.
One option would be to do this using QUERY and a FilterExpression. No need to define the LSI on this case. You would have to query by Hash Key with the EQ operator and then narrow the results with the Filter Expression. Here is an example with the Java SDK:
Table table = dynamoDB.getTable(tableName);
Map<String, Object> expressionAttributeValues = new HashMap<String, Object>();
expressionAttributeValues.put(":x", "11-24-2015");
expressionAttributeValues.put(":y", "11-26-2015");
QuerySpec spec = new QuerySpec()
.withHashKey("Code", "CodeValueHere")
.withFilterExpression("(StartDate between :x and :y) or (EndDate between :x and :y)")
.withValueMap(expressionAttributeValues);
ItemCollection<QueryOutcome> items = table.query(spec);
Iterator<Item> iterator = items.iterator();
while (iterator.hasNext()) {
System.out.println(iterator.next().toJSONPretty());
}
See Specifying Conditions with Condition Expressions for more details.
Additionally, although the previous query only uses the Hash Key , you can still group the records with the Range Key containing the dates in the following format:
StartDate#EndDate
Table Structure:
Code DateRange |StartDate |EndDate
ABC 11-24-2015#11-26-2015 |11-24-2015 |11-26-2015
ABC 12-12-2015#12-15-2015 |12-12-2015 |12-15-2015
ABC 10-05-2015#10-10-2015 |10-05-2015 |10-10-2015
PQR 03-24-2015#03-27-2015 |03-24-2015 |03-27-2015
PQR 05-04-2015#05-08-2015 |05-04-2015 |05-08-2015
This way If you happen to query only by Hash Key you would still get the records sorted by the dates. Also, I believe it is a good idea to follow the advice given about the unambiguous date format.nu
i am bit confused by the nature and working of query , I tried to access database which contains each name more than once having same EMPid so when i accessed it in my DROP DOWN LIST then same repetition was in there too so i tried to remove repetition by putting DISTINCT in query but that didn't work but later i modified it another way and that worked but WHY THAT WORKED, I DON'T UNDERSTAND ?
QUERY THAT DIDN'T WORK
var names = (from n in DataContext.EmployeeAtds select n).Distinct();
QUERY THAT WORKED of which i don't know how ?
var names = (from n in DataContext.EmployeeAtds select new {n.EmplID, n.EmplName}).Distinct();
why 2nd worked exactly like i wanted (picking each name 1 time)
i'm using mvc 3 and linq to sql and i am newbie.
Both queries are different. I am explaining you both query in SQL that will help you in understanding both queries.
Your first query is:
var names = (from n in DataContext.EmployeeAtds select n).Distinct();
SQL:-
SELECT DISTINCT [t0].[EmplID], [t0].[EmplName], [t0].[Dept]
FROM [EmployeeAtd] AS [t0]
Your second query is:
(from n in EmployeeAtds select new {n.EmplID, n.EmplName}).Distinct()
SQL:-
SELECT DISTINCT [t0].[EmplID], [t0].[EmplName] FROM [EmployeeAtd] AS
[t0]
Now you can see SQL query for both queries. First query is showing that you are implementing Distinct on all columns of table but in second query you are implementing distinct only on required columns so it is giving you desired result.
As per Scott Allen's Explanation
var names = (from n in DataContext.EmployeeAtds select n).Distinct();
The docs for Distinct are clear – the method uses the default equality comparer to test for equality, and the default comparer sees 4 distinct object references. One way to get around this would be to use the overloaded version of Distinct that accepts a custom IEqualityComparer.
var names = (from n in DataContext.EmployeeAtds select new {n.EmplID, n.EmplName}).Distinct();
Turns out the C# compiler overrides Equals and GetHashCode for anonymous types. The implementation of the two overridden methods uses all the public properties on the type to compute an object's hash code and test for equality. If two objects of the same anonymous type have all the same values for their properties – the objects are equal. This is a safe strategy since anonymously typed objects are essentially immutable (all the properties are read-only).
Try this:
var names = DataContext.EmployeeAtds.Select(x => x.EmplName).Distinct().ToList();
Update:
var names = DataContext.EmployeeAtds
.GroupBy(x => x.EmplID)
.Select(g => new { EmplID = g.Key, EmplName = g.FirstOrDefault().EmplName })
.ToList();
"IN" query is not working. Please guide me if i am wrong.
KaizenResultsInformationTable is MasterTable having field "recordinfo", this field contains Child table Ids as string.
kaizenResultsRecordInformationTable is Childtable having field "recordId".
I have to match records of child.
Query:
select recordinfo from KaizenResultsInformationTable
Output: ;0;1;2;3;4;5;6;7;8;9;10
Query:
select substr(replace(recordinfo,';','","'),3,length(recordinfo))
from KaizenResultsInformationTable`
Output: "0","1","2","3","4","5"
This query is not working:
select * from kaizenResultsRecordInformationTable
where substr(recordid,0,2) in (
select substr(replace(recordinfo,';','","'),3,length(recordinfo))
from KaizenResultsInformationTable
)
This query is working:
select * from kaizenResultsRecordInformationTable
where substr(recordid,0,2) in ("0","1","2","3","4","5")
You can't use in like that. In your second query, you are passing in a single string containing a comma-separated list of values.
It is better to represent a list of IDs as one record for each value.
Also, I'm not sure why you are taking a substring of your recordid. You should usually be storing one value per column.
However, if you can't change the schema, you can use string matching with 'like' instead of 'in'. Something like this should work:
select a.* from kaizenResultsRecordInformationTable a
join KaizenResultsInformationTable b
on (';'+b.recordinfo+';') LIKE ('%;'+trim(substr(recordid,0,2))+';%')
So if your recordinfo looks like 1;2;3;4;5;6, and your substr(recordid,0,2) looks like 1, this will include that row if ";1;2;3;4;5;6;" LIKE "%;1;%", which is true.